Anyone have an answer?

As one with an interest in astounding facts I hope someone can answer this
question. Hubble's field of view for one particular observation was equated
with the area of a dime at 75 feet, how many of those areas would there be
in the total sky, northern and southern hemispheres? Incidentally, Hubble
identified at least 1,500 galaxies in that observation.

In article ,
Lysdexic wrote:

As one with an interest in astounding facts I hope someone can answer this
question. Hubble's field of view for one particular observation was equated
with the area of a dime at 75 feet, how many of those areas would there be
in the total sky, northern and southern hemispheres?

Calculate the surface area of a sphere 75 feet in diameter; the relevant
formula is 4 * pi * r^2. Divide that by the area of a dime.

-- Richard
--
"Consideration shall be given to the need for as many as 32 characters
in some alphabets" - X3.4, 1963.

Wasn't it Lysdexic who wrote:
As one with an interest in astounding facts I hope someone can answer this
question. Hubble's field of view for one particular observation was equated
with the area of a dime at 75 feet, how many of those areas would there be
in the total sky, northern and southern hemispheres? Incidentally, Hubble
identified at least 1,500 galaxies in that observation.

The area of a sphere is 4*pi*r^2, so a sphere radius 75 feet has an area
of 70685.8 square feet.

The area of a circle is 2*pi*r^2, so the area of a US dime is 0.0108434
square feet.

So the total sky sphere is equivalent to 6.5 million dimes.

--
Mike Williams
Gentleman of Leisure

"Mike Williams" wrote in message
...
Wasn't it Lysdexic who wrote:
As one with an interest in astounding facts I hope someone can answer this
question. Hubble's field of view for one particular observation was
equated
with the area of a dime at 75 feet, how many of those areas would there be
in the total sky, northern and southern hemispheres? Incidentally, Hubble
identified at least 1,500 galaxies in that observation.

The area of a sphere is 4*pi*r^2, so a sphere radius 75 feet has an area
of 70685.8 square feet.


Yes

The area of a circle is 2*pi*r^2, so the area of a US dime is 0.0108434
square feet.


A dime is 1.79 cm diameter, or 1.79/30.48 feet in diameter = 0.058727 ft

A circle's area is pi r^2, not 2 pi r^2, so the area is 0.0027087 sq ft.

Using the correct size of a dime gives me 26,096,000 (approx) times the area
of a dime.

I double checked by doing it in metric units, same result.

So the total sky sphere is equivalent to 6.5 million dimes.


Your answer is a factor 4 out due to something in the dime area calculation.

--
Mike Dworetsky

(Remove pants sp*mbl*ck to reply)

Richard Tobin wrote in message ...

Calculate the surface area of a sphere 75 feet in diameter; the relevant
formula is 4 * pi * r^2. Divide that by the area of a dime.

got it

i'll calculate it this weekend

mk5000

"well i think it's a tiny little franchise that's really going to catch on.
it's gonna be a big deal for dreamworks. seriously, it's a blast. as a kid
i always wanted to be a cartoon more than anything else. and I got my
chance"--john krasinski

"Lysdexic" wrote in message
...
As one with an interest in astounding facts I hope someone can answer this
question. Hubble's field of view for one particular observation was
equated
with the area of a dime at 75 feet, how many of those areas would there be
in the total sky, northern and southern hemispheres? Incidentally, Hubble
identified at least 1,500 galaxies in that observation.


It's not necessarily the picture you were thinking of but the Hubble Ultra
Deep Field* image
has a field size of 3 arc minutes square**, which is comparable to a dime at
about 67 feet

Thus, you would need about 16,500,000 images to cover the sky***.
There are claimed to be about 10,000 individual galaxies in the HUDF image.


* http://hubblesite.org/newscenter/arc...eases/2004/07/
** http://hubblesite.org/newscenter/arc.../07/fastfacts/
*** HUDF required 1million seconds exposure time in total, hence it would
take appx 530,000 years to image the whole sky to that level of quality.

In uk.sci.astronomy message , Fri,
11 May 2007 18:41:20, Lysdexic posted:
As one with an interest in astounding facts I hope someone can answer this
question. Hubble's field of view for one particular observation was equated
with the area of a dime at 75 feet, how many of those areas would there be
in the total sky, northern and southern hemispheres? Incidentally, Hubble
identified at least 1,500 galaxies in that observation.

Make a straight row of touching dimes stretching 75 feet in each
direction (150 feet in all). Count them. The square of that is the
result that you want.

--
(c) John Stockton, Surrey, UK. Turnpike v6.05 MIME.
Web URL:http://www.merlyn.demon.co.uk/ - FAQqish topics, acronyms & links;
Astro stuff via astron-1.htm, gravity0.htm ; quotings.htm, pascal.htm, etc.
No Encoding. Quotes before replies. Snip well. Write clearly. Don't Mail News.

On Fri, 11 May 2007 18:41:20 +0800, "Lysdexic" wrote:
one particular observation was equated
with the area of a dime at 75 feet, how many of those areas would there be
in the total sky, northern and southern hemispheres?

It is a poor analogy, a dime, nor any other circular area, does not
tile the surface of a sphere

One could also ask " err, wots this dime thing anyhow" !
We're British dont'y'know,,,
stands back whilst everyone does Hubble in 10pees.

In article ,
WaltA wrote:

one particular observation was equated
with the area of a dime at 75 feet, how many of those areas would there be
in the total sky, northern and southern hemispheres?

It is a poor analogy, a dime, nor any other circular area, does not
tile the surface of a sphere

They do to a within about 15%.

-- Richard
--
"Consideration shall be given to the need for as many as 32 characters
in some alphabets" - X3.4, 1963.

On 12 May 2007 21:48:41 GMT, (Richard Tobin) wrote:

In article ,
WaltA wrote:

one particular observation was equated
with the area of a dime at 75 feet, how many of those areas would there be
in the total sky, northern and southern hemispheres?

It is a poor analogy, a dime, nor any other circular area, does not
tile the surface of a sphere

They do to a within about 15%.

Arghhh!! Spoilsport , that was going to be my next brain-teaser for
the group " how much is left over going spare " !!