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(william mook) wrote in message . com...
1.56 GW of light when reflected fully produces 1 kgf of thrust. So, 500,000 metric tons of thrust requires 780 TW. Call it one quadrillion watts. The sun produces 386 billion Q-Watts. So, by capturing all of the sun's output and delivering 12% of it reliably anywhere across 100 ly would be sufficient to accelerate 40 billion ships each 500,000 tons in mass per year. This is sufficient to power self-propelled space colonies near light speed for every family or individual on the planet. By structuring materials on the nanometer scale it is possible to make highly reflective films as described here; http://www.3m.com/about3M/technologi...olutions.jhtml http://www.photonics.com/spectra/tec...77/QX/read.htm These films are 99.9% reflective and are made of plastic. Films made of ceramics, carbon layers, or vapor deposited layers of metal like tungsten, can be equally reflective and thin and withstand high temperatures. A square meter of film that absorbs 0.1% of the light that falls on it will need to dissapate heat at 1/1000th the rate of a film that absorbs all the light that falls on it. The materials of the shell that I described earlier in this thread could absorb and re-radiate energy at about 10 MW per square meter. Multiply this by 2,000 - which involves radiation from both sides of a hot film and a factor of 1,000 because 99.9% of the energy is reflected, and you end up with 20 GW per square meter of reflected radiation to sustain this level of radiation into the vacuum. At these power levels 'thrust films' would produce around 10 kgf per square meter. At 10 grams per square meter a film by itself if illuminated at 20 GW per square meter would undergo accelerations of 1,000 gees! This is sufficient to accelerate to nearly light speed in 8 hours. Of course as speeds increase doppler shifts reduce thrust levels. Practical speed limits are about 1/3rd light speed. So, at 1,000 gees a film by itself would take less than 3 hours to accelerate to light speed. Of course, a structured film could be fired at another structured film for a new sort of accelerator. One involving significant mass as well as significant energy. Back to the more mundane uses of such a high powered film, consider a 500,000 ton spacecraft would require 50 square kilometers of laser light sail to accelerate at 1 gee. This is a sail about 8 km in diameter. A 100 ton spacecraft - something the size of the space shuttle - would require only 10,000 square meters of film to accelerate at 1 gee. A disk 120 meters across. It takes about a year at 1 gee to get to light speed. About 4 months to get to 1/3rd light speed at 1 gee. It is the nature of dichroic film to become more reflective the more layers one uses. This has diminishing returns though as things get thicker. Even so, it may be feasible to make films that are 1,000 times more reflective than considered here. If such super reflective films become possible this increases the energy one may handle with a film by 1,000 times. That's 10 tons per square meter, and 20 TW per square meter. At these super illumination levels it would take a film only 50,000 square meters to lift a super tanker and only 10 square meters to lift the space shuttle. What this means is that the films can pretty much be the outer skin of the spacecraft - avoiding the need to handle sails of the stuff to produce thrust. A disk shaped craft with super reflective skin, with perhaps deployable super reflective fins for guidance and boosted acceleration. The super-tanker sized vehicles would enjoy constant acceleration during boost phases of flight and might be spun to produce gravity forces during coast phases of flight. |
#13
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(william mook) writes:
(Alex Terrell) wrote in message . com... (william mook) wrote in message . com... (Alex Terrell) wrote in message . com... You would also heat up the sun, which would increase the rate of the fusion, which would heat up the sun, which could go Nova. Really? Consider, two spherical surfaces one nested inside the other sharing a common center. One is 800,000 kilometers across (the surface of the sun) another 2,000,000 kilometers across (the surface of the power shell). Now, if the temperatures of each of the surfaces are such that the amount of energy radiated from a sphere 2 million kilometers across is equal to the amount of energy radiated from a sphere 800,000 kilometers across - there is no opportunity for energy to accumulate in the sun, increasing rate of fusion presumably. You are correct in the steady state. However, you are effectively increasing the insulation of the sun. Therefore, to emit the same amount of radiation, it needs to be hotter. How much hotter? This is easy to compute. First figure out how much energy gets back to the solar surface. Then figure what the new stable temperature of the solar surface must be in order to handle this increased heat load. The first is a simple matter of geometry. Examine a point on the surface of the larger shell and sum over all points on the shell. Find that about 4% of the energy in the outer shell will indeed find its way back to the smaller sphere of the sun - worst case. Clever engineering can get around this. But let's not argue that point. Lets look at worst case and see if your concerns are valid. The second is a simple application of Stephan's law. Since energy radiated from a black body grows at a rate equal to the fourth power of the temperature, we merely take the quartic root of 1.04 to see that the temperature of a jacketed solar surface is less than 1% higher than the unjacketed solar surface. So, the temperature would rise from 5,770K to 5,827.7K I'm sorry, but stars don't work that way. Gravitationally bound bodies such as stars exhibit the rather peculiar property of "negative heat capacity" --- see http://www.arxiv.org/abs/cond-mat/9812172. Slow down the rate at which heat escapes from a star (effectively increasing the opacity of its atmosphere), and it _EXPANDS AND GETS BRIGHTER AND REDDER_. (The same thing happens if one compares high-metallicity stars to low-metallicity stars of the same mass: The higher opacity resulting from the higher fraction of "metals" causes the high-metallicity star to be larger, redder, and more luminous. The same thing is happening to the Sun: As it gets older and more hydrogen gets converted to helium, it gets brighter, fatter, and redder.) What you need to compute is instead how much more _area_ the Sun will need to dispose of the increased heat flux at the lower equilibrium temperature induced by the increase in the effective opacity of its atmosphere. -- Gordon D. Pusch perl -e '$_ = \n"; s/NO\.//; s/SPAM\.//; print;' |
#14
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An impressive use of numbers. Thank you for your time and brain.
You appear to be broadly correct, though I think I see one small error (william mook) wrote in message . com... Another way of looking at it: The spehere will reflect / reemit a proportion (50%) of the energy it receives in the direction of the sun. Not quite. A point on a shell operating as a black body radiator will emit energy in all directions. It is true that slightly more than half its energy outward and slightly less than half its energy inward. The half that is emitted outward will not heat the sun. The half that is emitted inward will be radiated in all directions from that point. Only a small range of angles will intercept the solar surface and send energy back to the sun. Yes, but the rest will go the shell, 50% to be emitted again towards the inside. A point at a radius of 1 million kilometers from the center of the sun will see the solar surface subtend about 43.6 degrees. This is about 4% of the sky that the point at 1 million kilometers sees. So, about 4% of the isotropic radiation radiated from each point will find its way back to the sun. Assuming of course that the radiators are not engineered to shadow the sun. But 96% goes to the shell, and 48% is reemitted. Assuming your 4% is correct, the radiation back to sun would be 4% / (1-i) where i is the proportion reflected/reemitted back inwards. For a black body shell, i=50%, so 8% ends up on the sun's surface. (A perfect, mirror would give i=1, and would give some interesting effects). That has the effect of increasing the heat generated by the sun by more than 50%. The surface temperature of the sun inside such a shell may rise in temperature sufficient to dump this extra 4% of energy into space - assuming each point radiates in all directions. This temperature to achieve this may be computed by Stephan's Law; P = sigma * T^4 = 5.67e-8 W/m2/K4 * T^4 where T is in kelvins. The sun's surface temperature is 5,770 K. An increase of 4% of power output from the sun would require the surface temperature rise by 1.04^(1/4) = 1.00985 or a little less than 1%. 1.08^(1/4) = a little less than 2% That is, the surface temperature of the sun worst case would increase by less than 58 C - from 5,770 K to 5,828 K. The core temperature which operates in the tens of millions of degrees would, once steady state was achieved in 10,000 years - would rise by the same 58 C - from say twenty million to twenty million and 58. Kinetic energy scales as the square of temperature so this one part in a million rise would cause a one part in a trillion rise in kinetic energy and result in one part in a trillion rise in reaction rates - worst case. This is not sufficient energy to maintain the higher temperature so it is not sufficient to cause a runaway heating effect as you suggest. Therefore there is no runaway rise. seems the sun is pretty stable. But this begs an interesting question. Could one increase the rate of fusion? (Nova's are something quite different see http://observe.arc.nasa.gov/nasa/spa...rdeath_4a.html ) This would brighten the star and increase total output of the sun. Which could be interesting if more energy is needed. Could this be done? I don't know. It does seem that if we have a sphere made of reflectors that return energy to the sun, then the sun would heat up. This is likely to result in an increase in the solar wind. Which could be interesting. The solar wind might be harvested for raw materials like hydrogen, helium, and other elements it contains. But since it takes on the order of 10,000 years for energy to move from deep inside the sun to the surface, it is likely to take equally long for surface changes to affect deep processes like rate of fusion (if it affects it at all!) But it would be cool to be able to control illumination levels on each of the planets while independently controlling stellar output over some range. But, I'm not smart enough to figure out right now if this will indeed happen. Maybe a solar astronomer can give us a clue. One thing is for certain. Theconditions are not right for a nova. What proportion would you need to reflect back to do so? It would shorten the life of the sun, but that life span is fantastically long to start out with. |
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