GRAVITATIONAL MECHANICS AND MASS

GRAVITATIONAL MECHANICS, MASS AND TOTAL ENERGY EQUILIBRIUM
Copyright 1984 to 2004 Allen C. Goodrich

ENERGY EQUILIBRIUM of the universe exista in the absence of an
energy transfer or at a constant total energy.
GRAVITATION AND MASS IN AN EQUILIBRIUM UNIVERSE
is explained as follows.

As the universe M expands, the potential energy PE of (M-m) ,relative
to mass m, decreases and because the total energy ( potential energy
PE and kinetic energy KE) of the universe is a constant, the kinetic energy
of the mass m, relative to the rest of the universe (M-m), must increase.
This is accomplished by an acceleration of the mass m. In an equilibrium
state of an expandng universe, the mass m is continually accelerating
relative to the center of mass of the effective universe, by rotation or
revolution about that center of this mass.
In the case of the planets, this is the revolution of the planet around the
sun.
( approximately the center of the effective universe M-m ).
This is called its mass. MASS m can be said to be the result of the effect
of the expansion of the rest of the universe on the density of the energy of m.
Mass m exists because of the expansion of the universe relative to the mass m .
GRAVITATION is the illusion involved in the change of the density of the mass.
As a result of the equation:
m (2 pi L )^2 / t ^2 + G (M-m)m /L = A constant M.

PE = G(M-m)m/L. KE = (2 pi L)^2 m / t^2. L=radial distance. m = mass
in question.(The result of internal rotation). t = time per revolution of m.
around (M-m). pi = 3.14159 .^ = to the power of, delta = change of.

It has been calculated that, at equilibrium, the values of PE and KE are
nearly the same and the planets and moons travel in nearly circular orbits
at a distance L from the center of mass (M-m). Only at this distance L
would a change in the value of L result in equal changes in the magnitude
,but opposite sign, of the values of PE and KE, occur, conserving the
equilibrium condition. ( of constant total energy).

A change (delta) of (2 pi L)^2 m /t^2 = - A change (delta) of G (M-m) m / L.
which would be necessary to conserve a constant total energy.

At energy equilibrium, the radial distance L of mass m is fixed,at a
particular value, because it would take an energy transfer with (M-m)
to change the value of L.

The equilibrium state of the universe, however, consists of an expansion
of the universe which is the decrease of the value of potential energy and
the increase of the value of kinetic energy, to maintain a constant total
energy. In an expanding universe - dela PE = + delta KE. This is true for
the planets of the solar system as well as the entire universe.As the
universe expands, the constant total energy of the universe makes it necessary
for the orbital distance L for any mass m relative to the rest of the effective

universe (M-m) to be determined by the expansion of the universe.Only at this
specific distance L will the value of kineic energy equal the value of
potential energy, for m relative to the rest of the mass of the universe (M-m)

and a (-) change of the potential energy of mass m relative to the rest of the
universe (M-m) will equal a (+) change of the kinetic energy of the mass m
relative to the rest of the effective universe.

Planets orbit the sun at a specific distance L to conserve total energy in an
expanding universe.

ELECTROMAGNETIC ,PHOTON AND CHARGE EFFECTS. ARE DEFINED
IN THE FOLLOWING BOOK.-- THE UNIVERSE:--Allen C. Goodrich

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