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Further proof gravity is a push...



 
 
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  #1  
Old March 16th 04, 04:04 AM
Rick Sobie
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Default Further proof gravity is a push...

Lets suppose, that the moon, was a Dyson sphere, and its power unit failed,
and its orbit began to decay, then it would hit the earth.

Then what would happen?

It would bounce a few times, and then finally contact the surface like two
cogwheels grinding the surface to a mushy pulp, and then finally
come to rest. Like two uneven barbells.

Yet we don't see any planets like that do we?


  #2  
Old March 16th 04, 04:22 AM
Sam Wormley
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Default Further proof gravity is a push...

Rick Sobie wrote:

Lets suppose, that the moon, was a Dyson sphere, and its power unit failed,
and its orbit began to decay, then it would hit the earth.


Ref: http://scienceworld.wolfram.com/physics/Gravity.html
Ref: Hartle, "Gravity: An Introduction to Einstein's General Relativity", Addison
Wesley (2003)

"A few properties of the gravitational interaction that help explain when
gravity is important can already be seen from the gravitational force law

F_grav = G m_1 m_2 / r_12^2

o Gravity is a universal interaction in Newtonian theory between all mass, and,
since E = mc^2, in relativistic gravity between all forms of energy.

o Gravity is unscreened. There are no negative gravitational charges to cancel
positive ones, and therefore it is not possible to shield (screen) the gravitational
interaction. Gravity is always attractive.

o Gravity is a long-range interaction. The Newtonian force law ia a 1/r^2
interaction. There is no length scale that sets a range for gravitational
interactions as there is for the strong and weak interactions.

o Gravity is the weakest of the four fundamental interactions acting between
individual elementary particles at accessible energy scales. The ratio of
the gravitational attraction to the electromagnetic repulsion between two
protons separated by a distance r is

F_grav G m_p^2 / r^2 G m_p^2
-------- = -------------------- = ------------- ~ 10^-36
F_elec e^2 / (4 pi e_0 r^2) (e^2/4pi e_0)

where m_p is the mass of the proton and e is its charge.

These four facts explain a great deal about the role gravity plays in physical
phenomena. They explain, for example, why, although it is the weakest force,
gravity governs the organization of the universe on the largest distance
scales of astrophysics and cosmology. These distance scales are far beyond
the subatomic ranges of the strong and the weak interactions. Electromagnetic
interactions COULD be long range were there any large-scale objects with net
electric charge. But the universe is electrically neutral, and electromagnetic
forces are so much stronger than gravitational forces that any large-scale net
charge is quickly neutralized. Gravity is left to govern the structure of the
universe on the largest scales.
  #3  
Old March 16th 04, 05:21 PM
Mike
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Default Further proof gravity is a push...

Sam Wormley wrote in message ...
Rick Sobie wrote:

Lets suppose, that the moon, was a Dyson sphere, and its power unit failed,
and its orbit began to decay, then it would hit the earth.


Ref: http://scienceworld.wolfram.com/physics/Gravity.html
Ref: Hartle, "Gravity: An Introduction to Einstein's General Relativity", Addison
Wesley (2003)

"A few properties of the gravitational interaction that help explain when
gravity is important can already be seen from the gravitational force law

F_grav = G m_1 m_2 / r_12^2

o Gravity is a universal interaction in Newtonian theory between all mass, and,
since E = mc^2, in relativistic gravity between all forms of energy.


Newtonian Theory = Metaphysics. The fact that F_grav = G m_1 m_2 /
r_12^2
works well in non-relativistic speeds is purely accidental and
derivable from a mixture of empirical and metaphysical assumptions
using Euclidean geometry (Read the Principia.

Copernican and Ptolemaic systems are Kinematically equivalent. Wake
up.

o Gravity is unscreened. There are no negative gravitational charges to cancel
positive ones, and therefore it is not possible to shield (screen) the gravitational
interaction. Gravity is always attractive.


What is this "gravitational charge" thing? Harry Potter stuff?


o Gravity is a long-range interaction. The Newtonian force law ia a 1/r^2
interaction. There is no length scale that sets a range for gravitational
interactions as there is for the strong and weak interactions.

Action-at-a-distance is metaphysics. Someone must warn poor kids that
suffer in schools.

o Gravity is the weakest of the four fundamental interactions acting between
individual elementary particles at accessible energy scales. The ratio of
the gravitational attraction to the electromagnetic repulsion between two
protons separated by a distance r is

F_grav G m_p^2 / r^2 G m_p^2
-------- = -------------------- = ------------- ~ 10^-36
F_elec e^2 / (4 pi e_0 r^2) (e^2/4pi e_0)

where m_p is the mass of the proton and e is its charge.

Proton rocket?

These four facts explain a great deal about the role gravity plays in physical
phenomena. They explain, for example, why, [snip out distorted views of reality]


The above four postulation, no facts by no means, explain nothing.
They are sham. (Actually an alchemists' view of the world).
  #4  
Old March 16th 04, 05:23 PM
Uncle Al
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Default Further proof gravity is a push...

Rick Sobie wrote:

Lets suppose, that the moon, was a Dyson sphere, and its power unit failed,

[snip]

"were a Dyson sphere" Subjunctive case, idiot.

"Az di bobe vot gehat beytsim volt zi geven mayn zeyde."
Do you have two grandfathers?

--
Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
"Quis custodiet ipsos custodes?" The Net!
  #5  
Old March 16th 04, 09:06 PM
Gregory L. Hansen
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Default Further proof gravity is a push...

In article U8u5c.814118$ts4.511491@pd7tw3no,
Rick Sobie wrote:
Lets suppose, that the moon, was a Dyson sphere, and its power unit failed,
and its orbit began to decay, then it would hit the earth.

Then what would happen?

It would bounce a few times, and then finally contact the surface like two
cogwheels grinding the surface to a mushy pulp, and then finally
come to rest. Like two uneven barbells.

Yet we don't see any planets like that do we?



If the moon were a Dyson sphere and its power unit failed, why would it do
anything that the moon isn't doing now? Is the moon's power supply still
in good shape?

--
"Don't try to teach a pig how to sing. You'll waste your time and annoy
the pig."
  #6  
Old March 16th 04, 10:26 PM
sts060
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Default Further proof gravity is a push...

"Rick Sobie" wrote in message news:U8u5c.814118$ts4.511491@pd7tw3no...
Lets suppose, that the moon, was a Dyson sphere,


It is not a Dyson sphere; that idea is easily disproven by simply
considering what the Earth-Moon system would look like if the Moon
contained a red dwarf star (minimum mass = 0.08 Msolar). This has
been pointed out several times.

Also, you said in the "Hoagland Debunked!" thread

The moon is not a Dyson Sphere, it is a disabled battle planet.


Granted, you are posing a hypothetical case, but I'm curious as to
which you think it is: Dyson sphere or "battle planet"? Have you
decided?

and its power unit failed,
and its orbit began to decay, then it would hit the earth.


No; the Moon is in free fall around the Earth (well, the Earth-Moon
barycenter, which is inside the Earth). No propulsion system keeps it
aloft. In fact, tidal interactions (*not* a fictional repulsive
central force) are forcing it gradually *away from* the Earth.

The gravitational force between the two is given by the equation
F=-GMm/R^2, where G is a positive constant, M = mass of the Earth, m =
mass of the Moon, and R is the distance between the centers of the two
bodies.

The equation indicates the gravitational force is attractive.
When applied to the Moon's motion, the equation describes the observed
physical reality.
Why, then should the gravitational force be described as "pushing"
(i.e., repulsive)?


Then what would happen?

It would bounce a few times, and then finally contact the surface like two
cogwheels grinding the surface to a mushy pulp, and then finally
come to rest. Like two uneven barbells.

Yet we don't see any planets like that do we?


No, we don't. Because planets and their moons don't work that way.
  #7  
Old March 16th 04, 10:56 PM
OhBrother
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Default Further proof gravity is a push...

On Tue, 16 Mar 2004 13:26:01 -0800, sts060 wrote:

It would bounce a few times, and then finally contact the surface like two
cogwheels grinding the surface to a mushy pulp, and then finally
come to rest. Like two uneven barbells.

Yet we don't see any planets like that do we?


No, we don't. Because planets and their moons don't work that way.


I think Rick has decided the best way to attract visitors to his sites is
to provide the most 'frightening' KoOk scenario's.

Hollow moon? Battle Planet? It seems like there is a great deal of
manufactured reality trailing out behind his suppositions that isn't on
the table, and isn't being shared. So much so
that I betcha he has volumes of 'Fantasy Fiziks' to back up each of his
regurgitations.

Then you come along with actual numbers, reality, reasoned thinking and
hope to battle for his conscious attention? Naw, in the real world
there's too much work involved. In Fantasy Fiziks you need only change
your mind and all problems are erased.

A noble quest but I don't think it will have much success. Good luck
though!

O'
 




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