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#121
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Gravitation and Maxwell's Electrodynamics, BOUNDARY CONDITIONS
"Sergey Karavashkin" wrote in message om... "George Dishman" wrote in message ... "Sergey Karavashkin" wrote in message om... "George Dishman" wrote in message ... "Aleksandr Timofeev" wrote in message om... For a resonance is indispensable: ..... It may sound strange but today the meaning of 'nonlinear system' is quite fuzzy. Examples of non-linearity for me would be the transistor in the circuit above that has an exponential relation between base current and Vbe, an FET used as the amplifier that has a quadratic Vgs to Idss relation or a thermistor used for amplitude stabilisation. The latter is non-linear if the resonant frequency is close to the thermal time constant but linear if it is much higher since the thermistor is a pure resistor at any given temperature. The result of non-linearity is usually to produce harmonics, predominantly second for the FET, third for the thermistor and lots for the transistor ;-) I hope that clarifies what I mean and why I do not consider it "indispensable" for resonance. In my work it is usually undesirable except in frequency multipliers. In all these cases you are absolutely right. In such calculations there actually appear quadratic, cubic etc. terms which require to consider higher harmonics. True, in these cases there exists one "but" from higher level of solutions than is used now. I'll try to explain. Let us consider an usual homogeneous finite lumped line, only the constraints between its elements are massive (in distinct from usual models where we take the constraints massless). What will occur there? In this case the constraints itself make a lumped line having its own resonance frequencies. Under definite conditions these frequencies will be LOWER than resonance frequencies of the main line (or between them). Wherethrough, if we consider such line as an usual model with massless constraints (and conventional mathematical tool allows us no other possibility), this line will be for us nonlinear, as the elastic line appears dependent on frequency. We will expand it into series, yield some harmonics, while factually this line is quite linear. Are you saying that, after any initial transient has decayed, a pure sine wave applied to such a line will create harmonics even if every element is linear? I would not expect that but I could be wrong. This is, of course, only one example, and there are very many questions. Far from all cases can be reduced to this example, but such example exists, can be calculated mathematically and modelled experimentally. ;-) I think you miss the point though: "Aleksandr Timofeev" wrote in message om... For a resonance is indispensable: - nonlinear transformer of energy; A RLC circuit is linear and resonant. Certainly systems can be non-linear but Aleksandr's statement was that a "nonlinear transformer of energy" was "indispensable" for resonance. I say that it is not "indispensable" and that resonance commonly occurs in systems where the power is absorbed by a linear element such as a resistor. So when you are speaking of nonlinear transformer of energy and when George Dishman speaks of linear RLC circuit, it would be interesting to ask you for more precise thesis. Aren't you against? I hope I have clarified my meaning, there are no higher order terms in the transfer characteristics of resistors, capacitors or inductors hence no harmonics produced. Note though that a pendulum need not be a linear system in my view since the restoring force is only proportional to displacement as an approximation at low amplitudes. In the light of models having resonance subsystems, I would like to recall you an air wave transformer that matches antenna with feeder. This transformer is fully "aside" the main trunk and is connected to it by only one end. None the less, it essentially changes the input impedance of antenna. And if we take many such transformers (or more complex circuits) and arrange them with a definite interval along the cable ... ? ;-) .... they are still linear by my understanding. [I wrote:] Remember, a child on a swing is a resonant system, small pushes correctly timed can build up a large amplitude, but it is not a wave phenomenon. May I ask you, what are the components of wave phenomenon? If a wave propagates in water on which a child swims - this is a wave phenomenon, but a child as a heterogeneity with which the wave interacts - this is not a wave phenomenon? ;-) It seems, you are suggesting too simplified approach. The words "wave phenomenon" mean a phenomenon created by waves. The interference patterns created when the waves reflect from the child are a wave phenomenon but the child would still be there if the waves were removed. Okay, let us take an usual infinite channel and direct to both its sides a plane surface wave. This is a wave process, isn't it? The source works and sends the wave to both sides of its place. Now we take a screen and cut off the channel from one side. Is it still wave process? Now it is created by direct and reflected WAVES. But we have in the channel now not a progressive but a standing wave! We don't stop and cut off the channel from another side. Now we have all conditions for resonance, and judging by your reasoning, this is already not a wave process, but the effect is created by way of multiple reflection of waves from boundaries... Of course that is a wave process. What has that to do with the child on the swing? The same with a child on the wave. A child is an obstacle for the wave with which the wave interacts. The wave itself is a process on the water surface; the properties of water, as well as properties of all obstacles on the water, form the features of wave processes on this water. Don't they? ;-) Yes, they are aspects of the system that is creating the phenomenon but they are not the phenomenon itself. But if a child sits on a pneumatic dolphin either stands on a boat, will it essentially change the pattern? I would say the pattern is a wave phenomenon but the child is only part of the system that is creating the pattern. Of course, this is correct. The child is not created by the waves. And water as well! ;-) Exactly. Sergey, I agree what you have said and you agree what I said so how do we differ? Perhaps you would like to say, if we think a child as an integral body, this will be not a parametric excitation, but if as a system having its own resonance subsystems, this will be a parametric excitation? Possibly, which parameter do you think is being varied? In this case, there will change not some parameter of elastic system of a child (or a child on a pneumatic toy, or on a boat) - i.e., the reaction of subsystem of a child to the external affection. Due to it, the interaction of wave with a child as an obstacle will also change. I don't see why you think this is parametric excitation, it seems to me that the waves are simply altering the water level and thus applying a varying upward force to the boat and child. If they subsystem of boat and child has its own resonances, the excitation is still by variation of the force and not by variation of any parameter of that subsystem. By the way, this has a great similarity with the dynamic EM field interaction with the resonance system of atom, as well as with one of the main causes, why long-sized ships are broken in storms. It was A.N. Krylov who studied ship strength against wave affection in the measure possible for mathematics of that time (first half of 20th century). He also tried to yield solutions close to analytical and applied matrixes. He made very much and with his name a great breakthrough in vibration theory has been connected, but he hadn't our solutions and our methodology. Possibly, but this is always a very conventional issue that depends on relationship between the natural frequencies and excitation frequency. ;-) Parametric excitation from what I have read on the subject means excitation by variation of one of the parameters of the system rather than by applying a simple signal. I would call a system where there are multiple resonant frequencies, such as the child on the boat, "compound". If you connect a motor to the plates of a capacitor to move them closer or further apart and use that in an LC circuit, it is "parametric" and the parameter being changed is the capacitance. One important aspect is that the resonant frequency is varied during each cycle in the parametric case although this is not a definition nor perhaps even necessary (if the parameter does not play a part in setting the resonant frequency). I wouldn't argue, such approach to parametric resonance is also justified. Simply, as I showed above, there can change not some parameter of the system elements but reaction of the very subsystem at definite frequencies. If the subsystem can resonate over a range of frequencies depending on amplitude so that it can respond to a harmonic of the primary source, then perhaps that system is exhibiting parametric resonance, but if the coupling is direct rather than via modulation of a parameter then I would not call it parametric excitation. The input impedance of resonance subsystem also is a parameter, isn't it? ;-) It is though it is of lesser importance in setting the operating frequency. However, I suppose it would be possible in theory to drive a system by variation of the input impedance. Perhaps I wouldn't touch this feature of vibration process, should we consider just the parametric RLC-oscillator. But, as I understand, you consider EM wave interaction with atom, and parametric oscillator is only some approach to grasp the processes occurring in atom. In this meaning, it seems to me important to account the change of input impedance of vibration system. ;-) In an atom it seems simple to me, any change in the energy of an orbiting electron in such a model would be likely to affect the radius of the orbit. That would clearly be a key parameter in determining the natural frequency. George |
#122
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Gravitation and Maxwell's Electrodynamics, BOUNDARY CONDITIONS
Dear Sergey Karavashkin:
"Sergey Karavashkin" wrote in message om... You are taking the offended pose and accuse me rude and wrong, but is it really so? Top posting is considered rude. You constantly refer to models that are wrong. You are not wrong, but perhaps only mistaken. I many times wrote you of contradictions in photon properties that are the underpinning of theory which you try to defend. But instead lifting these contradictions in my eyes, you every time change the subject of our discussion and accuse me hands-waving. See - even calling me devil again - see: You are not the devil. You do conjure arguments that are not associated with the topic at hand. It will not serve either of us to get swayed from the topic. If you wish to start a new one, then posters that know something about the topic, and are not inured to speaking with you about it can do so. 1) We all know, we receive EM waves "We" do not know this. This is your assertion. sequentially at the receiver and then amplify the signal (far from always - if necessary, we can investigate without amplifying). This is not the matter. The matter is, what the receiver receives! In order the received signal to have the time of coherence about 100 hours for radio waves and fractions of a second for special masers, with your representation of the flow of infinitesimal photons, photons have to be very well ordered. As does DNA. But this seems to occur frequently also. But, as is known, according to Planck's postulate, all the energy is within quantum. But to order photons, you need some additional controlling energy! Or they violate also conservation laws? With your approach, everything is possible. ;-) To order photons, you only need a Universe that maintains an "arrow of time". This is an easy thing. The photons arrive in the order emitted. 2) If your photons are infinitesimal, they would have quite strange fields. Their E-field would be not central but transverse and lie in polarisation plane of dynamic EM field. A half of period this field would be directed to one side, and another half - in opposite direction. Their H-field would be also very strange. I even don't mention that photon density in your model would vary along the field propagation, and in maximums of field strength there has to be bunching of photons (as you know, the energy of photons having the same frequency is similar - it means, the alternating field can be created in this case only and exceptionally by variation of their density). If we take into account that these photons are emitted by a huge number of atoms, the additional field that has to order these photons must be incredibly strong, and it has to propagate with photons. ;-) And this all agrees with experiment. In fact they are using light to do the reverse... manipulate matter based on the magnetic moment the matter has (or can be induced to have). 3) I separated the substantiation of the last statement to this item. You are stating, photons interact with each other in absence of any particles, and particular, of electrons. Only in head-on collisions. There is no evidence that photons are aware of one another otherwise. Presumably gravitation would allow hosts of photons to affect individual members... The fact that in this case you may not use QM, neither QED, nor QFT where the opposite has been proved - this is for your account. You even don't understand: when you so sufficiently and in all aspects change conventional interpretations of the theory which you are trying to defend, you in this way unambiguously admit these theories wrong!!!!! They cannot be wrong based on my testimony. But here is also another aspect. I understand, when you had to admit the infinitesimal size of photons, you have to admit it charged. I did no such thing. I also admitted the photon was the width of the Universe, if you'll recall. But if photons were charged, it will lead to the situation that the light beam will be sharply diverging and no lens can help you to reduce it to a point. This is your fabrication. You fix the apparent problem. Furthermore, as all photons move with the same velocity, a part of photons has to brake the photons following them. I don't follow why you think this "coupling" would be necessary or possible. In this case to postulate the constant velocity for particles would be ignorant, and SR will not help you to substantiate such postulates. In this case, you are talking to your shadow. I have said no such things. This is the wave process where the velocity of propagation of process in homogeneous space is constant - here we haven't such condition connected with the properties of medium. ;-) To arrange photons in the given shape, you cannot make it do without some additional field which would carry all information, as just it will form photon flow. What for are then the very photons? ;-) As I have stated to others, and I had thought I had for you, if the photon is the width of the Universe, the Universe is the medium. 4) Some more about point-sized photons. This is the problem of instantaneous radiation-absorption. You suggest photon point-sized and naturally suppose it carrying the field well less than period. Fine! Please explain me, how does photon carry the information about the light frequency? Frequency is observer dependent. This is not the photon's responsibility. As you know, in one reference frame the light has one frequency, in second - another, in the third - third frequency. Photon is not only point-sized and so it cannot contain the information of frequency, but it cannot transform, since all bodies that move with the light velocity aren't already subject of any transformations. ;-) Light has no mass. Therefore the transforms don't apply. What can change within photon if it doesn't carry any information and cannot transform as GR? I hear, you are again accusing me in ignorance... Also fine! I do not accuse you of ignorance, but of posturing (talking around the point) and obfuscation (hiding your intentions behind misdirection). It means, the detected frequency depends on the velocity with which we receive these flows? Right? ;-) Well, where is the information of frequency - in photon either in the distance between photons? This means, the energy of photons doesn't obey Planck law? ;-) You see, when we change the reference frame, the frequency changes - it means, the energy changes! ;-) See David, where to brings you your insistence to do not see and to accuse all us ignorant. Not "us all", Sergey. Physician, heal thyself. ;-) You have fully violated - rather, smashed the postulates and mathematical tool of QM, QED, QFT - and you want to prove us something? What's the conception on which you rely? That you again speak to all but what is the point. To which papers are you referring? For which of tens of topics that you have raised in an effort to avoid supporting "resonance" as a means of describing the photoelectric effect? Which topic do you need me to produce a paper on? Which mathematical tool do you use? This to what you are trying to refer has been built on other postulates, so even your virtual light particles you may not call photons, as this word means other concept, this concept has other phenomenology for which the tool of QM, QED, QFT has been developed. Your assertions, so far unsupported. 5) Concerning the boundary conditions for light which you don't grasp, despite Aleksandr's multiple explanations. What namely don't you understand? In your conception, light consists of photons whose density varies in space. These photons are permanently emitted by radiator and somewhere absorbed by receiver. Good so far... Of course, you took the full course of resonance systems! Don't you understand that the boundary conditions for a flow are determined by the pattern of source and sink? '-) Actually only for a bonded structure does the distance between source and measured displacement come in. Does the work function vary based on how far apart the source and conductive plate are? Do the electrons get a different remainder KE? The answer to both is "NO". Your argument is invalid. Strange... To the point, you are saying, you didn't see my reference to the solutions for mechanical systems. Again strange... Wasn't it you who suggested me to enlighten the newsgroup, how do I yield them? If you forgot, I can simply repeat this place from that my post to you. Thank you. I saw these as electrical circuits, despite the word "mechanical" embedded therein. http://angelfire.lycos.com/la3/selft...42/load42.html This is the dynamics (essentially) of a bridge, ladder, etc. The photoelectric effect does not seem to care what the bonding structure of the base metal is, nor is there a time delay in release of the photoelectron. This behaviour cannot be expressed by your structure. Your analog is invalid. http://angelfire.lycos.com/la3/selft...44/load44.html Still more bridge stuff... http://angelfire.lycos.com/la3/selft...46/load46.html Mechanical? Good to the end, as always Sergey. David A. Smith |
#123
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Gravitation and Maxwell's Electrodynamics, BOUNDARY CONDITIONS
"George Dishman" wrote in message ...
You still have a need to show that the energy loss in your "vibrating system" is less than the value needed to allow resonance. You cannot lose more than about half the energy per cycle or you cannot get resonance. Yes I suppose in certain systems resonance wont occur. but does that neccesarily mean that a resonating system of nodes in a medium cannot be compared to a wave only atom? I am not sure of your point there. Perhaps you should explain what you mean by "capacitor-like" because you certainly have me confused. I understand you don't mean it electrically. For example in a mass-spring system, the spring plays the part of a capacitor while the mass is the inductor but that has nothing to do with quantisation. I think its true I may assign the term tcapacitor like incorrectly. By `capacitor like` I assume a electrical capacitor takes a current lets say dc for now and re-outputs it in pulses of lets say 20 pulses per second. THats why I compare it to a bucket fillig and emptying literally. I assume a capacitor takes a steady flow of water and `quantizes` it into discreet packages. As if the steady water flow were diverted to a bucket which filled and then tipped over , released a pulse of water and then proceeded fill again. So on one side of the water bucket `capacitor` the flow is a steady flow whilst after the water bucket `capacitor` the flow comes in pulses of water interspersed with no water. However your analogy of the capacitor seems to imply that the capacitor in an electrical circuit doesnt take an electrical current and re output it at a different frequency but rather it just increases the voltage more like a water tank on a apartment roof gives the tenants a higher water pressure than if they were to get their water directly from the mains. But that only works if the water use is intermittent. In which case a capacitor could only work if either the usage demanded of it were intermitent or if the capacitor itself released the flow in pulses? A capacitor is like an infinitely high bucket of constant cross-section. The height of the water (and hence the pressure at the bottom) is proportional to the volume of water in the bucket and inversely proportional to the cross-sectional area, just as the voltage across a capacitor is proportional to the charge and inversely proportional to the capacitance. Fill the bucket too full and the sides rupture so you don't have a bucket any more. Apply too much voltage to a capacitor and you get a loud bang with a puff of smoke, you don't have a capacitor any more. Thanks for a simpler description in analogy there George. But could you add to it a bit and say how in that above analogy the pulsing occurs that supposedly a capacitor gives. Or at least what happens in the above analogy while the `water` flows. The analogy still doesnt make complete sense to me . For instance you say the height of the water is proportional to the volume of the water but you also say the height is infinite which suggests that in analogy the volume is infinite? I think theres a bit missing in your analogy as I dont quite understand. Is it that the height isnt infinite but when the bucket fills to a certain height it begins to drain at a constant rate sort of like a water reservoir on a building roof? What is the analogy mechanism that ties in the bucket above with the rest of the circuit. How does it drain ? And does it do so in pulses ie it releases all the water at once (thats what I assumed an analogy of an electrical capacitor does) or does it have an outflow pipe at the bottom releasing a constant flow of water? I don't follow that at all, in what way is there any similarity to a capacitor in that? Hopefully I have answered you above but just in case.. What I was trying to acheive was to allow a resonant system to be used as an analogy for a wave atom. In my overlapping of waves of different wavelengths I notice that a composite wave length of much longer than any of the 3 input wavelengths is acheived. The composite wave pulses at peak amplitude once every 4 seconds which is much greater than the extra input wavelength of 1 3/4 seconds frequency and the amplitude of the new composite peak is greater then the amplitude of the additional `driving` wavelength of 1 3/4 beats a second . What has happened is that a wavelength input into a vibrating system of two superposed wavelengths 1/2 and 1 beats a second is re-output at a new wavelength of greater amplitude but less than 1/2 the wavelength of the input frequency of 1 3/4 beats a second. My understanding of `capacitor` until now at least has been that a capacitor can take an input flow of one frequency and output it at a much lower frequency of greater amplitude. Hence my comparison of the resonating system described above as capacitor like. However it may be that an electrical capacitor is operating differently from what I thought as my earlier part of this post covers and your earlier description shows me. I also admit on thinking about it that a PMT outputs the input light energy in a series of pulses sometimes called photons. If the intensity of input light increases then the result is not an increase in pulse(photon QT calls them)amp-litude but an increase in pulse frequency. Therefore my above analogy does not help me as I only show how an increase in wavelength can result in a decreased output wavelength. What I need to do is see how a resonating system when given an additional driving force reacts. For instance in a resonating jar of water. The nodes are lets say 1/2 inch high and 1/2 inch diameter . What happens when the additional driving force is exerted? Does the node height respond by becoming lets say 1 inch in height with the same old diameter? And if so what happens when the amplitude of the additional driving force increases even more ? Does the node continue rising in height without altering its diameter so it theoretically can become under enough `additional driving force` a column of lets say 3 feet tall and 1/2 inch diameter of water? Somehow I doubt it . My guess is that at a certain point the node height reaches critical and releases its energy back to the system and falls back to 1/2 inch height . THen under the additional force it has to go back up and then fallss again . the result may be possibly that the node under additional driving force pulses at a overlapping frequency of one amplitude but a variable frequency proportional to the amplitude of the input driving force. In other words if this does occur in a resonant system then it can duplicate the neccesary analogy of what is seen in an atom in a PMT under input light conditions? What do you think? More importantly do you know if what happens to a resonant system is as I have described above? Because if it is I may have the answer to my big problem of describing how a wave only atom can quantize incoming radiation into similar amplitude pulses with the frequency proportional to the input intensity as seen in PMT`s. Sean |
#124
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Gravitation and Maxwell's Electrodynamics, BOUNDARY CONDITIONS
"Robert J. Kolker" wrote in message ...
How do you account for the efficacy of quantum electrodynamics which rests squarely on the theory of special relativity? Classical electrodynamics cannot account for the existence of atoms, the Compton effect or the photoelectric effect. To say nothing about the Lamb effect. Quantum theory has been supported in every experiment challange. It has yet to fail. Whereas classical physics cannot account for black body radiation, nor can it correctly predict the specific heat of many substances. So why does quantum theory work? I have yet to look at black body radiation but will try to answer that. But I disagree that QT answers it all. It cannot explain the missing 90 per cent of the mass in the universe and the other 10 per cent actually cant be acounted for either as QT and the standard model cannot explain the existence of matter and what causes gravity /mass. So really QT cant explaining anything at all. QT doesnt work, otherwise you would be able to tell me how QT explains the Unexplained speed of rotation of galaxies I dont know where you read me saying I support photon concept? Everything I have posted on these newsgroups is meant to show that I beleive that photons are non existent and imaginary. See the experiment of Grangier, Roger and Aspect which proves that photons exist and that the semi-classical theory of light and matter is not adequate. You havent read all my posts. I have actually shown mathematically that if a wave only atom can act as a capacitor it can predict the results of Grangiers experiment MORE accurately than QT. In fact QT cannot predict Grangiers results as it predicts a=0 wheras grangier got a=0.018. To get QT to work Grangier had to fiddle his results and add a unexplainable `Accidental rate` to get QT`s predictions to match observation. On the other hand classical does predict 0.018 and also predicts the decline in alpha proportionate to the decrease in input light per event. QT always predicts a=0 which is incorrect. Grangiers results are a vindication of classical theory and a good example of how QT does not work. Classical physics is deficient in explaining and predicting phenomena in the small and even in the large. Classical thermodynamics and statistical mechanics cannot account for black body radiation correctly. Classical theory also predicts and explains the high energy gamma ray observations made in GRB`s as I have done so at my website at www.gammarayburst.com for years. M M Gonzalez`s paper this august in Nature shows how QT and the standard model CANNOT EXPLAIN grb`S and the observed high energy gamma rays of GRB`s Sean |
#125
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Gravitation and Maxwell's Electrodynamics, BOUNDARY CONDITIONS
"sean" wrote in message om... "George Dishman" wrote in message ... You still have a need to show that the energy loss in your "vibrating system" is less than the value needed to allow resonance. You cannot lose more than about half the energy per cycle or you cannot get resonance. Yes I suppose in certain systems resonance wont occur. but does that neccesarily mean that a resonating system of nodes in a medium cannot be compared to a wave only atom? I am not sure of your point there. The tone of your post suggested you need not consider 'containment' further. In fact you always have to deal with it since you must ensure the energy isn't lost and usually the size of the container sets the wavelength hence the frequency of oscillation. I am using "container" very loosely here. Perhaps you should explain what you mean by "capacitor-like" because you certainly have me confused. I understand you don't mean it electrically. For example in a mass-spring system, the spring plays the part of a capacitor while the mass is the inductor but that has nothing to do with quantisation. I think its true I may assign the term tcapacitor like incorrectly. By `capacitor like` I assume a electrical capacitor takes a current lets say dc for now and re-outputs it in pulses of lets say 20 pulses per second. No, it is exactly the opposite, a capacitor is like a battery. You can put in pulses of current to charge it but the voltage remains substantially constant so it turns pulses into DC. Capacitors are often described by the function they perform, "reservoir capacitors" store power in a power supply to provide between the pulses it gets from the AC supply, "smoothing capacitors" iron out bumps caused by variation of current on a DC supply and "decoupling capacitors" eliminate voltage spikes that might otherwise cause interference to other devices. THats why I compare it to a bucket fillig and emptying literally. I assume a capacitor takes a steady flow of water and `quantizes` it into discreet packages. As if the steady water flow were diverted to a bucket which filled and then tipped over , released a pulse of water and then proceeded fill again. So on one side of the water bucket `capacitor` the flow is a steady flow whilst after the water bucket `capacitor` the flow comes in pulses of water interspersed with no water. However your analogy of the capacitor seems to imply that the capacitor in an electrical circuit doesnt take an electrical current and re output it at a different frequency but rather it just increases the voltage more like a water tank on a apartment roof gives the tenants a higher water pressure than if they were to get their water directly from the mains. That is very close. A large tank on the roof fed via a narrow pipe is like a battery. A small amount of water gives you the full head of pressure after which adding any further volume of water gives only a slight change. A capacitor is like pushing the water into the bottom of a vertical drainpipe. The head of water is proportional to the volume of water in the pipe. But that only works if the water use is intermittent. In which case a capacitor could only work if either the usage demanded of it were intermitent or if the capacitor itself released the flow in pulses? The capacitor produces a steady head of water and releases it at whatever rate is taken by the thing that is regulating the flow. That is it gives a substantially steady voltage and the load determines the current. It can accept charge in pulses and release it smoothly or you can charge it with a low constant current and take it out in pulses. The capacitor doesn't care. A capacitor is like an infinitely high bucket of constant cross-section. The height of the water (and hence the pressure at the bottom) is proportional to the volume of water in the bucket and inversely proportional to the cross-sectional area, just as the voltage across a capacitor is proportional to the charge and inversely proportional to the capacitance. Fill the bucket too full and the sides rupture so you don't have a bucket any more. Apply too much voltage to a capacitor and you get a loud bang with a puff of smoke, you don't have a capacitor any more. Thanks for a simpler description in analogy there George. But could you add to it a bit and say how in that above analogy the pulsing occurs that supposedly a capacitor gives. Capacitors don't produce pulses, they soak them up and eliminate them. that's why I couldn't follow your analogy. Or at least what happens in the above analogy while the `water` flows. The analogy still doesnt make complete sense to me . For instance you say the height of the water is proportional to the volume of the water but you also say the height is infinite which suggests that in analogy the volume is infinite? Finite volume of water in an infinitely high _bucket_. I think theres a bit missing in your analogy as I dont quite understand. Is it that the height isnt infinite but when the bucket fills to a certain height it begins to drain at a constant rate sort of like a water reservoir on a building roof? No, no matter how much water you add, the pressure at the bottom just keeps increasing (until something breaks!). What is the analogy mechanism that ties in the bucket above with the rest of the circuit. Pressure at the bottom = voltage Flow rate in/out of bucket = current How does it drain ? A pipe attached to the bottom of the bucket would act like a wire connected to the capacitor. And does it do so in pulses ie it releases all the water at once (thats what I assumed an analogy of an electrical capacitor does) or does it have an outflow pipe at the bottom releasing a constant flow of water? The latter but the rate of flow (current) is controlled entirely by the tap at the other end of the outflow pipe. Incidentally, stuffing a rag into the pipe would be the equivalent of a resistor (flow rate proportional to pressure difference). A bucket with a hole in the bottom stuffed with a rag does not produce a "vibrating system" in the sense of the head of water going up and down regularly. That's why an RC circuit cannot be resonant on its own. I don't follow that at all, in what way is there any similarity to a capacitor in that? Hopefully I have answered you above but just in case. Yes, I now see what you meant. A capacitor is not a good analogy. You could construct a model more like your idea by using something like a spark-gap connected to a capacitor. A spark-gap is a glass or ceramic container filled with gas. It is a good insulator until the voltage reaches a certain level when strength of the electric field ionises the gas. It then conducts until the current falls below some low value. This would be like having a pressure relief valve at the bottom of the bucket that opens at some high but safe pressure and then doesn't close until the water is just trickling out. What I was trying to acheive was to allow a resonant system to be used as an analogy for a wave atom. In my overlapping of waves of different wavelengths I notice that a composite wave length of much longer than any of the 3 input wavelengths is acheived. The composite wave pulses at peak amplitude once every 4 seconds which is much greater than the extra input wavelength of 1 3/4 seconds frequency and the amplitude of the new composite peak is greater then the amplitude of the additional `driving` wavelength of 1 3/4 beats a second . What has happened is that a wavelength input into a vibrating system of two superposed wavelengths 1/2 and 1 beats a second is re-output at a new wavelength of greater amplitude but less than 1/2 the wavelength of the input frequency of 1 3/4 beats a second. The amplitude will show beats but it remains the sum of two sine waves, they don't mix unless you have a non-linear element. My understanding of `capacitor` until now at least has been that a capacitor can take an input flow of one frequency and output it at a much lower frequency of greater amplitude. Hence my comparison of the resonating system described above as capacitor like. However it may be that an electrical capacitor is operating differently from what I thought as my earlier part of this post covers and your earlier description shows me. Yes, that is the case. It takes in pulses and gives out DC. I also admit on thinking about it that a PMT outputs the input light energy in a series of pulses sometimes called photons. One part takes in light and gives out electrons. They are accelerated and hit a screen that gives out photons when hit by electrons. The combination gives more photons out than went in. If the intensity of input light increases then the result is not an increase in pulse(photon QT calls them)amp-litude but an increase in pulse frequency. When one photon hits some part of the first screen, the electron released is focussed onto a corresponding part of the second screen so you get a burst of lots of photons from a single point on the second screen. The PMT only forms an image because there is a fixed relationship between the location where the first photon hit and the location where the final photons are released. Think of night-vision goggles. Therefore my above analogy does not help me as I only show how an increase in wavelength can result in a decreased output wavelength. Don't confuse the frequency of the photon with the rate at which the photons are produced. What I need to do is see how a resonating system when given an additional driving force reacts. For instance in a resonating jar of water. The nodes are lets say 1/2 inch high and 1/2 inch diameter . That "1/2 inch diameter" is fixed by the diameter of the jar. What happens when the additional driving force is exerted? Does the node height respond by becoming lets say 1 inch in height with the same old diameter? And if so what happens when the amplitude of the additional driving force increases even more ? Does the node continue rising in height without altering its diameter so it theoretically can become under enough `additional driving force` a column of lets say 3 feet tall and 1/2 inch diameter of water? Somehow I doubt it . Be careful again, the water is limited because it has a finite volume. Think of bowing a violin string harder. If you take a photograph, you will always see a sine wave. The amplitude increases with increasing input but the wavelength is defined by the distance between the bridge and fret. Going back to the start of your post, that is why I emphasised that you cannot ignore the need to define clearly what is contaning the energy. For an electron in orbit round a proton, it is the length of the orbit (DeBroglie again). My guess is that at a certain point the node height reaches critical and releases its energy back to the system and falls back to 1/2 inch height . Nope, the restoring force pushing the water back down must be proportonal to the height to get a sine wave. The power is force times velocity. As the water passes horizontal there is no force and maximum speed. As it continues to rise the force is downwards but the speed is upwards so energy lost is negative, the water gains potential energy but the force is acting to slow the water so it loses kinetic energy. When it is static at the top, it has maximum potential and no kinetic energy. If the height is sin(wt), the speed is cos(wt) and the THen under the additional force it has to go back up and then fallss again . the result may be possibly that the node under additional driving force pulses at a overlapping frequency of one amplitude but a variable frequency proportional to the amplitude of the input driving force. In other words if this does occur in a resonant system then it can duplicate the neccesary analogy of what is seen in an atom in a PMT under input light conditions? What do you think? Waves superimpose. If you mix two sine waves, you can separate them just by filtering. That's why you can 'tune in' a radio signal without knowing what other signals are present. If you put them into a non-linear system, for example where the restoring force is proportional to the square of the displacement, then you get the sum and difference of the pair of input frequencies. That can be done with certain crystals and shining high-intensity (infra)red laser light on such material can produce blue light More importantly do you know if what happens to a resonant system is as I have described above? A _simple_ resonant system is like a flywheel, it stores energy in a vibrating system but you need some sort of non-linearity to convert it to other frequencies. Aleksandr and Sergey have been talking a lot about complex systems where multiple resonant circuits at different frequencies are coupled together with non-linear parts in various places. Because if it is I may have the answer to my big problem of describing how a wave only atom can quantize incoming radiation into similar amplitude pulses with the frequency proportional to the input intensity as seen in PMT`s. Sorry, neither capacitors nor resonant systems quantise anything. You can treat an electron in orbit round the nuleus as a resonant system but it only accepts power at it natural frequency, that's what resonance means. That can be used to explain spectral lines but of course it is the opposite of what you want for the photo-electric effect. In that, once you exceed the threshold, the ejected electron energy is E = hv - W so there is no hint of a unique frequency at which it works as you should have if resonance were involved. George |
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Gravitation and Maxwell's Electrodynamics, BOUNDARY CONDITIONS
Dear George Dishman:
"George Dishman" wrote in message ... .... No, it is exactly the opposite, a capacitor is like a battery. You can put in pulses of current to charge it but the voltage remains substantially constant so it turns pulses into DC. Capacitors are often described by the function they perform, "reservoir capacitors" store power in a power supply to provide between the pulses it gets from the AC supply, "smoothing capacitors" iron out bumps caused by variation of current on a DC supply and "decoupling capacitors" eliminate voltage spikes that might otherwise cause interference to other devices. Just in addition, there are 0.8 farad capacitors (for limited applied voltage) that are quite small, and are in *fact* batteries. Blew me away, because I had heard of building-sized capacitors for igniting various reactions... David A. Smith |
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Gravitation and Maxwell's Electrodynamics, BOUNDARY CONDITIONS
\(formerly\)" dlzc1.cox@net wrote in message news:wVobb.5654$gv5.4178@fed1read05...
Dear Sergey Karavashkin: "Sergey Karavashkin" wrote in message om... \(formerly\)" dlzc1.cox@net wrote in message news:myJ6b.47123$Qy4.9078@fed1read05... ... Once again, what can you report us of a role a feedback in generators of auto-oscillations? One photon, one electron. What feedback is required? In the photoelectric effect, none is required. Well, do you need something at all? ;-) It isn't some form of standing wave. This was Alexsandr's question, the role of feedback. And an electron in an orbital surely *is* a standing wave, at least in "host" it is. Now conduction electrons are something else again. By the way, should you attentively study QM, you would see, the solution of Schroedinger equation for potential well is just standing wave. ;-) True. Should you also ponder what you read in the books and work with original literature, you would note that in solutions of Schroedinger equations the energy of electron is proportional to the level of energy quantization. And in Bohr's solutions the principle of quantization relates to the TRANSITION of electrons between levels. This is the matter of principle. Fine, but this is a different type of emission. Discrete absoprtion and emission of characterisitc frequencies of light. It is how stellar spectra are identified, for example. Resonance requires in-phase displacement and acceleration. The inductor acts as one (di/dt), and the capacitance as the other (integral[i.dt]) in phase space. Offloading the inductance to "the Universe" is well and good, but leaves you with no adequate momentum storage term. The electron in the photoelectric effect isn't really moving, ?????????????? "Standing wave" remember? If the electron had a discernable macroscopic motion, it would produce a magnetic field. And it produces. These are you relativists who postulate everything because of lack of comprehension. And you postulate just because you don't grasp what there occurs. But arrogance... unless it has been freed of the surface, and it is then no longer feeding back. There is no parallel. Are you absolutely sure? ;-) I am. David A. Smith |
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Gravitation and Maxwell's Electrodynamics, BOUNDARY CONDITIONS
\(formerly\)" dlzc1.cox@net wrote in message news:yVqbb.5719$gv5.1519@fed1read05...
Dear Sergey Karavashkin: "Sergey Karavashkin" wrote in message om... \(formerly\)" dlzc1.cox@net wrote in message news:z1t6b.46391$Qy4.38651@fed1read05... ... I always wonder, how do you confuse yourself by substituting the statement of problem by the desirable model. What concern RC-oscillator has here? The wave model of photoeffect is based on Stop there. RC circuit has what for a frequency threshold? As frequency is increased, what does the amplitude in an RC circuit do? What is the resonant frequency of an RC circuit? There is no parallel. Regrettably, you began confusing some things. First, where have you seen in my text that RC-circuit has any relation to the frequency threshold in photoeffect? This is Sean's model, and before stopping me, it would be nice of you to read my respond to Sean. ;-) Sorry. If that is not the model being discussed, then I need have no part in it. See the title of the thread. Second, Aleksandr's and Sean's models differ much. Factually, Aleksandr uses the terminology of RC-circuit as an analogy, in order to get a simpler approach to mathematics, since vibration processes have been better studied in theory of electric circuits than in mechanics. Though he very soon will run there into a barrier connected with the fact that you all don't know our methodology. ;-) Third, the analogy between dynamical mechanical systems and electric circuits exists, we have it developed. Should you really want to know something, you wouldn't be lazy to look through the paper which I referred you to. Then I'll ask you for the second time... provide the link please. Maybe, then you would have less questions - though, as I see, you all weren't told at the universities about vibration systems more than pendulums. On one hand, your teachers don't know more, and on the other, lest to overload your self-confidence - and for sex you needn't more! (Perhaps this is why such professors as Stephen Speicher so much like Russian girls which know some more about vibration systems). ;-) Fourth, you are asking Aleksandr of the feedback in parametric oscillator. First answer you yourself (not me - I know): what's the difference between the active filter and auto-oscillator? ;-) And where from appear vibrations in auto-oscillator when it's switched on and due to what one or several fixed frequencies are selected from the spectrum of noise? ;-) When you understand these issues, you will be able to answer yourself all your questions. ;-) Like "when will Sergey get to the point"? The title is boundary conditions. To the point, you still didn't answer me intelligibly, why the maximum of quantum output coincides with the maximum of EM wave absorption. ;-) It doesn't in the photoelectric effect. The quantum output is either proportional to intensity, or the difference between threshold and photon energy, depending on how you want to define your nebulous term. If this has no relation to resonance, then to what it relates? Only I would ask you, please David, without your surrealism. ;-) My surrealism is not in question. Your reality is what we are discussing. Thus, should you don't cram but study in your red-stone universities, you would have less difficulties with understanding, less absurdly virtual ideas and ambitiously dogmatic statements. ;-) Right. Provide the link to your "mechanical" model, please. David, it's now several times as I answered all these questions and linked you to my references. No reason to repeat. You "don't see" them - well, behave as you want. But I will not deepen into substantiation of wave nature of photoeffect until you confirm your readiness to perceive complex material. Still I see your very insufficient level of knowledge and no willing to discuss seriously serious things. Your statement [David] It doesn't in the photoelectric effect. The quantum output is either proportional to intensity, or the difference between threshold and photon energy, depending on how you want to define your nebulous term. [Sergey] says only that even in QM your knowledge is limited with popular slogans. If you make principle of it, I'll put on my web site CONVENTIONAL diagrams of quantum output of electrons from metal superimposed with the plot of reflection factor. I suggested you to have an independent consultation in literature, saying, such effects have been experimentally revealed very long ago. But you don't need knowledge, neither understanding of physical processes. This is your right and difficulties of universities and foundations that fund you. I'm not a waiter, please don't behave with me capriciously. Let us suspend this issue until you demonstrate the necessary level of knowledge and responsible attitude to our discussion. Sergey. David A. Smith |
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Gravitation and Maxwell's Electrodynamics, BOUNDARY CONDITIONS
"Robert J. Kolker" wrote in message ...
sean wrote: Hi Sergey I think you are wrong about me being a relativist who applies that to new theories. I have always avoided learning any physics that explains itself in GR or QT terms as I consider Einstein, Bohr et al to be completely wrong about everything. Everything I learn I do so only if the textbook information can be described in wave only or mechanical classical terms . How do you account for the efficacy of quantum electrodynamics which rests squarely on the theory of special relativity? Classical electrodynamics cannot account for the existence of atoms, the Compton effect or the photoelectric effect. To say nothing about the Lamb effect. Quantum theory has been supported in every experiment challange. It has yet to fail. Whereas classical physics cannot account for black body radiation, nor can it correctly predict the specific heat of many substances. So why does quantum theory work? I dont know where you read me saying I support photon concept? Everything I have posted on these newsgroups is meant to show that I beleive that photons are non existent and imaginary. See the experiment of Grangier, Roger and Aspect which proves that photons exist and that the semi-classical theory of light and matter is not adequate. Classical physics is deficient in explaining and predicting phenomena in the small and even in the large. Classical thermodynamics and statistical mechanics cannot account for black body radiation correctly. Bob Kolker Bob, this is a prayer. Don't forget, when Planck only yielded his famous formula, grounding on not enough substantiated premise that portions of energy in quantization are equal, he supposed just this process of quantized emission. However in most cases it is justified only in average study. If we take the process without an average, the hypothesis of quantization loses its grounds. Though you will not understand. Should you actually want to understand, you wouldn't mention again Aspect's experiments whom only one lazy yet didn't smash. One may not tell physics through set teeth standing in haughty pose. Such appearance is not very good. But to rely on some experiments, you have to be sure, they are well grounded. Many times on different threads I raised the same questions - you either responded slogans or didn't respond at all. This is your matter and your right. However you are not the Bob who discussed a year ago. Not that Bob. Sergey. |
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