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Riedt’s constant Y = 5022635



 
 
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  #1  
Old January 15th 18, 11:23 PM posted to sci.astro
Peter Riedt
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Posts: 83
Default Riedt’s constant Y = 5022635

Riedt’s constant Y = 5022635

The value of Y connects the nine major planets by their semi major axis
divided by their orbital velocity and divided by their orbital period in earth years.

rm vm opy Y=rm/vm/opy
MER 57,909,231,029 47872.33119 0.2408416 5022635
VEN 108,209,525,401 35020.93000 0.6151856 5022635
EAR 149,598,319,494 29784.86500 0.9999988 5022635
MAR 227,943,771,564 24130.71224 1.8807278 5022635
JUP 778,342,761,465 13056.07169 11.8693454 5022635
SAT 1,426,714,892,866 9643.82000 29.4548244 5022635
URA 2,870,633,540,862 6798.95700 84.0627938 5022635
NEP 4,498,393,012,162 5432.26100 164.8713207 5022635
PLU 5,906,438,090,764 4737.55900 248.2214844 5022635
  #2  
Old January 16th 18, 08:47 AM posted to sci.astro
Libor 'Poutnik' Stříž
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Posts: 48
Default Riedt’s constant Y = 5022635

Dne 15/01/2018 v 23:23 Peter Riedt napsal(a):
Riedt’s constant Y = 5022635

The value of Y connects the nine major planets by their semi major axis
divided by their orbital velocity and divided by their orbital period in earth years.

rm vm opy Y=rm/vm/opy
MER 57,909,231,029 47872.33119 0.2408416 5022635
VEN 108,209,525,401 35020.93000 0.6151856 5022635
EAR 149,598,319,494 29784.86500 0.9999988 5022635
MAR 227,943,771,564 24130.71224 1.8807278 5022635
JUP 778,342,761,465 13056.07169 11.8693454 5022635
SAT 1,426,714,892,866 9643.82000 29.4548244 5022635
URA 2,870,633,540,862 6798.95700 84.0627938 5022635
NEP 4,498,393,012,162 5432.26100 164.8713207 5022635
PLU 5,906,438,090,764 4737.55900 248.2214844 5022635


What remains is to express the relation
of Y to G.Ms
where G is Gravitation constant
and Ms is the Sun mass.

BTW, if you consider 5,906,438,090,764 as unstable parameter,
why so many valid digits ? It is not scientific approach.

I would rather say a parameter with faked accuracy.

--
Poutnik ( The Pilgrim, Der Wanderer )

A wise man guards words he says,
as they say about him more,
than he says about the subject.
  #3  
Old January 16th 18, 12:34 PM posted to sci.astro
Peter Riedt
external usenet poster
 
Posts: 83
Default Riedt’s constant Y = 5022635

On Tuesday, January 16, 2018 at 3:47:14 PM UTC+8, Libor 'Poutnik' StÅ™Ã*ž wrote:
Dne 15/01/2018 v 23:23 Peter Riedt napsal(a):
Riedt’s constant Y = 5022635

The value of Y connects the nine major planets by their semi major axis
divided by their orbital velocity and divided by their orbital period in earth years.

rm vm opy Y=rm/vm/opy
MER 57,909,231,029 47872.33119 0.2408416 5022635
VEN 108,209,525,401 35020.93000 0.6151856 5022635
EAR 149,598,319,494 29784.86500 0.9999988 5022635
MAR 227,943,771,564 24130.71224 1.8807278 5022635
JUP 778,342,761,465 13056.07169 11.8693454 5022635
SAT 1,426,714,892,866 9643.82000 29.4548244 5022635
URA 2,870,633,540,862 6798.95700 84.0627938 5022635
NEP 4,498,393,012,162 5432.26100 164.8713207 5022635
PLU 5,906,438,090,764 4737.55900 248.2214844 5022635


What remains is to express the relation
of Y to G.Ms
where G is Gravitation constant
and Ms is the Sun mass.

Yes.
  #4  
Old January 16th 18, 03:10 PM posted to sci.astro
Martin Brown[_3_]
external usenet poster
 
Posts: 189
Default Riedt’s constant Y = 5022635

On 15/01/2018 22:23, Peter Riedt wrote:
Riedt’s constant Y = 5022635

The value of Y connects the nine major planets by their semi major axis
divided by their orbital velocity and divided by their orbital period in earth years.

rm vm opy Y=rm/vm/opy
MER 57,909,231,029 47872.33119 0.2408416 5022635
VEN 108,209,525,401 35020.93000 0.6151856 5022635
EAR 149,598,319,494 29784.86500 0.9999988 5022635
MAR 227,943,771,564 24130.71224 1.8807278 5022635
JUP 778,342,761,465 13056.07169 11.8693454 5022635
SAT 1,426,714,892,866 9643.82000 29.4548244 5022635
URA 2,870,633,540,862 6798.95700 84.0627938 5022635
NEP 4,498,393,012,162 5432.26100 164.8713207 5022635
PLU 5,906,438,090,764 4737.55900 248.2214844 5022635


How exciting - more numerical mumbo jumbo! R /(kR/T)/T = k

At least Kepler's third law T^2 = k.a^3 has useful predictive power.

--
Regards,
Martin Brown
  #5  
Old January 16th 18, 10:11 PM posted to sci.astro
Paul B. Andersen[_10_]
external usenet poster
 
Posts: 10
Default Riedt’s constant Y = 5022635

Den 15.01.2018 23.23, skrev Peter Riedt:
Riedt’s constant Y = 5022635

The value of Y connects the nine major planets by their semi major axis
divided by their orbital velocity and divided by their orbital period in earth years.

rm vm opy Y=rm/vm/opy
MER 57,909,231,029 47872.33119 0.2408416 5022635
VEN 108,209,525,401 35020.93000 0.6151856 5022635
EAR 149,598,319,494 29784.86500 0.9999988 5022635
MAR 227,943,771,564 24130.71224 1.8807278 5022635
JUP 778,342,761,465 13056.07169 11.8693454 5022635
SAT 1,426,714,892,866 9643.82000 29.4548244 5022635
URA 2,870,633,540,862 6798.95700 84.0627938 5022635
NEP 4,498,393,012,162 5432.26100 164.8713207 5022635
PLU 5,906,438,090,764 4737.55900 248.2214844 5022635



For any object moving in a circle, we have:

v = 2π⋅r/Ts
whe
v is the orbital speed in metres per second
r is the radius of the circle in metres
Ts is the period in seconds

Riedt’s constant Y = r/v/Ty
where Ty is the period in year

Y = r/(2π⋅r/Ts)/Ty = Ty/(2π⋅Ts)
Ty/Ts = 31556952
Y = 5022445

What's the point with your constant?


--
Paul

https://paulba.no/
  #6  
Old January 16th 18, 10:57 PM posted to sci.astro
Libor 'Poutnik' Stříž
external usenet poster
 
Posts: 48
Default Riedt’s constant Y = 5022635

Dne 16/01/2018 v 12:34 Peter Riedt napsal(a):
On Tuesday, January 16, 2018 at 3:47:14 PM UTC+8, Libor 'Poutnik' StÅ™Ã*ž wrote:
Dne 15/01/2018 v 23:23 Peter Riedt napsal(a):
Riedt’s constant Y = 5022635

The value of Y connects the nine major planets by their semi major axis
divided by their orbital velocity and divided by their orbital period in earth years.

rm vm opy Y=rm/vm/opy
MER 57,909,231,029 47872.33119 0.2408416 5022635
VEN 108,209,525,401 35020.93000 0.6151856 5022635
EAR 149,598,319,494 29784.86500 0.9999988 5022635
MAR 227,943,771,564 24130.71224 1.8807278 5022635
JUP 778,342,761,465 13056.07169 11.8693454 5022635
SAT 1,426,714,892,866 9643.82000 29.4548244 5022635
URA 2,870,633,540,862 6798.95700 84.0627938 5022635
NEP 4,498,393,012,162 5432.26100 164.8713207 5022635
PLU 5,906,438,090,764 4737.55900 248.2214844 5022635


What remains is to express the relation
of Y to G.Ms
where G is Gravitation constant
and Ms is the Sun mass.

Yes.

So .....

BTW, semi major axis of planets
definitely is not known with precision of 1 metre.
It is manifestation of ignorance.

Especially the one of Pluto.
Also, it fluctuates because of influence of big planets.

--
Poutnik ( The Pilgrim, Der Wanderer )

A wise man guards words he says,
as they say about him more,
than he says about the subject.
  #7  
Old January 16th 18, 11:10 PM posted to sci.astro
Anders Eklöf
external usenet poster
 
Posts: 100
Default Riedt's constant Y = 5022635

Peter Riedt wrote:

Riedt's constant Y = 5022635

The value of Y connects the nine major planets by their semi major axis
divided by their orbital velocity and divided by their orbital period in
earth years.

rm vm opy Y=rm/vm/opy
MER 57,909,231,029 47872.33119 0.2408416 5022635
VEN 108,209,525,401 35020.93000 0.6151856 5022635
EAR 149,598,319,494 29784.86500 0.9999988 5022635
MAR 227,943,771,564 24130.71224 1.8807278 5022635
JUP 778,342,761,465 13056.07169 11.8693454 5022635
SAT 1,426,714,892,866 9643.82000 29.4548244 5022635
URA 2,870,633,540,862 6798.95700 84.0627938 5022635
NEP 4,498,393,012,162 5432.26100 164.8713207 5022635
PLU 5,906,438,090,764 4737.55900 248.2214844 5022635


This is funny - so funny I thought someone was impersonising Riedt for
fun. But I checked the headers, and it's really him.

Different IP, but the same network, and IPs are dynamic, so...

--
I recommend Macs to my friends, and Windows machines
to those whom I don't mind billing by the hour
  #8  
Old January 17th 18, 12:55 AM posted to sci.astro
Peter Riedt
external usenet poster
 
Posts: 83
Default Riedt’s constant Y = 5022635

On Wednesday, January 17, 2018 at 5:11:46 AM UTC+8, Paul B. Andersen wrote:
Den 15.01.2018 23.23, skrev Peter Riedt:
Riedt’s constant Y = 5022635

The value of Y connects the nine major planets by their semi major axis
divided by their orbital velocity and divided by their orbital period in earth years.

rm vm opy Y=rm/vm/opy
MER 57,909,231,029 47872.33119 0.2408416 5022635
VEN 108,209,525,401 35020.93000 0.6151856 5022635
EAR 149,598,319,494 29784.86500 0.9999988 5022635
MAR 227,943,771,564 24130.71224 1.8807278 5022635
JUP 778,342,761,465 13056.07169 11.8693454 5022635
SAT 1,426,714,892,866 9643.82000 29.4548244 5022635
URA 2,870,633,540,862 6798.95700 84.0627938 5022635
NEP 4,498,393,012,162 5432.26100 164.8713207 5022635
PLU 5,906,438,090,764 4737.55900 248.2214844 5022635



For any object moving in a circle, we have:

v = 2π⋅r/Ts
whe
v is the orbital speed in metres per second
r is the radius of the circle in metres
Ts is the period in seconds

Riedt’s constant Y = r/v/Ty
where Ty is the period in year

Y = r/(2π⋅r/Ts)/Ty = Ty/(2π⋅Ts)
Ty/Ts = 31556952
Y = 5022445

What's the point with your constant?


--
Paul

https://paulba.no/


What's the point with restating my formula?
  #9  
Old January 17th 18, 08:39 AM posted to sci.astro
Martin Brown[_3_]
external usenet poster
 
Posts: 189
Default Riedt’s constant Y = 5022635

On 16/01/2018 23:55, Peter Riedt wrote:
On Wednesday, January 17, 2018 at 5:11:46 AM UTC+8, Paul B. Andersen wrote:
Den 15.01.2018 23.23, skrev Peter Riedt:
Riedt’s constant Y = 5022635

The value of Y connects the nine major planets by their semi major axis
divided by their orbital velocity and divided by their orbital period in earth years.

rm vm opy Y=rm/vm/opy
MER 57,909,231,029 47872.33119 0.2408416 5022635
VEN 108,209,525,401 35020.93000 0.6151856 5022635
EAR 149,598,319,494 29784.86500 0.9999988 5022635
MAR 227,943,771,564 24130.71224 1.8807278 5022635
JUP 778,342,761,465 13056.07169 11.8693454 5022635
SAT 1,426,714,892,866 9643.82000 29.4548244 5022635
URA 2,870,633,540,862 6798.95700 84.0627938 5022635
NEP 4,498,393,012,162 5432.26100 164.8713207 5022635
PLU 5,906,438,090,764 4737.55900 248.2214844 5022635



For any object moving in a circle, we have:

v = 2π⋅r/Ts
whe
v is the orbital speed in metres per second
r is the radius of the circle in metres
Ts is the period in seconds

Riedt’s constant Y = r/v/Ty
where Ty is the period in year

Y = r/(2π⋅r/Ts)/Ty = Ty/(2π⋅Ts)
Ty/Ts = 31556952
Y = 5022445

What's the point with your constant?


--
Paul

https://paulba.no/


What's the point with restating my formula?


He is pointing out that it is a boring numerical identity with a value
that depends only on the measurement units used and nothing else.

--
Regards,
Martin Brown
  #10  
Old January 19th 18, 04:57 AM posted to sci.astro
Peter Riedt
external usenet poster
 
Posts: 83
Default Riedt’s constant Y = 5022635

On Wednesday, January 17, 2018 at 3:39:24 PM UTC+8, Martin Brown wrote:
On 16/01/2018 23:55, Peter Riedt wrote:
On Wednesday, January 17, 2018 at 5:11:46 AM UTC+8, Paul B. Andersen wrote:
Den 15.01.2018 23.23, skrev Peter Riedt:
Riedt’s constant Y = 5022635

The value of Y connects the nine major planets by their semi major axis
divided by their orbital velocity and divided by their orbital period in earth years.

rm vm opy Y=rm/vm/opy
MER 57,909,231,029 47872.33119 0.2408416 5022635
VEN 108,209,525,401 35020.93000 0.6151856 5022635
EAR 149,598,319,494 29784.86500 0.9999988 5022635
MAR 227,943,771,564 24130.71224 1.8807278 5022635
JUP 778,342,761,465 13056.07169 11.8693454 5022635
SAT 1,426,714,892,866 9643.82000 29.4548244 5022635
URA 2,870,633,540,862 6798.95700 84.0627938 5022635
NEP 4,498,393,012,162 5432.26100 164.8713207 5022635
PLU 5,906,438,090,764 4737.55900 248.2214844 5022635



For any object moving in a circle, we have:

v = 2π⋅r/Ts
whe
v is the orbital speed in metres per second
r is the radius of the circle in metres
Ts is the period in seconds

Riedt’s constant Y = r/v/Ty
where Ty is the period in year

Y = r/(2π⋅r/Ts)/Ty = Ty/(2π⋅Ts)
Ty/Ts = 31556952
Y = 5022445

What's the point with your constant?


--
Paul

https://paulba.no/


What's the point with restating my formula?


He is pointing out that it is a boring numerical identity with a value
that depends only on the measurement units used and nothing else.

--
Regards,
Martin Brown


What else could there be to make it more exciting?
 




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