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Even Relativistic Doppler Effect Topples Einstein's Relativity



 
 
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  #1  
Old March 10th 16, 10:26 AM posted to sci.astro
Pentcho Valev
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Default Even Relativistic Doppler Effect Topples Einstein's Relativity

Any interpretation of the Doppler effect (moving observer) proves, explicitly or implicitly, that the speed of light relative to the observer varies with the speed of the observer, in violation of Einstein's relativity:

http://rockpile.phys.virginia.edu/mod04/mod34.pdf
"Now let's see what this does to the frequency of the light. We know that even without special relativity, observers moving at different velocities measure different frequencies. (This is the reason the pitch of an ambulance changes as it passes you it doesn't change if you're on the ambulance). This is called the Doppler shift, and for small relative velocity v it is easy to show that the frequency shifts from f to f(1+v/c) (it goes up heading toward you, down away from you). There are relativistic corrections, but these are negligible here."

http://www.hep.man.ac.uk/u/roger/PHY.../lecture18.pdf
"The Doppler effect - changes in frequencies when sources or observers are in motion - is familiar to anyone who has stood at the roadside and watched (and listened) to the cars go by. It applies to all types of wave, not just sound. (...) Moving Observer. Now suppose the source is fixed but the observer is moving towards the source, with speed v. In time t, ct/λ waves pass a fixed point. A moving point adds another vt/λ. So f'=(c+v)/λ. (...) RELATIVISTIC DOPPLER EFFECT. These results depend on the absolute velocities of the source and observer, not just on the relative velocity of the two. That seems odd, but is allowable as sound waves are waves in a medium, and motion relative to the medium may legitimately matter. But for light (or EM radiation in general) there is no medium, and this must be wrong. This needs relativity. (...) If the source is regarded as fixed and the observer is moving, then the observer's clock runs slow. They will measure time intervals as being shorter than they are in the rest frame of the source, and so they will measure frequencies as being higher, again by a γ factor: f'=(1+v/c)γf..."

That is, according to standard interpretations,

f' = f(1+v/c) = (c+v)/λ

when v is low (relativistic corrections are negligible), and

f' = γf(1+v/c) = γ(c+v)/λ

when v is high (relativistic corrections are not negligible). Accordingly, the speed of the light relative to the moving observer is

c' = c+v

when v is low, and

c' = γ(c+v)

when v is high. Einstein's relativity is violated in either case.

Here are explicit refutations of Einstein's 1905 constant-speed-of-light postulate:

http://a-levelphysicstutor.com/wav-doppler.php
"vO is the velocity of an observer moving towards the source. This velocity is independent of the motion of the source. Hence, the velocity of waves relative to the observer is c + vO. (...) The motion of an observer does not alter the wavelength. The increase in frequency is a result of the observer encountering more wavelengths in a given time."

http://physics.bu.edu/~redner/211-sp...9_doppler.html
"Let's say you, the observer, now move toward the source with velocity vO. You encounter more waves per unit time than you did before. Relative to you, the waves travel at a higher speed: v'=v+vO. The frequency of the waves you detect is higher, and is given by: f'=v'/λ=(v+vO)/λ."

Pentcho Valev
  #2  
Old March 10th 16, 12:56 PM posted to sci.astro
Pentcho Valev
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Default Even Relativistic Doppler Effect Topples Einstein's Relativity

The easiest way to refute Einstein's relativity:

Consider a light source emitting a series of pulses the distance between which is d (e.g. d = 300000 km). A stationary observer (receiver) measures the frequency of the pulses to be f = c/d:

http://www.einstein-online.info/imag...ler_static.gif

The observer starts moving with speed v towards the light source - the measured frequency shifts from f = c/d to f' = (c+v)/d (Doppler effect):

http://www.einstein-online.info/imag...ector_blue.gif

Question: Why does the frequency shift from f = c/d to f' = (c+v)/d ?

Answer 1 (fatal for Einstein's relativity): Because the speed of the pulses relative to the observer shifts from c to c' = c+v.

Answer 2 (possibly saving Einstein's relativity): Because...

There is no reasonable statement that could become Answer 2.

Pentcho Valev
  #3  
Old March 11th 16, 03:32 PM posted to sci.astro
Pentcho Valev
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Posts: 8,078
Default Even Relativistic Doppler Effect Topples Einstein's Relativity

http://www.phys.uconn.edu/~gibson/No...6_3/Sec6_3.htm
Professor George N. Gibson, University of Connecticut: "To understand the moving observer, imagine you are in a motorboat on the ocean. If you are not moving, the boat will bob up and down with a certain frequency determined by the ocean waves coming in. However, imagine that you are moving into the waves fairly quickly. You will find that you bob up and down more rapidly, because you hit the crests of the waves sooner than if you were not moving. So, the frequency of the waves appears to be higher to you than if you were not moving. Notice, the waves themselves have not changed, only your experience of them. Nevertheless, you would say that the frequency has increased. Now imagine that you are returning to shore, and so you are traveling in the same direction as the waves. In this case, the waves may still overtake you, but at a much slower rate - you will bob up and down more slowly. In fact, if you travel with exactly the same speed as the waves, you will not bob up and down at all. The same thing is true for sound waves, or ANY OTHER WAVES. (...) The formula for the frequency that the observer will detect depends on the speed of the observer; the larger the speed the greater the effect. If we call the speed of the observer, Vo, the frequency the observer detects will be: f'=f(1+Vo/Vwave). Here, f is the original frequency and Vwave is the speed of the wave."

For light waves we have

f'= f(1+Vo/Vwave) = f(1+Vo/c) = (c+Vo)/λ

where λ is the wavelength and c'=c+Vo is the speed of the waves relative to the moving observer.

Clearly the speed of light relative to the observer varies with the speed of the observer, in violation of Einstein's relativity.

Taking into account the relativistic corrections (time dilation) will change the above formula into

f' = γ(c+Vo)/λ

where γ is the Lorentz factor. In this case the speed of the light relative to the moving observer is

c' = γ(c+Vo)

and Einstein's relativity is violated again.

Pentcho Valev
 




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