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Quadibloc - 17th Attempt
"Quadibloc" wrote in message
... (begin quote) At the end of Section 3 we find the transformation derived: tau=beta(t-vx/c^2), xi=beta(x-vt), eta=y, zeta=z, where beta=1/sqrt(1-v^2/c^2). With trivial algebraic manipulation we can derive the inverse transformation: t=beta(tau+v(xi)/c^2), x=beta(xi+v(tau)), y=eta, z=zeta. (end quote) =============================================== Not only is Savard hopeless at simple algebra, he quotes the drool of some unnamed moron who is equally hopeless. Perhaps he can show, step-by-step, his trivial derivation, like this: xi = beta(x-vt) Divide both sides of the equation by beta xi/beta = beta(x-vt)/beta Since beta/beta = 1, xi/beta = 1*(x-vt) Add vt to both sides of the equation xi/beta +vt = (x-vt)+vt Since vt - vt = 0, x = xi/beta +vt Why is Savard multiplying xi by beta instead of dividing? -- This message is brought to you from the keyboard of Lord Androcles, Zeroth Earl of Medway. When I get my O.B.E. I'll be an earlobe. |
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