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On Mon, 02 May 2011 18:48:38 -0700, "W. eWatson"
wrote: On 5/2/2011 2:28 PM, Steve Willner wrote: In , "W. writes: My xy plane is in the plane of the equator, and its projection into the sky represents the celestial equator. Declination is measured +/- from the celestial equator to each pole along great circle lines that pass through each pole. Somewhere on the celestial equator is point from where RA is measured. To go from RA/Dec to an x,y,z unit vector is just simple trignometry: x = cos(dec)*cos(RA) y = cos(dec)*sin(RA) z = sin (dec) Make sure to convert RA/dec to degrees or radians (whatever units your calculator or program uses). It's easy to forget to multiply hours by 15 to get degrees. The zero point of RA is the place where the ecliptic and celestial equator intersect with the equinox heading north. Both this zero point and the location of the celestial poles changes with respect to the stars because of precession. If you want a _current_ x,y,z unit vector, you need to start from current RA/Dec coordinates rather than coordinates at a standard "ecliptic and equinox" (B1950 or J2000). The Meeus book will tell you how to do that calculation. Ah, the obliquity of the ecliptic (e) is what I need. Don't see why you need that. Did you mean ecliptic coordinates rather than celestial? Whoops, I posed the question backwards. I have the x,y,z coordinates of a vector and I want to convert them to ra/dec. In a unit sphere I think of z as pointing through the north pole, x pointing south through 1,0,0, and y pointing east through 0,1,0. In my case, precession does not enter into matters. I'm constructing a simulation that is mostly grounded in az/el and lat/lng. I wrote a program that produces the path of a fake meteor moving in a straight line. Time is not yet useful as a consideration yet. The direction of the line points to the radiant point in the sky. Meteors lie on a great circle, hence pass their plane passes through the earth's center (spherical earth). My program has not yet needed ra/dec, which is usually the measure of the radiant point in the sky and is given in ra/dec. However,I have the data from a similar program, and they provide the radiant as ra/dec. internally, my program seems sound when I sort of run it backwards. I get agreeable results. I want to see if the independent source and I agree. See if this explanation regarding nomenclature will help clarify things and perhaps bring an end to the random and inexplicable outbursts of vituperation. You have written a program that simply calculates the path of a meteor in XYZ coordinates whose origin is in the equatorial plane. From the XYZ coordinates you want to calculate the pitch and yaw or elevation and azimuth as measured on an equatorial mount that would point at the meteor. You apparently raised the hackles of purists by using the terms right ascension and declination which have specific astronomical meaning and are measured from the point of Aries if I recall correctly, and therefore has no place in your problem. I think you will find that the equations I gave you will give you the correct result. John Polasek |
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Thread | Thread Starter | Forum | Replies | Last Post |
Converting RA/Dec to earth centered coordinates? | William Hamblen[_2_] | Astronomy Misc | 1 | May 3rd 11 02:49 AM |
Converting star coordinates to x,y,z | [email protected] | UK Astronomy | 4 | December 11th 04 10:28 PM |
converting star coordinates to x,y,z | [email protected] | Amateur Astronomy | 28 | December 10th 04 05:45 PM |
converting star coordinates to x,y,z | [email protected] | Astronomy Misc | 3 | December 9th 04 07:34 PM |
converting coordinates | J. Jason Fry | Amateur Astronomy | 8 | May 31st 04 06:27 PM |