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In message , ralph sansbury
writes RS The confusion is in the inadequate concept. The rest mass of a photon is zero, its mass in motion due to the relativity increase is infinity so (1/2)mv^2 =(1/2)mc^4 =infinity times c^4 but also hf where f is the frequency is equal to the kinetic energy of the moving photon (1/2)mv^2. This says that infinity is equal to a finite number. Because of such confusion in the concept I am questioning conclusions like you're here based on its use. Re a solar sail, this involves much stronger magnetic forces than the absorption of radiation by a distant spacecraft antenna. GD I'm not aware of any magnetic effect on solar sails. RS I am aware of the light momentum photon energy argument "that when light is emitted from a source there is a recoil effect". But I am suggesting that there is no evidence for cases like the 8Watt transmitter on a distant spacecraft and that solar sails involve much greater Wattage and that light pressure on mirrors etc involve oscillations in the source and the receiver/reflector acting on each other. That is the mechanism(see Feynman Lectures p34-10), Bvq, on oscillating charge moving up and down at velocity v in the direction of the propagation of the fields E and B causes a driving pressure in the direction of the light beam which is called light pressure. Do you know any evidence besides the blanket application of the momentum argument showing such pressure effects in cases where the emission of photons occurs in an isolated source like the spacecraft? Ralph I thought your thesis was that there is no velocity? As I'm sure you're well aware, the only way to measure the light pressure from an 8 watt spacecraft transmitter is to look very accurately at its motion, and then disentangle light pressure from the other forces on it. That's being done for the "Pioneer anomalous acceleration", for instance. What does the available power, or even the power density, have to do with it anyway? But light pressure is routinely being used in laboratories. Look at MECHANICAL ACTION OF LIGHT ON ATOMS http://www.wspc.com/books/physics/0585.html Laser Manipulation of Atoms http://tycho.usno.navy.mil/clockdev/slowing.htm for instance. -- Rabbit arithmetic - 1 plus 1 equals 10 Remove spam and invalid from address to reply. |
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![]() "ralph sansbury" wrote in message ... "George Dishman" wrote in message ... "ralph sansbury" wrote in message ... RS Baez FAQ says that some people want to change the notation of E^2=(m_0)^2c^4+p^2c^2 where p=mv=Ev/c^2. Even in the more recent texts the distinction between rest mass and the mass increase due to relativity of a mass in motion is made in the description of the formula if not in the notation. This is part of what it says: "These days, when physicists talk about mass in their research, they always mean invariant mass. The symbol m for invariant mass is used without the subscript 0. Although the idea of relativistic mass is not wrong, it often leads to confusion, .... Using the word "mass" unqualified to mean relativistic mass is wrong because the word on its own will usually be taken to mean invariant mass." I am over 50 and have never known "mass" to mean anything but invariant mass. I am aware of the old "relativistic mass" but have alwys known it as a shorthand notation representing m_r = m / sqrt(1 - (v/c)^2) GD It is not a split but a change. It will take a long time for old ways to die out but there is no debate about it. As the FAQ pages say, one of the reasons the term "relativistic mass" is being dropped is because of these confusions that it creates. RS The confusion is in the inadequate concept. The rest mass of a photon is zero, its mass in motion due to the relativity increase is infinity so (1/2)mv^2 =(1/2)mc^4 =infinity times c^4 but also hf where f is the frequency is equal to the kinetic energy of the moving photon (1/2)mv^2. This says that infinity is equal to a finite number. Because of such confusion in the concept I am questioning conclusions like you're here based on its use. Now try it the conventional way: The mass of the photon is zero. If it could be at rest the mass would be zero. When it is moving it is zero. The mass of any particle is the same whether it is moving or not. When a particle is moving, its total energy is the sum of its mass (times c^2) and its kinetic energy. There you are, no confusion at all. Re a solar sail, this involves much stronger magnetic forces than the absorption of radiation by a distant spacecraft antenna. GD I'm not aware of any magnetic effect on solar sails. RS I am aware of the light momentum photon energy argument "that when light is emitted from a source there is a recoil effect". Right, and the evidence for this is the Compton Effect and laser manipulation of particles at small scales, lab radiometers at medium scales and solar sails at large scale. All rely on the principle that light carries momentum. But I am suggesting that there is no evidence for cases like the 8Watt transmitter on a distant spacecraft and that solar sails involve much greater Wattage and that light pressure on mirrors etc involve oscillations in the source and the receiver/reflector acting on each other. That is the mechanism(see Feynman Lectures p34-10), Bvq, on oscillating charge moving up and down at velocity v in the direction of the propagation of the fields E and B causes a driving pressure in the direction of the light beam which is called light pressure. None of that suggests that light doesn't carry momentum, it is just a classical description of the mechanism. Do you know any evidence besides the blanket application of the momentum argument showing such pressure effects in cases where the emission of photons occurs in an isolated source like the spacecraft? Pressure is nothing but the transfer of momentum and the examples I have suggested all require momentum transfer. If you want to use classical field theory to describe it, there should be no problem in principle but it might be difficult in practice. I am still not clear what you are looking for. You started this thread by saying: Instances of light pressure on reflective surfaces and Compton like scattering of xrays at lower frequencies with the missing energy transformed into the linear movement of the electron suggests a recoil of the electron but not of the photon. That is incorrect since the relationships in the Compton Effect require both the incoming and outgoing photon to carry momentum. That is your evidence. George |
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![]() "George Dishman" wrote in message ... "ralph sansbury" wrote in message ... "George Dishman" wrote in message ... "ralph sansbury" wrote in message ... RS Baez FAQ says that some people want to change the notation of E^2=(m_0)^2c^4+p^2c^2 where p=mv=Ev/c^2. Even in the more recent texts the distinction between rest mass and the mass increase due to relativity of a mass in motion is made in the description of the formula if not in the notation. This is part of what it says: "These days, when physicists talk about mass in their research, they always mean invariant mass. The symbol m for invariant mass is used without the subscript 0. Although the idea of relativistic mass is not wrong, it often leads to confusion, ... Using the word "mass" unqualified to mean relativistic mass is wrong because the word on its own will usually be taken to mean invariant mass." I am over 50 and have never known "mass" to mean anything but invariant mass. I am aware of the old "relativistic mass" but have alwys known it as a shorthand notation representing m_r = m / sqrt(1 - (v/c)^2) GD It is not a split but a change. It will take a long time for old ways to die out but there is no debate about it. As the FAQ pages say, one of the reasons the term "relativistic mass" is being dropped is because of these confusions that it creates. RS The confusion is in the inadequate concept. The rest mass of a photon is zero, its mass in motion due to the relativity increase is infinity so (1/2)mv^2 =(1/2)mc^4 =infinity times c^4 but also hf where f is the frequency is equal to the kinetic energy of the moving photon (1/2)mv^2. This says that infinity is equal to a finite number. Because of such confusion in the concept I am questioning conclusions like you're here based on its use. Now try it the conventional way: The mass of the photon is zero. If it could be at rest the mass would be zero. When it is moving it is zero. The mass of any particle is the same whether it is moving or not. Yes for the rest mass. But the mass increase according to Einstein is (rest mass)/(1-v^2/c^2)^1/2 for something moving at speed v =c, this implies the mass has increased to infinity. This appears to be what happens to electrons and protons etc in a mass spectrometer moving at speeds of .1c etc and so the mass of a photon at c in this context would be infinite. When a particle is moving, its total energy is the sum of its mass (times c^2) and its kinetic energy But for the photon of frequency f, it is hf which is neither zero or infinity. There you are, no confusion at all. Wrong. Of course you can add other premises and disclaimers but this is just another form of confusion. Re a solar sail, this involves much stronger magnetic forces than the absorption of radiation by a distant spacecraft antenna. GD I'm not aware of any magnetic effect on solar sails. RS I am aware of the light momentum photon energy argument "that when light is emitted from a source there is a recoil effect". Right, and the evidence for this is the Compton Effect and laser manipulation of particles at small scales, lab radiometers at medium scales and solar sails at large scale. All rely on the principle that light carries momentum. But I am suggesting that there is no evidence for cases like the 8Watt transmitter on a distant spacecraft and that solar sails involve much greater Wattage and that light pressure on mirrors etc involve oscillations in the source and the receiver/reflector acting on each other. That is the mechanism(see Feynman Lectures p34-10), Bvq, on oscillating charge moving up and down at velocity v in the direction of the propagation of the fields E and B causes a driving pressure in the direction of the light beam which is called light pressure. None of that suggests that light doesn't carry momentum, it is just a classical description of the mechanism. Imagine an 8W light bulb and the photons emitted by the tungsten filament. What do the oscillations of charge magnetically push against? As you said before, the randomly directed pushes on each other cancel so that there is no net push. Thus it seems there is only the mathematical momentum argument in conjunction with a self contradictory photon as evidence that there is such a push. Not very reliable. |
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![]() "ralph sansbury" writes: Yes for the rest mass. But the mass increase according to Einstein is (rest mass)/(1-v^2/c^2)^1/2 for something moving at speed v =c, this implies the mass has increased to infinity. This appears to be what happens to electrons and protons etc in a mass spectrometer moving at speeds of .1c etc and so the mass of a photon at c in this context would be infinite. For photons, whose rest mass is defined to be zero, the equation above becomes 0/0, or undefined. It does not tend to infinity. Therefore you are not using an appropriate equation. Thus it seems there is only the mathematical momentum argument in conjunction with a self contradictory photon as evidence that there is such a push. Not very reliable. As George pointed out, there are very nice atom trapping experiments that rely on radiation pressure. The papers by Grangier et al and Aspect et al are highly convincing regarding the photon nature of light. CM References 1. Aspect, A. et al 1981, Phys Rev Let, 47, 460 2. Grangier, P., Roger, G. & Aspect, A. 1986, Europhys. Lett., 4, 173 |
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![]() "Craig Markwardt" wrote in message news ![]() "ralph sansbury" writes: Yes for the rest mass. But the mass increase according to Einstein is (rest mass)/(1-v^2/c^2)^1/2 for something moving at speed v =c, this implies the mass has increased to infinity. This appears to be what happens to electrons and protons etc in a mass spectrometer moving at speeds of .1c etc and so the mass of a photon at c in this context would be infinite. For photons, whose rest mass is defined to be zero, the equation above becomes 0/0, or undefined. It does not tend to infinity. Undefined or Contradictory-in either case not very reliable. you have to do arbitrary things to make the concept work. It is obviously a problematic concept shown to be even more problematic by the experiments you refer to and my experiment with Pockkels cell shutters . Therefore you are not using an appropriate equation. The choice of appropriate equation here is somewhat arbitrary and more so than in the application of the magnetic force equation. Thus it seems there is only the mathematical momentum argument in conjunction with a self contradictory photon as evidence that there is such a push. Not very reliable. As George pointed out, there are very nice atom trapping experiments that rely on radiation pressure. I am not quarrelling with these and other facts about radiation pressure but just pointing out that you cant extrapolate from these to the 8watt transmitter or light bulb. The papers by Grangier et al and Aspect et al are highly convincing regarding the photon nature of light. Again irrelevant wrt spacecraft transmitter etc. Ralph References 1. Aspect, A. et al 1981, Phys Rev Let, 47, 460 2. Grangier, P., Roger, G. & Aspect, A. 1986, Europhys. Lett., 4, 173 |
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"ralph sansbury" wrote in message ...
"Craig Markwardt" wrote in message news ![]() "ralph sansbury" writes: Yes for the rest mass. But the mass increase according to Einstein is (rest mass)/(1-v^2/c^2)^1/2 for something moving at speed v =c, this implies the mass has increased to infinity. This appears to be what happens to electrons and protons etc in a mass spectrometer moving at speeds of .1c etc and so the mass of a photon at c in this context would be infinite. For photons, whose rest mass is defined to be zero, the equation above becomes 0/0, or undefined. It does not tend to infinity. I am not a mathematician, but it seems to me that this situation is only occuring when v and c are equal. When vc, if sq root(-1) is allowed, as per the raspberries I received when suggesting non-existent, then there is an (defined) result for the equation Jim G |
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![]() "Jim Greenfield" wrote in message om... "ralph sansbury" wrote in message ... "Craig Markwardt" wrote in message news ![]() "ralph sansbury" writes: Yes for the rest mass. But the mass increase according to Einstein is (rest mass)/(1-v^2/c^2)^1/2 for something moving at speed v =c, this implies the mass has increased to infinity. This appears to be what happens to electrons and protons etc in a mass spectrometer moving at speeds of .1c etc and so the mass of a photon at c in this context would be infinite. For photons, whose rest mass is defined to be zero, the equation above becomes 0/0, or undefined. It does not tend to infinity. I am not a mathematician, but it seems to me that this situation is only occuring when v and c are equal. When vc, if sq root(-1) is allowed, as per the raspberries I received when suggesting non-existent, then there is an (defined) result for the equation Yes and someone called these tachyons(and it is perfectly reasonable to suppose orbiting charged particles at such speeds inside the electron and proton without assuming them to increase to infinite mass and undefinedness as c is approached from above). But to get back to the subject of reasons aside from momentum conservation to expect aspacecraft to be shoved back by the emission of 8Watt,GHz photons from its transmitter. The magnetic force argument would make this possible and this argument it seems to me is more convincing than the photon momentum argument. given the somewhat arbitrary undefined self contradictory nature of the photon. That is the pushing of the oscillating electrons in the center feed wire of a dish antenna against the reflected oscillations in the dish might push against the dish. Now the question is is this enough to explain the anomalous acceleration? |
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![]() "Jim Greenfield" wrote in message om... "ralph sansbury" wrote in message ... "Craig Markwardt" wrote in message news ![]() "ralph sansbury" writes: Yes for the rest mass. But the mass increase according to Einstein is (rest mass)/(1-v^2/c^2)^1/2 for something moving at speed v =c, this implies the mass has increased to infinity. This appears to be what happens to electrons and protons etc in a mass spectrometer moving at speeds of .1c etc and so the mass of a photon at c in this context would be infinite. For photons, whose rest mass is defined to be zero, the equation above becomes 0/0, or undefined. It does not tend to infinity. I am not a mathematician, but it seems to me that this situation is only occuring when v and c are equal. Exactly, v=c for photons so trying to use the old "relativistic mass" approach doesn't work. This is what we are trying to explain to Ralph. When vc, if sq root(-1) is allowed, as per the raspberries I received when suggesting non-existent, then there is an (defined) result for the equation This is just one of the reasons why tachyons are considered to be unlikely in the real world. For some things imaginary values don't seem reasonable, in other cases they can be a useful tool. George |
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![]() "ralph sansbury" wrote in message ... Yes and someone called these tachyons(and it is perfectly reasonable to suppose orbiting charged particles at such speeds inside the electron and proton without assuming them to increase to infinite mass and undefinedness as c is approached from above). The mass of the photon remains zero. The factor called reativistic mass can be useful for massive particles as long as you remain aware of its limitations but is doesn't work for photons as it becomes undefined (not infinite). But to get back to the subject of reasons aside from momentum conservation to expect aspacecraft to be shoved back by the emission of 8Watt,GHz photons from its transmitter. The magnetic force argument would make this possible and this argument it seems to me is more convincing than the photon momentum argument. Since you seem to be saying that both would imply the craft will experience a force, they are not in conflict and no choice is needed. given the somewhat arbitrary undefined self contradictory nature of the photon. You mean the contradictions you invent by using 19th century concept that cannot be applied to massless particles and trying to do just that? That is the pushing of the oscillating electrons in the center feed wire of a dish antenna against the reflected oscillations in the dish might push against the dish. If the craft is pushed by this, how is momentum conserved? For photons, the balancing momentum is simply carried off by the particles. In your description, the eletrons in the feed and the dish are both attached to the craft. Now the question is is this enough to explain the anomalous acceleration? No. The measured acceleration corresponds to 56W of power and is towards the Sun while the beam is 8W and pushes the craft away from the Sun. The anomaly is treated as 63W equivalent since 8W worth of push is used overcoming the beam reaction. George |
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In message , ralph sansbury
writes Yes and someone called these tachyons(and it is perfectly reasonable to suppose orbiting charged particles at such speeds inside the electron and proton without assuming them to increase to infinite mass and undefinedness as c is approached from above). But to get back to the subject of reasons aside from momentum conservation to expect aspacecraft to be shoved back by the emission of 8Watt,GHz photons from its transmitter. The magnetic force argument would make this possible and this argument it seems to me is more convincing than the photon momentum argument. given the somewhat arbitrary undefined self contradictory nature of the photon. That is the pushing of the oscillating electrons in the center feed wire of a dish antenna against the reflected oscillations in the dish might push against the dish. Now the question is is this enough to explain the anomalous acceleration? It can't explain the acceleration because it's acting in the wrong direction. Radiation pressure from the dish (or on the dish from solar radiation) will push the spacecraft away from us, while the "Pioneer effect" acts to slow it down, apparently pushing in the other direction. If your theory can provide the correct acceleration for heat emission from the RTGs people might start listening to you. BTW, "orbiting charged particles" inside the electron would imply it has structure, and AFAIK every observation says it doesn't. -- Rabbit arithmetic - 1 plus 1 equals 10 Remove spam and invalid from address to reply. |
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