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Moon's mass



 
 
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  #11  
Old March 11th 12, 08:43 PM posted to uk.sci.astronomy
OG
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Posts: 780
Default Moon's mass

On 11/03/2012 18:07, Szczepan Bialek wrote:
napisal w wiadomosci
...
On 09/03/2012 09:07, Szczepan Bialek wrote:

Is the " 1/81.3 " calculated before 1960s or after?
S*

A quick search of Google Books shows that it was known to be of that
order
of magnitute at least 150 years ago
http://books.google.co.uk/books?id=1...20MOON&f=false

"Jarrold& sons, 1853"

So the " Missions of the 1960s" did not change it.
The same like with the "G" measured by Cavendish.
S*


I'm sure the space missions of the 60s would have allowed a
significantly
more accurate calculation of the mass of the Moon.

I am too.
But the mass of the Moon is not important.
The "G" (gravity constant) is very important. The "G" measured by
Cavendish
is wrong because the balls had the excess of electrons.
The direct measurement on the Moon is free from that error.

But the result is still a secret.
S*


In fact, Cavendish didn't measure G, as Newton's equation wasn't expressed
in that form until much later.
Cavendish's intention was to measure the density of the Earth. Using his
results it is possible to calculate a value for G.

I've no idea what you are talking about as regards to the error, but his
results are within 1% of the currently accepted value.


The Earth has the excess of electrons. So the Cavendish balls were
electrically charged.
The effect is size dependent. The Moon dust levitate because the Moon has
also the excess of electrons.
What will be G if you use the Moon and the small particle?

To measure the G it should be used the very large balls. For example the
Moon and the astronaut.
Do you agree?
S*



I've no idea what you're talking about. Don't mistake this for interest.
  #12  
Old March 12th 12, 09:21 AM posted to uk.sci.astronomy
Szczepan Bialek
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Posts: 51
Default Moon's mass


Uzytkownik "OG" napisal w wiadomosci
...
On 11/03/2012 18:07, Szczepan Bialek wrote:


The Earth has the excess of electrons. So the Cavendish balls were
electrically charged.
The effect is size dependent. The Moon dust levitate because the Moon has
also the excess of electrons.
What will be G if you use the Moon and the small particle?

To measure the G it should be used the very large balls. For example the
Moon and the astronaut.
Do you agree?


I've no idea what you're talking about. Don't mistake this for interest.


In 1969 (after Apollo landing on the Moon) the Earth/Moon mass ratio and the
densities ratio were directly measured.
Now are ISS. It is like the Moon. It attracts astronauts when they are in
space.
The mass of the ISS is known. So the G was measured in the new way.

I am asking if the results from the space era are published?

May be that they are the same as the "150 years old".
I simply do not know.
And what about you?
S*


 




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