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Horizontal and Vertical Translation of Functions
I know it's math but it does fit in some way into astronomy field which is
why I'm posting here. I don't understand following question... Can anyone telll me what am I suppose to do..? Question The function y=f(x) is given. Describe how the graphs of the following functions can be obtained from the graph of y=f(x). (a) y = f(x)+5 What am I suppose to do with this? 2nd question.... I under the y=sequare root x x y 0 0 1 1 4 2 9 3 16 4 but that's where i'm totally lost y=square root x + 2 (x + 2 are underneath square root) x y -2 1 -1 2 -2 3 -7 4 -14 5 if x is -2 won't -2 and plus +2 would cross out eachother and answer would be 0? and same confusion i have with rest of y-axis. thanks in advance Happy Linux User -- Happy Linux User |
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Venona Wickstrom wrote:
I know it's math but it does fit in some way into astronomy field which is why I'm posting here. There are several math groups that would be more appropriate. I don't understand following question... Can anyone telll me what am I suppose to do..? Question The function y=f(x) is given. Describe how the graphs of the following functions can be obtained from the graph of y=f(x). (a) y = f(x)+5 What am I suppose to do with this? Compare the graph of some f(x) with that of f(x) + 5. How does one relate to the other? In other words, given f(x) how might you draw a graph of f(x) + 5 without calculating and plotting the individual points? You've already given yourself a clue in the subject line ... 2nd question.... I under the y=sequare root x x y 0 0 1 1 4 2 9 3 16 4 but that's where i'm totally lost Me, too. It appears that some of the question in missing: what is "I"? But the table appears correct as a listing of some values of the function y = sqrt(x). y=square root x + 2 (x + 2 are underneath square root) x y -2 1 -1 2 -2 3 -7 4 -14 5 if x is -2 won't -2 and plus +2 would cross out eachother and answer would be 0? and same confusion i have with rest of y-axis. There's definitely something wrong here; the tabulated points don't even lie on a parabola. The first three taken alone suggest a left-opening parabola with vertex (-1,2); an equation for the latter is y = 2 +/- sqrt(-(x+1)), which produces a table like this: x y -2 1 -1 2 -2 3 -5 4 -10 5. OTOH the graph of y = +/- sqrt(x+2) is a right-opening parabola with vertex (-2,0), giving values of x y -2 0 -1 +/- 1 2 +/- 2 7 +/- 3 14 +/- 4 23 +/- 5. -- Odysseus |
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