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Why Blackholes Don't Wobble ???



 
 
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  #1  
Old September 14th 03, 02:50 AM
G=EMC^2 Glazier
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Default Why Blackholes Don't Wobble ???

Three best reasons are a blackhole is natures most perfect sphere,and it
is spinning very close to light speed and lastly it has the most inertia
for its size. Reality is if a blackhole wobbled it would give its
presence away even if it was all alone(possibly anyway) Bert

  #2  
Old September 14th 03, 10:41 PM
G=EMC^2 Glazier
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Like to add that wobble creates waves that past through space at "C" and
in some cases instantaneously. That depends on the reference frame. It
these waves hit the Earth they would be received at the speed of "C" If
they were going from one end of the universe to another their travel
time would be zero. Bert

  #3  
Old September 14th 03, 10:41 PM
G=EMC^2 Glazier
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Like to add that wobble creates waves that past through space at "C" and
in some cases instantaneously. That depends on the reference frame. It
these waves hit the Earth they would be received at the speed of "C" If
they were going from one end of the universe to another their travel
time would be zero. Bert

  #6  
Old September 15th 03, 04:20 AM
G=EMC^2 Glazier
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Llanzian I'm going with GR as discribed by Werner Israel. Blackholes
are perfectly spherical. Roger Penrose,and John Wheeler agree on this.
However I could stand corrected for I'm smart enough to know an object
spinning very fast has to flattern at the poles,and bulge at its
equaton. I don't know Kerr,but I think he must have figured this out,for
it is reality. Still I claim a fast spinning (close to
"C") BH does not wobble. I'm consintrating my thoughts how wobble is
used by nature in both the micro and macro realm,and I'll keep posting
these thoughts more and more. I see a sameness in photon wave lengths
and wobble. I see a sameness in wobbling,and the vibrations of
strings(string theory).

  #7  
Old September 15th 03, 04:20 AM
G=EMC^2 Glazier
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Llanzian I'm going with GR as discribed by Werner Israel. Blackholes
are perfectly spherical. Roger Penrose,and John Wheeler agree on this.
However I could stand corrected for I'm smart enough to know an object
spinning very fast has to flattern at the poles,and bulge at its
equaton. I don't know Kerr,but I think he must have figured this out,for
it is reality. Still I claim a fast spinning (close to
"C") BH does not wobble. I'm consintrating my thoughts how wobble is
used by nature in both the micro and macro realm,and I'll keep posting
these thoughts more and more. I see a sameness in photon wave lengths
and wobble. I see a sameness in wobbling,and the vibrations of
strings(string theory).

  #10  
Old September 18th 03, 10:00 PM
G=EMC^2 Glazier
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Well another reason why a blackhole does not wobble is it has no moving
particles inside its event horizon. Nothing to take its spin off the
center of its axis. The Earth gave me this thought because its spinning
axis does tilt and this creates very noticeable wobble. We have to also
keep in mind its great mass density(as much as a million suns some
times) sees to it that it is not easy to disturb(push around)
Bert

 




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