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EQUATION OF TIME Quandary
The equation of time, which produces the solar analemma
and determines what times of year the sun is "fast"(ahead of clock time) or slow, indicates that at 40 degrees north latitude, the sun is, in October, 20 minutes fast. According to Astronomical Apps on USNO, the sun is also 20 minutes fast at 40 degrees SOUTH latitude(cutting through southern Australia). Now instinct tells me that the equation of time should be reversed for latitudes south of the Equator, IE: sun should be 20 minutes slow at mid-south hemisphere latitudes. So am I right? |
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EQUATION OF TIME Quandary
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EQUATION OF TIME Quandary
Barry Schwarz:
Thanks for straightening me out on that. My initial reasoning had to do with the earth's attitude between solstices. Pretend you are the sun, looking out at Earth. In June, the top half(north) tilts toward you. In December, the bottom half, (south) tilts toward you. In between, and surrounding the equinoxes, the earth is "slanted" to one side or the other, even when the equator is dead straight at you. *That* is what I thought produced the equation of time. And actually, where I live(CT) is 2.5 degrees east of our prime meridian(75W). That equates to solar time being 6 minutes fast, or 16 minutes at the prime +6 = solar time being 22 min fast. Local solar noon in late October is thus 11:38AM. Roughly twenty minutes. |
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