Strong gravitational fields

What is the g value of the strongest gravitational field discovered so far?
Is it greater than g~10^30 m/s^2 ?

On Sun, 2 Sep 2007 00:52:13 +0200, "q-bit"
wrote:

What is the g value of the strongest gravitational field discovered so far?
Is it greater than g~10^30 m/s^2 ?

What's the surface gravity of a 3 solar mass Schwarzschild black hole?

"Eric Gisse" wrote
On Sun, 2 Sep 2007 00:52:13 +0200, "q-bit" wrote:

What is the g value of the strongest gravitational field discovered so far?
Is it greater than g~10^30 m/s^2 ?

What's the surface gravity of a 3 solar mass Schwarzschild black hole?

Why do you mention "3 solar masses"? What's so special about it?
M = 5.9673E30 kg
R = 8864 m
g = 5.07E12 m/s^2 ; ie. the surface gravity
Look, this g on the surface means about 17,000 times the speed of light...

In the following paper g~10^30 m/s^2 is mentioned:
Mario Goto, "The Equivalence Principle and gravitational and
inertial mass relation of classical charged particle"
http://arxiv.org/pdf/physics/0104021

On Sun, 02 Sep 2007 02:30:16 GMT, Sam Wormley
wrote:

Eric Gisse wrote:
On Sun, 2 Sep 2007 00:52:13 +0200, "q-bit"
wrote:

What is the g value of the strongest gravitational field discovered so far?
Is it greater than g~10^30 m/s^2 ?

What's the surface gravity of a 3 solar mass Schwarzschild black hole?

Assuming that "surface" refers to event horizon, would not the
gravitational strength be the same for *all* Schwarzschild black holes?

No.

A 3 solar mass black hole has a much stronger surface gravity than a 3
million solar mass black hole.

Surface gravity goes at 1/4GM. As mass increases, surface gravity
decreases.

On Sun, 2 Sep 2007 03:28:32 +0200, "q-bit"
wrote:

"Eric Gisse" wrote
On Sun, 2 Sep 2007 00:52:13 +0200, "q-bit" wrote:

What is the g value of the strongest gravitational field discovered so far?
Is it greater than g~10^30 m/s^2 ?

What's the surface gravity of a 3 solar mass Schwarzschild black hole?

Why do you mention "3 solar masses"? What's so special about it?

Either I like the shape of the number "3" or it is because that is a
typical size of a stellar black hole.

M = 5.9673E30 kg
R = 8864 m
g = 5.07E12 m/s^2 ; ie. the surface gravity

....and wrong.

Sorry, your high school education is worthless. You cannot use
Newtonian gravitation here. Surface gravity for a black hole is 1/4GM.


Look, this g on the surface means about 17,000 times the speed of light...

Look, stupid. The quantity "g" is an acceleration, not a velocity.

Weren't you taught units?


In the following paper g~10^30 m/s^2 is mentioned:
Mario Goto, "The Equivalence Principle and gravitational and
inertial mass relation of classical charged particle"
http://arxiv.org/pdf/physics/0104021

You don't even understand calculus. Who the **** do you think your
fooling?

This paper has NOTHING to do with what you wrote.

Dear Sam Wormley:

"Sam Wormley" wrote in message
news:q0qCi.65952$Xa3.17591@attbi_s22...
Eric Gisse wrote:
....
A 3 solar mass black hole has a much stronger surface
gravity than a 3 million solar mass black hole.

Surface gravity goes at 1/4GM. As mass increases,
surface gravity decreases.

But the event horizon is that boundary when light cant
escape, so right at the horizon the gravitational strength
should be the same, by definition.

The *esacpe velocities* are the same at the event horizon. The
"surface" gravitation is not.

David A. Smith

On Sun, 02 Sep 2007 03:23:02 GMT, Sam Wormley
wrote:

Eric Gisse wrote:
On Sun, 02 Sep 2007 02:30:16 GMT, Sam Wormley
wrote:

Eric Gisse wrote:
On Sun, 2 Sep 2007 00:52:13 +0200, "q-bit"
wrote:

What is the g value of the strongest gravitational field discovered so far?
Is it greater than g~10^30 m/s^2 ?
What's the surface gravity of a 3 solar mass Schwarzschild black hole?
Assuming that "surface" refers to event horizon, would not the
gravitational strength be the same for *all* Schwarzschild black holes?

No.

A 3 solar mass black hole has a much stronger surface gravity than a 3
million solar mass black hole.

Surface gravity goes at 1/4GM. As mass increases, surface gravity
decreases.


But the event horizon is that boundary when light cant escape, so
right at the horizon the gravitational strength should be the same,
by definition.

-Sam

Is that boundary at the same point for all black holes?

"Eric Gisse" wrote
On Sun, 2 Sep 2007 03:28:32 +0200, "q-bit" wrote:
"Eric Gisse" wrote
On Sun, 2 Sep 2007 00:52:13 +0200, "q-bit" wrote:

What is the g value of the strongest gravitational field discovered so far?
Is it greater than g~10^30 m/s^2 ?

What's the surface gravity of a 3 solar mass Schwarzschild black hole?

Why do you mention "3 solar masses"? What's so special about it?

Either I like the shape of the number "3" or it is because that is a
typical size of a stellar black hole.

M = 5.9673E30 kg
R = 8864 m
g = 5.07E12 m/s^2 ; ie. the surface gravity

...and wrong.

BS. It is correct!

Sorry, your high school education is worthless. You cannot use
Newtonian gravitation here. Surface gravity for a black hole is 1/4GM.

Tell us more GR BS, Dumb Eric!
The laws of the universe (Newton's laws) are valid for all masses alike,
without making any difference between planet, sun, or black hole.

Look, this g on the surface means about 17,000 times the speed of light...

Look, stupid. The quantity "g" is an acceleration, not a velocity.
Weren't you taught units?

The dumb one is just yourself. g is of course accelleration, but translates
to velocity when in action.

In the following paper g~10^30 m/s^2 is mentioned:
Mario Goto, "The Equivalence Principle and gravitational and
inertial mass relation of classical charged particle"
http://arxiv.org/pdf/physics/0104021

You don't even understand calculus.

Shut up, dumb Eric! I do understand calculus more than you!
Not necessarily your braindamaged GR calculus, but my calculus
gives at least correct results.

Who the **** do you think your fooling?
This paper has NOTHING to do with what you wrote.

Then you must be blind because g~10^30 m/s^2 is mentioned there like I said.
Who the **** do you think your fooling?

"q-bit" wrote
"Eric Gisse" wrote
On Sun, 2 Sep 2007 03:28:32 +0200, "q-bit" wrote:
"Eric Gisse" wrote
On Sun, 2 Sep 2007 00:52:13 +0200, "q-bit" wrote:

What is the g value of the strongest gravitational field discovered so far?
Is it greater than g~10^30 m/s^2 ?

What's the surface gravity of a 3 solar mass Schwarzschild black hole?

M = 5.9673E30 kg
R = 8864 m
g = 5.07E12 m/s^2 ; ie. the surface gravity

...and wrong.

BS. It is correct!

Sorry, your high school education is worthless. You cannot use
Newtonian gravitation here. Surface gravity for a black hole is 1/4GM.

Tell us more GR BS, Dumb Eric!
The laws of the universe (Newton's laws) are valid for all masses alike,
without making any difference between planet, sun, or black hole.

Addendum: if what Dumb Eric says were true (it definitely is wrong,
he is the biggest GR liar!) it even would mean
11234439734210220.5 m/s = ie. about 374,000 times the speed of light! :-)))

Look, this g on the surface means about 17,000 times the speed of light...

Dumb Eric doesn't know what he talkes about! I said 17,000 times c,
but he denies this and says "no, it's only 1/4 GM". But Dumb Eric is
that much bad in maths that he does not understand that 1/4 GM
means even much mo about 374,000 times c !!! :-)))
ROTFL! :-)))

Dumb Eric, is now your GR-world breaking apart? :-)
Do all the GR lies still make sense to yourself? :-)
Q.E.D.!

On Sun, 2 Sep 2007 07:32:53 +0200, "q-bit"
wrote:

"q-bit" wrote
"Eric Gisse" wrote
On Sun, 2 Sep 2007 03:28:32 +0200, "q-bit" wrote:
"Eric Gisse" wrote
On Sun, 2 Sep 2007 00:52:13 +0200, "q-bit" wrote:

What is the g value of the strongest gravitational field discovered so far?
Is it greater than g~10^30 m/s^2 ?

What's the surface gravity of a 3 solar mass Schwarzschild black hole?

M = 5.9673E30 kg
R = 8864 m
g = 5.07E12 m/s^2 ; ie. the surface gravity

...and wrong.

BS. It is correct!

Sorry, your high school education is worthless. You cannot use
Newtonian gravitation here. Surface gravity for a black hole is 1/4GM.

Tell us more GR BS, Dumb Eric!
The laws of the universe (Newton's laws) are valid for all masses alike,
without making any difference between planet, sun, or black hole.

Addendum: if what Dumb Eric says were true (it definitely is wrong,
he is the biggest GR liar!) it even would mean
11234439734210220.5 m/s = ie. about 374,000 times the speed of light! :-)))

Acceleration is not velocity.


Look, this g on the surface means about 17,000 times the speed of light...

Dumb Eric doesn't know what he talkes about! I said 17,000 times c,
but he denies this and says "no, it's only 1/4 GM". But Dumb Eric is
that much bad in maths that he does not understand that 1/4 GM
means even much mo about 374,000 times c !!! :-)))
ROTFL! :-)))

1) I said 1/4GM. That is not the same as .25 * GM. Two seconds
checking units would reveal the error - except you don't understand
dimensional analysis.

2) Acceleration is not velocity.

3) The quanitty 1/4GM is for units in which c = 1. Ten bucks says you
aren't even entering the right numbers.

4) You are stupid. It is a good thing you post under a pseudonym
because you are showing the entire planet how stupid you are for all
time in an archived medium.


Dumb Eric, is now your GR-world breaking apart? :-)
Do all the GR lies still make sense to yourself? :-)
Q.E.D.!

How old are you? 16? 17?

You are coming to an intellectual gunfight armed with a twig someone
tossed you. You don't know what you are talking about, and it is
obvious to *everyone* but yourself.