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"Destination Moon" question
Pat Flannery wrote:
So would this work any way, shape, or form? Maybe if they took the fins and warhead off of the V-2, considering that it wouldn't have to deal with air drag, I am not quite able to tell from what I see at http://en.wikipedia.org/wiki/V-2_roc...hnical_details if the "jet vanes" are attached to the fins or to the body. rick jones -- oxymoron n, commuter in a gas-guzzling luxury SUV with an American flag these opinions are mine, all mine; HP might not want them anyway... feel free to post, OR email to rick.jones2 in hp.com but NOT BOTH... |
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"Destination Moon" question
They were running "Destination Moon" today, and towards the beginning
one of the characters claims a V-2 missile fired from the surface of the Moon could travel to Earth. Max velocity of a V-2 was 1.6 km/s, but that was in a ballistic, not vertical, trajectory. According to the Wikipedia article escape velocity from the Moon is 2.38 km/s, but that's escape velocity, not kicking something into Earth's gravity field. So would this work any way, shape, or form? Maybe if they took the fins and warhead off of the V-2, considering that it wouldn't have to deal with air drag, and the engine's thrust would be higher when fired in vacuum? It sounds like something a aerospace writer from around the time of the movie would point out. Pat |
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"Destination Moon" question
On 1/11/2011 5:01 PM, Rick Jones wrote:
I am not quite able to tell from what I see at http://en.wikipedia.org/wiki/V-2_roc...hnical_details if the "jet vanes" are attached to the fins or to the body. Luckily, you've just run into a V-2 maniac. :-) The graphite exhaust vanes run off a seperate set of electrical motors and drive connections than the aerodynamic control surfaces on the tail fins. The graphite vane assembly attaches to the base of the rocket body: http://www.v2rocket.com/start/makeup/infopic05.jpg Pat |
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"Destination Moon" question
Max velocity of a V-2 was 1.6 km/s, but that was in a ballistic, not vertical, trajectory. According to the Wikipedia article escape velocity from the Moon is 2.38 km/s, but that's escape velocity, not kicking something into Earth's gravity field. I'm having trouble understanding the use of Max Velocity here. Did the V-2 attain a maximum velocity of 1.6 km/sec in the Earth's Gravitational Field at the end of the powered portion of the trajectory. To get there it expended potential energy equivilent of approximately average mass x g x height, and Kinetic energy of 1/2 final mass x velocity squared, plus air resistance term. On the moon g is one sixth of earth, and there's no air resistance. So reaching escape velocity seems more than reasonable, or am I missing something in the way Max Velocity is defined. Val Kraut |
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"Destination Moon" question
On 1/12/2011 8:28 AM, Val Kraut wrote:
Max velocity of a V-2 was 1.6 km/s, but that was in a ballistic, not vertical, trajectory. According to the Wikipedia article escape velocity from the Moon is 2.38 km/s, but that's escape velocity, not kicking something into Earth's gravity field. I'm having trouble understanding the use of Max Velocity here. Did the V-2 attain a maximum velocity of 1.6 km/sec in the Earth's Gravitational Field at the end of the powered portion of the trajectory. To get there it expended potential energy equivilent of approximately average mass x g x height, and Kinetic energy of 1/2 final mass x velocity squared, plus air resistance term. On the moon g is one sixth of earth, and there's no air resistance. So reaching escape velocity seems more than reasonable, or am I missing something in the way Max Velocity is defined. Max velocity for the V-2 would be the speed it was going at the moment its engine stopped firing (its impact speed was considerably lower due to air drag on the way down) but at engine cutoff it was moving very near to horizontal on its ballistic arc. If launched vertically it would be ascending against the Earth's gravity field during the entire engine burn, so its velocity on engine burn-out would be lower than on ballistic flight to London (the altitude record for a V-2 launched vertically was 206 km). The trick is figuring out what "lunar escape velocity" means. If the Moon were an independent planetary body rather than in orbit around the Earth, that would be easy to do... escape velocity would mean the velocity that an object would need to get to to leave its gravitational influence and enter orbit around the Sun. But in this case an object doesn't need to do that, it just needs enough velocity to get to the point between the Moon and Earth where the attraction of the Earth's gravity becomes greater than that of the Moon, and it will fall all the rest of the way on its own. So I need to figure out A.) How much weight could be stripped off of a V-2 by removing everything not needed for operation in Earth's atmosphere. B.) How much of an improvement in specific impulse the engine gets by operating in vacuum during its whole burn C.) If those two together give it enough "umph" to get to to the point where it would fall towards Earth rather than back into the Moon. Pat |
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"Destination Moon" question
On Jan 11, 10:43*pm, Pat Flannery wrote:
They were running "Destination Moon" today, and towards the beginning one of the characters claims a V-2 missile fired from the surface of the Moon could travel to Earth. Max velocity of a V-2 was 1.6 km/s, but that was in a ballistic, not vertical, trajectory. According to the Wikipedia article escape velocity from the Moon is 2.38 km/s, but that's escape velocity, not kicking something into *Earth's gravity field. So would this work any way, shape, or form? Maybe if they took the fins and warhead off of the V-2, considering that it wouldn't have to deal with air drag, and the engine's thrust would be higher when fired in vacuum? It sounds like something a aerospace writer from around the time of the movie would point out. Pat According to this Astronautix page the V-2 had a gross mass of 12,805 kg and empty mass of 4,008 kg, and a vacuum Isp of 239 sec: V-2. http://www.friends-partners.org/part...ade/lvs/v2.htm From this we can calculate the delta-V in vacuum as 239*9.8ln(12,805/4,009) = 2,720 m/s. This page gives a table of delta-V's in the Earth-Moon system: Delta-v budget. Earth–Moon space. http://en.wikipedia.org/wiki/Delta-v...0.93Moon_space With aerobraking it gives the delta-V as 2,740 m/s. So likely it could have made it back to Earth orbit. BTW, the movies is available on YouTube: Destination Moon. http://www.youtube.com/watch?v=DsisGSBlQqo Bob Clark |
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