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Einstein's Most Illustrious Red Herring.
On Dec 5, 9:24 am, PD wrote:
On 12/5/2011 2:05 AM, Koobee Wublee wrote: Just how fvcking difficult is it to start your stop watch and stop your fvcking stop watch?shrug So are you standing at the starting location of the traversal when you begin the stop watch? Or are you standing at the finishing location of the traversal when you begin the stop watch? Whatever you want to do. It is a supposed to be a free country. shrug If so, how do you compensate for the time it took for the light from the distant event to get to you? You tell Him. shrug Be VERY specific here. It is up to you. shrug (If you'd like to say, "I don't compensate for it at all because I don't need to," then let's just go that route first.) A better question to ask are why synchronizations are necessary and synchronizations of what time flow to what time flow. shrug When playing with your stop watch, there is no synchronizations involved. Just pressstart and thenstop. Most of the cases, the start andstop are the same button. When measuring speed, there is no synchronization of any sorts involved. So, just how fvcking difficult can this be? peter webb is a malicious troll. peter webb needs to go to hell and stay there, and enjoy the cesspool of the fermented diarrhea of Einstein the nitwit, the plagiarist, and the liar --- peter webb’s god.shrug |
#12
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Einstein's Most Illustrious Red Herring.
On Dec 5, 2:55 am, "Paul B. Andersen" wrote:
On 05.12.2011 09:05, Koobee Wublee wrote: Just how fvcking difficult is it to start your stop watch and stop your fvcking stop watch?shrug When playing with your stop watch, there is no synchronizations involved. Just pressstart and thenstop. Most of the cases, the start andstop are the same button. When measuring speed, there is no synchronization of any sorts involved. So, just how fvcking difficult can this be? peter webb is a malicious troll. peter webb needs to go to hell and stay there, and enjoy the cesspool of the fermented diarrhea of Einstein the nitwit, the plagiarist, and the liar --- peter webb’s god.shrug Can you please explain how you would measure the speed of light, according to your definition of speed? That is a red herring, Paul, and you know it. shrug If you dispute the way he defined what speed is, you are welcome to define your own definition, but be very prepared when He comes down on you harder than Thor’s hammer. shrug |
#13
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Einstein's Most Illustrious Red Herring.
On Dec 5, 9:21 am, PD wrote:
On 12/4/2011 4:07 PM, Koobee Wublee wrote: Daryl McCullough does not know what he is talking about. Speed is an observer dependent quantity, and it certainly DOES NOT depend on any synchronizing bull****. Speed is defined as [observed] displacement [moved] divided by the observer’s time it takes to traverse that said displacement. And how do you propose to measure the time for something to traverse a distance? After all, the two events marking the beginning and ending of that traversal are in different locations. So be specific in how you would mark the time difference between two spatially separated events. The same issue also applies to if you decide indeed two time flows need to be synchronized when measuring speed. How do you deal with it then? shrug Gee! This is Galilean stuff.shrug [rest of garbage snipped] You need to understand what speed is first. It is the basics. shrug |
#14
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Einstein's Most Illustrious Red Herring.
"Koobee Wublee" wrote in message ... On Dec 5, 9:24 am, PD wrote: On 12/5/2011 2:05 AM, Koobee Wublee wrote: Just how fvcking difficult is it to start your stop watch and stop your fvcking stop watch?shrug So are you standing at the starting location of the traversal when you begin the stop watch? Or are you standing at the finishing location of the traversal when you begin the stop watch? Whatever you want to do. It is a supposed to be a free country. shrug __________________________________________ No, he was asking how *you* calculate the speed without synchronising clocks at some point, which you claimed to be able to do. Why won't you answer? Is it because you can't do this without synchronising clocks, and you don't want to admit that you don't know what you are talking about, and so you are ignoring the question so as to not look like an idiot? |
#15
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Einstein's Most Illustrious Red Herring.
"Koobee Wublee" wrote in message ... On Dec 5, 2:55 am, "Paul B. Andersen" wrote: On 05.12.2011 09:05, Koobee Wublee wrote: Just how fvcking difficult is it to start your stop watch and stop your fvcking stop watch?shrug When playing with your stop watch, there is no synchronizations involved. Just pressstart and thenstop. Most of the cases, the start andstop are the same button. When measuring speed, there is no synchronization of any sorts involved. So, just how fvcking difficult can this be? peter webb is a malicious troll. peter webb needs to go to hell and stay there, and enjoy the cesspool of the fermented diarrhea of Einstein the nitwit, the plagiarist, and the liar --- peter webb’s god.shrug Can you please explain how you would measure the speed of light, according to your definition of speed? That is a red herring, Paul, and you know it. shrug _______________________________ No its not. It is a perfectly reasonable question. How would you measure the speed of light without synchronising clcoks? If you dispute the way he defined what speed is, you are welcome to define your own definition, but be very prepared when He comes down on you harder than Thor’s hammer. shrug _______________________________________ So why don't you answer the question? You claimed to be able to measure speed of light without synchronising clocks, when asked how, you go on about Thor's hammer and some vague religious mumbo jumbo. Typical nutter. |
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Einstein's Most Illustrious Red Herring.
On Dec 5, 9:42 pm, "Peter Webb" wrote:
"Koobee Wublee" wrote: So are you standing at the starting location of the traversal when you begin the stop watch? Or are you standing at the finishing location of the traversal when you begin the stop watch? Whatever you want to do. It is a supposed to be a free country. shrug No, he was asking how *you* calculate the speed without synchronising clocks at some point, which you claimed to be able to do. Why won't you answer? You don’t need any synchronizations between two time flows to measure speed, dumb ass. shrug Is it because you can't do this without synchronising clocks, and you don't want to admit that you don't know what you are talking about, and so you are ignoring the question so as to not look like an idiot? Is peter webb now a bitch of PD? shrug |
#17
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Einstein's Most Illustrious Red Herring.
"Koobee Wublee" wrote in message ... On Dec 5, 9:42 pm, "Peter Webb" wrote: "Koobee Wublee" wrote: So are you standing at the starting location of the traversal when you begin the stop watch? Or are you standing at the finishing location of the traversal when you begin the stop watch? Whatever you want to do. It is a supposed to be a free country. shrug No, he was asking how *you* calculate the speed without synchronising clocks at some point, which you claimed to be able to do. Why won't you answer? You don’t need any synchronizations between two time flows to measure speed, dumb ass. shrug _____________________________________ So you claim. Now show us how it is done. Is it because you can't do this without synchronising clocks, and you don't want to admit that you don't know what you are talking about, and so you are ignoring the question so as to not look like an idiot? Is peter webb now a bitch of PD? shrug ______________________________ No. But still you don't answer the question. Why not? |
#18
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Einstein's Most Illustrious Red Herring.
On 06.12.2011 06:23, Koobee Wublee wrote:
On Dec 5, 2:55 am, "Paul B. Andersen" wrote: On 05.12.2011 09:05, Koobee Wublee wrote: Just how fvcking difficult is it to start your stop watch and stop your fvcking stop watch?shrug When playing with your stop watch, there is no synchronizations involved. Just pressstart and thenstop. Most of the cases, the start andstop are the same button. When measuring speed, there is no synchronization of any sorts involved. So, just how fvcking difficult can this be? peter webb is a malicious troll. peter webb needs to go to hell and stay there, and enjoy the cesspool of the fermented diarrhea of Einstein the nitwit, the plagiarist, and the liar --- peter webb’s god.shrug Can you please explain how you would measure the speed of light, according to your definition of speed? That is a red herring, Paul, and you know it.shrug I can understand why you can't answer the question. :-) There is no way you can measure the speed of light, where "speed" is according to your definition; "Speed is defined as [observed] displacement [moved] divided by the observer’s time it takes to traverse that said displacement." So maybe your definition of speed isn't very sensible? -- Paul http://www.gethome.no/paulba/ |
#19
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Einstein's Most Illustrious Red Herring.
On Dec 6, 3:12 am, "Paul B. Andersen" wrote:
On 06.12.2011 06:23, Koobee Wublee wrote: That is a red herring, Paul, and you know it.shrug I can understand why you can't answer the question. :-) Really? What? shrug There is no way you can measure the speed of light, where "speed" is according to your definition; Therefore, the question is a red herring. shrug "Speed is defined as [observed] displacement [moved] divided by the observer s time it takes to traverse that said displacement." So maybe your definition of speed isn't very sensible? Let’s see. An object moved for 3 meters in 1 second. According to the above definition of speed, it should read 3 meters per second. What does your definition of speed give you? shrug If you have issues with the above definition of speed, it is entirely your own problem. Giggling like a tusseladd withdrawn from reality and occasionally sucking your thumbs does not hide the fact that it is still your problem. shrug If you have problems with the following, you need to resolve it yourself, and only you can do it. shrug ** Speed = sqrt((ds/dt)^2) |
#20
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Einstein's Most Illustrious Red Herring.
the galilean **** does not bother itself
with the internal (angular) momenta of atoms, which are not simply abstract (as supposed by the professors of quantum weirdness .-) we can formulate a gedanken, where you put yourself, the atom of (say) plutonium in Einstein's superfast elevator; given that your electrons are an 1820th of the mass of your protons, how does acceleration & deceleration look to your nucleus? This is Galilean stuff. |
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