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Spider Jerusalem wrote:
Point well taken. I suppose they could live on spirulina grown in tanks at 3 kw/person, but that wouldn't be much of a life, not having any real food. http://www.spirulina.com/ It's the pic on the left that gets me - I think these people intend to terraform the _Moon_! Marshall Savage of _The Millennial Project_ did sing the praises of spirulina, as well as proposing a development plan which wasn't supposed to produce much visible stuff for a few years yet. It'd be nice to think that Spirulina.com is actually part of an on-track Plan. -xx- Damien X-) |
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Ian Stirling wrote:
In sci.space.policy WLM wrote: Point well taken. I suppose they could live on spirulina grown in tanks at 3 kw/person, but that wouldn't be much of a life, not having any real food. As far as the cooling is concerned, that would probably be a power *source* instead of requiring power. The temperature of the space For this to be true, you've got to have much larger radiators. Say the heat source is at 273K. The heat loss per square meter of radiator is of the order of 500W/m^2 or so. Let's say you want to run the heat engine between 273K and 137K (50% efficiency with an ideal engine), your radiators need to be 16 times as large, assuming the same heat output. On the flip-side, your energy gathering area can be 50% smaller. Could you, or someone, expand on what was going on here? "Radiators need to be 16 times as large" -- as large as what? The 137K radiators after heat recovery would have to be 16 times larger than the 273K radiators with more energy loss? Energy = k * Temperature^4? Wait, that doesn't seem to make sense... -xx- Damien X-) |
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In sci.space.policy Damien R. Sullivan wrote:
Ian Stirling wrote: In sci.space.policy WLM wrote: Point well taken. I suppose they could live on spirulina grown in tanks at 3 kw/person, but that wouldn't be much of a life, not having any real food. As far as the cooling is concerned, that would probably be a power *source* instead of requiring power. The temperature of the space For this to be true, you've got to have much larger radiators. Say the heat source is at 273K. The heat loss per square meter of radiator is of the order of 500W/m^2 or so. Let's say you want to run the heat engine between 273K and 137K (50% efficiency with an ideal engine), your radiators need to be 16 times as large, assuming the same heat output. On the flip-side, your energy gathering area can be 50% smaller. Could you, or someone, expand on what was going on here? "Radiators need to be 16 times as large" -- as large as what? The 137K radiators after heat recovery would have to be 16 times larger than the 273K radiators with more energy loss? Energy = k * Temperature^4? Wait, that doesn't seem to make sense... It's not energy which is proportional to T^4, but energy emission from a radiating surface in general. Google "stephan-boltzmann" Basically, as the temperature of the radiator goes down, the amount it can radiate per unit area (given a 0K environment) goes as the fourth power of the temperature. So, to remove a constant amount of heat, you need the radiator to be larger. |
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On 12 Sep 2004 15:17:08 GMT, Ian Stirling
wrote: In sci.space.policy Damien R. Sullivan wrote: Could you, or someone, expand on what was going on here? "Radiators need to be 16 times as large" -- as large as what? The 137K radiators after heat recovery would have to be 16 times larger than the 273K radiators with more energy loss? Energy = k * Temperature^4? Wait, that doesn't seem to make sense... It's not energy which is proportional to T^4, but energy emission from a radiating surface in general. Google "stephan-boltzmann" Basically, as the temperature of the radiator goes down, the amount it can radiate per unit area (given a 0K environment) goes as the fourth power of the temperature. So, to remove a constant amount of heat, you need the radiator to be larger. Black body radiation is sigma T**4, where T is in deg absolute (is that Kelvin or Rankin these days?). This is one of the few formulae I still remember from engineering school after thirty-plus years. You can radiate more if you can change sigma, which is a constant for each type of material. However, the changes aren't huge compared to the effect of the temperature differences. Mary -- Mary Shafer Retired aerospace research engineer |
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Mary Shafer wrote:
Black body radiation is sigma T**4, where T is in deg absolute (is that Kelvin or Rankin these days?). This is one of the few formulae I still remember from engineering school after thirty-plus years. The SI unit is the kelvin. You can radiate more if you can change sigma, which is a constant for each type of material. However, the changes aren't huge compared to the effect of the temperature differences. sigma is a universal constant. You're thinking that the full equation is P = e sigma A T^4, where e is the emissivity, and A is the surface area, T is the thermodynamic temperature, and sigma is a fundamental constant. -- __ Erik Max Francis && && http://www.alcyone.com/max/ / \ San Jose, CA, USA && 37 20 N 121 53 W && AIM erikmaxfrancis \__/ Can I walk with you / 'Till the day that the world stops turning -- India Arie |
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