A simple proof of the Nonexistance of Black Holes.

While Stephen Hawking recently came to the conclusion black holes are not
what he thought they were, I find it amazing he took decades to come to that
conclusion. Using a proof that relies on relativistic arguments instead of
information conservation makes things easier to comprehend. It is assumed
that a non rotating black hole will be observed to have a spherical event
horizon if observed by someone at rest with respect to the black hole. Now,
if the black hole is passing by someone at some relativistic velocity, that
observer will see that the black holes' event horizon is no longer
spherical, and that it is foreshortened in the direction of motion
according to the rules of relativity. Indeed, the faster the black hole
passes by the observer, the more flattened out the event horizon will become
in the direction of motion. Eventually, there will come a point in the
velocity curve, when the event horizon will be congruent with the
singularity producing it. At that point, the singularity will no longer be
shielded from the outside observer - it will be visible along the direction
of motion, and able to interact with the external environment.

Since this can not happen, and assuming the rules of geometrodynamics hold
for all observers in any inertial frame, there can not exist black holes of
the type currently envisioned. Damn that was simple. I shall now go on to
prove the existence of God...

Greysky

www.allocations.cc
Learn how to build a FTL radio; presently partially off-line pending
government approved modifications...

Killfile time.

"Greysky" wrote in message
m...
While

Greysky wrote:
the faster the black hole
passes by the observer, the more flattened out the event horizon will become
in the direction of motion. Eventually, there will come a point in the
velocity curve, when the event horizon will be congruent with the
singularity producing it.

Not true. This is easily seen by interchanging black hole and observer.
It is also seen by noting that the existence of points of the manifold
between singularity and horizon implies that they do not intersect
(which you apparently call "congruent", you misuse this word) -- this is
independent of any motion of either black hole or observer.

And the singularity does not "produce" the horizon, they are both merely
geometric properties of the manifold....

The only possible "proof" of the nonexistence of black holes is an
exhaustive search of the universe. Good luck....


Tom Roberts

"Tom Roberts" wrote in message
. ..

Not true. This is easily seen by interchanging black hole and observer. It
is also seen by noting that the existence of points of the manifold
between singularity and horizon implies that they do not intersect (which
you apparently call "congruent", you misuse this word) -- this is
independent of any motion of either black hole or observer.

Therefore, you agree with me that Lorentz Transform only describes what is
observed and not necessarily what reality is.

The only possible "proof" of the nonexistence of black holes is an
exhaustive search of the universe. Good luck....

Or you can be as abstract as Mr. Hobba by closing his eyes doing the
searching. Any abstract type of thinking also produces the same equal
abstractness in imagination. However, reality checks.

So, exploring deeper in this subject of black holes, it is a common belief
that a black hole would be affected by the curvature of spacetime created by
another black hole. It is thus understood that 2 black holes have no
problems merging. In doing so, we will be enlightened with a show of
massive amount of gravitational waves. However, according to Schwarzschild
metric, a black creates a well in spacetime so deep that nothing can escape
itself. Since you should also believe in the gravitational wave not
traveling beyond the speed of light, and if the speed of light cannot escape
a black hole, how then can gravitational wave escape this black hole to
affect anything outside? Perhaps, you can resolve this paradox.

"Koobee Wublee" wrote in message
news:udDee.11388$tQ.1600@fed1read06...

"Tom Roberts" wrote in message
. ..

Not true. This is easily seen by interchanging black hole and observer.
It
is also seen by noting that the existence of points of the manifold
between singularity and horizon implies that they do not intersect
(which
you apparently call "congruent", you misuse this word) -- this is
independent of any motion of either black hole or observer.

Therefore, you agree with me that Lorentz Transform only describes what is
observed and not necessarily what reality is.

Semantic gibberish, expressed in you own private language, devoid of any
objective content. Stick to standard terminology if you want to be
understood. Of course that would mean actually studying a text on
relativity - something you have no shown a willingness to do

Bill


The only possible "proof" of the nonexistence of black holes is an
exhaustive search of the universe. Good luck....

Or you can be as abstract as Mr. Hobba by closing his eyes doing the
searching. Any abstract type of thinking also produces the same equal
abstractness in imagination. However, reality checks.

So, exploring deeper in this subject of black holes, it is a common belief
that a black hole would be affected by the curvature of spacetime created
by
another black hole. It is thus understood that 2 black holes have no
problems merging. In doing so, we will be enlightened with a show of
massive amount of gravitational waves. However, according to
Schwarzschild
metric, a black creates a well in spacetime so deep that nothing can
escape
itself. Since you should also believe in the gravitational wave not
traveling beyond the speed of light, and if the speed of light cannot
escape
a black hole, how then can gravitational wave escape this black hole to
affect anything outside? Perhaps, you can resolve this paradox.

"Bill Hobba" wrote in message ...

"Koobee Wublee" wrote in message
news:udDee.11388$tQ.1600@fed1read06...

"Tom Roberts" wrote in message
. ..

Not true. This is easily seen by interchanging black hole and observer.
It
is also seen by noting that the existence of points of the manifold
between singularity and horizon implies that they do not intersect
(which
you apparently call "congruent", you misuse this word) -- this is
independent of any motion of either black hole or observer.

Therefore, you agree with me that Lorentz Transform only describes what is
observed and not necessarily what reality is.

Semantic gibberish, expressed in you own private language, devoid of any
objective content. Stick to standard terminology if you want to be
understood. Of course that would mean actually studying a text on
relativity - something you have no shown a willingness to do

Bill

"describes what is observed and not necessarily what reality is."
What a silly thing to say - specially for a retired aerospace
engineer like Australopitheticus ;-)

Dirk Vdm

"describes what is observed and not necessarily what reality is."
What a silly thing to say - specially for a retired aerospace
engineer like Australopitheticus ;-)

he is okay in his statemet, in return you full of ****

tomorrows observations have to be undoubtly more accurate then
what we call for observations today

you fools...

"Koobee Wublee" wrote in message news:udDee.11388$tQ.1600@fed1read06...

"Tom Roberts" wrote in message
. ..

Not true. This is easily seen by interchanging black hole and observer. It
is also seen by noting that the existence of points of the manifold
between singularity and horizon implies that they do not intersect (which
you apparently call "congruent", you misuse this word) -- this is
independent of any motion of either black hole or observer.

Therefore, you agree with me that Lorentz Transform only describes what is
observed and not necessarily what reality is.

All of science only describes what is observed. Reality can never be known.

The only possible "proof" of the nonexistence of black holes is an
exhaustive search of the universe. Good luck....

Or you can be as abstract as Mr. Hobba by closing his eyes doing the
searching. Any abstract type of thinking also produces the same equal
abstractness in imagination. However, reality checks.

So, exploring deeper in this subject of black holes, it is a common belief
that a black hole would be affected by the curvature of spacetime created by
another black hole. It is thus understood that 2 black holes have no
problems merging. In doing so, we will be enlightened with a show of
massive amount of gravitational waves. However, according to Schwarzschild
metric, a black creates a well in spacetime so deep that nothing can escape
itself. Since you should also believe in the gravitational wave not
traveling beyond the speed of light, and if the speed of light cannot escape
a black hole, how then can gravitational wave escape this black hole to
affect anything outside? Perhaps, you can resolve this paradox.

AllYou! wrote:
"Koobee Wublee" wrote in message
news:udDee.11388$tQ.1600@fed1read06...

"Tom Roberts" wrote in message
. ..

Not true. This is easily seen by interchanging black hole and
observer. It
is also seen by noting that the existence of points of the
manifold
between singularity and horizon implies that they do not
intersect (which
you apparently call "congruent", you misuse this word) -- this is

independent of any motion of either black hole or observer.

Therefore, you agree with me that Lorentz Transform only describes
what is
observed and not necessarily what reality is.

All of science only describes what is observed. Reality can never be
known.

The only possible "proof" of the nonexistence of black holes is
an
exhaustive search of the universe. Good luck....

Or you can be as abstract as Mr. Hobba by closing his eyes doing
the
searching. Any abstract type of thinking also produces the same
equal
abstractness in imagination. However, reality checks.

So, exploring deeper in this subject of black holes, it is a common
belief
that a black hole would be affected by the curvature of spacetime
created by
another black hole. It is thus understood that 2 black holes have
no
problems merging. In doing so, we will be enlightened with a show
of
massive amount of gravitational waves. However, according to
Schwarzschild
metric, a black creates a well in spacetime so deep that nothing
can escape
itself. Since you should also believe in the gravitational wave
not
traveling beyond the speed of light, and if the speed of light
cannot escape
a black hole, how then can gravitational wave escape this black
hole to
affect anything outside? Perhaps, you can resolve this paradox.




Everyone bow to the great god of the 'Perceivable' :

Are you sure you wanted to make that response to me?

"Raving Loonie" wrote in message
oups.com...

AllYou! wrote:
"Koobee Wublee" wrote in message
news:udDee.11388$tQ.1600@fed1read06...

"Tom Roberts" wrote in message
. ..

Not true. This is easily seen by interchanging black hole and
observer. It
is also seen by noting that the existence of points of the
manifold
between singularity and horizon implies that they do not
intersect (which
you apparently call "congruent", you misuse this word) -- this is

independent of any motion of either black hole or observer.

Therefore, you agree with me that Lorentz Transform only describes
what is
observed and not necessarily what reality is.

All of science only describes what is observed. Reality can never be
known.

The only possible "proof" of the nonexistence of black holes is
an
exhaustive search of the universe. Good luck....

Or you can be as abstract as Mr. Hobba by closing his eyes doing
the
searching. Any abstract type of thinking also produces the same
equal
abstractness in imagination. However, reality checks.

So, exploring deeper in this subject of black holes, it is a common
belief
that a black hole would be affected by the curvature of spacetime
created by
another black hole. It is thus understood that 2 black holes have
no
problems merging. In doing so, we will be enlightened with a show
of
massive amount of gravitational waves. However, according to
Schwarzschild
metric, a black creates a well in spacetime so deep that nothing
can escape
itself. Since you should also believe in the gravitational wave
not
traveling beyond the speed of light, and if the speed of light
cannot escape
a black hole, how then can gravitational wave escape this black
hole to
affect anything outside? Perhaps, you can resolve this paradox.




Everyone bow to the great god of the 'Perceivable' :