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#31
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Well quarks are the building sub-particles that create the structure
of protons. I see protons like I see a finished object(all of its parts) Neutrons with their quark structure came before protons,because protons come from neutron decay. I would like to know why neutrons stop decaying inside a nucleus? I would like to know when the last free neutron is going to decay.? I know it all comes under probability,but this is my spacetime(give me a break) I want answers now. Well I'll give my New Year thought. Neutron stars are unstable,and decay. They do it in a rather tricky way. Bert |
#32
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G=EMC^2 Glazier wrote:
Well quarks are the building sub-particles that create the structure of protons. I see protons like I see a finished object(all of its parts) Neutrons with their quark structure came before protons,because protons come from neutron decay. I would like to know why neutrons stop decaying inside a nucleus? It is called the strong nuclear force. It works at the level of the nucleus of the atom. It is provided by nucleons, protons and neutrons. I would like to know when the last free neutron is going to decay.? I know it all comes under probability,but this is my spacetime(give me a break) I want answers now. Well I'll give my New Year thought. Neutron stars are unstable,and decay. They do it in a rather tricky way. Bert Neutron stars are subject to the strong nuclear force as well. Their instability may come only if protons themselves decay, as predicted by some grand unified theories. To date, all experimental efforts to observe such decay have come up empty. |
#33
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Scott You left our "gluons" that is the particle responsible for the
strong force. Just thought of this Question. Does the Hydrogen nucleas have a gluon? I don't think so. How about heavy hydrogen? I think so. Bert |
#34
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G=EMC^2 Glazier wrote:
Scott You left our "gluons" that is the particle responsible for the strong force. Just thought of this Question. Does the Hydrogen nucleas have a gluon? I don't think so. How about heavy hydrogen? I think so. Bert If I wanted to give a detailed treatise on particle physics, I would have. But, as this is a news group and long responses are not encouraged - it is assumed given sufficient starting information the person asking the questions is bright enough to do further research from that starting point - I chose not to. |
#35
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Scott Hmmmmmmmmmmm Bert
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#36
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![]() "G=EMC^2 Glazier" wrote in message ... Scott You left our "gluons" that is the particle responsible for the strong force. Just thought of this Question. Does the Hydrogen nucleas have a gluon? I don't think so. How about heavy hydrogen? I think so. Bert Hi Bert, Hope you had a good Christmas & New Year. The hydrogen nucleus would "contain" gluons, since these are the mediators of the strong nuclear force that binds the constituent quarks into a proton. In deuterium, the binding of the nucleons is a secondary effect, similar in some ways to the van der Waals force that causes attraction between elctrically neutral molecules. DaveL |
#37
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![]() "Greg Neill" wrote in message . .. "Dark Helmet" wrote in message t... Greg, this makes a lot of sense. Thanks for taking the time to do this. Now, this leads me to a few more questions. First, what exactly is space then that allows it to expand faster than than the speed of light? Well, that's the $64,000 question. A definitive answer to that would require a grand unifying Theory of Everything. The best we can do right now is turn to the General Theory of Relativity and Maxwell's equations for its properties. It boils down to a handful of properties, such as permitivity and permeability and curvature. It has no mass, stiffness, or other mechanical properties. Second, since light is travelling through expanding space and all space is expanding, would light only travel at a relative speed of c in an infinitesimally small area of space? For example, light leaving my monitor screen at this moment is in a portion of space that is expanding away from me, although small, so this light will really not reach me at a true speed of c. Thoughts? You would measure a difference in speed if the space between you and your monitor were expanding. Alas, it is not. The space occupied by gravitationally bound systems does not participate in the overall expansion. That means that the space encompassing us, the planet, the solar system, the galaxy, and the local galactic cluster is not participating in the expansion. Greg, Happy New Year. One more thought on this subject. First, I assume we can observe stars beyond the local galactic cluster. Assuming this, if light travels at c only in gravitationally bound systems such as the local galactic cluster, is it possible that things we take for certain locally do not apply beyond? For example, could the measured red shift of a star beyond the local galactic cluster be "distorted" due to constants such as c not applying across such vast distances? In other words, is it possible that the red shift may have been distorted in travelling from one gravitationally bound system, outside of it, to another, etc? Dark Helmet |
#38
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"Dark Helmet" wrote in message
t... Greg, Happy New Year. One more thought on this subject. First, I assume we can observe stars beyond the local galactic cluster. Assuming this, if light travels at c only in gravitationally bound systems such as the local galactic cluster, is it possible that things we take for certain locally do not apply beyond? For example, could the measured red shift of a star beyond the local galactic cluster be "distorted" due to constants such as c not applying across such vast distances? In other words, is it possible that the red shift may have been distorted in travelling from one gravitationally bound system, outside of it, to another, etc? Happy New Year to you too! Resolving individual stars beyond the local cluster is difficult, but individual supernovas can be seen. We can certainly make out collections of stars, i.e. galaxies. Light always travels at c in its local parcel of space, whether or not the space is expanding. That is to say, an observer will always measure the local speed to be c. If c did not apply in different places, then the local physics there would be different and this would show up in the atomic spectrum, and measures of what is called the fine structure constant, which is very sensitive indeed to the value of c. Also, if for some reason the speed of light were to change from region to region in a haphazard fashion, it would show up as a lot of confusion in the red-shift distance scale when we look in different directions. |
#39
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![]() "Greg Neill" wrote in message . .. "Dark Helmet" wrote in message t... Greg, Happy New Year. One more thought on this subject. First, I assume we can observe stars beyond the local galactic cluster. Assuming this, if light travels at c only in gravitationally bound systems such as the local galactic cluster, is it possible that things we take for certain locally do not apply beyond? For example, could the measured red shift of a star beyond the local galactic cluster be "distorted" due to constants such as c not applying across such vast distances? In other words, is it possible that the red shift may have been distorted in travelling from one gravitationally bound system, outside of it, to another, etc? Happy New Year to you too! Resolving individual stars beyond the local cluster is difficult, but individual supernovas can be seen. We can certainly make out collections of stars, i.e. galaxies. How do you know they are collections of stars if we can't make them out individually? Maybe they are just some weird light flashes? |
#40
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"Whisper" wrote in message ...
"Greg Neill" wrote in message . .. "Dark Helmet" wrote in message t... Greg, Happy New Year. One more thought on this subject. First, I assume we can observe stars beyond the local galactic cluster. Assuming this, if light travels at c only in gravitationally bound systems such as the local galactic cluster, is it possible that things we take for certain locally do not apply beyond? For example, could the measured red shift of a star beyond the local galactic cluster be "distorted" due to constants such as c not applying across such vast distances? In other words, is it possible that the red shift may have been distorted in travelling from one gravitationally bound system, outside of it, to another, etc? Happy New Year to you too! Resolving individual stars beyond the local cluster is difficult, but individual supernovas can be seen. We can certainly make out collections of stars, i.e. galaxies. How do you know they are collections of stars if we can't make them out individually? Maybe they are just some weird light flashes? Take a look at some Hubble pics, especially some of the deep field views. |
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