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How to Make Use of an Asteroid on Earth
On 1/03/2010 3:49 AM, William Mook wrote:
On Feb 28, 1:15 am, Pat wrote: On 2/27/2010 12:42 PM, Damon Hill wrote: A large disturbance can, and has been observed, to break up asteroids into multiple impactors. Ask the Jovians. And all that took was a mild dive through Jupiter's gravity field. Here's a whole other approach to deflecting a asteroid:http://www.mikebrotherton.com/diamonds/?page_id=134 Pat Right! Applied pressure must accelerate less than surface gravity. Exceed surface gravity and parts are left behind - definitely. It will take care and planning, but it will be less difficult than say herding sheep - that's why the ability to apply small spot sizes (or small explosions for the micro-nukes) broadly and quickly across a surface will be important. Absolutely. I find it difficult to reconcile the need for small thrust with any kind of nuke, particularly as there's a limit to how small a nuke can be. However, making one's nuke tunnel into the middle of the 'roid, which would presumably require little energy in a lightly compacted object, and then detonating it, would seem likely to scatter the thing all over the sky, with most of it missing the Earth entirely provided the action is not left until the last moment. Sylvia. |
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How to Make Use of an Asteroid on Earth
On Feb 28, 6:15*pm, Sylvia Else wrote:
On 1/03/2010 3:49 AM, William Mook wrote: On Feb 28, 1:15 am, Pat *wrote: On 2/27/2010 12:42 PM, Damon Hill wrote: A large disturbance can, and has been observed, to break up asteroids into multiple impactors. *Ask the Jovians. And all that took was a mild dive through Jupiter's gravity field. Here's a whole other approach to deflecting a asteroid:http://www.mikebrotherton.com/diamonds/?page_id=134 Pat Right! * Applied pressure must accelerate less than surface gravity. Exceed surface gravity and parts are left behind - definitely. *It will take care and planning, but it will be less difficult than say herding sheep - that's why the ability to apply small spot sizes (or small explosions for the micro-nukes) broadly and quickly across a surface will be important. *Absolutely. I find it difficult to reconcile the need for small thrust with any kind of nuke, particularly as there's a limit to how small a nuke can be. The pulse is largely UV light in vacuum, and it is spread over a large area. So, a pulse spread over a large illuminated surface ejects material quickly, but evenly - and if done at the right rate, provides a series of pulses that produce a controlled thrust. For example, take a sphere 50 km in diameter massing 1e+17 tons with a surface gravity of 0.0025 m/sec^2 and a density of 1.2e3 kg/m3. Let's say we want to accelerate this evenly at 0.0010 m/sec^2. This is less than half the surface gravity. Imagine a nuclear pulse that deposits UV light across one side of this sphere so that it ejects material to some depth at 50 km/sec. F = ma = mdot * Ve a = 0.001 m/sec/sec m = 1e+17 kg F = 1e+14 N Ve = 5e+4 m/sec so... mdot = 1e+14/5e+4 = 2e+9 kg/sec Since the hemisphere contains 5.9e+10 kg/cm of depth, then a gamma flash would need to blow away material across that surface at a rate of 33.8 microns per second. and E = 1/2 m * Ve^2 -- W = 1/2 * mdot * Ve^2 -- W = 1/2 * F * Ve So, 2e+9 kg/sec at 50,000 m/sec implies a power of 2.5e+18 Watts. Fusion produces 6.45e+14 Joules/kg - so this requires the detonation of 3.5 metric tons of lithium deuteride per second - to maintain this low rate of acceleration. With 100 blasts per second - each blast a few millionths of a second - produce very sharp gamma bursts, but these are thermalized when absorbed by the surface of the planetoid and it takes a milli-second to clear away before the next pulse. 10,000 microseconds between pulses the system settles down due to gravity, and another pulse arrives. Each bomblet is only 70 kg of materials twenty liters in size positioned in such a way as to produce a controlled directed blast of ejecta from the body which is thoroughly mapped and probed before engineered pulses are applied to it. However, making one's nuke tunnel into the middle of the 'roid, which would presumably require little energy in a lightly compacted object, and then detonating it, would seem likely to scatter the thing all over the sky, Which is why you don't do it. Its best to think of the thing as liquid, and transporting it in a way as not to produce waves. with most of it missing the Earth entirely provided the action is not left until the last moment. Um.. I'm talking about GATHERING ASTEROIDS INTO USEFUL ORBITS FOR PROCESSING INTO USEFUL PRODUCTS FOR HUMAN INDUSTRY. So, you're missing the point Sylvia. We close our mines and refineries, processing plants and factories on Earth and move them all to orbit - using teleoperated robots. http://en.wikipedia.org/wiki/Asimo Sylvia. |
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How to Make Use of an Asteroid on Earth
On 1/03/2010 12:22 PM, William Mook wrote:
For example, take a sphere 50 km in diameter massing 1e+17 tons with a surface gravity of 0.0025 m/sec^2 and a density of 1.2e3 kg/m3. Let's say we want to accelerate this evenly at 0.0010 m/sec^2. This is less than half the surface gravity. Imagine a nuclear pulse that deposits UV light across one side of this sphere so that it ejects material to some depth at 50 km/sec. F = ma = mdot * Ve a = 0.001 m/sec/sec m = 1e+17 kg F = 1e+14 N Ve = 5e+4 m/sec so... mdot = 1e+14/5e+4 = 2e+9 kg/sec Since the hemisphere contains 5.9e+10 kg/cm of depth, then a gamma flash would need to blow away material across that surface at a rate of 33.8 microns per second. and E = 1/2 m * Ve^2 -- W = 1/2 * mdot * Ve^2 -- W = 1/2 * F * Ve So, 2e+9 kg/sec at 50,000 m/sec implies a power of 2.5e+18 Watts. Fusion produces 6.45e+14 Joules/kg - so this requires the detonation of 3.5 metric tons of lithium deuteride per second - to maintain this low rate of acceleration. With 100 blasts per second - each blast a few millionths of a second - produce very sharp gamma bursts, but these are thermalized when absorbed by the surface of the planetoid and it takes a milli-second to clear away before the next pulse. 10,000 microseconds between pulses the system settles down due to gravity, and another pulse arrives. Each bomblet is only 70 kg of materials twenty liters in size positioned in such a way as to produce a controlled directed blast of ejecta from the body which is thoroughly mapped and probed before engineered pulses are applied to it. However, making one's nuke tunnel into the middle of the 'roid, which would presumably require little energy in a lightly compacted object, and then detonating it, would seem likely to scatter the thing all over the sky, Which is why you don't do it. Its best to think of the thing as liquid, and transporting it in a way as not to produce waves. with most of it missing the Earth entirely provided the action is not left until the last moment. Um.. I'm talking about GATHERING ASTEROIDS INTO USEFUL ORBITS FOR PROCESSING INTO USEFUL PRODUCTS FOR HUMAN INDUSTRY. An object such as you described would have a Roche limit of about 20,000 km, so not so readily accessible. But a more serious objection is that it's one thing to take an asteroid that crosses Earths orbit, and move it so that it does so about when the Earth is there. It's quite another to get it into orbit round the Earth, which is going to require a significant change in velocity. And if your preferred asteroid doesn't come anywhere near Earth's orbit anyway... Sylvia. |
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How to Make Use of an Asteroid on Earth
On Mar 1, 12:42*am, Sylvia Else wrote:
On 1/03/2010 12:22 PM, William Mook wrote: For example, take a sphere 50 km in diameter massing 1e+17 tons with a surface gravity of 0.0025 m/sec^2 and a density of 1.2e3 kg/m3. *Let's say we want to accelerate this evenly at 0.0010 m/sec^2. *This is less than half the surface gravity. Imagine a nuclear pulse that deposits UV light across one side of this sphere so that it ejects material to some depth at 50 km/sec. F = ma = mdot * Ve a = 0.001 m/sec/sec m = 1e+17 kg F = 1e+14 N Ve = 5e+4 m/sec so... mdot = 1e+14/5e+4 = 2e+9 kg/sec Since the hemisphere contains 5.9e+10 kg/cm of depth, then a gamma flash would need to blow away material across that surface at a rate of 33.8 microns per second. and E = 1/2 m * Ve^2 -- * W = 1/2 * mdot * Ve^2 *-- *W = 1/2 * F * Ve So, 2e+9 kg/sec at 50,000 m/sec implies a power of 2.5e+18 Watts. Fusion produces 6.45e+14 Joules/kg - so this requires the detonation of 3.5 metric tons of lithium deuteride per second - to maintain this low rate of acceleration. With 100 blasts per second - each blast a few millionths of a second - produce very sharp gamma bursts, but these are thermalized when absorbed by the surface of the planetoid and it takes a milli-second to clear away before the next pulse. *10,000 microseconds between pulses the system settles down due to gravity, and another pulse arrives. Each bomblet is only 70 kg of materials twenty liters in size positioned in such a way as to produce a controlled directed blast of ejecta from the body which is thoroughly mapped and probed before engineered pulses are applied to it. However, making one's nuke tunnel into the middle of the 'roid, which would presumably require little energy in a lightly compacted object, and then detonating it, would seem likely to scatter the thing all over the sky, Which is why you don't do it. Its best to think of the thing as liquid, and transporting it in a way as not to produce waves. with most of it missing the Earth entirely provided the action is not left until the last moment. Um.. I'm talking about GATHERING ASTEROIDS INTO USEFUL ORBITS FOR PROCESSING INTO USEFUL PRODUCTS FOR HUMAN INDUSTRY. An object such as you described would have a Roche limit of about 20,000 km, so not so readily accessible. But a more serious objection is that it's one thing to take an asteroid that crosses Earths orbit, and move it so that it does so about when the Earth is there. It's quite another to get it into orbit round the Earth, which is going to require a significant change in velocity. And if your preferred asteroid doesn't come anywhere near Earth's orbit anyway... Sylvia. I think I mentioned that the total delta vee is 6.5 km/sec - with most of that at Earth. Let's do an example calculation. Let's take an object from Ceres to Earth orbit. The equation to use is the vis viva equation; v = sqrt( mu * (2/r - 1/a)) Ceres orbit is a=2.7663 AU (413.8 Gm) V = 17.882 km/sec Earth orbit is a=1.0000 AU (149.6 Gm) V = 29.783 km/sec The transfer orbit is a=1.8832 US (281.7 Gm) And velocity at aphelion is; V(2.7663 AU) = 13.049 km/sec which is 4.833 km/sec decrease in speed. Given the surface gravity of Ceres is 0.27 m/sec2 it would take at least 5 hours to impart that speed to Ceres in a way that would not tear it apart. The velocity at perihelion is; V(1.0000 AU) = 36.098 km/sec which is 6.315 km/sec decrease in speed again. Given the surface gravity of Ceres is 0.27 m/sec2 it would take at least 8 hours to impart that speed to Ceres in a way that would not tear it apart. Total delta vee is 11.148 km/sec. With an exhaust speed of 50.000 km/ sec we can calculate how much of Ceres must be vaporized to carry out this transfer. 19.99% of the total mass of Ceres. The jet energy contained in the plume is 1.25 trillion joules per metric ton of propellant - with only 1/3 of the energy showing up in the plume this means that 3.75 trillion joules are expended in a fusion pulse unit per metric ton. So, each metric ton of ejecta requires 2 grams of lithium 6 deuteride or Boron 10 or other aneutronic fusion fuel. So a total of 3.77e+17 kg of fusion fuel is needed to be applied to energize 1.89e+20 kg of Ceres surface in a way to impart this delta vee There are 4.35e+9 kg of Boron produced each year. There are 1.70e+7 kg of Lithium produced each year. So, it would take a massive millionfold increase in the production rates of these materials to use them in the way described here. Not much deuterium is produced each year, but there's plenty of it in the oceans, so this might be an interesting source. The production rates of fusion materials on Earth today limits the rates to about 1 millionth the mass of Ceres. This is something that's 1/100th the diameter of Ceres - EACH YEAR. So, something about 5 km in diameter - each year - is the limit of what we can expect. Even so, the mass of materials is stupendous - sufficient to provide for everyone's material needs. Once you've got Ceres or another low density object on orbit, Silvia is correct, the Roche radius determines how close you can bring it before it breaks up into a ring; The Roche Radius for Ceres is d = R * (2* rho(M)/rho(m))^(1/3) = 11,115 km Where; R = 6.371 Mm rho(M) = 5.515 g/cc rho(m) = 2.077 g/cc SO, if you navigate the planetoid into a tight orbit say 1,000 km above Earth, it will rip apart due to gravitational forces. But, is breaking up a planetoid that you want to process into useful stuff a bad thing? To me it seems like a good way to use tidal forces to process asteroids for you. Why not get relatively dense objects and use them as shepherd moons to keep pieces from being a threat to navigation and safety and then bring stuff into the space between the shepherd moons and let tidal forces tear them apart for you? Then send free-flying solar powered industrial satellites to process the pieces that are found there? This is the way I'd do it. |
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How to Make Use of an Asteroid on Earth
A theta-pinch method to compress fissile materials like weapons grade
plutonium or highly enriched uranium can get densities 10 to 100 times resting density. This is 3 to 30 times the densities achieved by using shaped plastic explosives. 10 kg of Plutonium in a sphere 10 cm in diameter forms a critical mass at resting density. 15 kg of Uranium-233 in a sphere 11 cm in diameter ditto. Uranium 235 requires 52 kg of material in a sphere 17 cm in diameter for explosion. Compressing to 3x resting density reduces masses to 10% - 1 kg Pu, 1.5 kg U-233, 5.2 kg of U-235. Compressing to 100x resting density reduces masses to 0.01% - 1 gram of Pu, 1.5 grams of U-233, 5.2 grams of U-235. Using anti-matter to catalyze fissile reactions increases neutron yield from 2 to 9 neutrons per fission which reduces things by another factor of 10 - 100 mg to 520 mg of fissile material. There are 2000 metric tons of weapons grade materials in the world. With theta-pinch techniques, it is possible to create millions of 'triggers' for propulsive fusion units. Fusion units consist of lithium-deuteride, or boron-10 triggered by fission 'sparks' The shape of the fusion fuel once detonated, determines the shape of the resulting blast. A long cylinder produces an explosion that spreads out from the center of the cylinder like a sheet. A plate produces an explosion that spreads out from the surface of the plate forming a blast focused along a line passing perpendicular to the center of the sheet. Changing the shape of things makes things more interesting. A kg of fusion material detonated by a few milligrams of fissile triggering material form the basis of a propulsive unit. A disc of boron 10 a few microns thick and a few meters wide - detonated from the center - plated with MEMS based chemical rockets to maneuver freely in space - and equipped with a coating on one side that glows intensely in the X-ray region when energized - that coating covered with MEMS based phase control units - described here http://www.youtube.com/watch?v=jWuL4sZ3ppY The sheet is detonated by a fissile trigger. The blast wave spreads across the surface, energizing the coating. The coating sticks around about 20 times longer than the boron sheet that energizes it - and glows intensely in the X-ray region all that time. The phase control rods are oriented to form a controlled well-defined pattern of X-ray light in a specific area. That's it! A vehicle, brings a few thousand of these self powered sheets to the vicinity of an appropriately sized asteroid. They self-deploy around the asteroid, after a careful survey is done, and then they detonate according to a well engineered sequence producing well defined regions of intense Xray illumination to create well defined high speed jets of ejecta from the surface of the asteroid - all times and controlled so as to maintain the integrity of the asteroid as its being moved. |
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How to Make Use of an Asteroid on Earth
In sci.space.policy message
, Sun, 28 Feb 2010 16:22:19, Sylvia Else posted: Well, yes, but the point is that if, as is suspected, asteroids are held together by gravity, then the force that can be applied without making them come apart is very small. Changing the orbit of such an object would require the application of a small force over an extended period of time, which is going to be hard to achieve using bombs. In the present context, "bomb" has inappropriate connotations. A nuke exploding near an asteroid is not like a hand-grenade in the same room. It gives (I suppose) no solid shrapnel, and rather little blast, for its energy, in the sense of moving gas. It should be thought of more as a VERY bright flash-bulb. Neither would give much push to a perfect mirror, because photons have a poor momentum/energy ratio. A force applied at a point will of course tend to scatter a rubble-pile; the same is not true of a well-distributed force. A rubble-pile passing not far outside its Roche Limit with a large body will receive a considerable force, but fairly evenly distributed. -- (c) John Stockton, nr London, UK. Turnpike v6.05 MIME. Web URL:http://www.merlyn.demon.co.uk/ - FAQqish topics, acronyms & links; Astro stuff via astron-1.htm, gravity0.htm ; quotings.htm, pascal.htm, etc. No Encoding. Quotes before replies. Snip well. Write clearly. Don't Mail News. |
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How to Make Use of an Asteroid on Earth
Dr J R Stockton wrote in
nvalid: This assumes the object is a reasonably solid object; more recent data suggests most asteroids are dusty accretions loosely constituted by their own weak gravity. A large disturbance can, and has been observed, to break up asteroids into multiple impactors. Ask the Jovians. Procede cautiously. YSCIB. Remember that in a vacuum a nuke generates comparatively little direct blast. The idea is not to give the whole target a massive shock, but to dump enough energy into the surface that it boils. The ejecta will go radially outwards from most of the illuminated hemisphere, pushing the rest inwards. That is a comparatively favourable situation. The necessary caution should not be exaggerated. Assuming that by using "Jovians" you are referring to the impacts of SL-9 (D/1993 F2) in 1994 : it was broken up in 1992 when it passed within Jupiter's Roche limit. It felt a substantial tidal field for some hours, pulling it apart. The analogy is weak. As are the forces holding together rubble piles, especially elongated ones. I disagree that Jupiter's gravity "pulled apart" SL-9; it almost certainly induced a tumble that the object pulled itself apart into it's many constituent parts. Wouldn't take much considering the very tiny amount of gravity present to hold it together. An adjacent nuclear explosion would do the same if the energy caused surface material to ablate violently. These things will have to be handled with relative delicacy. --Damon |
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How to Make Use of an Asteroid on Earth
On 2/03/2010 5:36 AM, William Mook wrote:
SO, if you navigate the planetoid into a tight orbit say 1,000 km above Earth, it will rip apart due to gravitational forces. But, is breaking up a planetoid that you want to process into useful stuff a bad thing? It's an exceptionally bad idea. When it breaks up, the pieces don't enter nice well behaved circular orbits. They enter elliptal crossing orbits. That is, the pieces will subsequently collide with each other. You'd end up with a space debris problem on a vast scale. To me it seems like a good way to use tidal forces to process asteroids for you. Why not get relatively dense objects and use them as shepherd moons to keep pieces from being a threat to navigation and safety and then bring stuff into the space between the shepherd moons and let tidal forces tear them apart for you? You have to find them first. Sylvia. |
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How to Make Use of an Asteroid on Earth
On Mar 1, 9:41�pm, Sylvia Else wrote:
On 2/03/2010 5:36 AM, William Mook wrote: SO, if you navigate the planetoid into a tight orbit say 1,000 km above Earth, it will rip apart due to gravitational forces. But, is breaking up a planetoid that you want to process into useful stuff a bad thing? It's an exceptionally bad idea. When it breaks up, the pieces don't enter nice well behaved circular orbits. They enter elliptal crossing orbits. That is, the pieces will subsequently collide with each other. You'd end up with a space debris problem on a vast scale. To me it seems like a good way to use tidal forces to process asteroids for you. Why not get relatively dense objects and use them as shepherd moons to keep pieces from being a threat to navigation and safety and then bring stuff into the space between the shepherd moons and let tidal forces tear them apart for you? You have to find them first. Sylvia. can you imagine the ground effects of a rubble asteroid breaking up in earth orbit? lets see it would cool the planet, maybe cause a ice age, cause massive food production problems cut off most or all space ased operations like satellite tv, telephone, and credit card processing, disrupt or end air travel, since the debris could get sucked into jet engines, ISS would be toast, access to space perhaps ended for thousands or millions of years, it could end life as we know it on the earth........ all bbecause a asteroid happened to play pool with the earth, and direct iumpact with the surface wouldnt be necessary |
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How to Make Use of an Asteroid on Earth
In sci.space.policy message ,
Mon, 1 Mar 2010 18:10:16, Damon Hill posted: Dr J R Stockton wrote in . invalid: Assuming that by using "Jovians" you are referring to the impacts of SL-9 (D/1993 F2) in 1994 : it was broken up in 1992 when it passed within Jupiter's Roche limit. It felt a substantial tidal field for some hours, pulling it apart. The analogy is weak. As are the forces holding together rubble piles, especially elongated ones. I disagree that Jupiter's gravity "pulled apart" SL-9; it almost certainly induced a tumble that the object pulled itself apart into it's many constituent parts. Wouldn't take much considering the very tiny amount of gravity present to hold it together. An adjacent nuclear explosion would do the same if the energy caused surface material to ablate violently. You are entitled to your own opinion. I doubt whether anyone else will want it. You should endeavour to obtain a physics degree, or to consult reputable authorities. -- (c) John Stockton, near London. Web URL:http://www.merlyn.demon.co.uk/ - FAQish topics, acronyms, & links. Correct = 4-line sig. separator as above, a line precisely "-- " (RFC5536/7) Do not Mail News to me. Before a reply, quote with "" or " " (RFC5536/7) |
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