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On Oct 1, 6:04*pm, Tom Roberts wrote in
sci.physics.relativity: But yes, just outside the horizon, if one fired a bullet outward at 0.999 c or so, it would slow down and essentially halt at distance infinity. But a light beam emitted outward there would not slow down (as measured locally, anywhere along its trajectory); it would be greatly redshifted, however. Honest Roberts do you really believe that nobody knows what "would not slow down as measured locally" means? Will the bullet slow down as measured locally? You just know no limits, Honest Roberts. |
#12
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![]() On 2-Oct-2009, Pentcho Valev wrote: Honest Roberts do you really believe that nobody knows what "would not slow down as measured locally" means? Will the bullet slow down as measured locally? You just know no limits, Honest Roberts. People talk about spagettification if one got near to a black hole... That is really crap because it neglects the gyroscopy of the object approaching the black hole... There has to be a gateway to the center... You can't fall to the center of the earth and stand at the center of the earth but it is still possible to stand at the center of the earth by following the torroidal magnetic lines that lead to the center. -- Tell it to the Marines. |
#13
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Dear eric gisse
On Oct 1, 4:37*pm, eric gisse wrote: dlzc wrote: [...] You hyperboilically fly around a black hole within (I believe) 3M and Last stable orbit. No. With the event horizon at 2M (as previously described in this thread), the closest possible stable orbit for matter is 6M. Arbitrary acceleration can let you get arbitrarily close to r = 2M. You mangled the original newsgroup listing, so Tom's excellent and thorough response did not make it on the sci.astro branch of this thread. Please be careful how you apply Occam's razor here... David A. Smith |
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Dear Tom Roberts:
original newsgroup list corrected On Oct 1, 9:53*pm, Tom Roberts wrote: N:dlzcD:aol T:com (dlzc) wrote: "eric gisse" wrote in message ... dlzcwrote: You hyperboilically fly around a black hole within (I believe) 3M and Last stable orbit. Photon sphere is 3M. *Last stable orbit for matter is 6M. * * * [This is all for a Schwarzschild black hole. r is the usual Schw. coordinate.] There is an unstable circular null geodesic at r=3M that orbits the black hole, which might be what you are trying to say, but "photon sphere" does not mean that to me. The typical definition is an "Einstein ring" with an infinite number of "laps". http://en.wikipedia.org/wiki/Photon_sphere What I would call the "photon sphere" is right at the horizon, r=2M -- that is, outgoing light at the horizon remains at the horizon (an unstable situation). Einstein rings and your "salmon swimming upstream" are both unstable, for a structure that will continue to add or expell contents. The smallest stable timelike orbit is indeed at r=6M, and I'm pretty sure it is true that if an ORBIT goes inside r=6M it will destabilize and fall in or fly away. Yes, Eric just was thinking "Schwarzchild radii" rather than tying it to mass directly, and I was hoping to unconfuse the issue with the OP. But there are hyperbolic-like timelike trajectories that come in from far away, approach between r=3M and r=6M, and then leave; these are not orbits, and none come closer than r=3M. It is also true that any timelike or null geodesic that comes from far away and gets below r=3M will enter the horizon (in some cases it can circle the horizon several times before entering). But light that is headed outward and emitted by a timelike object from 2Mr3M will get away; that's different from light coming in from far away. Arbitrary acceleration can let you get arbitrarily close to r = 2M. If you choose a different coordinate system. *This leaves you still 1M out from the event horizon. Not really. The horizon is at r=2M. Coordinate choice has nothing whatsoever to do with the locus of the horizon or the location a given spaceship is able to hover outside it with a given thrust [#]. With arbitrarily-high thrust, a spaceship could hover arbitrarily close to the horizon at r=2M. This is an unstable situation if its r is close to 2M. * * * [#] Coordinate choice only affects your DESCRIPTION, not the physical situation. "A miss is as good as a mile." Eric was selling r_S as 1M. It is off by a factor of 2. And coordinate choice clarity is necessary: http://en.wikipedia.org/wiki/Mars_Climate_Orbiter http://casa.colorado.edu/~ajsh/orbit.html Hmmm. This page says "The orbit at 2 Schwarzschild radii corresponds to zero kinetic energy at infinity, so it is possible to fall freely into this orbit from infinity without rocket power." -- this is wrong, and it is NOT possible to enter an orbit at ANY radius without thrusting, when one starts from infinity and is free-falling [@]. Here by "orbit" I mean a trajectory with a permanent spatial path circling the black hole. * * This is easy to see, as the spatial path of any timelike geodesic can be traversed in the opposite direction, within the region outside the horizon -- an incoming * * trajectory that falls into into an orbit, when reversed, would mean it is not an orbit. An elegant argument. * * *[@] And gravitational radiation is neglected, as for test particles like rocket ships compared to stars. Tom Roberts Thank you. David A. Smith |
#16
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bz wrote:
wrote in news:ha2lvp$f4d$1 @skeeter.ucdavis.edu: If she now sticks her hand toward the horizon, she's in trouble. Her hand needs a huge acceleration to remain at rest, but it doesn't have a rocket attached; it's accelerating only because it's connected to the rest of her body, which presumably is in her spacecraft. Bones aren't strong enough to transmit a near-infinite acceleration; nothing is. What if the black hole were the size and mass of our universe? Who do you think might stick her hand into an infinite universe? ![]() Bernhard |
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Bernhard Kuemel wrote in news:4765c$4ac657af$557f726a
: bz wrote: wrote in news:ha2lvp$f4d$1 @skeeter.ucdavis.edu: If she now sticks her hand toward the horizon, she's in trouble. Her hand needs a huge acceleration to remain at rest, but it doesn't have a rocket attached; it's accelerating only because it's connected to the rest of her body, which presumably is in her spacecraft. Bones aren't strong enough to transmit a near-infinite acceleration; nothing is. What if the black hole were the size and mass of our universe? Who do you think might stick her hand into an infinite universe? ![]() Someone that was outside it. There is no way to prove that it is infinite. If I remember correctly, "someone" has calculated that the amount of matter is "close" to the amount that would be needed for a black hole the size of the known universe. Perhaps we live inside a black hole. http://www.mathpages.com/home/kmath339.htm Bernhard -- bz please pardon my infinite ignorance, the set-of-things-I-do-not-know is an infinite set. |
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bz wrote:
Bernhard Kuemel wrote in news:4765c$4ac657af$557f726a : bz wrote: wrote in news:ha2lvp$f4d$1 @skeeter.ucdavis.edu: If she now sticks her hand toward the horizon, she's in trouble. Her hand needs a huge acceleration to remain at rest, but it doesn't have a rocket attached; it's accelerating only because it's connected to the rest of her body, which presumably is in her spacecraft. Bones aren't strong enough to transmit a near-infinite acceleration; nothing is. What if the black hole were the size and mass of our universe? Who do you think might stick her hand into an infinite universe? ![]() Someone that was outside it. There is no way to prove that it is infinite. If I remember correctly, "someone" has calculated that the amount of matter is "close" to the amount that would be needed for a black hole the size of the known universe. Perhaps we live inside a black hole. Which direction is the singularity? http://www.mathpages.com/home/kmath339.htm Bernhard |
#19
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Can you say despagettification? I spagettify and despagettify every time I
enter or leave my apartment complex but then again what the hell do I know, I'm just a schizo. I may be Islam's pi ion but I hopefully have my own pi ion... or pi ions looking out for my interests without my giving direction. Nod means no, shake your head means yes, mutiny is not an option. -- Tell it to the Marines. |
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