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Titius-Bode Rule becomes a law of physics from Maxwell EquationsChapt16.15 Gravity Cells #1456 ATOM TOTALITY 5th ed
It gives me pleasure to turn the Titius Bode Rule into a science
physics law of Nature. It gives me pleasure because it is basically the Solid Body Rotation of the Sun's gravity-cell. Maybe I should find a better name for gravity-cell for its importance is to nullify the 220km/sec of the Sun's linear speed in space while Earth has only 29km/sec. So is there a term in the Maxwell Equations for a rotation that compensates for electricity current versus magnetism? Is it a displacement current in the Ampere/Maxwell law? So that a gravity-cell is actually just the displacement current in Ampere/Maxwell law or is it the magnetic current density in the Faraday law when magnetic monopoles are included? At the moment, I do not know. But let me start talking about the Titius Bode Rule and why it exists because gravity is EM-gravity out of the Maxwell Equations. --- quoting Wikipedia on the Titius-Bode Rule --- Here are the distances of planets in the Solar System, calculated from the rule and compared with the real ones: Graphical plot using data from table to the left Planet k T-B rule distance (AU) Real distance (AU) % error (using real distance as the accepted value) Mercury 0 0.4 0.39 2.56% Venus 1 0.7 0.72 2.78% Earth 2 1.0 1.00 0.00% Mars 4 1.6 1.52 5.26% Ceres1 8 2.8 2.77 1.08% Jupiter 16 5.2 5.20 0.00% Saturn 32 10.0 9.54 4.82% Uranus 64 19.6 19.2 2.08% Neptune 128 38.8 30.06 29.08% Pluto1 256 77.22 39.44 95.75% 1 Ceres was considered a planet from 1801 until the 1860s. Pluto was considered a planet from 1930 to 2006. Both are now classified as dwarf planets. 2 While the difference between the T-B rule distance and real distance seems very large here, if Neptune is 'skipped,' the T-B rule's distance of 38.8 is quite close to Pluto's real distance with an error of only 1.62%. [edit] Theoretical explanations There is no solid theoretical explanation of the Titius–Bode law, but if there is one it is possibly a combination of orbital resonance and shortage of degrees of freedom: any stable planetary system has a high probability of satisfying a Titius–Bode-type relationship. --- end quoting Wikipedia on Titius-Bode Rule --- Now basically the Titius-Bode Rule is a doubling. Now look at these speeds of planets in which I included Ceres and Pluto: Sun 
____ Speed in Space 220 km/sec 
Equatorial Rotation velocity 7,000 km/hour Mercury 
____ Orbital speed Â*47 km/sec 
Equatorial Rotation velocity 10 km/hour Venus 
____ Orbital speed 35 km/sec 
Equatorial Rotation velocity 6 km/hour Earth 
____ Orbital speed Â*29 km/sec 
Equatorial Rotation velocity 1,674 km/hour Mars 
____ Orbital speed Â*24 km/sec 
Equatorial Rotation velocity 868 km/hour Ceres ____ Orbital speed 17km/sec Jupiter 
____ Orbital speed Â*13 km/sec 
Equatorial Rotation velocity 45,300 km/hour Saturn 
____ Orbital speed Â*9 km/sec 
Equatorial Rotation velocity 35,500 km/hour Uranus 
____ Orbital speed Â*6 km/sec 
Equatorial Rotation velocity 9,320 km/hour Neptune 

____ Orbital speed Â*5 km/sec 
Equatorial Rotation velocity 9,660 km/hour Pluto ____ Orbital speed 4 km/sec So how is the Titius-Bode Rule become a law of physics? Well, when gravity is EM-gravity, then the Space gravity around the Sun is a extended sphere out to the Oort Cloud and this sphere rotates slowly around that axis. The rotation of that axis nullifies the huge speed of the Sun of its 220km/sec and allows for small speeds like the Earth at 29km/sec or Jupiter at 13km/sec allows them to remain bounded- bonded into the Solar System. If not for the gravity cell rotating in solid body rotation, then in 10 years time the planets of the Sun would migrate out to the Kuiper belt and the Solar System would disintegrate day by day. Now the reason there is a tiny mismatch for Neptune and Pluto in the Titius Bode Rule is because in the rule we have to compensate for the gravity cell set up by Jupiter and Saturn which has a influence on the uniformity of the Sun's gravity cell and we see this in the fact of Uranus having a 97degree axial tilt and that the asteroid belt is rubble instead of a solid planet due to the Jupiter-Saturn nexus. The Solar System, our Solar System is completely governed by electricity and magnetism and gravity is a EM-gravity. -- Google seems to have stopped doing author-archives as of 2012. Only Drexel's Math Forum has done a excellent, simple and fair author- archiving of AP posts to sci.math for the past several years as seen he http://mathforum.org/kb/profile.jspa?userID=499986 Archimedes Plutonium http://www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies |
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Sun's 220km/sec in the plane of ecliptic?? Chapt16.15 Gravity Cells#1457 ATOM TOTALITY 5th ed
On Apr 3, 3:47Â*pm, Archimedes Plutonium
wrote: It gives me pleasure to turn the Titius Bode Rule into a science physics law of Nature. It gives me pleasure because it is basically the Solid Body Rotation of the Sun's gravity-cell. Maybe I should find a better name for gravity-cell for its importance is to nullify the 220km/sec of the Sun's linear speed in space while Earth has only 29km/sec. So is there a term in the Maxwell Equations for a rotation that compensates for electricity current versus magnetism? Is it a displacement current in the Ampere/Maxwell law? So that a gravity-cell is actually just the displacement current in Ampere/Maxwell law or is it the magnetic current density in the Faraday law when magnetic monopoles are included? At the moment, I do not know. But let me start talking about the Titius Bode Rule and why it exists because gravity is EM-gravity out of the Maxwell Equations. --- quoting Wikipedia on the Titius-Bode Rule --- Here are the distances of planets in the Solar System, calculated from the rule and compared with the real ones: Graphical plot using data from table to the left Planet k T-B rule distance (AU) Real distance (AU) % error (using real distance as the accepted value) Mercury 0 0.4 0.39 2.56% Venus 1 0.7 0.72 2.78% Earth 2 1.0 1.00 0.00% Mars 4 1.6 1.52 5.26% Ceres1 8 2.8 2.77 1.08% Jupiter 16 5.2 5.20 0.00% Saturn 32 10.0 9.54 4.82% Uranus 64 19.6 19.2 2.08% Neptune 128 38.8 30.06 29.08% Pluto1 256 77.22 39.44 95.75% 1 Ceres was considered a planet from 1801 until the 1860s. Pluto was considered a planet from 1930 to 2006. Both are now classified as dwarf planets. 2 While the difference between the T-B rule distance and real distance seems very large here, if Neptune is 'skipped,' the T-B rule's distance of 38.8 is quite close to Pluto's real distance with an error of only 1.62%. [edit] Theoretical explanations There is no solid theoretical explanation of the Titius–Bode law, but if there is one it is possibly a combination of orbital resonance and shortage of degrees of freedom: any stable planetary system has a high probability of satisfying a Titius–Bode-type relationship. --- end quoting Wikipedia on Titius-Bode Rule --- Now basically the Titius-Bode Rule is a doubling. Now look at these speeds of planets in which I included Ceres and Pluto: Sun 
____ Speed in Space 220 km/sec 
Equatorial Rotation velocity 7,000 km/hour Mercury 
____ Orbital speed Â*47 km/sec 
Equatorial Rotation velocity 10 km/hour Venus 
____ Orbital speed 35 km/sec 
Equatorial Rotation velocity 6 km/hour Earth 
____ Orbital speed Â*29 km/sec 
Equatorial Rotation velocity 1,674 km/hour Mars 
____ Orbital speed Â*24 km/sec 
Equatorial Rotation velocity 868 km/hour Ceres ____ Orbital speed 17km/sec Jupiter 
____ Orbital speed Â*13 km/sec 
Equatorial Rotation velocity 45,300 km/hour Saturn 
____ Orbital speed Â*9 km/sec 
Equatorial Rotation velocity 35,500 km/hour Uranus 
____ Orbital speed Â*6 km/sec 
Equatorial Rotation velocity 9,320 km/hour Neptune 

____ Orbital speed Â*5 km/sec 
Equatorial Rotation velocity 9,660 km/hour Pluto ____ Orbital speed 4 km/sec So how is the Titius-Bode Rule become a law of physics? Well, when gravity is EM-gravity, then the Space gravity around the Sun is a extended sphere out to the Oort Cloud and this sphere rotates slowly around that axis. The rotation of that axis nullifies the huge speed of the Sun of its 220km/sec and allows for small speeds like the Earth at 29km/sec or Jupiter at 13km/sec allows them to remain bounded- bonded into the Solar System. If not for the gravity cell rotating in solid body rotation, then in 10 years time the planets of the Sun would migrate out to the Kuiper belt and the Solar System would disintegrate day by day. Now the reason there is a tiny mismatch for Neptune and Pluto in the Titius Bode Rule is because in the rule we have to compensate for the gravity cell set up by Jupiter and Saturn which has a influence on the uniformity of the Sun's gravity cell and we see this in the fact of Uranus having a 97degree axial tilt and that the asteroid belt is rubble instead of a solid planet due to the Jupiter-Saturn nexus. The Solar System, our Solar System is completely governed by electricity and magnetism and gravity is a EM-gravity. Now I am having a hard time of locating a vital piece of information. I need to know the direction of Sun's motion, its 220 km/sec relative to the plane of the ecliptic. I would hazard to guess that the motion is parallel to the plane of ecliptic, in other words the linear forward motion of the Sun is the plane ecliptic itself as if the plane had a arrow of direction. I intuitively find it hard to think that the motion of the Sun is anywhere off the plane of the ecliptic. I had a look in Kaufmann's text Universe on page 461 and he talks about the Sun relative to stars nearby and the Perseus arm, Orion bridge and Sagittarius arm. I looked in Wikipedia for some light shed on the question with no luck. So the question is quite simple, as to what is the direction of motion of the Sun of its 220km/sec relative to the Plane of the Ecliptic? Is the direction in the plane or is it some angle off that plane? -- Google seems to have stopped doing author-archives as of 2012. Only Drexel's Math Forum has done a excellent, simple and fair author- archiving of AP posts to sci.math for the past several years as seen he http://mathforum.org/kb/profile.jspa?userID=499986 Archimedes Plutoniumhttp://www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies |
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0 degrees Sun's 220km/sec in the plane of ecliptic?? Chapt16.15Gravity Cells #1458 ATOM TOTALITY 5th ed
On Apr 3, 6:24*pm, Archimedes Plutonium
wrote: On Apr 3, 3:47*pm, Archimedes Plutonium (snipped) Now I am having a hard time of locating a vital piece of information. I need to know the direction of Sun's motion, its 220 km/sec relative to the plane of the ecliptic. I would hazard to guess that the motion is parallel to the plane of ecliptic, in other words the linear forward motion of the Sun is the plane ecliptic itself as if the plane had a arrow of direction. I intuitively find it hard to think that the motion of the Sun is anywhere off the plane of the ecliptic. I had a look in Kaufmann's text Universe on page 461 and he talks about the Sun relative to stars nearby and the Perseus arm, Orion bridge and Sagittarius arm. I looked in Wikipedia for some light shed on the question with no luck. So the question is quite simple, as to what is the direction of motion of the Sun of its 220km/sec relative to the Plane of the Ecliptic? Is the direction in the plane or is it some angle off that plane? Let me phrase my question more clearly. Let me define the Sun's ecliptic as the plane in which the Sun's equator radiates outward, so that the Sun's equator plane forms the Solar System ecliptic. Now it happens from Maxwell Equations in EM gravity that all the planets lie mostly or near that ecliptic. When electricity and magnetism forms gravity, then the bodies would lie near or on that ecliptic. Now the question of direction of the Sun's 220 km/sec is a vector direction of an angle from the center of the Sun. Is the Sun moving its 220km/sec of a vector that is in that equator and thus ecliptic? Or is that 220km/sec some angle off of that equator-ecliptic plane? For instance is the 220km/sec in a direction of the poles of the Sun and thus the motion is 90degrees from the ecliptic? If the direction is 0degrees then the 220km/sec is in the ecliptic. Now if the Sun is 0degrees of its 220km/sec, then the question is, at what day of the Earth year is the Sun moving to? In other words, as the Earth revolves around the Sun, there is one day of that revolution in which the Sun is moving in Space in that direction. -- Google seems to have stopped doing author-archives as of 2012. Only Drexel's Math Forum has done a excellent, simple and fair author- archiving of AP posts to sci.math for the past several years as seen he http://mathforum.org/kb/profile.jspa?userID=499986 Archimedes Plutonium http://www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies |
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0 degrees Sun's 220km/sec in the plane of ecliptic?? Chapt16.15Gravity Cells #1458 ATOM TOTALITY 5th ed
On 04/03/2013 07:58 PM, Archimedes Plutonium wrote:
On Apr 3, 6:24 pm, Archimedes Plutonium wrote: On Apr 3, 3:47 pm, Archimedes Plutonium (snipped) Now I am having a hard time of locating a vital piece of information. I need to know the direction of Sun's motion, its 220 km/sec relative to the plane of the ecliptic. I would hazard to guess that the motion is parallel to the plane of ecliptic, in other words the linear forward motion of the Sun is the plane ecliptic itself as if the plane had a arrow of direction. I intuitively find it hard to think that the motion of the Sun is anywhere off the plane of the ecliptic. I suspect that the 3-D rectangular origin (0, 0, 0) in rectangular coordinates is or is near the centre of mass (barycentre) of the solar system. The ecliptic is a reference plane that approximates very well the mean orbit of the earth around the sun. I had a look in Kaufmann's text Universe on page 461 and he talks about the Sun relative to stars nearby and the Perseus arm, Orion bridge and Sagittarius arm. I looked in Wikipedia for some light shed on the question with no luck. So the question is quite simple, as to what is the direction of motion of the Sun of its 220km/sec relative to the Plane of the Ecliptic? Is the direction in the plane or is it some angle off that plane? I sincerely doubt that people in solar dynamics would use an ecliptic reference plane where the sun would move at 220 km/sec . In the old days, the proper motions of extra-solar stars relative to the earth were not known. Wikipedia quote: The Sun travels in a nearly circular orbit (the solar circle) about the center of the Milky Way at a speed of about 220 km/s at a radius of 8 ± 0.65 kpc from the center,[4][5] which can be taken as the rate of rotation of the Milky Way itself at this radius.[6][7] cf.: http://en.wikipedia.org/wiki/Proper_motion dave Let me phrase my question more clearly. Let me define the Sun's ecliptic as the plane in which the Sun's equator radiates outward, so that the Sun's equator plane forms the Solar System ecliptic. Now it happens from Maxwell Equations in EM gravity that all the planets lie mostly or near that ecliptic. When electricity and magnetism forms gravity, then the bodies would lie near or on that ecliptic. Now the question of direction of the Sun's 220 km/sec is a vector direction of an angle from the center of the Sun. Is the Sun moving its 220km/sec of a vector that is in that equator and thus ecliptic? Or is that 220km/sec some angle off of that equator-ecliptic plane? For instance is the 220km/sec in a direction of the poles of the Sun and thus the motion is 90degrees from the ecliptic? If the direction is 0degrees then the 220km/sec is in the ecliptic. Now if the Sun is 0degrees of its 220km/sec, then the question is, at what day of the Earth year is the Sun moving to? In other words, as the Earth revolves around the Sun, there is one day of that revolution in which the Sun is moving in Space in that direction. -- Google seems to have stopped doing author-archives as of 2012. Only Drexel's Math Forum has done a excellent, simple and fair author- archiving of AP posts to sci.math for the past several years as seen he http://mathforum.org/kb/profile.jspa?userID=499986 Archimedes Plutonium http://www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies -- Jesus is an Anarchist. -- J.R. |
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what day of year 2012 did Sun's 220km/sec cross the Earth's revolvingorbit Chapt16.15 Gravity Cells #1459 ATOM TOTALITY 5th ed
On Apr 3, 7:43*pm, David Bernier wrote:
On 04/03/2013 07:58 PM, Archimedes Plutonium wrote: On Apr 3, 6:24 pm, Archimedes Plutonium wrote: On Apr 3, 3:47 pm, Archimedes Plutonium (snipped) Now I am having a hard time of locating a vital piece of information. I need to know the direction of Sun's motion, its 220 km/sec relative to the plane of the ecliptic. I would hazard to guess that the motion is parallel to the plane of ecliptic, in other words the linear forward motion of the Sun is the plane ecliptic itself as if the plane had a arrow of direction. I intuitively find it hard to think that the motion of the Sun is anywhere off the plane of the ecliptic. I suspect that the 3-D rectangular origin (0, 0, 0) in rectangular coordinates is or is near the centre of mass (barycentre) of the solar system. The ecliptic is a reference plane that approximates very well the mean orbit of the earth around the sun. I had a look in Kaufmann's text Universe on page 461 and he talks about the Sun relative to stars nearby and the Perseus arm, Orion bridge and Sagittarius arm. I looked in Wikipedia for some light shed on the question with no luck. So the question is quite simple, as to what is the direction of motion of the Sun of its 220km/sec relative to the Plane of the Ecliptic? Is the direction in the plane or is it some angle off that plane? I sincerely doubt that people in solar dynamics would use an ecliptic reference plane where the sun would move at 220 km/sec . In the old days, the proper motions of extra-solar stars relative to the earth were not known. Wikipedia quote: The Sun travels in a nearly circular orbit (the solar circle) about the center of the Milky Way at a speed of about 220 km/s at a radius of 8 ± 0.65 kpc from the center,[4][5] which can be taken as the rate of rotation of the Milky Way itself at this radius.[6][7] cf.:http://en.wikipedia.org/wiki/Proper_motion dave Let me phrase my question more clearly. Let me define the Sun's ecliptic as the plane in which the Sun's equator radiates outward, so that the Sun's equator plane forms the Solar System ecliptic. Now it happens from Maxwell Equations in EM gravity that all the planets lie mostly or near that ecliptic. When electricity and magnetism forms gravity, then the bodies would lie near or on that ecliptic. Now the question of direction of the Sun's 220 km/sec is a vector direction of an angle from the center of the Sun. Is the Sun moving its 220km/sec of a vector that is in that equator and thus ecliptic? Or is that 220km/sec some angle off of that equator-ecliptic plane? For instance is the 220km/sec in a direction of the poles of the Sun and thus the motion is 90degrees from the ecliptic? If the direction is 0degrees then the 220km/sec is in the ecliptic. Now if the Sun is 0degrees of its 220km/sec, then the question is, at what day of the Earth year is the Sun moving to? In other words, as the Earth revolves around the Sun, there is one day of that revolution in which the Sun is moving in Space in that direction. -- Google seems to have stopped doing author-archives as of 2012. Only Drexel's Math Forum has done a excellent, simple and fair author- archiving of AP posts to sci.math for the past several years as seen he http://mathforum.org/kb/profile.jspa?userID=499986 Archimedes Plutonium http://www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies -- Jesus is an Anarchist. *-- J.R. Hi David, let me see if I can make my question more clear. Suppose I am holding the Sun (a big ball) and you nearby at a distance of say 10meters is holding a ball called Earth. Now you are revolving (walking very slowly around me) and a complete revolution is 365 days. Now the Plane of Ecliptic is defined as the poles of the Sun forming an equator and this equator extended outwards from the Sun is the plane of ecliptic. Now it happens to be the case that most of the planets lie in this plane of ecliptic. Now I am standing still while you walk around me holding the Sun. But what if I start to move, the Sun moving, and it does not have to be fast motion compared to Earth's 29km/sec. I do not have to move a 220km/sec which would be brisk and fast compared to 29km/sec. Let us say I am moving slowly, about a fraction of the pace that David holding Earth is moving around the Sun. So, the question, is David, at what day of the year, say last year of 2012, of what day of the year did the Sun cross the point in the Earth's revolution since the Sun is moving in Space at 220km/sec. Did this crossing of the Earth's revolution happen on a winter day? or a Spring or Summer or Autumn day? You see, David, the flaw of Newtonian gravity and General Relativity is that they are theories based on a premiss that the Sun has 0 speed in Space. If the Sun has no speed in Space, then planets of slow speeds like Jupiter of 13km/sec can go around the Sun and be a stable system for billions of years. But if the Sun moves at 220km/sec in Space, then a Jupiter going around the Sun at 13km/sec can only be stable and going on for billions of years if a gravity-cell exists for the Sun where a axis extends out to the Oort Cloud and this cell rotates on that axis, and provides a Solid-Body-Rotation of all the objects in the Solar System. So that regardless of Sun moving at 2km/ sec or 220km/sec or 500km/sec, that the planets will tag along and the solar system remain stable because the entire solar system is rotating around a gravity cell axis. My question, David, was, what day of year 2012 did the Sun moving at 220km/sec cross the path of where Earth was going to revolve in its 365 days? Was it a winter or spring or summer or autumn day of 2012 where the Sun passed the spot in the revolution of Earth in its plane of ecliptic orbit. In other words, our entire solar system is a solid body rotation produced by Maxwell Equations. I realize all of this is new to physics and astronomy, because no-one has ever asked this question before-- what day of the year 2012 did the Sun traverse the spot of the Earth's orbit. -- Google seems to have stopped doing author-archives as of 2012. Only Drexel's Math Forum has done a excellent, simple and fair author- archiving of AP posts to sci.math for the past several years as seen he http://mathforum.org/kb/profile.jspa?userID=499986 Archimedes Plutonium http://www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies |
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what day of year 2012 did Sun's 220km/sec cross the Earth's revolvingorbit Chapt16.15 Gravity Cells #1459 ATOM TOTALITY 5th ed
On 04/03/2013 10:20 PM, Archimedes Plutonium wrote:
On Apr 3, 7:43 pm, David Bernier wrote: On 04/03/2013 07:58 PM, Archimedes Plutonium wrote: On Apr 3, 6:24 pm, Archimedes Plutonium wrote: On Apr 3, 3:47 pm, Archimedes Plutonium (snipped) Now I am having a hard time of locating a vital piece of information. I need to know the direction of Sun's motion, its 220 km/sec relative to the plane of the ecliptic. I would hazard to guess that the motion is parallel to the plane of ecliptic, in other words the linear forward motion of the Sun is the plane ecliptic itself as if the plane had a arrow of direction. I intuitively find it hard to think that the motion of the Sun is anywhere off the plane of the ecliptic. I suspect that the 3-D rectangular origin (0, 0, 0) in rectangular coordinates is or is near the centre of mass (barycentre) of the solar system. The ecliptic is a reference plane that approximates very well the mean orbit of the earth around the sun. I had a look in Kaufmann's text Universe on page 461 and he talks about the Sun relative to stars nearby and the Perseus arm, Orion bridge and Sagittarius arm. I looked in Wikipedia for some light shed on the question with no luck. So the question is quite simple, as to what is the direction of motion of the Sun of its 220km/sec relative to the Plane of the Ecliptic? Is the direction in the plane or is it some angle off that plane? I sincerely doubt that people in solar dynamics would use an ecliptic reference plane where the sun would move at 220 km/sec . In the old days, the proper motions of extra-solar stars relative to the earth were not known. Wikipedia quote: The Sun travels in a nearly circular orbit (the solar circle) about the center of the Milky Way at a speed of about 220 km/s at a radius of 8 ± 0.65 kpc from the center,[4][5] which can be taken as the rate of rotation of the Milky Way itself at this radius.[6][7] cf.:http://en.wikipedia.org/wiki/Proper_motion dave Let me phrase my question more clearly. Let me define the Sun's ecliptic as the plane in which the Sun's equator radiates outward, so that the Sun's equator plane forms the Solar System ecliptic. Now it happens from Maxwell Equations in EM gravity that all the planets lie mostly or near that ecliptic. When electricity and magnetism forms gravity, then the bodies would lie near or on that ecliptic. Now the question of direction of the Sun's 220 km/sec is a vector direction of an angle from the center of the Sun. Is the Sun moving its 220km/sec of a vector that is in that equator and thus ecliptic? Or is that 220km/sec some angle off of that equator-ecliptic plane? For instance is the 220km/sec in a direction of the poles of the Sun and thus the motion is 90degrees from the ecliptic? If the direction is 0degrees then the 220km/sec is in the ecliptic. Now if the Sun is 0degrees of its 220km/sec, then the question is, at what day of the Earth year is the Sun moving to? In other words, as the Earth revolves around the Sun, there is one day of that revolution in which the Sun is moving in Space in that direction. -- Google seems to have stopped doing author-archives as of 2012. Only Drexel's Math Forum has done a excellent, simple and fair author- archiving of AP posts to sci.math for the past several years as seen he http://mathforum.org/kb/profile.jspa?userID=499986 Archimedes Plutonium http://www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies -- Jesus is an Anarchist. -- J.R. Hi David, let me see if I can make my question more clear. Suppose I am holding the Sun (a big ball) and you nearby at a distance of say 10meters is holding a ball called Earth. Now you are revolving (walking very slowly around me) and a complete revolution is 365 days. Now the Plane of Ecliptic is defined as the poles of the Sun forming an equator and this equator extended outwards from the Sun is the plane of ecliptic. Now it happens to be the case that most of the planets lie in this plane of ecliptic. Now I am standing still while you walk around me holding the Sun. But what if I start to move, the Sun moving, and it does not have to be fast motion compared to Earth's 29km/sec. I do not have to move a 220km/sec which would be brisk and fast compared to 29km/sec. Let us say I am moving slowly, about a fraction of the pace that David holding Earth is moving around the Sun. So, the question, is David, at what day of the year, say last year of 2012, of what day of the year did the Sun cross the point in the Earth's revolution since the Sun is moving in Space at 220km/sec. Did this crossing of the Earth's revolution happen on a winter day? or a Spring or Summer or Autumn day? You see, David, the flaw of Newtonian gravity and General Relativity is that they are theories based on a premiss that the Sun has 0 speed in Space. If the Sun has no speed in Space, then planets of slow speeds like Jupiter of 13km/sec can go around the Sun and be a stable system for billions of years. But if the Sun moves at 220km/sec in Space, then a Jupiter going around the Sun at 13km/sec can only be stable and going on for billions of years if a gravity-cell exists for the Sun where a axis extends out to the Oort Cloud and this cell rotates on that axis, and provides a Solid-Body-Rotation of all the objects in the Solar System. So that regardless of Sun moving at 2km/ sec or 220km/sec or 500km/sec, that the planets will tag along and the solar system remain stable because the entire solar system is rotating around a gravity cell axis. I suggest to get an intuition about the gravitational perturbation of the Oort Cloud and other light-years away masses on the main solar system bodies, to have a look at Newton's elementary study of moon tidal forces on the earth. Gravity is an inverse square law. So, at the point on earth Now closest to the Moon, the Moon pulls a bit more on a standard kilogram etalon (Paris, France) than it would to on an "identical twin" standard kilogram etalon (Paris, France) located at the other end of the earth: antipodal to the point nearest to our Moon Now ... That, in essence, is the nature of tidal forces. Through mathematical tricks, we can substract the force on a standard kilogram etalon (Paris, France) imaginationationanally located Now at the earth's very centre (of Gravity) ... Newton and his geometric diagrams on moon tidal forces on the earth's surface: http://en.wikipedia.org/wiki/Lunar_t...f_lunar_motion That section explains the perturbation of a faraway big massive body on nearby things that are far enough away that the differential gravity field from one place to the second can cause so-called tidal forces, etc. dave My question, David, was, what day of year 2012 did the Sun moving at 220km/sec cross the path of where Earth was going to revolve in its 365 days? Was it a winter or spring or summer or autumn day of 2012 where the Sun passed the spot in the revolution of Earth in its plane of ecliptic orbit. I don't understand, sorry. In other words, our entire solar system is a solid body rotation produced by Maxwell Equations. I realize all of this is new to physics and astronomy, because no-one has ever asked this question before-- what day of the year 2012 did the Sun traverse the spot of the Earth's orbit. [...] -- Jesus is an Anarchist. -- J.R. |
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it is called Solar Apex Chapt16.15 Gravity Cells #1460 ATOM TOTALITY5th ed
That was painful, but finally found the information. It is called
Solar Apex. Here is what Wikipedia says about it: The solar apex (Apex of the Sun's Way) is the direction that the Sun travels with respect to the Local Standard of Rest. In lay terms, it's the "target" within the Milky Way that the Sun appears to be "chasing" as it orbits the galaxy. It should not be confused with the Sun's "motion" through the Zodiac, which is not a real 3D motion, but a 2D parallax effect due to change in our vantage point (the Earth's revolving around the Sun). The general direction of the solar apex is southwest of the star Vega near the constellation of Hercules. --- end quoting Wikipedia --- I do not know what day of the year of 2012 that the Sun traversed the orbit of Earth to so to speak "go to Vega the solar-apex". Anybody know? And whether that crossing of the path of what was Earth's projected revolution is the same from year to next or varies every year? Now the reason the Solar Apex is so very important is that the Sun creates a plane of ecliptic and then because the Sun is not 0 speed but 220km/sec speed in Space, that the Sun crosses its plane of ecliptic that it formed in time past and now has reformed in time present. So that Newtonian gravity and General Relativity are false theories, because the planets cannot keep up with a Sun moving at 220km/sec while Earth is moving at 29km/sec. What is the solution? Gravity is from the Maxwell Equations and that the Sun has a gravity cell that extends out to the Oort Cloud and rotates on that cell axis. The rotation is solid-body-rotation and thus Earth at 29km/sec and Sun at 220km/sec, the rotation makes null the 220km/sec. There is no denying the Sun moves in Space at 220km/sec. There is no denying the Earth moves in Space at 29km/sec. There is no denying that Newtonian gravity and General Relativity cannot keep the Earth bound and bonded to the Sun when one has 220 and the other has 29 speeds. So what must be done? We throw out Newtonian gravity and General Relativity and realize that the Sun has magnetic monopoles of Space that has a axis out to the Oort Cloud and this Sun gravity cell is in rotation. This rotation keeps the planets bound and bonded to the Sun. -- Google seems to have stopped doing author-archives as of 2012. Only Drexel's Math Forum has done a excellent, simple and fair author- archiving of AP posts to sci.math for the past several years as seen he http://mathforum.org/kb/profile.jspa?userID=499986 Archimedes Plutonium http://www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies |
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comparing the Jupiter Apex Chapt16.15 Gravity Cells #1461 ATOMTOTALITY 5th ed
Let me talk briefly on the Jupiter Apex compared to Solar Apex. The
Solar Apex is in the direction of Vega and it has Earth and Jupiter in revolution around the Sun. Trouble is with these facts that Sun is moving at 220km/sec and Earth at 29km/sec and Jupiter at 13km/sec that within 10 years the Solar System would of disintegrated apart and no longer a bounded bonded system of planets moving around the Sun, for the Sun would have speeded away from its planets. That means Newtonian gravity and General Relativity are fake theories. What saves the Solar System is gravity from the Maxwell Equations, call it EM-gravity. Every mass has a number of magnetic monopoles, and they all attract, never repulsion of north and south magnetic monopoles. The Sun has the greatest amount of mass in the Solar System and thus the greatest number of magnetic monopoles. These monopoles compose Space itself and form Faraday lines of force. The Sun's magnetic monopoles forms the Space out to and including the Oort Cloud and call it the Sun's gravity cell. So that in EM-gravity the Sun pulls Earth and Jupiter towards the Sun, but also, the Sun's gravity cell rotates or spins. So the EM gravity that the Sun applies to Earth and Jupiter is the direct pull of the Sun on Earth and Jupiter, but that is not the full force of EM-gravity because we have to include the spin of the Sun's gravity cell upon the orbit of Earth and Jupiter. The spin of the Sun's gravity-cell makes null the 220km/sec motion because the gravity cell is centered at the center of the Sun and so the Sun receives none of the spin-potential, but the planets each receive spin-potential of that axis rotation of the gravity cell. It is that axis of rotation which is solid body rotation, that allows for Earth to have a 29km/sec and Jupiter 13km/sec and still remain revolving around the Sun, even though the Sun is moving at 220km/sec. Now why would Newton or Maxwell believe in Newtonian gravity when the Sun is moving at such a high speed compared to its planets? Well the answer is quite simple, in that only by the 20th century were we able to accurately measure the speeds of the Sun and planets. So for Newton and Maxwell, they would accept Newtonian gravity for they assumed the speed of the Sun was near 0 speed. However, let us run the same data on the satellites of Jupiter: Jupiter has orbital speed of 13.0 km/sec Io has orbital speed of 17km/sec Europa has orbital speed of 13.7 km/sec and faster than Jupiter's 13km/ sec Ganymede has orbital speed of 10 km/sec Callisto has orbital speed of 8 km/sec So here again we have the situation of a central gravitational object is moving faster in Space than several of its bounded-bonded objects. We know the Jupiter Apex is in the direction of the Sun and moving at 13.0km/sec and while moving it is keeping in tow four satellites, three of which have a slower speed than what Jupiter has. Solution: Jupiter has a EM-gravity cell which extends far in Space around Jupiter of magnetic monopoles and this cell is spherical in shape and has an axis as the extension of Jupiter's own axis and this cell axis rotates or spins in solid-body-rotation around that axis. That spin saves those satellites of Jupiter from meandering away from Jupiter for the spin makes the Jupiter motion of 13.0km/sec null but it keeps the motion of the satellites and augments their bounded and bondedness to Jupiter. Now Newton and Maxwell knew that Jupiter had satellites but neither of them knew what speeds they had. So we cannot blame either Newton or Maxwell for keeping Newtonian gravity, for they simply did not have the speed data that was gained in the 20th century. However, we can blame the physicists and astronomers of the 20th century for sleeping on the job of science. Because when we fully learned that the Sun was racing ahead of its planets by a speed of 220km/sec and the Earth a mere paltry 29km/sec, that the 20th century scientists should have rung the alarm bells and thrown out Newtonian gravity and General Relativity and found refuge in the Maxwell Equations that EM-gravity was the work-box of the Cosmos. P.S. I saw an interesting NOVA show tonight called Ancient Computer, the story of the Ancient Computer of the Antikythera Mechanism. I was trying to think of a link up with that computer box of Moon eclipses by Ancient Greeks and what I am facing today of Solar Apex and Jupiter Apex. I guess I could say that in way can you craft a box where a big wheel is moving faster than a little wheel yet the little wheel keeps up and maintains its revolutions. -- Google seems to have stopped doing author-archives as of 2012. Only Drexel's Math Forum has done a excellent, simple and fair author- archiving of AP posts to sci.math for the past several years as seen he http://mathforum.org/kb/profile.jspa?userID=499986 Archimedes Plutonium http://www.iw.net/~a_plutonium whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies |
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