principle of planetary rotation

(Jeff Root) wrote in message . com...
"peter" ) replied to Jeff Root:

I STUDIED BSC UP TO UNIVERSITY LEVEL I AM 26 YEAR OLD,WHO EVER WANT
TO CONTRIBUTE SHOULD HAVE A MATURE UNDER STANDING OF SCI ,AS I SAID
I DISCREDICT HALF OF PRESENT DAY SCI I HAVE 23 PAPER I HAVE WRITERN
WHICH I HAVE NOT PUBLISH YET,ABOUT THE PRINCIPLE I PROPOSED I HAVE
AN EXPERIMENT I HAVE CARRIED OUT,I TO CARRY OUT MORE TO CONFIRM MY
RESULT,IT ONLY CARRIED OUT THE EQUATOR AND ONLY IN MARCH AND JULY

Rest assured, Peter, that everyone who has replied to you in
this thread so far has a much better understanding of physics
and astronomy than you have. You needn't worry about that.

I'm interested to know what kind of experiment you carried out,
and what observations you made at the equator in March and July.

let me assured you that what you known is a small fraction of
what ever i known.You better of because i can express my self to
the read well,

Then I recommend that you start doing so. If it is worth your
time and effort to post here, then it is worth your time and
effort to make your posts readable.

i carried out an experiment on march 21 2003,the aim to comfirm
that photon are deflected toward the west by earth planetary
magnetic feild

The word "field" has the "i" before the "e".

it was a 14 hour experiment from sun rise to sun set.
i choose march because it is the month when the earth is not
tilted.

You meant, "the rotation axis of the Earth is not tilted toward
or away from the Sun." It is still tilted, of course.

by measuring the angle between the earth and light ray from the
sun at time interval of 1 hour.

So you didn't actually carry out an experiment, you just made
observations. That's fine, but you shouldn't have said that you
carried out an experiment when you didn't.

computing the angle i was able to determine that

Did you mean "computing the angle between the observed position
and the position expected by standard theory"? You just said
that you measured the angle, so it must be something else that
you computed.

real light is deflected toward the west and of all ray that
enter the planet there is an resultant angle at which they are
absorbed.

So the Sun appeared farther east than it actually was. How did
you determine the actual position of the Sun at the time of each
observation of the apparent position?

What correction did you apply for atmospheric refraction?

Where were you on the equator when you made these observations?

If you need the all calculation i was post it but i want to
carry out 8 time to confirm my result that is 4 years.

No problem. We can wait.

-- Jeff, in Minneapolis





I did carry out the experiment it was a simple experiment,it showed result

"peter" wrote in message
om...


I did carry out the experiment it was a simple experiment,it showed result

Bravo. Let's see them then.

"peter" ) replied to Jeff Root:

I did carry out the experiment it was a simple experiment,it
showed result

You said that the "experiment" consisted of:

measuring the angle between the earth and light ray from the
sun at time interval of 1 hour.

That is not an experiment. It is, however, a reasonable thing
to observe. If this description is correct, then you did not
carry out an experiment. You only made observations. Nothing
wrong with that.

Without giving away anything about your secret invention
concept, please tell us:

How you determined the actual position of the Sun at the time
of each observation of the apparent position.

What correction you applied for atmospheric refraction.

Where on the equator you made these observations.

-- Jeff, in Minneapolis

..

peter wrote:



I am working on an invention if i post this evedence legaly i will
lose my partern right,

What is a "partern?"

with this evidence some can develop it that is
why i am holding on this .I am trying out theoretical research if
imformation can be stored in an electrons in atoms .

Once again we need to translate from Loon to human.

Do you have any idea what you are talking about?

wrote in message . ..
(peter) wrote:
EXAPERIMENTAL SETUP

CHAPTER THREE
3.0 RESEARCH DESIGIN
This research was set up to investigate the present of resultant angle
and to determine its degrees to fine of if photon are charge and are
deflected by earth magnetic field .
3.1 STUDY AREA
This research was carried out on sun light rays .The condition under
investigation was to determine the if photon were charge and are
deflected by earth magnetic field and to also ivestigate presnt of
resultant angle of light on earth surface and determine its degrees
3.2 DATA COLLECTION
this was done both qualitatively and quantitatively by marking the
position of the shadow at time interval of one hour measurement taken
were computed to fine out the angle of incident using trigometric
function of angle.
3.3 INSTRUMENT AND REQUIREMENT USED
Campass direction,long straight pole,clock.open flat leveled
ground,sunny weather,
3.4 PROCEDURE

This experiment was carried out on march /20/2003 on a open 60 km from
the equator.
The ground was level covering a radius of 20 meters using leveler to
ensure that the ground was not tilted.
Using a compass the direction the north and south direction was
determined and a striaght north-south line was drawn.The west and east
direction was also determined and west-east line was drawn.AT the
point were this two line cross each other a 7 feet long striaght thin
pole was fixed vertically at right angle to the ground.
The experiment setted at 3 GMT at sun rise the position of shadow of
the pole was marked at regular time interval of one hour through the
day up to sun set at 16 GMT.
A striaght line was drawn from each of the position marked through to
the center were the pole was fixed.Lenght of each of the drawn line
was taken and recorded .
The angle of light rays to be computed were divided into two.angle of
ray from sun rise to 90 degree and angle from 90 degree to angle of
rays at sun set.lenght was taken for
The lenghts recorded was used in the trigonometrical determination of
angle of the rays.
Rays from sun rise to ray with 90 degrees were computed from
trigonometric function of angle of eastern line lenght aganist the
lenght of line drawn from the shadow to the center were the pole was
fixed and rays from 90 degree to sun set were computed from
trigonometric function of angle of western line lenght aganist the
lenght of line drawn from the shadow to the center were the pole was
fixed.

CHAPTER FOUR

4.0 DATE PRESENTATION AND ANALYSIS OF DATA
Angle of light ray from sun rise to 90 degree was computed as
E=antisin z/y
angle of light rays rom 90 to sun set was computed as
B=antisin c/a
The resultant angle was computed as shown below

Cos A = CosB-CosE

A=anticos(cosB-coE)

A is resutant angle
Cos E is average angle of rays less than 90 computed with relative to
the eastern line(from sun rise to 90)
Cos B is average angle of rays lees than 90 computed with relative to
the western line(from 90 degree to sun set)
z is the lenghts of lines drawn from shadow of the the pole of rays
from sun rise to 90 degree
c is the lenght of lines drawn from shadow of the pole of rays from 90
degrees to sun set
y is the lenght on the eastern line used in calculating angle E
a is the lenght on the western line used in calculating angle A

4.1 TREATMENT OF RESULTS

Table of result of angle E

TIME(GMT) Angle(Degrees)
3 0.00
4 10.00
5 26.00
6 35.00
7 40.00
8 60.00
9 78.00

average angle E=35.57142857 degrees

Table of result of angle B
TIME(GMT) Angle(Degrees)
10 89.0
11 70.0
12 55.60
13 41.20
14 25.90
15 14.00
16 0.00

average angle B=42.24285714 degrees

CALCULATION OF RESULTANT ANGLE (A)

Resultant angle is the angle which is used to calculate the attraction
force resolution into centripetal force.


Cos A= Cos E- Cos B
A=antiCos(Cos E-Cos B)
A=antiCos(Cos 35.57142857-Cos 42.24285714)

A=85.808857125 degrees

the resultant angle A= 85.80857125 degrees for electromagnetic
spectrum(Photon) of visible light on planet earth.

(peter) wrote:

wrote in message . ..
(peter) wrote:
EXAPERIMENTAL SETUP

Your experimental setup and methods are seriously flawed - see below.

CHAPTER THREE
3.0 RESEARCH DESIGIN
This research was set up to investigate the present of resultant angle
and to determine its degrees to fine of if photon are charge and are
deflected by earth magnetic field .
3.1 STUDY AREA
This research was carried out on sun light rays .The condition under
investigation was to determine the if photon were charge and are
deflected by earth magnetic field and to also ivestigate presnt of
resultant angle of light on earth surface and determine its degrees

This doesn't make any sense. Determine degrees of what? What do you
mean by "resultant angle"? And please start using a spell checker so
I at least have a vague idea what you're on about.

3.2 DATA COLLECTION
this was done both qualitatively and quantitatively by marking the

What do you mean by "qualitatively"? In this kind of experiment only
exact measurements can have any meaning, so any subjective impressions
cannot be used.

position of the shadow at time interval of one hour measurement taken
were computed to fine out the angle of incident using trigometric
function of angle.
3.3 INSTRUMENT AND REQUIREMENT USED
Campass direction,long straight pole,clock.open falt leveled
ground,sunny weather,
3.4 PROCEDURE

This experiment was carried out on march /20/2003 on a open 60 km from
the equator.

Did you compute the effect of not being exactly on the equator? How
much would this affect your results?

What was your exact lat/long, and just as importantly, what was your
elevation above sea level? What about your horizon? If there were
any obstructions such as buildings, hills, trees etc. you wouldn't be
able to accurately determine sunrise or sunset.

The ground was level covering a radius of 20 meters using leveler to
ensure that the ground was not tilted.

What's a "leveler"? Do you mean a device (like a spirit level) to
measure the slope, or some kind of device to create a flat area?

Using a compass the direction the north and south direction was
determined and a striaght north-south line was drawn.The west and east
direction was also determined and west-east line was drawn.AT the

Are you aware that magnetic North is _not_ the same as true North?
Did you take this into account when constructing your coordinate
system? This seems to me to be one of the most fundamental flaws in
your whole "experiment".

point were this two line cross each other a 7 feet long striaght thin
pole was fixed vertically at right angle to the ground.

How did you ensure it was vertical? What was it made of (to know if
it might bend)? How much of the pole was in the ground, and how much
remained projecting above? All of these could affect your results.

The experiment setted at 3 GMT at sun rise the position of shadow of
the pole was marked at regular time interval of one hour through the
day up to sun set at 16 GMT.

Well, a quick check puts you near the East coast of Africa, either in
Somalia or Kenya. However, on 20th March the Sun rose at 03:00 and
set at 15:00, so you've either made a fundamental error in your
observations or you have the date wrong....

Of course the Sun isn't a point source, so the rise and set times
could be slightly earlier and later than these by a few minutes.

I presume you also took into account this fact that the Sun isn't a
point source when designing your experiment and when analysing your
data?

A striaght line was drawn from each of the position marked through to
the center were the pole was fixed.Lenght of each of the drawn line
was taken and recorded .

How were these measured? And how accurately? Why were measurements
only taken at hourly intervals? How accurate was your "clock" come to
that?

If there is any deflection of photons by magnetic fields, the effect
would be so small that you'd have to be making measurements accurate
to microns - which I somehow doubt you were doing.

The angle of light rays to be computed were divided into two.angle of
ray from sun rise to 90 degree and angle from 90 degree to angle of
rays at sun set.lenght was taken for
The lenghts recorded was used in the trigonometrical determination of
angle of the rays.
Rays from sun rise to ray with 90 degrees were computed from
trigonometric function of angle of eastern line lenght aganist the
lenght of line drawn from the shadow to the center were the pole was
fixed and rays from 90 degree to sun set were computed from
trigonometric function of angle of western line lenght aganist the
lenght of line drawn from the shadow to the center were the pole was
fixed.

I've read this at least ten times and can't figure out what you mean.
The angle was computed from the lengths of two lines, one being the
shadow projected by the pole - what's the other length?

Is it some datum on the East-West axis? If so, how did you measure
it, and how accurately?

CHAPTER FOUR

4.0 DATE PRESENTATION AND ANALYSIS OF DATA
Angle of light ray from sun rise to 90 degree was computed as
E=antisin z/y

What are z and y? If I was trying to calculate the angle of the Sun
I'd do it as arctan (pole_height / shadow_length). To use arcsin
you'd need the hypotenuse length, which you haven't defined or
calculated.

angle of light rays rom 90 to sun set was computed as
B=antisin c/a
The resultant angle was computed as shown below

Cos A = CosB-CosE

A=anticos(cosB-coE)

A is resutant angle

What does this mean? I've read it again about ten times, but can't
figure out what you're trying to calculate.

Where do these equations come from? (That might best be treated as a
rhetorical question, since I think I know the answer

Cos E is average angle of rays less than 90 computed with relative to
the eastern line(from sun rise to 90)
Cos B is average angle of rays lees than 90 computed with relative to
the western line(from 90 degree to sun set)
z is the lenghts of lines drawn from shadow of the the pole of rays
from sun rise to 90 degree
c is the lenght of lines drawn from shadow of the pole of rays from 90
degrees to sun set
y is the lenght on the eastern line used in calculating angle E
a is the lenght on the western line used in calculating angle A

Ah, so z is the shadow length and y is some datum length along the E-W
axis. I still don't see what arcsin(z/y) gives you.

You need to define your terminology and symbols _before_ you use them.
If this is the standard of the 25 papers you claim to have written,
it's no surprise they remain unpublished )

4.1 TREATMENT OF RESULTS

Table of result of angle E

TIME(GMT) Angle(Degrees)
3 0.00
4 10.00
5 26.00
6 35.00
7 40.00
8 60.00
9 78.00

average angle E=35.57142857 degrees

These figures are only given to integer degrees! You're supposed to
be measuring a tiny effect and you're only bothering to measure to one
degree accuracy?

Giving an average to 8 decimal places is meaningless.

Table of result of angle B
TIME(GMT) Angle(Degrees)
10 89.0
11 70.0
12 55.60
13 41.20
14 25.90
15 14.00
16 0.00

average angle B=42.24285714 degrees

Hang on - you've got that extra hour in there again!!!! This is
beginning to look very suspicious....

You're apparently posting from Belgium, so were you in Africa on
holiday, for work, or what? Did you just happen to be there on 20th
March (but somehow measured an extra hour of daylight)?

Maybe you were installing a satellite communications system? I'm sure
if you ask one of the "technical people" you work with, they can
explain where you've gone wrong in your calculations)

CALCULATION OF RESULTANT ANGLE (A)

Resultant angle is the angle which is used to calculate the attraction
force resolution into centripetal force.


Cos A= Cos E- Cos B
A=antiCos(Cos E-Cos B)
A=antiCos(Cos 35.57142857-Cos 42.24285714)

A=85.808857125 degrees

the resultant angle A= 85.80857125 degrees for electromagnetic
spectrum(Photon) of visible light on planet earth.

Again 8 decimal places is totally pointless when your measurements are
only done to 1 place at best. You've also neglected to explain how
you accounted for your position not being on the equator, for your
elevation, for atmospheric effects such as refraction, etc. etc. etc.

All in all very poor work. You never did say whether you got that BSc
you were supposedly studying for....

DP

[I'm beginning to think I have too much time on my hands going through
this badly presented gibberish. If only the clouds would clear I'd
have better things to do ]

--
Nattering Nabob #1 of the MOHSG

(alpha version of .sig)

Calculating E and B following the experiment would at best return gibberish
since you have randomly determinerd to meaasure at only a few discrete
points. Shift the measurements half an hour and you would get E and B
basically the same. This makes E and B useless.

The formula you apply after that,
Cos A= Cos E- Cos B
could use some explanation from you, but as for E and B you dont have any
significant numbers.

the resultant angle A= 85.80857125 degrees for electromagnetic
spectrum(Photon) of visible light on planet earth.

And does this agree with your prediction ?

Big problem is of course that you have not established what the accuracy is,
yet returns 10 digits, from a measurement giving 0 digits accuracy (from
what Ican see).

"thinking 1000 faster than others can be a bad thing, if you skip the
thoughts that keeps it together" ;o)

Clear Skies,
Magnus

The Commentator wrote in message ...
peter wrote:



I am working on an invention if i post this evedence legaly i will
lose my partern right,

What is a "partern?"

A partern right is legal ownership right give to an inventor for
specified period of time.


with this evidence some can develop it that is
why i am holding on this .I am trying out theoretical research if
imformation can be stored in an electrons in atoms .

Once again we need to translate from Loon to human.

Do you have any idea what you are talking about?


Yes i do have but it long way to be develop into an invention there is
need for alot of creative thinking it will take some time to have a
presentable invention i can not specify on the time because
probability that it will work is 1/10( that is ten percent)

"Magnus Nyborg" wrote in message ...
Calculating E and B following the experiment would at best return gibberish
since you have randomly determinerd to meaasure at only a few discrete
points. Shift the measurements half an hour and you would get E and B
basically the same. This makes E and B useless.
E and B is very importance for testing your result (credibility of you
result and experiment)

The reasion of E and B is to determine to which side are light rays
deflected, the side with less average angle is the side to which the
rays are deflected.If the experiment showed that avarage of E was
equal to B it would mean that light ray are not affected by planet
earth magnetic field

The formula you apply after that,
Cos A= Cos E- Cos B
could use some explanation from you, but as for E and B you dont have any
significant numbers.

E and B averages of angles taken from calculated angle between the
shadow and the west-east line drawn when the experiment was setup.
E represent average of angle from sun rise to about miday when the sun
ray are coming from over head (90 degrees).
B represent average of angle from mid-day to sun set.

the angle are taken from regular time interval forme i took 1 hour
interval.

wrote in message . ..
(peter) wrote:

wrote in message . ..
(peter) wrote:
EXAPERIMENTAL SETUP

Your experimental setup and methods are seriously flawed - see below.

CHAPTER THREE
3.0 RESEARCH DESIGIN
This research was set up to investigate the present of resultant angle
and to determine its degrees to fine of if photon are charge and are
deflected by earth magnetic field .
3.1 STUDY AREA
This research was carried out on sun light rays .The condition under
investigation was to determine the if photon were charge and are
deflected by earth magnetic field and to also ivestigate presnt of
resultant angle of light on earth surface and determine its degrees

This doesn't make any sense. Determine degrees of what? What do you
mean by "resultant angle"? And please start using a spell checker so
I at least have a vague idea what you're on about.

3.2 DATA COLLECTION
this was done both qualitatively and quantitatively by marking the

What do you mean by "qualitatively"? In this kind of experiment only
exact measurements can have any meaning, so any subjective impressions
cannot be used.

position of the shadow at time interval of one hour measurement taken
were computed to fine out the angle of incident using trigometric
function of angle.
3.3 INSTRUMENT AND REQUIREMENT USED
Campass direction,long straight pole,clock.open falt leveled
ground,sunny weather,meter ruler
3.4 PROCEDURE

This experiment was carried out on march /20/2003 on a open 60 km from
the equator.

Did you compute the effect of not being exactly on the equator? How
much would this affect your results?
if you are to carry out the experiment at the equator your will have
to have a very tall pole to be about to have measureable shadow lenght
especially at mid-day when the lenght of the shadow is vrey small that
lead error during computation of result.

60 km from equator was the best place

What was your exact lat/long, and just as importantly, what was your
elevation above sea level?

sea level does not need ,what is importance is to ensure that the
ground is not tilted(flat)
What about your horizon? If there were
any obstructions such as buildings, hills, trees etc. you wouldn't be
able to accurately determine sunrise or sunset.
you will not be able to seen the shadow of the pole hence you will not
be able to mark the position of the pole therefore because the shadow
from building ,tree will cover you experimental ground,

The ground was level covering a radius of 20 meters using leveler to
ensure that the ground was not tilted.

What's a "leveler"?
a instrument used in constructor is does have liqiud in side and air
pocket when the air pocket is at make center it means that the ground
is flat
Do you mean a device (like a spirit level) to
measure the slope, or some kind of device to create a flat area?

yes that is what i mean


Using a compass the direction the north and south direction was
determined and a striaght north-south line was drawn.The west and east
direction was also determined and west-east line was drawn.AT the

Are you aware that magnetic North is _not_ the same as true North?
YES i known that the north magnetic pole (some place in northern
canada)
Did you take this into account when constructing your coordinate
system?
yes account of that factor.
This seems to me to be one of the most fundamental flaws in
your whole "experiment".

point were this two line cross each other a 7 feet long striaght thin
pole was fixed vertically at right angle to the ground.

How did you ensure it was vertical? What was it made of (to know if
it might bend)?

You can determine if the pole is verticle with right angle set square

How much of the pole was in the ground, and how much

just enough to hold the pole on verticle position.
remained projecting above?
at least most of the 7 feet it should not be less than 6.8 feet for a
good result.

All of these could affect your results.

The experiment setted at 3 GMT at sun rise the position of shadow of
the pole was marked at regular time interval of one hour through the
day up to sun set at 16 GMT.

Well, a quick check puts you near the East coast of Africa, either in
Somalia or Kenya. However, on 20th March the Sun rose at 03:00 and
set at 15:00, so you've either made a fundamental error in your
observations or you have the date wrong....
there is not fundamental error East Afican sun rose at 03:22 GMT i
started recording at 3:00 GMT just before sun rise with a zero in
order to cover all the data.

Of course the Sun isn't a point source, so the rise and set times
could be slightly earlier and later than these by a few minutes.

Point of focus here is the direct rays from sun which have not under
gone any defraction reflection or interferance.


I presume you also took into account this fact that the Sun isn't a
point source when designing your experiment and when analysing your
data?

A striaght line was drawn from each of the position marked through to
the center were the pole was fixed.Lenght of each of the drawn line
was taken and recorded .

How were these measured? the lengh were measured in centimeter using meter ruler and angle of the rays computed using trigonometric function of angle.
And how accurately? +-0.01 centimeter
Why were measurements
only taken at hourly intervals? That was my choose
How accurate was your "clock" come to
I was using alarm clock.I can not tell the accuracy the alarm clock
from motorala phone was set at an hour interval.each measurement i
carried at every hourly interval out took less 2 minutes ,that can be
used to fine the accuracy
that?

If there is any deflection of photons by magnetic fields, the effect
would be so small that you'd have to be making measurements accurate
to microns - which I somehow doubt you were doing.

Distance of magnetic field through which light photon travel is
60000000 meter that is from shock wave to earth surface.that distance
and earth magnetic field strenght is enough to deflect photon to ward
the west up to about 1450 meter away from the linear path of light
expected.

The angle of light rays to be computed were divided into two.angle of
ray from sun rise to 90 degree and angle from 90 degree to angle of
rays at sun set.lenght was taken for
The lenghts recorded was used in the trigonometrical determination of
angle of the rays.
Rays from sun rise to ray with 90 degrees were computed from
trigonometric function of angle of eastern line lenght aganist the
lenght of line drawn from the shadow to the center were the pole was
fixed and rays from 90 degree to sun set were computed from
trigonometric function of angle of western line lenght aganist the
lenght of line drawn from the shadow to the center were the pole was
fixed.

I've read this at least ten times and can't figure out what you mean.
The angle was computed from the lengths of two lines, one being the
shadow projected by the pole - what's the other length?
From tragonometric function of angle you need two lenght of a right
triangle to compute an angle using cos,sin,tangent.
so if you have the length of the shadow you draw up a right angle
triangle with the west-east line take coresponding mearsurement on
west-east line and you can trigonometrically calculate angle of direct
ray from the sun at that time.

Is it some datum on the East-West axis? If so, how did you measure
it, and how accurately?
not East-west is line drawn to help compute angle

CHAPTER FOUR

4.0 DATE PRESENTATION AND ANALYSIS OF DATA
Angle of light ray from sun rise to 90 degree was computed as
E=antisin z/y

What are z and y? If I was trying to calculate the angle of the Sun
I'd do it as arctan (pole_height / shadow_length). To use arcsin
you'd need the hypotenuse length, which you haven't defined or
calculated.

There is need for experimental set up diagram this part well


angle of light rays rom 90 to sun set was computed as
B=antisin c/a
The resultant angle was computed as shown below

Cos A = CosB-CosE

A=anticos(cosB-coE)

A is resutant angle

What does this mean? I've read it again about ten times, but can't
figure out what you're trying to calculate.
resultant angle is the angle at which the deflected ray reach earth
surface.
if the resultant is computed and found out to be 90 degree when the
earth is not tilted it mean that the light are not affect by magnetic
field.i found some thing like 85.808857125 degrees which mean earth
magnetic field does have effect on light rays.
From the E average angle and B average angle,we can determine to
which direction the photon of light wave are delflected.The one with a
lower average determines the direction of deflect.which for this
experiment is E with 35.57142857
ray for E reach the earth east at angle which such clearly the west
ward diflection.


I WILL CONTINUE FROM HERE NEXT TIME