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On Jun/12/2020 at 13:27, Greg (Strider) Moore wrote :
"Scott Kozel"Â* wrote in message Something that I read in the literature a few years ago, what happens if the cable breaks? It would depend on where it breaks, as to what part falls to the ground, what part heads out into space, and what part might just wave around at high altitude and not fall. Also the expense of rebuilding part or all of the elevator cable. I saw someone do the math once. Ignoring any payloads, the cable itself is so light that it "falling" on pretty much anyone or anything most likely wouldn't do much kinetic damage. As for other problems (say falls against a road, truck runs into it) that's another issue. What happens is a complex issue. I wouldn't trust it to gently lay itself on the ground. If the cable breaks, I would get out of its path. Imagine if the cable breaks near the top. The broken off part just flies off, we can ignore that part. The top of the cable still anchored to the ground is still pulling the bottom part up but the bottom part is pulling down harder than the top part, so the cable is slowly coming down vertically. At first the cable is still taut, but it is gaining vertical speed downward. This puts some slack in the top of the cable, not the bottom where the pull is stronger. The bottom part of the cable is accumulating on the ground near the anchor point. After a while, the top part has too much angular speed for its lower altitude and starts to pull the cable eastward. As the cable gets lower, this eastward pull becomes stronger and the cable that was on the ground near the anchor point starts being pulled eastward. When all the slack of the grounded cable is taken up, the cable now has significant eastward speed and you have a huge mass with significant speed pulling eastward. SNAP. Not pretty. Now imagine that instead of breaking near the top, the cable breaks near geosynchronous altitude. Much the same as above happens again, even if the top part at geosynchronous altitude is not pulling up, it wants to stay at its altitude but is pulled down by the bottom part. Things go along much as in the case where the initial break was much higher up, it only happens in a different time frame. Imagine this time that the cable breaks at an altitude of 10,000. This time ignore the bottom part which hits the ground. A little more surprisingly, the top part will do much as the two examples above. The cable first goes up vertically, then the bottom part loses angular momentum. It starts pulling the cable westwardly, this westwardly pull accelerates, but mostly in the bottom, while the top is accumulating some slack. After a while, the top part receives the cue that there is a big westwardly pull. Again SNAP. In reality, all of the above can happen together. Different parts of the cable will be pulling in different directions there will be some slack accumulating here and there and the the cable becoming taut again and snapping here and there. The pieces falling to the ground might not be taut. Who knows, you could have some big balls of cable that have curled up. And even if you don't have big balls of cable, you can have some cable fall lightly to the ground and then be dragged eastward pulling anything with it. The physical properties of the material used to make the cable would also have an effect on what happens. Just a simple cable breaking could have a mostly unpredictable chaotic outcome. One could put in some apparatus here and there on the cable to keep it somewhat under control. If you roll in the cable where some slack accumulates, you don't end up having wide speed differences for different parts of the cable. It certainly would be fairly spectacular to see though! Yes. :-( Alain Fournier |
#42
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On Saturday, June 13, 2020 at 12:01:34 PM UTC-4, Alain Fournier wrote:
[. . . .] Just a simple cable breaking could have a mostly unpredictable chaotic outcome. One could put in some apparatus here and there on the cable to keep it somewhat under control. If you roll in the cable where some slack accumulates, you don't end up having wide speed differences for different parts of the cable. Part of the reason for having the Earth anchor being on a platform well out in the ocean. Still, the various outcomes could affect shipping and aviation over a wide area. |
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On Jun/14/2020 at 01:43, JF Mezei wrote :
On 2020-06-13 12:01, Alain Fournier wrote: What happens is a complex issue. I wouldn't trust it to gently lay itself on the ground. If the cable breaks, I would get out of its path. Following assumes a cut just below geosynchronous altitude and a tether of equal mass from sea level to cut. The way I see it, a mass exerts upward force when its orbital speed is higher than needed at that altitude and it isn't allowed to rise. With the 0 point being geosyncrhonous altitude, when the cut happens, the position of cable at -1m is pretty close to having orbital speed. So it weights less than the same lenght of cable at sea level, not only because gravity is less, but also because it is nearly at orbital speed where its weight (strict definition) would be near 0. So with cable at sea level wanting to accelerate down at 9.8m/s2, the portion at the top wants to go down at only 0.1 m/s2 (pr whatever low value). The lower end wanting to accelerate more than the top would create tension in cable, keeping it straight. So far correct? Not really. At very first, yes that is what will happen. The bottom part will pull the cable down under some tension. This will cause parts higher up to go eastward. Pieces higher up will start going eastward slower than pieces in the middle, but with time the pieces higher up will get more eastward speed than those in the middle. You get a chaotic result, the cable breaks at multiple places. Since the tip of cable had enough energy to almost be in orbit, as it is pulled down, it will reach an altitude where its energy is above what is necessary to be in orbit, below which, the cable will have upward force and want to slow down the fall. So, when the tip of cable is pulled down, its orbital instinct will be to try to increase its forward speed. Won't that result in part of the force pulling upwards since the cable will end up diagonal? Won't that also slow down the fall? Yes it will, but this phenomenon will happen all along the cable with different intensities and different speeds at different heights. Big picture, will the cable trying to move eastward during its fall give back to the planet the eastward spin that the planet gave up when it accelerated the cable? The cable will give some negligeable amount of eastward spin to the planet when it falls. I'm not quite sure what you mean by "the spin the planet gave up when it accelerated the cable". When the cable is put in place, it is put there at orbital speed at geosynchronous orbit. The planet does not lose angular momentum when you anchor the cable to the ground. The planet does lose some momentum when a payload goes up the elevator. The amount of angular momentum the cable will give the planet uppon falling to the ground has nothing to do with the amount the planet lost while payloads were going up. More imkportantly, will a 36,000km cable end up almostly circling the equator (40,000) as it falls, or will there be significant amounts of cable that will be piulot onto itself, greatly reducing the distance covered as the cable falls back down? Sorry, I can't parse piulot. Now, changing cable to "structure". If it breaks at geostationary AND ground levels, are there scenarios where distribution of mass and energy might result in the structure going horizontal and at half geostationary orbit ? (aka: top part lowering from geo to half and bottom part dragged up to half geo? No. A cable in orbit will always take a vertical orientation because of tidal forces. The cable might break up in several pieces and some pieces might go kind of horizontal momentarily (while spinning). But the pieces that stay in orbit will stabilize in a vertical orientation. Alain Fournier |
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You can look at the simulations of broken space elevator cables at
https://gassend.net/spaceelevator/breaks/index.html I don't know that guy and I haven't validated his simulations but I have no reasons to believe that his simulations are not accurate. Alain Fournier On Jun/15/2020 at 04:34, JF Mezei wrote : On 2020-06-14 06:51, Alain Fournier wrote: Not really. At very first, yes that is what will happen. The bottom part will pull the cable down under some tension. This will cause parts higher up to go eastward. In wanting to go eastward, won't the cable also end up pulling up because wanting to go faster will only work for so long until the slack is gone and the increased speed is decelerated back to geosynch speed of one orbit per 24 hours? Pieces higher up will start going eastward slower than pieces in the middle, but with time the pieces higher up will get more eastward speed than those in the middle. You get a chaotic result, the cable breaks at multiple places. So if the cable between LEO and Geo breaks up, won't each individual segment just drop till they are at an orbital speed that matches their altitude? For pieces low enough, they won't have enough altitude to convert a droip in altitude into horizontal speed enough to stay in orbit, so they will hit atmosphere and drop to sea level. So assuming such a tether has separateion mechanism, not all of it would fall down since pieces high enough to achieve orbital speed as they drop. And if it breaks up into seperate segments, it also means that the "heavy" segments near ground stop pulling down thosesegments near geo. The cable will give some negligeable amount of eastward spin to the planet when it falls. I'm not quite sure what you mean by "the spin the planet gave up I was thinking about the spin the Earth woudl give up when it accelerates the elevators as they rise. But you're right in that the cable itself is more likely to be assembled with rocket engines accelerating it. More imkportantly, will a 36,000km cable end up almostly circling the equator (40,000) as it falls, or will there be significant amounts of cable that will be piulot onto itself, greatly reducing the distance covered as the cable falls back down? Sorry, I can't parse piulot. Sorry, pile up. Assuming the cable doesn't break, would it fall down drawing a stright line towards the east that almost goes around all the globe? Or woulf there be periods where the cable piles up onto itself, then perhaps moves some, pules up again (at which point the whole 36,000km of cable make span perhaps just 1000km, with piles containing 36km of cable left every 10km. No. A cable in orbit will always take a vertical orientation because of tidal forces. Sorry for basic orbital mechanic quaestion: say you have a 1000km cable which is vertical, and the top at 36,000km altitude. (lets say for sake of discussion geostationary is 36,001) So a piece at 36,000 altitude is going at 9424km/h when on tether. The piece at 35,000 altitiude is going ay 9162km/h. Both have sale 360°/24 hours angular speed. Now, say the whole segment drops 1000km. How will the speeds of each end accelerate relative to each other? Will the top end up with more angular speed than the bottom? Or vice versa? Or would it remain strictly the same? If either side wants to accelerate horizontally more than the other, won't the cable end up near horizontal eventually? |
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