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how many positrons at center of Sun to imitate gravity; #133; 3rd ed;Atom Totality (Atom Universe) theory
Alright, here is an interesting calculation. Suppose everything
I said about Positron Space is true. Then there resides a specific amount of positrons as the center of the Sun. Now I will only talk about Sun and Earth but all the others need to be computed. So there are a specific number of positrons at the center of the Sun that hold together our Solar System as we formally used to know of as gravity force. So now we know the mass of the Sun and Earth. And all of that mass is Electron Mass of an Electron of the Atom Totality. Now the force of gravity is 10^-40 weaker than the Coulomb force. More precise, if memory serves is 10^-39. But either one will do for our crude calculations. So, now, here is the force of gravity in the Atom Totality theory. We know the mass of both Sun and Earth and the force of gravity that binds them together. So now, instead of gravity we simply have the Coulomb force binding them. And the total mass is converted to how many electrons would be Sun and Earth. Now we compute how many positrons have to reside in the center of Sun and center of Earth in order for their gravity to become a normal Coulomb force. It is not going to be many positrons that are needed to imitate the force of gravity since the regular Coulomb is 10^40 stronger. The only real fascinating question for me, is why noone ever did this before? Archimedes Plutonium, www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies |
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how many positrons at center of Sun to imitate gravity; #134; 3rded; Atom Totality (Atom Universe) theory
On Aug 9, 12:59*am, Archimedes Plutonium
wrote: Alright, here is an interesting calculation. Suppose everything I said about Positron Space is true. Then there resides a specific amount of positrons as the center of the Sun. Now I will only talk about Sun and Earth but all the others need to be computed. So there are a specific number of positrons at the center of the Sun that hold together our Solar System as we formally used to know of as gravity force. So now we know the mass of the Sun and Earth. And all of that mass is Electron Mass of an Electron of the Atom Totality. Now the force of gravity is 10^-40 weaker than the Coulomb force. More precise, if memory serves is 10^-39. But either one will do for our crude calculations. So, now, here is the force of gravity in the Atom Totality theory. We know the mass of both Sun and Earth and the force of gravity that binds them together. So now, instead of gravity we simply have the Coulomb force binding them. And the total mass is converted to how many electrons would be Sun and Earth. The conversion may have to be that of a nucleon mass, instead of a electron mass. Or the mass of a single hydrogen atom. What I am doing in summary form is replacing the force of gravity by a regular Coulomb force and saying that the positrons form Space and their attraction for ordinary matter (since ordinary matter are the electrons of the Atom Totality) gives us the perception of gravity. Now we compute how many positrons have to reside in the center of Sun and center of Earth in order for their gravity to become a normal Coulomb force. It is not going to be many positrons that are needed to imitate the force of gravity since the regular Coulomb is 10^40 stronger. The only real fascinating question for me, is why noone ever did this before? Archimedes Plutonium,www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies |
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how many positrons at center of Sun to imitate gravity; #133; 3rded; Atom Totality (Atom Universe) theory
On Aug 8, 10:59*pm, Archimedes Plutonium
wrote: Alright, here is an interesting calculation. Suppose everything I said about Positron Space is true. Nothing you say is true. Then there resides a specific amount of positrons as the center of the Sun. Positrons are not as the center of the Sun. Now I will only talk about Sun and Earth but all the others need to be computed. All the other what, moron? So there are a specific number of positrons at the center of the Sun that hold together our Solar System as we formally used to Do you mean 'formerly' or 'formally', you vacuous ****? know of as gravity force. So now we know the mass of the Sun and Earth. And all of that mass is Electron Mass of an Electron of the Atom Totality. The Sun doesn't have mass, you blathering puke. Now the force of gravity is 10^-40 weaker than the Coulomb force. More precise, if memory serves is 10^-39. You have no memory, you ignorant discarded tissue sample. But either one will do for our crude calculations. You couldn't calculate your way out of a wet paper bag, you mendacious twit. So, now, here is the force of gravity in the Atom Totality theory. "Atom Totality Theory" We know the mass of both Sun and Earth and the force of gravity that binds them together. So now, instead of gravity we simply have the Coulomb force binding them. Binding them to what? you festering fountain of falsehoods? Eh??? And the total ass Got that right, ya tard. is converted to how many electrons would be Sun and Earth. How many, Poindexter? Now we compute how many positrons have to reside in the center of Sun and center of Earth in order for their gravity to become a normal Coulomb force. I'm bored to tears. Plunge knitting needles into my every suffering orifice. It is not going to be many positrons that are needed to imitate the force of gravity since the regular Coulomb is 10^40 stronger. Stronger that what, cretin? The only real fascinating question for me, is why noone ever did this before? I fart your electric yellow brain dildo. Archimedes Plutonium,www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies I shriek with |
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how many positrons at center of Sun to imitate gravity; #133; 3rded; Atom Totality (Atom Universe) theory
On Aug 9, 8:24*am, Eddie Parker wrote:
On Aug 8, 10:59*pm, Archimedes Plutonium wrote: Alright, here is an interesting calculation. Suppose everything I said about Positron Space is true. Nothing you say is true. Then there resides a specific amount of positrons as the center of the Sun. Positrons are not as the center of the Sun. Now I will only talk about Sun and Earth but all the others need to be computed. All the other what, moron? So there are a specific number of positrons at the center of the Sun that hold together our Solar System as we formally used to Do you mean 'formerly' or 'formally', you vacuous ****? know of as gravity force. So now we know the mass of the Sun and Earth. And all of that mass is Electron Mass of an Electron of the Atom Totality. The Sun doesn't have mass, you blathering puke. Now the force of gravity is 10^-40 weaker than the Coulomb force. More precise, if memory serves is 10^-39. You have no memory, you ignorant discarded tissue sample. But either one will do for our crude calculations. You couldn't calculate your way out of a wet paper bag, you mendacious twit. So, now, here is the force of gravity in the Atom Totality theory. "Atom Totality Theory" We know the mass of both Sun and Earth and the force of gravity that binds them together. So now, instead of gravity we simply have the Coulomb force binding them. Binding them to what? *you festering fountain of falsehoods? *Eh??? And the total ass Got that right, ya tard. is converted to how many electrons would be Sun and Earth. How many, Poindexter? Now we compute how many positrons have to reside in the center of Sun and center of Earth in order for their gravity to become a normal Coulomb force. I'm bored to tears. *Plunge knitting needles into my every suffering orifice. It is not going to be many positrons that are needed to imitate the force of gravity since the regular Coulomb is 10^40 stronger. Stronger that what, cretin? The only real fascinating question for me, is why noone ever did this before? I fart your electric yellow brain dildo. Archimedes Plutonium,www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies I shriek with So the world is one atom, I don't get it. We may be in one atom, and there may be infinite number of atoms. This atom just carries its energies, Each vibration sequence ignites energy, and then it fades away into dark energy, which after reaching anti-gravity levels of white holes, explode, the Universe rips apart from all the anti- gravity building infinitely, I mean a new vibration initiates, but is trapped in four dimensions, but by necessity the Universe has to have infinite dimensions in infinite time frames and so on, minus one applies. Infinite - 1 is not energy, which is fundamental. There is no such thing as infinite - 1. We can try to calculate it, but the answer remains the same: infinite - 1. |
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how many positrons at center of Sun to imitate gravity; #133; 3rded; Atom Totality (Atom Universe) theory
On Aug 9, 1:42*am, gb wrote:
On Aug 9, 8:24*am, Eddie Parker wrote: On Aug 8, 10:59*pm, Archimedes Plutonium wrote: Alright, here is an interesting calculation. Suppose everything I said about Positron Space is true. Nothing you say is true. Then there resides a specific amount of positrons as the center of the Sun. Positrons are not as the center of the Sun. Now I will only talk about Sun and Earth but all the others need to be computed. All the other what, moron? So there are a specific number of positrons at the center of the Sun that hold together our Solar System as we formally used to Do you mean 'formerly' or 'formally', you vacuous ****? know of as gravity force. So now we know the mass of the Sun and Earth. And all of that mass is Electron Mass of an Electron of the Atom Totality. The Sun doesn't have mass, you blathering puke. Now the force of gravity is 10^-40 weaker than the Coulomb force. More precise, if memory serves is 10^-39. You have no memory, you ignorant discarded tissue sample. But either one will do for our crude calculations. You couldn't calculate your way out of a wet paper bag, you mendacious twit. So, now, here is the force of gravity in the Atom Totality theory. "Atom Totality Theory" We know the mass of both Sun and Earth and the force of gravity that binds them together. So now, instead of gravity we simply have the Coulomb force binding them. Binding them to what? *you festering fountain of falsehoods? *Eh??? And the total ass Got that right, ya tard. is converted to how many electrons would be Sun and Earth. How many, Poindexter? Now we compute how many positrons have to reside in the center of Sun and center of Earth in order for their gravity to become a normal Coulomb force. I'm bored to tears. *Plunge knitting needles into my every suffering orifice. It is not going to be many positrons that are needed to imitate the force of gravity since the regular Coulomb is 10^40 stronger. Stronger that what, cretin? The only real fascinating question for me, is why noone ever did this before? I fart your electric yellow brain dildo. Archimedes Plutonium,www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies I shriek with So the world is one atom, I don't get it. We may be in one atom, and there may be infinite number of atoms. This atom just carries its energies, Each vibration sequence ignites energy, and then it fades away into dark energy, which after reaching anti-gravity levels of white holes, explode, the Universe rips apart from all the anti- gravity building infinitely, I mean a new vibration initiates, but is trapped in four dimensions, but by necessity the Universe has to have infinite dimensions in infinite time frames and so on, minus one applies. Infinite - 1 is not energy, which is fundamental. There is no such thing as infinite - 1. We can try to calculate it, but the answer remains the same: infinite - 1.- Hide quoted text - - Show quoted text - Finally someone who understands! God Bless You, and all success to you and your loved ones. |
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how many positrons at center of Sun to imitate gravity; #134; 3rded; Atom Totality (Atom Universe) theory
On Aug 8, 11:19*pm, Archimedes Plutonium
wrote: On Aug 9, 12:59*am, Archimedes Plutonium wrote: Alright, here is an interesting calculation. Suppose everything I said about Positron Space is true. Then there resides a specific amount of positrons as the center of the Sun. Now I will only talk about Sun and Earth but all the others need to be computed. So there are a specific number of positrons at the center of the Sun that hold together our Solar System as we formally used to know of as gravity force. So now we know the mass of the Sun and Earth. And all of that mass is Electron Mass of an Electron of the Atom Totality. Now the force of gravity is 10^-40 weaker than the Coulomb force. More precise, if memory serves is 10^-39. But either one will do for our crude calculations. So, now, here is the force of gravity in the Atom Totality theory. We know the mass of both Sun and Earth and the force of gravity that binds them together. So now, instead of gravity we simply have the Coulomb force binding them. And the total mass is converted to how many electrons would be Sun and Earth. The conversion may have to be that of a nucleon mass, instead of a electron mass. Or the mass of a single hydrogen atom. What I am doing in summary form is replacing the force of gravity by a regular Coulomb force and saying that the positrons form Space and their attraction for ordinary matter (since ordinary matter are the electrons of the Atom Totality) gives us the perception of gravity. Now we compute how many positrons have to reside in the center of Sun and center of Earth in order for their gravity to become a normal Coulomb force. It is not going to be many positrons that are needed to imitate the force of gravity since the regular Coulomb is 10^40 stronger. The only real fascinating question for me, is why noone ever did this before? Archimedes Plutonium,www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies Because gravity alone is simply insufficient, our sun as with most other stars should have an internal binding force similar to that of the electron and positron, or if you like similar to that well enough measured strong force of an atom. Thus far there's not a living soul in mainstream physics that's willing to suggest the quantity and/or the specific density of those stellar electrons and positrons. However, several researchers have concluded that black holes contain a significant if not entire portion of their mass as positrons (aka anti-matter) within their event horizon, whereas perhaps each and every electron that enters the BH event horizon converts into a positron. ~ BG |
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how many positrons at center of Sun to imitate gravity; #133; 3rded; Atom Totality (Atom Universe) theory
On Aug 9, 1:42*am, gb wrote:
On Aug 9, 8:24*am, Eddie Parker wrote: On Aug 8, 10:59*pm, Archimedes Plutonium wrote: Alright, here is an interesting calculation. Suppose everything I said about Positron Space is true. Nothing you say is true. Then there resides a specific amount of positrons as the center of the Sun. Positrons are not as the center of the Sun. Now I will only talk about Sun and Earth but all the others need to be computed. All the other what, moron? So there are a specific number of positrons at the center of the Sun that hold together our Solar System as we formally used to Do you mean 'formerly' or 'formally', you vacuous ****? know of as gravity force. So now we know the mass of the Sun and Earth. And all of that mass is Electron Mass of an Electron of the Atom Totality. The Sun doesn't have mass, you blathering puke. Now the force of gravity is 10^-40 weaker than the Coulomb force. More precise, if memory serves is 10^-39. You have no memory, you ignorant discarded tissue sample. But either one will do for our crude calculations. You couldn't calculate your way out of a wet paper bag, you mendacious twit. So, now, here is the force of gravity in the Atom Totality theory. "Atom Totality Theory" We know the mass of both Sun and Earth and the force of gravity that binds them together. So now, instead of gravity we simply have the Coulomb force binding them. Binding them to what? *you festering fountain of falsehoods? *Eh??? And the total ass Got that right, ya tard. is converted to how many electrons would be Sun and Earth. How many, Poindexter? Now we compute how many positrons have to reside in the center of Sun and center of Earth in order for their gravity to become a normal Coulomb force. I'm bored to tears. *Plunge knitting needles into my every suffering orifice. It is not going to be many positrons that are needed to imitate the force of gravity since the regular Coulomb is 10^40 stronger. Stronger that what, cretin? The only real fascinating question for me, is why noone ever did this before? I fart your electric yellow brain dildo. Archimedes Plutonium,www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies I shriek with So the world is one atom, I don't get it. We may be in one atom, and there may be infinite number of atoms. This atom just carries its energies, Each vibration sequence ignites energy, and then it fades away into dark energy, which after reaching anti-gravity levels of white holes, explode, the Universe rips apart from all the anti- gravity building infinitely, I mean a new vibration initiates, but is trapped in four dimensions, but by necessity the Universe has to have infinite dimensions in infinite time frames and so on, minus one applies. Infinite - 1 is not energy, which is fundamental. There is no such thing as infinite - 1. We can try to calculate it, but the answer remains the same: infinite - 1. In specific volume and mass, what are the smallest parts of an atom? How do we know this to be true or false, or is the LHC eventually going to give us a better objective kind of subatomic knowledge? ~ BG |
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how many positrons at center of Sun to imitate gravity; #135; 3rded; Atom Totality (Atom Universe) theory
On Aug 9, 10:19*am, BradGuth wrote:
On Aug 8, 11:19*pm, Archimedes Plutonium (snipped) Because gravity alone is simply insufficient, our sun as with most other stars should have an internal binding force similar to that of the electron and positron, or if you like similar to that well enough measured strong force of an atom. Thus far there's not a living soul in mainstream physics that's willing to suggest the quantity and/or the specific density of those stellar electrons and positrons. *However, several researchers have concluded that black holes contain a significant if not entire portion of their mass as positrons (aka anti-matter) within their event horizon, whereas perhaps each and every electron that enters the BH event horizon converts into a positron. *~ BG There should have been plenty of scientists willing and able to speak of gravity as a positron mass at the center of a large massive object ever since Dirac published his book Directions in Physics 1978, but the physics community was too off course, off track with General Relativity. I roughly compute that the positron mass at the center of the Sun to imitate or mimic or recreate the force of gravity is the size concentration of a cherry (sour cherry fruit) or the size of the tip of a little finger. How many positrons fit into a cherry size? And the size of the Earth positron center would be in cubic micron units. The Sun's size is cubic millimeters. For Earth all that is needed is a volume of about a red blood cell full of positrons. So I place a challenge on the force of gravity, that it can either be as thought of previously that mass attracts mass, or it can be thought of as a Coulomb force where positron-Space is attracting ordinary matter of an Atom Totality. Now there should be several proofs that Positrons are the force of gravity and I venture to list a partial list: (a) Positrons would have no minimum mass to form a gravitational bonded system, whereas mass-gravity has a minimum that is larger than some reported asteroids gravitationally bound. If you have a few positrons in the center of a asteroid you can quickly have a bound system with other asteroids. (b) The oblateness of planets and stars should not exist to the extent seen with mass-gravity. The agreement between observed oblateness and theoretical oblateness is better with positron-gravity. (c) Resonance of gravitational bounded systems is easier to explain with gravity as Positrons than with gravity as mass. Archimedes Plutonium, www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies |
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how many positrons at center of Sun to imitate gravity; #135; 3rded; Atom Totality (Atom Universe) theory
On Aug 9, 11:14*am, Archimedes Plutonium
wrote: On Aug 9, 10:19*am, BradGuth wrote: On Aug 8, 11:19*pm, Archimedes Plutonium (snipped) Because gravity alone is simply insufficient, our sun as with most other stars should have an internal binding force similar to that of the electron and positron, or if you like similar to that well enough measured strong force of an atom. Thus far there's not a living soul in mainstream physics that's willing to suggest the quantity and/or the specific density of those stellar electrons and positrons. *However, several researchers have concluded that black holes contain a significant if not entire portion of their mass as positrons (aka anti-matter) within their event horizon, whereas perhaps each and every electron that enters the BH event horizon converts into a positron. *~ BG There should have been plenty of scientists willing and able to speak of gravity as a positron mass at the center of a large massive object ever since Dirac published his book Directions in Physics 1978, but the physics community was too off course, off track with General Relativity. I roughly compute that the positron mass at the center of the Sun to imitate or mimic or recreate the force of gravity is the size concentration of a cherry (sour cherry fruit) or the size of the tip of a little finger. How many positrons fit into a cherry size? And the size of the Earth positron center would be in cubic micron units. The Sun's size is cubic millimeters. For Earth all that is needed is a volume of about a red blood cell full of positrons. So I place a challenge on the force of gravity, that it can either be as thought of previously that mass attracts mass, or it can be thought of as a Coulomb force where positron-Space is attracting ordinary matter of an Atom Totality. Now there should be several proofs that Positrons are the force of gravity and I venture to list a partial list: (a) Positrons would have no minimum mass to form a gravitational bonded system, whereas mass-gravity has a minimum that is larger than some reported asteroids gravitationally bound. If you have a few positrons in the center of a asteroid you can quickly have a bound system with other asteroids. (b) The oblateness of planets and stars should not exist to the extent seen with mass-gravity. The agreement between observed oblateness and theoretical oblateness is better with positron-gravity. (c) Resonance of gravitational bounded systems is easier to explain with gravity as Positrons than with gravity as mass. Archimedes Plutonium,www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies If we were made primarily of electrons (of which by way of atom by atom objective accounting we are), and the core of Earth was primarily that of positrons would in fact attract us. However, if trying to stand upon a planet or moon of mostly electrons might tend to repel us. So, how much of Earth is made of positrons, as opposed to being electrons? How the heck do we determine if Earth is more or less chuck full of positrons? I'm thinking the magic or holy grail of gravity is a whole lot more complex than just electrons and positrons. ~ BG |
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how many positrons at center of Sun to imitate gravity; #133; 3rded; Atom Totality (Atom Universe) theory
Archimedes Plutonium wrote:
Alright, here is an interesting calculation. Suppose everything I said about Positron Space is true. [snip rest of crap] Suppose turds were sausages. Let's eat them with relish! I cannot believe how incredibly stupid Archie-Poo is. I mean rock-hard stupid. Blazing hot mid-day sun on Mercury stupid. Surface of Venus under 80 atmospheres of red hot carbon dioxide and sulfuric acid vapor dehydrated for 300 million years rock-hard stupid. Stupid so stupid that it goes way beyond the stupid we know into a whole different sensorium of stupid. Archie-Poo is trans-stupid stupid. Meta-stupid. Stupid so collapsed upon itself that it is within its own Schwarzschild radius. Black hole stupid. Stupid gotten so dense and massive that no intellect can escape. Singularity stupid. Archie-Poo emits more stupid/second than our entire galaxy otherwise emits stupid/year. Quasar stupid. Nothing else in the universe can be this stupid. Archie-Poo is an oozingly putrescent primordial fragment from the original Big Bang of Stupid, a pure essence of stupid so uncontaminated by anything else as to be beyond the laws of physics that define maximally extrapolated hypergeometric n-dimensional backgroundless stupid as we can imagine it. Archie-Poo is Planck stupid, a quantum foam of stupid, a vacuum decay of stupid, a grand unified theory of stupid. Archie-Poo is the epitome of stupidity, the epiphany of stupid, the apotheosis of stupidity. Archie-poo is stooopid. -- Uncle Al http://www.mazepath.com/uncleal/ (Toxic URL! Unsafe for children and most mammals) http://www.mazepath.com/uncleal/lajos.htm#a2 |
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