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#21
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Hubble makes 3D dark matter map
Hans Aberg wrote:
One idea that comes to my mind is that very young, nearby galaxies are very hard to observe for two reasons: they are faint, and quickly gets absorbed into larger galaxies. Why would any even exist? Surely after ~14 billion years, most of the easily accumulated intergalactic gas has long ago gathered into galaxies, and the remaining cases gathering more recently would be so thinly scattered throughout the universe that the chance of even one being "nearby" for useful meanings of that vague term would be "slender to none"? FWIW xanthian. |
#22
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Hubble makes 3D dark matter map
ebunn=40lfa221051.richmond.edu wrote:
[Mod. note: quoted text deleted. The text below is MIME-damaged. I don't have time to fix it. Please post only in ASCII. -- mjh] Looking a bit more at Ted's calculations, it unclear what fraction of 7 x 10=5E=7B-25=7D g/cm=5E3 is considered dark matter. the wiki page http://en.wikipedia.org/wiki/Milky_Way provides the relevant parameters of the Milky Way Solar mass 1.99E+33 g Milky Way mass 5.80E+11 solar masses Milky Way mass 1.15E+45 g Milky Way diameter 100,000 light years Milky Way diameter (D) 9.46E+22 cm Milky Way diameter (R) 4.73E+22 cm Milky Way thickness .01*D 9.46E+20 cm Milky Way rotation velocity 2.00E+07 cm/sec (200 km/sec) Milky Way age 13.4 billion years Newtonian G 6.67E-08 cm=5E3 / (g sec) v is constant with R at 200 km/sec which implies as Ted says: dM =3D (v=5E2/G) dR which implies dM =3D K dR but here is the point and correct me if I am wrong: The relationship dM =3D K dR does not have to be in a sphere for the derivation to be valid. Observations indicate that the Milky Way is essentially a disc. then paraphrasing Ted here The incremental volume of the Milky Way disc is 2 pi thickness R dR, so the local density is rho =3D v=5E2 / (2 pi thickness G R) =3D (2.00E+07)=5E2 / (2*pi*(9.46E+20)*(6.67E-08)*(4.73E+22)) =3D 2.13E-23 g/cm=5E3 this value of density (rho) at R says nothing about the nature of the matter whether it is dark matter or other. It is an average value of all stars, dust, gas, dark matter, etc at R. the wiki page http://en.wikipedia.org/wiki/Milky_Way indicates that: 'The distance from the Sun to the galactic center is estimated at 26,000 =B1 1400 light-years=22 so the local (rho) density at our solar system would be: rho (local) =3D 2.13E-23 * 50,000/26,000 =3D 4.1E-23 g/cm=5E3 but this value again is an average value of all stars, dust, gas, dark matter, etc at R (local). The key question is how after 13.4 billion years does the Milky Way galaxy have a distribution of mass which is proportional to R or (dM =3D K dR). Calculations indicate that a persistent and continuous force over 13.4 billion years related to universe critical density (6E-30 g/cm=5E3) as applied to galactic mass will result in (dM =3D K dR). Richard |
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Hubble makes 3D dark matter map
In article , "Kent Paul Dolan"
wrote: One idea that comes to my mind is that very young, nearby galaxies are very hard to observe for two reasons: they are faint, and quickly gets absorbed into larger galaxies. Why would any even exist? One problem, from the point of view of theory, is that they have been observed. :-) Surely after ~14 billion years, most of the easily accumulated intergalactic gas has long ago gathered into galaxies, and the remaining cases gathering more recently would be so thinly scattered throughout the universe that the chance of even one being "nearby" for useful meanings of that vague term would be "slender to none"? Big Bangists must explain it in terms of the Big Bang. :-) I suggested it might come from tunneling of matter out of black holes, which in fact leads to a complicated model in order to work, but can in principle be tested. It was discussed here before. That is in part I am asking these questions. If there one is looking for a*situation where QM and GR closely interact, that is either the early universe (if there was one), or black holes; I do not know of any other situation. -- Hans Aberg |
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Hubble makes 3D dark matter map
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#25
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Hubble makes 3D dark matter map
ebunn=40lfa221051.richmond.edu wrote:
In article mt2.0-23776-1168506825=40hercules.herts.ac.uk, Richard Saam rdsaam=40att.net wrote: If the density of dark matter is anywhere close to critical density =7E10=5E-30 g/cc, its influence on planetary orbits would be negligible That's right. In fact, the density of dark matter in the neighborhood= of the solar system is considerably larger than the critical density, = but it's still far too small to have a measurable effect on solar system d= ynamics. Working out why is a nice exercise. The orbital speed of objects in our Galaxy is approximately v=3D200 km= /s over quite a range of orbital radii, including the Sun's orbital radiu= s. Assuming the Galaxy's mass distribution can be approximated as a spher= ical halo, the mass Mwithin a radius R obeys GM/R=5E2 =3D v=5E2/R, so M =3D v=5E2 R / G. Since v is roughly constant as a function of R, the mass in a thin spherical shell is dM =3D (v2/G) dR. The volume of the shell is 4 pi = R2 dR, so the local density is rho =3D v=5E2 / (4 pi G R=5E2). At the Sun's orbital radius, this works out to 7 x 10=5E=7B-25=7D g/cm= 3. If you don't assume a spherical halo, then the numbers change somewhat= , but the order of magnitude doesn't. Suppose you filled the solar system with material at this density. The amount of stuff within Pluto's orbit would be equal to this densit= y times the volume of a sphere of radius equal to Pluto's orbit. That w= orks out to 6 x 10=5E=7B17=7D kg, or less than a trillionth of a solar mass= ... -Ted Looking a bit more at Ted's calculations, it unclear what fraction of 7 x 10=5E=7B-25=7D g/cm3 is considered dark matter. the wiki page http://en.wikipedia.org/wiki/Milky_Way provides the relevant parameters of the Milky Way Solar mass 1.99E+33 g Milky Way mass 5.80E+11 solar masses Milky Way mass 1.15E+45 g Milky Way diameter 100,000 light years Milky Way diameter (D) 9.46E+22 cm Milky Way diameter (R) 4.73E+22 cm Milky Way thickness .01*D 9.46E+20 cm Milky Way rotation velocity 2.00E+07 cm/sec (200 km/sec) Milky Way age 13.4 billion years Newtonian G 6.67E-08 cm3 / (g sec) v is constant with R at 200 km/sec which implies as Ted says: dM =3D (v=5E2 / G) dR which implies dM =3D K dR but here is the point and correct me if I am wrong: The relationship dM =3D K dR does not have to be in a sphere for the derivation to be valid. Observations indicate that the Milky Way is essentially a disc. then paraphrasing Ted here The incremental volume of the Milky Way disc is 2 pi thickness R dR, so the local density is rho =3D v=5E2 / (2 pi thickness G R) =3D (2.00E+07)=5E2 / (2*pi*(9.46E+20)*(6.67E-08)*(4.73E+22)) =3D 2.13E-23 g/cm=5E3 this value of density (rho) at R says nothing about the nature of the matter whether it is dark matter or other. It is an average value of all stars, dust, gas, dark matter, etc at R. the wiki page http://en.wikipedia.org/wiki/Milky_Way indicates that: 'The distance from the Sun to the galactic center is estimated at 26,000 =B1 1400 light-years=22 so the local (rho) density at our solar system would be: rho (local) =3D 2.13E-23 * 50,000/26,000 =3D 4.1E-23 g/cm3 but this value again is an average value of all stars, dust, gas, dark matter, etc at R (local). The key question is how after 13.4 billion years does the Milky Way galaxy have a distribution of mass which is proportional to R or (dM =3D K dR). Calculations indicate that a persistent and continuous force over 13.4 billion years related to universe critical density (6E-30 g/cm3) as applied to galactic mass will result in (dM =3D K dR). Richard |
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Hubble makes 3D dark matter map
In article ,
Hans Aberg wrote: In article , wrote: Yet another suggestion for dark matter, that comes to my mind, is dark planetary systems, that is, essentially a star system before the star has ignited. Is that possible or impossible by current theoretical knowledge? Well, the planets are a bit of a red herring he the star completely dominates the mass of a star system, so what you're asking is whether protostars can be the dark matter. The answer is no for any number of reasons. First, protostars are observable, especially in the infrared, so we have quite a good idea of how many there are. Second, a protostar remains a protostar for only a limited time before becoming a star. So the number of stars we see sets a good limit on the number of protostars. The subject of when planetary systems form and what they look like as they do is quite an interesting one. It's been getting a lot of attention in recent years as infrared observations have gotten better. It ends up having nothing at all to do with the dark matter, but it's a lot of fun in its own right. -Ted -- [E-mail me at , as opposed to .] |
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Hubble makes 3D dark matter map
wrote:
In article , Richard Saam wrote: If the density of dark matter is anywhere close to critical density ~10^-30 g/cc, its influence on planetary orbits would be negligible That's right. In fact, the density of dark matter in the neighborhood of the solar system is considerably larger than the critical density, but it's still far too small to have a measurable effect on solar system dynamics. Working out why is a nice exercise. The orbital speed of objects in our Galaxy is approximately v=200 km/s over quite a range of orbital radii, including the Sun's orbital radius. Assuming the Galaxy's mass distribution can be approximated as a spherical halo, the mass Mwithin a radius R obeys GM/R^2 = v^2/R, so M = v^2 R / G. Since v is roughly constant as a function of R, the mass in a thin spherical shell is dM = (v^2/G) dR. The volume of the shell is 4 pi R^2 dR, so the local density is rho = v^2 / (4 pi G R^2). At the Sun's orbital radius, this works out to 7 x 10^{-25} g/cm^3. If you don't assume a spherical halo, then the numbers change somewhat, but the order of magnitude doesn't. Suppose you filled the solar system with material at this density. The amount of stuff within Pluto's orbit would be equal to this density times the volume of a sphere of radius equal to Pluto's orbit. That works out to 6 x 10^{17} kg, or less than a trillionth of a solar mass. -Ted Looking a bit more at Ted's calculations, it is unclear what fraction of 7E-25 g/cm^3 is considered dark matter. The wiki page http://wikipedia.org/wiki/Milky_Way provides some of the relevant parameters of our Milky Way Galaxy Solar Mass 1.99E33 g Milky Way Mass 5.8E11 solar mass Milky Way Mass (M) 1.15E45 g Milky Way diameter 100,000 light years Milky Way diameter (D) 9.46E22 cm Milky Way radius (R) 4.73E22 cm Milky Way thickness .01 D 9.46E20 cm Milky Way rotation velocity (v) 2.0E7 cm/sec (200 km/sec) Milky Way age 13.4 billion years Newtonian (G) 6.67E-8 cm^3 / (g sec) rotational velocity (v) is constant with R at 200 km/sec which implies as Ted says: dM = (v^2 / G) dR which implies dm = K dR (where K is constant) but here is a divergent point from Ted: The relationship dM = K dR does not have to be in a sphere for the derivation to be valid. Observation indicates that the Milky Way is essentially a disc. then paraphrasing Ted he The incremental volume of the Milky Way is 2 pi thickness R dR so the local density (rho) is: rho = v^2 / (2 pi thickness G R) = (2.0E7)^2 / (2*pi*(9.46E20)*(6.67E-8)*(4.73E22)) = 2.13E-23 g/cm^3 this value of density (rho) at R says nothing about the nature of the matter whether it is dark matter or other. It is an average value of all stars, dust, gas, dark matter, etc at R. The wiki page: http://wikipedia.org/wiki/Milky_Way indicates that: 'The distance from the Sun to the galactic center is estimated at 26,000 +/- 1400 light years. So the local (rho) density at our solar system would be: rho = 2.13E-23 g/cm^3 * 50,000 / 26,000 = 4.1E-23 g/cm^3 but this value again is an average value of all stars, dust, gas, dark matter, etc at R (local). The key question is how after 13.4 billion years does the Milky Way galaxy have a distribution of mass which is proportional to R or (dM = K dR). Calculations indicate that a persistent and continuous force over 13.4 billion years related to the universe critical density (6E-30 g/cm^3) as applied to galactic mass results in (dM = K dR) and consistent with the Milky Way Mass of 1.15E45 g. Richard |
#28
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Hubble makes 3D dark matter map
In article ,
Richard Saam wrote: wrote: Looking a bit more at Ted's calculations, it is unclear what fraction of 7E-25 g/cm^3 is considered dark matter. It depends on where you are and over what size scale you're willing to average. What we think we know observationally is the average density of all stuff (visible and dark), averaged over largish volumes of space. To decide how much of that stuff is dark matter, you'd want to subtract off the mass of all the stuff you can see. The number that I gave is an estimate of the density averaged over pretty large volumes -- in particular, over volumes that extend significantly above and below the scale height of the visible disc of the Galaxy. Over that sort of volume, most of the mass is due to dark matter: the visible stuff is only, maybe, 1/3 or 1/4 of the total. On the other hand, right in the disc of the Galaxy, the density of visible stuff (stars, etc.) is quite a bit higher, so right in the solar neighborhood the fraction of all the matter that's dark is probably smaller. We think that the dark matter is pretty smoothly distributed over these sort of scales, so within a factor of a few (which is all I cared about) the above number should be about equal to the local dark matter density. I don't think we can say anything more precise than that. rotational velocity (v) is constant with R at 200 km/sec which implies as Ted says: dM = (v^2 / G) dR which implies dm = K dR (where K is constant) but here is a divergent point from Ted: The relationship dM = K dR does not have to be in a sphere for the derivation to be valid. Yes, it does. The rule it's derived from, M = v^2 R / G, which is essentially Kepler's third law, is derived based on a spherically symmetric distribution of matter. Observation indicates that the Milky Way is essentially a disc. The visible stuff is. The overall density is not. That's really part of the point: the distribution of mass as inferred by its gravitational effects does not match the distribution of visible matter. From observations of only things in the disc of the Galaxy, you can't tell whether the overall density distribution in the Galaxy is disc-like or spherical, but from observations out of the plane you can: the orbits of things significantly above or below the disc will be different depending on whether the bulk of the mass in the Galaxy lies in the disc or is spread out in a more three-dimensional way. Observations of such objects show that the bulk of the mass of the Galaxy is indeed spread out in a three-dimensional volume, as opposed to being confined to a disc, although the exact shape is debated. I'm not an expert on the details of this stuff, but here's a sample article that discusses some observational constraints: http://arxiv.org/abs/astro-ph/0107248 -Ted -- [E-mail me at , as opposed to .] |
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Hubble makes 3D dark matter map
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