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What is "Mean Radius" for Orbits
Hi,
I've been wondering about the definition of "Mean Radius" for orbital parameters. On Wikipedia I got these orbital data for Uranus Satellites: Titania Semi-major Axis: 435,910 km Mean Radius : 436,300 km Eccentricity : 0.0011 Oberon Semi-major Axis: 583,520 km Mean Radius : 583,519 km Eccentricity : 0.0014 If the "Mean Radius" is defined as the radius of a circle whose area equals to the area of a given ellipse, then the relationship between the semi-major axis and the mean radius is given by: a = R / ((1 - e^2)^(1/4)) where a = semi-major axis R = mean radius e = eccentricity However, using the above equation yields to different results, especially for Titania. Where do I get wrong, the definition of the derivation? TIA |
#2
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What is "Mean Radius" for Orbits
Hi,
Perhaps what is meant by mean radius is the following: Let R(t) be the distance from, e.g. Titania, to the barycenter of the orbit (for this case, the barycenter is very, very close to Uranus' center.), and let P be the period of Titania's orbit. Then the mean value of R(t) along one orbit is just 1/P * integral(R(t) dt) from zero to P where the location of the ephemeris is arbitrary. Hope that helps. Jason Harris Ricky Romaya wrote: Hi, I've been wondering about the definition of "Mean Radius" for orbital parameters. On Wikipedia I got these orbital data for Uranus Satellites: Titania Semi-major Axis: 435,910 km Mean Radius : 436,300 km Eccentricity : 0.0011 Oberon Semi-major Axis: 583,520 km Mean Radius : 583,519 km Eccentricity : 0.0014 If the "Mean Radius" is defined as the radius of a circle whose area equals to the area of a given ellipse, then the relationship between the semi-major axis and the mean radius is given by: a = R / ((1 - e^2)^(1/4)) where a = semi-major axis R = mean radius e = eccentricity However, using the above equation yields to different results, especially for Titania. Where do I get wrong, the definition of the derivation? TIA |
#3
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What is "Mean Radius" for Orbits
In article ,
Ricky Romaya writes: On Wikipedia I got these orbital data for Uranus Satellites: Titania Semi-major Axis: 435,910 km Mean Radius : 436,300 km Eccentricity : 0.0011 Oberon Semi-major Axis: 583,520 km Mean Radius : 583,519 km Eccentricity : 0.0014 There's something very odd here. I don't know of an official definition of "mean radius," but if it means something sensible, it ought to be equal to semi-major axis for a circular orbit. In the above data, the more elliptical orbit has mean radius nearly equal to semi-major axis. That doesn't make sense. I also don't see why mean radius should be greater than semi-major axis in one case and less in the other. _Allen's Astrophysical Quantities_ gives the eccentricities as 0.0022 and 0.0008, respectively, and agrees with the above semi-major axes. Does that work out better? Perhaps mean radius should just not be taken seriously. -- Steve Willner Phone 617-495-7123 Cambridge, MA 02138 USA (Please email your reply if you want to be sure I see it; include a valid Reply-To address to receive an acknowledgement. Commercial email may be sent to your ISP.) |
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