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"beavith" wrote in message
... however, give me a quick primer in fractions... does x/yx = x/y/x ? reducing, i get 1/y and x^2/y you should not be getting x^2/y If we take x/y/x and arrange it like this ... (x/y)/x division by x is the same as multiplication by its inverse, so ... (x/y)/x = x/y * 1/x = 1/y |
#12
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On Tue, 22 Jun 2004 09:33:51 -0400, "John Zinni"
wrote: "beavith" wrote in message .. . however, give me a quick primer in fractions... does x/yx = x/y/x ? reducing, i get 1/y and x^2/y you should not be getting x^2/y If we take x/y/x and arrange it like this ... (x/y)/x ahhh! so x/y/1/x would be x^2/y. thanks..... it did seem like a bizarre unit. division by x is the same as multiplication by its inverse, so ... (x/y)/x = x/y * 1/x = 1/y |
#13
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On Tue, 22 Jun 2004 09:33:51 -0400, "John Zinni"
wrote: "beavith" wrote in message .. . however, give me a quick primer in fractions... does x/yx = x/y/x ? reducing, i get 1/y and x^2/y you should not be getting x^2/y If we take x/y/x and arrange it like this ... (x/y)/x ahhh! so x/y/1/x would be x^2/y. thanks..... it did seem like a bizarre unit. division by x is the same as multiplication by its inverse, so ... (x/y)/x = x/y * 1/x = 1/y |
#14
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beavith wrote:
so x/y/1/x would be x^2/y. As long as you parse it as (x/y)/(1/x). Reading left to right, as a calculator program might, i.e. ((x/y)/1)/x, would give a different result, 1/y again. Same for x/(y/(1/x)). I think your original problem with "x/y/x" is that you were parsing it as x/(y/x) -- but going back to the original km/s/Mpc, I think it clearly has to be grouped as (km/s)/Mpc. Moral: use parentheses to avoid ambiguity. (For expressing units you can also use exponential notation, e.g. km·s^-1·Mpc^-1 -- I think you'll find this practice adopted by many physics texts and journals. But it's ugly as hell in ASCII.) -- Odysseus |
#15
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beavith wrote:
so x/y/1/x would be x^2/y. As long as you parse it as (x/y)/(1/x). Reading left to right, as a calculator program might, i.e. ((x/y)/1)/x, would give a different result, 1/y again. Same for x/(y/(1/x)). I think your original problem with "x/y/x" is that you were parsing it as x/(y/x) -- but going back to the original km/s/Mpc, I think it clearly has to be grouped as (km/s)/Mpc. Moral: use parentheses to avoid ambiguity. (For expressing units you can also use exponential notation, e.g. km·s^-1·Mpc^-1 -- I think you'll find this practice adopted by many physics texts and journals. But it's ugly as hell in ASCII.) -- Odysseus |
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On Wed, 23 Jun 2004 02:28:00 GMT, Odysseus
wrote: beavith wrote: so x/y/1/x would be x^2/y. As long as you parse it as (x/y)/(1/x). Reading left to right, as a calculator program might, i.e. ((x/y)/1)/x, would give a different result, 1/y again. Same for x/(y/(1/x)). I think your original problem with "x/y/x" is that you were parsing it as x/(y/x) -- but going back to the original km/s/Mpc, I think it clearly has to be grouped as (km/s)/Mpc. that's right. time to dust off the old algebra book for some light evening reading. Moral: use parentheses to avoid ambiguity. (For expressing units you can also use exponential notation, e.g. km·s^-1·Mpc^-1 -- I think you'll find this practice adopted by many physics texts and journals. But it's ugly as hell in ASCII.) thanks, O, JZ. quandary resolved. |
#17
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On Wed, 23 Jun 2004 02:28:00 GMT, Odysseus
wrote: beavith wrote: so x/y/1/x would be x^2/y. As long as you parse it as (x/y)/(1/x). Reading left to right, as a calculator program might, i.e. ((x/y)/1)/x, would give a different result, 1/y again. Same for x/(y/(1/x)). I think your original problem with "x/y/x" is that you were parsing it as x/(y/x) -- but going back to the original km/s/Mpc, I think it clearly has to be grouped as (km/s)/Mpc. that's right. time to dust off the old algebra book for some light evening reading. Moral: use parentheses to avoid ambiguity. (For expressing units you can also use exponential notation, e.g. km·s^-1·Mpc^-1 -- I think you'll find this practice adopted by many physics texts and journals. But it's ugly as hell in ASCII.) thanks, O, JZ. quandary resolved. |
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