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On Feb 23, 9:34 am, bz wrote:
HW@....(Henri Wilson) wrote : Bob, the only so called evidence AGAINST the BaTh was De Sitter's work. We know now why that is wrong. Incorrect. There is a LOT more evidence against BaTh. http://www.mpe.mpg.de/ir/GC/index.php That is not the text that appears on that main index page. I suspect you found this paper on a link somewhere on that page, but that it was in a frame so the URL displayed still showed the main page. However, I found the paper you quoted he http://www.asa3.org/aSA/PSCF/1988/PSCF3-88Phillips.html - Randy |
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"Randy Poe" wrote in
ups.com: On Feb 23, 9:34 am, bz wrote: HW@....(Henri Wilson) wrote : Bob, the only so called evidence AGAINST the BaTh was De Sitter's work. We know now why that is wrong. Incorrect. There is a LOT more evidence against BaTh. http://www.mpe.mpg.de/ir/GC/index.php That is not the text that appears on that main index page. I suspect you found this paper on a link somewhere on that page, but that it was in a frame so the URL displayed still showed the main page. However, I found the paper you quoted he http://www.asa3.org/aSA/PSCF/1988/PSCF3-88Phillips.html Thanks! I hate frames! - Randy -- bz please pardon my infinite ignorance, the set-of-things-I-do-not-know is an infinite set. |
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On 23 Feb 2007 01:45:05 -0800, "George Dishman"
wrote: On 23 Feb, 09:07, HW@....(Henri Wilson) wrote: On Fri, 23 Feb 2007 00:11:56 -0000, "George Dishman" wrote: "Henri Wilson" HW@.... wrote in message .. . On Thu, 22 Feb 2007 11:23:57 -0000, "George Dishman" Electromagnetic. Magnetic alone doesn't propagate. The pulsar is a rotating magnet. How the electric component comes into the picture is not certain. Look up "near field", the effects significant in antenna design and RFI problems. However, for the pulsar the magnetic field just provides the energy and some mechanism in the plasma probably produces the actual radiation. The details aren't clear yet AFAIK. It could easily be generated in radiation belts around the whole binary system. That might act as a local EM reference frame You still haven't learned what "reference frame" means. Don't be silly George. I am using the term loosely here. The actual reference frame is that of the barycentre. I'm saying there is a surrounding 'field' of some description that is virtually at rest wrt the barycentre and which tends to unify the speed of all light inside the region to 'c' WRT the region. I say 'tends to' becuase its effect must obviously taper off with distance from the centre. When I said the field 'constitutes a local reference frame' I mean 'the field defines the same frame as the barycentre' and can be used as a reference for light speed. It is just as legitimate to say 'speed wrt the barycentre' as 'speed wrt the field'. They have the same meaning. and unify the emitted light speeds. We are assuming its speed wrt Earth varies between about c+/- 0.00009. No, we are taking as a given that the time between pulse arrivals varies by about 90 parts per million. Some of that variation is due to the velocity but some will be due to c+v pulses catching up to c-v pulses a little in the time before extinction equalises their speeds. ...and that results in exactly the same doppler shift as your own model. What do you mean by my "own model", SR or my corrections to your Ritzian version? SR. The only basic difference is that for small values of v, one uses the equation (c+v)/c and the other c/(c-v). It isn't inverse square, it is inverse exponential, but either way most will be in that sort of time frame. I was talking about whatever it is that causes the unification. I was speculating that its effect must drop off with distance from the star....that's over and above the exponential approach to equilibrium. OK. This is perfectly in accordance with my concept of an EM FOR surrounding large mass centres. It is not a plain 'gravity' effect. That happens separately and shows up as Shapiro delay. "Frame of reference" is a mathematical construct of no relevance to the topic. Think of it as meaning a coordinate system whose origin is the pulsar, nothing more. Coordinates don't affect light. Not according to SR.... ![]() Yes, in SR ![]() The origin of this frame is the barycentre of the pair. The origin of a frame is whatever origin you use for the measured values. I didn't mean 'origin' as in 0,0 on a graph. I meant the frame owes its existence to the fact that there is a definable centre of mass for the whole system. My light speeds can be specified relative to the barycentre....or to the surrounding 'field' at rest with the barycentre...same frame.. . Instead, calculate the sine wave and then plot the difference between the perfect sine wave and your curve. That is the "residual" which you will find in the published papers. Give the value for the maximum of that curve. Why would I want to calculate it when the computer can do it for me .. Oh Henry, obviously I meant you get your program to do the calculation and add another curve to the plots! OK. and give answers for a broad range of parameter values? You're not up to date George. George you solved the wrong problem. The integral is of hte form Total time= intgrl [1/(1+Ae^-kt)].dt (c=1) A solution is: t +log(1+Ae^-kt) between 0 and t. I found a simple way to closely approximate the integral using the sum of a GP instead...it is also faster to run. the terms are 1/(1+0.00009),1/(1+0.00009X),1/(1+0.00009X2),1/(1+0.00009X3).........1/(1+0*.00009X^n) Since the 0.00009 is small, this can be closely approximated with: (1-0.00009),(1-0.00009X),(1-0.00009X2)...........................(1-0.00009*X^n) The sum is (n+1) -(1-0.00009)*(X^n-1)/(X-1) wherer n is the number of light days and X is the unification rate (eg., 0.99995 per Lday) The single calculation t = vR/c^2 will be even quicker ;-) That is really your biggest problem, you don't seem to have the familiarity with maths that you need to follow a lot of the arguments. Now you're starting to sound like geesey.... You are still using an iterative method when a direct calculation would do the job. It suggests you aren't really comfortable with this level of maths. George, I DO use an equation. ...the sum of the above GP. The problem is, every sample point around the orbit has a different value for v. I am suggesting you only need to calculate t = vR/c^2 for the value of v at each point rather than your iterative sum at each point. Sorry, I'm not with you. What's R? It has dimensions of length. I can't see an extinction RATE anywhere there. We'll see when you un-normalise the curves, I hadn't realised you did that and thought you meant the physics made their height the same. Their heights ARE almost the same for small magnitude variations. Without extinction, the amplitude of the red curve cannot be any greater than that of the blue one. That is where you are wrong, without extinction the red curve increases with distance until the peaks reaches c at the critical distance. With extinction the red curve starts rising above the blue but is asymptotic to a constant curve and will be close to that at several times the extinction distance. George I think we are talking about different things again. I'll explain what the two curves represent. The blue one is the true c+v lightspeed wrt a flat plane normal to the observer LOS and close to the source. (We can ignore travel time across the orbit). The program assumes that hypothetical pulses of equal brightness are emitted at regular time intervals by the source as it orbits. At the observer distance, these pulses arrive in different concentrations, due to bunching. The program divides the orbit period into 500 equal time intervals and counts the number of pulses that arrive at the observer in each interval. This is a direct indicator of apparent brightness variation. The red curve is derived by averaging the true SOURCE velocities of all the pulses that arrive in each particular interval. The maximum of the blue curve is c+v. So the maximum of the red curve can never be higher than that. Certainly there are points on the red curve that are higher than those of the blue at the same phase....but that's not the issue. George "When a true genius appears in the world, you may know him by this sign, that the dunces are all in confederacy against him." --Jonathan Swift. |
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![]() Henri Wilson wrote: No you've got it all wrong George. The BLUE curve is the actual one. Several conflicting descriptions of the red and blue curves have been given. Could you state definitively what each curve represents? Leonard |
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On 23 Feb 2007 02:48:36 -0800, "George Dishman"
wrote: On 23 Feb, 09:39, HW@....(Henri Wilson) wrote: On Thu, 22 Feb 2007 23:59:59 -0000, "George Dishman" wrote: "Henri Wilson" HW@.... wrote in message .. . On Thu, 22 Feb 2007 10:17:35 -0000, "George Dishman" Thanks to Jeff Root for pointing out my misunderstanding of your definition. You are still completely misunderstanding the whole thing. I did misunderstand which angle your were describing previously. Consider this where B is the barycentre of the system, P is the pulsar, D is the Dwarf and E is the Earth: D B E P I was saying you could neglect the angle P-E-B. Obviously you still need to take the direction of the pulsar velocity into account. Yes OK. The benefit was just that you then get the conventional value as a simple confidence check by setting the distance to zero. I have checked. No. We are not using a grating. Individual pulses have their time of arrival noted against an atomic clock. Remember they are 2.95 ms apart so the 'wavelength' is 885 km. The inverse of the time between arrivals is the pulse repetion frequency. That frequency is what is turned into the published orbital parameters and is what give the 339 Hz +/- 30 mHz values. That's due to normal doppler 'bunching'. No, it is what is observed. It results from a combination of the normal bunching due to the varying distance from Earth and also the catch-up effect. There's NO 'catch up effect' in YOUR theory. I know Henry, the program is supposed to simulate the physics of ballistic theory. BaTh bunching is virtually the same. I told you, the program deliberately normalises the heights of the two curves to make shape comparison easier. If you like I will get it to plot a true amplitude comparison. That would help but what we need is the numerical values. Why? So you can plot them just as the computer does? I can print out the values if you like. Just the value at the peak. The purpose is to allow the parameters to be adjusted until this value reads 27km/s so we know when we have a match. I told you that the red curve is an average speed of the light that arrives in a set time interval. I htink you can imagine the effect bunching has on that. I don't want to imagine, I want the comuter to do that for me. ......Explained in my other message. OK we agree on that. Consider two pulses transmitted just before and just after the neutron star passes behind the dwarf as seen from Earth. This is the point of highest acceleration and the second catches the first at the maximum rate. First consider no extinction. The diagram shows the earlier pulse 'a' already ahead of 'b' at the time when b is emitted: b a b a b a * a b a b The time between pulses goes to zero at the critical distance. Now add extinction: b a b a b a b a b a b a b a The 'wavelength' settles down to a constant value but it is less than the original. George, George.... Consider what happens to pulses emitted when the pulsar is at the sides of the orbit. ..where there is NO aceleration. They are also equally spaced for the whole journey. Yes, at those points you only get the velocity effect but at any other location in the orbit the spacing is affected by both the velocity _and_ the acceleration. BUT THE SPACING IS NOT THE SAME AS THAT BETWEEN THE FORMER ONES a and b. In other words, the normal doppler pattern is there whether you use BaTh or constant c. The normal Doppler is there of course, I haven't disputed that, but it isn't the whole story. The pulse spacing is also affected by what I describe above and you need to take that into account AS WELL to get the full answer. The program takes everything into account. Why don't you experiment with it? I have, it gives the wrong value because you only take the bunching due to c+v vs c-v into account on the brightness curve, not the velocity curve. The predicted velocity is derived from the time between pulses so you need to take into account there too. Ah, I think I know what you are saying now. You are claiming that the closer the bunching, the shorter the wavelength...and the higher the observed doppler shift. Yes that should be true for the pulsar...but it is not true in my program..... So what is the difference? The difference is that it is the change in the actual width of the pulsar pulses in each bunch that is analogous to what my program does. Do you see what I mean? In reality, the width of the pulsar pulses varies by the same doppler fraction as does the distance between pulses. (~90 parts per million) So you have to average the WIDTHS of pulses and NOT their spacing to generate your equivalent of my red curve. The bunching itself is an indicator of brightness variation. You have to include the difference in emission times of course. Yes. Note that this effect is in addition to the normal Doppler change due to velocity alone (but at the location we are considering the radial speed is zero). Yes assume that is zero. Only at that point, I agree with your description above that velocity plays a part elsewhere. I'm becoming a bit confused as to what we are actually talking about now. At any point arond the orbit, pulses are being sent with a time gap of 2.95 ms. That gap is reduced at the receiver for two reasons: a) the velocity of the pulsar towards the receiver means that consecutive pulses travel different distances. That is the normal Doppler effect. b) if the pulses are transmitted at different speeds then faster pulses can 'catch up' to slower ones reducing the gap (or 'fall behind' if the second pulse is slower increasing the gap) and hence the time between reception depends on how much of this effect happens before extinction equalises the speeds. This effect is not taken into account in published velocity curves so the published values will be higher or lower than the simple Doppler value. That effect is not indicative of source velocity. Part (a) is dependent on the radial component of velocity at the time of transmission, part (b) depends on the acceleration at the same time and of course both vary round the orbit. Your program includes effect (a) but not effect (b). You'll have to rethink this in light of what I have said. George "When a true genius appears in the world, you may know him by this sign, that the dunces are all in confederacy against him." --Jonathan Swift. |
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On Fri, 23 Feb 2007 14:34:00 +0000 (UTC), bz
wrote: HW@....(Henri Wilson) wrote in : On Wed, 21 Feb 2007 15:37:12 +0000 (UTC), bz wrote: HW@....(Henri Wilson) wrote in : You must play by the rules of the game. Everything must be consistent with c'=c+v. You must deal with all the implications, you can not pick and choose which you want to deal with. Rubbish Rubbish? How can you pick and choose effects while ignoring other predictable effects and claim to be a follower of science, as describe it in your book? Bob, the only so called evidence AGAINST the BaTh was De Sitter's work. We know now why that is wrong. Incorrect. There is a LOT more evidence against BaTh. http://www.mpe.mpg.de/ir/GC/index.php [quote] In 1953, however, Parry Moon and Domina Spencer analyzed a number of visual binaries to see whether the phenomenon predicted by Bergmann would even be visible in the first place.7 They assumed the Ritz hypothesis8, but their computations showed that Bergmann's predicted multiple images for binaries would not, in fact, be observed. (They do not elaborate on de Sitter's prediction of spurious eccentricities, and they do not mention whether they reexamined his data or not.) Hence, they concluded that visual binaries proved absolutely nothing about the constancy of the velocity of light. [emphasis mine]In the same article, Moon and Spencer performed a similar analysis of spectroscopic binaries and of Cepheid variables.9 They concluded that the Ritz hypothesis would produce spurious spectral lines, but no such phenomenon was observed.[end emphasis] .... is Fox's criticism-that the observations of de Sitter and Bergmann did not take the Ewald and Oseen extinction effect into account-still valid? Definitely not, for by 1964 direct evidence for the validity of Einstein's postulate on the velocity of light was provided by a number of experimenters: D. Sadeh; T.A. Filippas and J.G. Fox; and T. Alvager et al.14 All of these experimenters measured the velocity of gamma rays which had been emitted by decaying subatomic particles moving at nearly the speed of light. In every case, the velocity of the gamma rays equaled that of the normal velocity of light in free space. In no case did the velocity of the gamma rays behave as proposed by Ritz. In addition to the above Earth-based experiments, in 1977 K. Brecher used radiation from pulsars (rotating neutron stars which emit radiation in a periodic manner) to show that the speed of light was independent of the motion of the source.15 Neither Brecher's experiment nor the ones mentioned in the preceding paragraph were subject to Fox's criticism. Hence, observations of both terrestrial and extra-terrestrial phenomena have shown once and for all that Ritz's hypothesis is invalid. .... [unquote] Yes. We know all about these exeriments and their wrong conclusions. -- bz please pardon my infinite ignorance, the set-of-things-I-do-not-know is an infinite set. "When a true genius appears in the world, you may know him by this sign, that the dunces are all in confederacy against him." --Jonathan Swift. |
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HW@....(Henri Wilson) wrote in
: bz said: ..... In addition to the above Earth-based experiments, in 1977 K. Brecher used radiation from pulsars (rotating neutron stars which emit radiation in a periodic manner) to show that the speed of light was independent of the motion of the source.15 Neither Brecher's experiment nor the ones mentioned in the preceding paragraph were subject to Fox's criticism. Hence, observations of both terrestrial and extra-terrestrial phenomena have shown once and for all that Ritz's hypothesis is invalid. .... [unquote] Yes. We know all about these exeriments and their wrong conclusions. Then, when you said Bob, the only so called evidence AGAINST the BaTh was De Sitter's work. you were not being candid. -- bz please pardon my infinite ignorance, the set-of-things-I-do-not-know is an infinite set. remove ch100-5 to avoid spam trap |
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On 23 Feb 2007 13:14:05 -0800, "Leonard Kellogg" wrote:
Henri Wilson wrote: No you've got it all wrong George. The BLUE curve is the actual one. Several conflicting descriptions of the red and blue curves have been given. Could you state definitively what each curve represents? Yes. George is totally confused...(isn't every relativist?) The blue curve is the true velocity of the source wrt the observer. The red one is the velocity curve that a distant observer would calculate as true using doppler shift measured with a grating. How wrong can one be? Leonard "When a true genius appears in the world, you may know him by this sign, that the dunces are all in confederacy against him." --Jonathan Swift. |
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![]() "Henri Wilson" HW@.... wrote in message ... On 23 Feb 2007 13:14:05 -0800, "Leonard Kellogg" wrote: Henri Wilson wrote: No you've got it all wrong George. The BLUE curve is the actual one. Several conflicting descriptions of the red and blue curves have been given. Could you state definitively what each curve represents? Yes. George is totally confused...(isn't every relativist?) The blue curve is the true velocity of the source wrt the observer. Exactly the way I used it every time except once. What's your problem Henry, you can't cope with the physics so you have to go to town on a typo? The red one is the velocity curve that a distant observer would calculate as true using doppler shift measured with a grating. That it what it is supposed to be but Henry has an error in his calculation at the moment. How wrong can one be? Your program is out by a factor of about 11000 for the test case we tried. George |
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![]() "Henri Wilson" HW@.... wrote in message ... On 23 Feb 2007 02:48:36 -0800, "George Dishman" wrote: On 23 Feb, 09:39, HW@....(Henri Wilson) wrote: On Thu, 22 Feb 2007 23:59:59 -0000, "George Dishman" wrote: "Henri Wilson" HW@.... wrote in message .. . On Thu, 22 Feb 2007 10:17:35 -0000, "George Dishman" .... I can print out the values if you like. Just the value at the peak. The purpose is to allow the parameters to be adjusted until this value reads 27km/s so we know when we have a match. I told you that the red curve is an average speed of the light that arrives in a set time interval. I htink you can imagine the effect bunching has on that. I don't want to imagine, I want the computer to do that for me. .....Explained in my other message. I'm not sure which message you are referring to, I haven't seen one saying anything about showing that numerical value on the screen but maybe I missed it. .... The normal Doppler is there of course, I haven't disputed that, but it isn't the whole story. The pulse spacing is also affected by what I describe above and you need to take that into account AS WELL to get the full answer. The program takes everything into account. Why don't you experiment with it? I have, it gives the wrong value because you only take the bunching due to c+v vs c-v into account on the brightness curve, not the velocity curve. The predicted velocity is derived from the time between pulses so you need to take into account there too. Ah, I think I know what you are saying now. Yes you do vbg!! Put it in your diary, it has taken weeks for you to see this but the penny has at last dropped :-) You are claiming that the closer the bunching, the shorter the wavelength...and the higher the observed doppler shift. Yes Henry. The frequency is the pulse repetition rate which is what is used to determine the speed, so the "wavelength" is the distance between consecutive pulses. Yes that should be true for the pulsar...but it is not true in my program..... Right, that's the program error I have been describing to you all these weeks :-) At least now you know what the problem is. So what is the difference? The difference is that it is the change in the actual width of the pulsar pulses in each bunch that is analogous to what my program does. Do you see what I mean? In reality, the width of the pulsar pulses varies by the same doppler fraction as does the distance between pulses. (~90 parts per million) Correct, the pulse width is about 1.5% of the period and that factor remains constant as the pulses travel. So you have to average the WIDTHS of pulses and NOT their spacing to generate your equivalent of my red curve. As you say, the width varies by the same fraction as the gap so it doesn't matter whether you take the ratio of the observed width to mean width or of the observed gap to the mean gap, they should give the same apparent speed. If that was your intention it should have worked but the curve on the screen doesn't tie up with that and I suspect if you showed the numerical value of the peak it would be too low. That's why I have been saying there is a bug in your software. The bunching itself is an indicator of brightness variation. Yes, but it also affects the _apparent_ Doppler shift so affects the apparent speed as well, that's the speed calculated by astronomers which is based only on the PRF and which you show as the red curve. I'm becoming a bit confused as to what we are actually talking about now. At any point arond the orbit, pulses are being sent with a time gap of 2.95 ms. That gap is reduced at the receiver for two reasons: a) the velocity of the pulsar towards the receiver means that consecutive pulses travel different distances. That is the normal Doppler effect. b) if the pulses are transmitted at different speeds then faster pulses can 'catch up' to slower ones reducing the gap (or 'fall behind' if the second pulse is slower increasing the gap) and hence the time between reception depends on how much of this effect happens before extinction equalises the speeds. This effect is not taken into account in published velocity curves so the published values will be higher or lower than the simple Doppler value. That effect is not indicative of source velocity. Correct, but it does affect the velocity which an astronomer would calculate from the pulse timing. Remember you already have " The blue curve is the true velocity of the source wrt the observer." so we are here talking about " The red one is the velocity curve that a distant observer would calculate as true using doppler shift ...". Those quotes are from your other post. It is the latter curve calculated from the pulse rate that I have been telling you is wrong. Now you understand why. Part (a) is dependent on the radial component of velocity at the time of transmission, part (b) depends on the acceleration at the same time and of course both vary round the orbit. Your program includes effect (a) but not effect (b). You'll have to rethink this in light of what I have said. I don't need to rethink, you have now understood and stated the problem. What you need to do now is make the program produce the correct red curve and preferably show the peak velocity value as text like your min/max brightness. George |
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