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On 8 Jun, 00:18, HW@....(Henri Wilson) wrote:
On Wed, 6 Jun 2007 20:41:44 +0100, "George Dishman" wrote: "Henri Wilson" HW@.... wrote in message news ![]() On Tue, 05 Jun 2007 00:19:01 -0700, George Dishman wrote: On 4 Jun, 22:52, HW@....(Henri Wilson) wrote: It has been modified. I can't dpo any beter without spending a lot more time and it I would prefer you used your imagination.....which you have done below. I think you could have done better with less effort, it still shows the overall sphere moving which is not correct. Yes it is. The big sphere belongs to the larger star and moves with IT. There are two aspects, first consider an alpha particle in the solar wind at the radius of Pluto but far from any of the planets. The motion of the Jupiter slightly changes the gravitational _acceleration_ but not the location or speed directly so from that point of view changes in the sphere are limited to distances from the source star comparable to the radius of its movement round the barycentre. On the other hand, we have detected signals from CMEs running into the termination shock. There is significant random variation from such outbursts. Basically the effect of motion due to that of the source is far less than the noise and showing the outer regions as unmoving would be more accurate. The small sphere is centred around the smaller star. In actual fact the large sphere should have a bump on it..but that's too hard. Only close in. I assume also , the shorter the period, the greater the phase lag between sphere and star. Probabably but it is moot beyond a small region in the centre. If you want to do it properly, you should probably calculate an inverse square for each star and add them at each point and then plot a contour map but that's a lot of effort for little gain. Yes. I have shown the basic principle. That's enough at this stage. It is misleading though, the sphere shouldn't be moving. Did you read what I said in the other thread about using Maxwell's equation to explain this? I didn't but I don't see that it relates to my point, the light can only respond in one way so it must be the combination and showing two separate spheres is misleading. Ah, but you shouldn't assume that light speed is completely determined by the sphere. I have stressed that it is a weak effect, that takes time and distance. It isn't an assumption, we calculated distances of circa a light minute and the sphere is many light hours in radius. (use fixed pitch) -S |a |b b--|---------------------------//--------------------------|---------------*-----------------------Earth -s |a' |b' S and s represent a binary pair of stars, orbiting a barycentre b. At points a and a', which are near the two stars and at rest wrt the baycentre, Maxwell's two constants are measured. The resulting calculation shows light speed to be c+v and c-v respectively wrt the barycentre. (The readings are clearly affected by the movement of the two masses). You get the permeability and permittivity of the material and from that a refractive index. The speed is then c/n relative to the material for both stars. That would transform to the frame of the barycentre in accordance with Fizeau's measurements. It wouldn't be c+v or c-v but a speed that depended primarily on the outward speed of the material wrt the barycentre. I'm not thinking in terms of 'solar wind' any more. I'm suggesting other factors are responsible such as charge. The only charges _are_ the solar wind. I reckon if you measure Maxwell's two factors when moving relative to a star you will not get c for an answer. the closer you ar to it, the greater will be the deviation...just a hunch... You don't get c, you get c/n and yes n it will be greater in the denser material closer to the star. In summary, my concept of EM reference spheres is fully supported and explained by Maxwell's equations. Not true, for a given set of measurements, Maxwell's Equations only give a single value of speed. Ballistic theory requires that, at least initially, light from one star has a different speed from light from the other so ballistic theory is always going to be incompatible with Maxwell's Equations. You didn't read my experiment. I did but it doesn't illustrate the problem so I wrote a similar version that does. What I am saying is that if you perform experiments to measure the permeability and permittivity of space whilst MOVING TOWARDS THE SUN at v, then you would calculate light speed to be c+v. What I am saying is that if you perform experiments to measure the permeability and permittivity of space, you get a single value for each. That tells you the speed of light at that location relative to your instruments. Light from a spacecraft moving towards you at 0.1c and one moving away at 0.1c would both have that speed according to Maxwell but would have different speeds according to ballistic theory. Forget Maxwell's Equations Henry, they are of no use to you. On the contrary. If you had bothered to think about the experiment I described you would understand why. And if you read mine you should see why ballistic theory is incompatible. Your version only has a single light source so doesn't show the problem that Maxwell's Equations give one value for the speed while ballistic theory requires light from different sources to move at different speeds. True. I don't think the solar wind is the main factor in this. I think it could be something to do with electric charge and the capacitance of volumes of space. Space has no charge though, it is only the charged particles, mainly electrons, protons and alpha particles, that cause the deviation from the vacuum value. That's oversimplifying the problem. There is a 'field around every charge. It permeates space. What does that imply? That the absence of charges implies an absence of fields and that the fields move with the charges. In our topic the charges are those in the stellar wind. I don't see your point, I am saying the change to uniform speed is essentially complete before the light leaves the sphere. Are you disagreeing? Yes. I am assuming planets don't have significant 'spheres'. Well they have an atmosphere perhaps but it is of limited extent. Very limited. It wont significantly affect the light from the star. Right, so we can ignore planets and my point stands, the change to uniform speed is essentially complete before the light leaves the sphere of the star. If ony one star is involved, light speed wrt the star's surface generally doesn't change much as it passes through the sphere. It would still leave the sphere at around c wrt the star and c+v wrt Earth. However that wouldn't be true for short periods because the sphere would most likely lag well behind the star. OK, assume the inner regions of the sphere move with the star but the outer regions lag so there is some difference in speed between the star and the outer edge of the sphere. My point is that since the speed equalisation distance is much smaller than the sphere, the light is in equilibrium, essentially moving at c/n as it passes through the sphere and it leaves at c (or c/n) relative to the edge of the sphere, not the star. Two points: We can probably assume the inverse square law applies...so what happesn son the outskirts maty not be very important. We know the distance is short overall. If the equalisation factor varies as inverse square, the equalised speed would be in equilibrium with the material close in but might decouple in the farther regions, but the flow speed becomes relatively constant there (variations due to CMEs and other stellar events are more significant). secondly, we cannot assume refractive index operates as it would in the case of a pure 'matter medium'. We can because refractive index is simply defined as the ratio of the speed to c. No need Henry. Close in it would be complex but the light is always changing to be c/n relative to the part of the sphere it is travelling through so by the time it leaves at the termination shock (or whatever boundary you choose), it is only the last bit that defines the speed entering the ISM. But the spheres aren't homogeneous by any means. Their 'strength' must drop off rapidly with distance for one thing. Sure, they both drop at around inverse square but so what? The light rapidly reaches c/n relative to the mean motion of the mix. As it departs the sphere, its speed approaches c wrt the mix...ie., basically, wrt the star. No, wrt the mix is correct but remember the mix is moving at perhaps 400 km/s relative to the Sun and should be something of that order for other stars too. It might be very slightly different from c due to an 'outer layer' effect....and this could indeed explain certain small differences between BaTh predictions and actual observed brightness curves. Not really, all the light is moving at the same speed so the c+v and c-v difference has been eliminated. You need to study the history of science a bit, (I've written a book on it, will that do?). Maybe you should have learnt the subject before writing the book, physics starts with observations and tries to derive concepts to explain them. that's basically what I said. ...the maths come later... No, _empirical_ maths is how the observations are made into usable tools, concepts follow from the maths. as verification and for technology to follow. Maths is used to model an initial concept and do some quantitative analysis.. Look at the development of quantum theory. It didn't start with the corpusclar theory of light which was conceptual and a dead end, it cam first from observation to which The Rayleigh fitted a simple empirical formula. It didn't attempt to give an explanation, it was just a useful tool. That had the drawback of the ultra-violet catastrophe which Wein solved again by fitting a better curve to the data. Planck solved that and was driven to the idea of quantisation in attempting to resolve the problem at low frequencies. The concept came out of the third iteration of empirical physics. Planck merely fiddled with curves till he found one that fitted. Exactly - the empirical maths came before the concept, and Rayleigh and Wein's maths came before Planck's work. .and these can be quite philosophical ..but it is still physics. I'm a firm believer in models George. They don't have to be mechanical but they will always be physical....because if they aren't already, they will immediately define a new branch of physics. They're nice to have - we all want to understand, but physics isn't about understanding, it is about making accurate predictions. Predictions are indeed important. My program correctly predicts variable star curves, using BaTh. No, you still have your maths wrong. Huygens tells you their direction of motion, your handwaving doesn't so it isn't 'better', in fact it isn't a theory since it doesn't allow you to calculate the direction of the beam while Huygens' method does. Leonard Kellogg agrees with me. I haven't seen his post yet. George |
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It seems this went missing.
"Henri Wilson" HW@.... wrote in message ... On Mon, 4 Jun 2007 22:44:06 +0100, "George Dishman" wrote: "Henri Wilson" HW@.... wrote in message . .. On Mon, 04 Jun 2007 05:45:29 -0700, George Dishman wrote: I don't find it difficult to follow what you are suggesting at all. What the difficulty lies is in explaining to you why it is not possible because that explanation uses Fourier analysis and an understanding of RF that is beyond your experience. For christ's sake George, can uyyou not get it into your head that this is not a purely wave phenomenon. It has nought to do with fourier analysis. Can you not get it into your head that Fourier analysis is based on pure maths and applies to _all_ arbitrary waveforms. It is nothing more than the repeated application of a simple identity. If you are thinking of a monochromatic beam, Why would I be thinking of a monochromatic beam when I clearly said "_all_ arbitrary waveforms"? You said you had used Fourier Transforms but it looks as though you have no idea what they are at all. An FT takes any arbitrary waveform and tells you the amplitudes and phases of a series of sine waves which, if added, reproduce the waveform. In terms of light, it tells you what set of monochromatic beams need to be mixed to create the total. the observed wavelength IS also the individual photon wavelengh. Yes, that is what I have been saying all along and which you denied in the past. If the latter is VDoppler or ADoppler shifted, so is the whole beam. Again, that is what I have been telling you. It doesn't matter if individual photons move wrt others in the beam. That's less clear. Obviously it can only happen in ballistic theory but the effect would be that sometimes overlapping photons add constructively but sometimes destructively. In fact it is quite possibly their random phase distribution that accounts for Huygen's Principle. No, the principle works for an individual photon. Again bear in mind that individual photons are deflecte from a grating at the same angle as the macroscopic waves. The disconnect arises because it seems you cannot understand that the same Doppler formula must apply to sidebands and carrier in a pulsed signal. If those pulses are to travel at c+v as ballistic theory requires then the sine wave components each have to comply with that Doppler formula. Not in my model. Yes in your model, you just don't understand maths well enough to see the unavoidable connection. I understand the maths perfectly well George. I also know that what you are saying is not relevant to my model. It is relevant since it defines how light is observed to behave. The same must be true for any other sine wave, be it a CW RF signal or a monochromatic light source or an individual frequency in a white source. The intrinsic oscillations of incividual photons is independent of their combined effect. Not possible Henry - how do you make a pure sine wave out of components at a different frequency? I'll give you a hint - it isn't possible. Of course it isn't. I never said it was. Yes you did, you said and RF CW signal was actually amplitude modulated white light. The frequencies in white light are many orders higher than RF. Of course the intrinsic frequency of a photon which is part of a sine wave has to be the same as that of the macroscopic wave from the correspondence between the macroscopic intensity and photon impact distributions using a grating and a PM tube, which in turn means individual photons are subject to the same Doppler formula as macroscopic sine waves. this is the part that you insist on getting wrong. Nope, it is bloody obvious that the place on a tube where most photons land is also the place where the signal has its highest intensity. Diffraction angle should be independent of the arrival phases of individual photons. Can you not see the possible link between phase randomicity and reinforcement? I can't see how you think that can explain why each _individual_ photon is diffracted by the angle. What it all means is that photons from an accelerated source _must_ compress by exactly the same ratio as the bunching of the photons that we analysed for the pulsars. Not so George. Yes so Henry. There are two possibilities. If it does as you say then the only way to check is to determine the doppler shift of the white light that makes up each pulse......not easy... Not at all, and this is where you don't know how to use the maths. You can take a monochromatic beam and apply sine wave amplitude modulation. That produces sidebands which can be separated from the carrier by reflecting the modulated beam from a grating. See the papers on terabit WDM for the spectrum showing the sidebands and the specification of a grating designed for this purpose or see if you can find what part Fujitsu or Alcatel used. Each of the three resulting beams is itself monochromatic at fc-fm, fc and fc+fm respectively. Above you said: the observed wavelength IS also the individual photon wavelengh. which is correct, so the photons in the lower sideband all have a frequency of fc-fm. You can confirm that by considering what you would see if you took the extracted sideband of a WDM channel carrying a single sine wave, shone it on an echelle and then turned the brightness down until you saw single photons on a PM tube. Now if you emit that waveform from an accelerated source, your Doppler equation applies to each of the three beams separately. If you then recombine them by the reverse method and detect it with a photodiode, you get back the modulation. The 'bunching' of the waves in the modulation is defined by the Doppler shift formula that was applied to the three monochromatic beams so there is a direct mathematical link between individual photon Doppler and the pulse bunching formula. If you want the sine waves in the modulation to move at c+v, the photons must have the Doppler shift corresponding to the bunching formula so they must be fully compressible. If it does not, then my claim that pulsar velocites are a lot smaller than they appear is correct. We have analysed the pulsars and we derived results from observations. It's one of the few areas where we were able to work through and reach agreement. The mathematical link from considering the effect on sidebands tells us that photon Doppler must be the same as macroscopic bunching formula. That doesn't conflict with any of the observations or experiments and is directly derivable from ballistic theory, it only disagrees with your 'concept' of photon being like springs. All your handwaving about photons being like springs does nothing but indicate that you don't really understand ballistic theory yet and you haven't progressed beyond Sekerin's error. I am obviously way ahead of both YOU and Sekerin. Not if you can't even understand a simple Fourier analysis, you are way behind most undergraduates and every radio designer on the planet. The plain fact is, you can't understand MY model. The plain fact is that I not only understand it but have shown how your handwaving is incompatible with ballistic theory while you can't even follow the link despite numerous explanations. Give some thought to the terabit WDM spectrum and perhaps you will start to follow. At some point I expect you to say "wait a minute, that's impossible" for one specific reason and when you do I'll know you've grasped the implications. In fact that aspect is not only possible but the basis of the technology, but I'm sure you'l argue it can't happen nonetheless. George |
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On Fri, 08 Jun 2007 05:57:23 -0700, George Dishman
wrote: It seems this went missing. "Henri Wilson" HW@.... wrote in message .. . On Mon, 4 Jun 2007 22:44:06 +0100, "George Dishman" Can you not get it into your head that Fourier analysis is based on pure maths and applies to _all_ arbitrary waveforms. It is nothing more than the repeated application of a simple identity. If you are thinking of a monochromatic beam, Why would I be thinking of a monochromatic beam when I clearly said "_all_ arbitrary waveforms"? You said you had used Fourier Transforms but it looks as though you have no idea what they are at all. An FT takes any arbitrary waveform and tells you the amplitudes and phases of a series of sine waves which, if added, reproduce the waveform. In terms of light, it tells you what set of monochromatic beams need to be mixed to create the total. I'm thoroughly aware of what a Fourier series can produce George. It basically says that any periodic function can be expressed as a series of terms containing multiples of the fundamental frequency. Any curve can be broken down into separate single frequency components. However if it is not periodic, then there is no point in trying....because you will get a different answer every time you repeat the experiment. I fail to see any connection between Fourier analysis and my theory of light rays. the observed wavelength IS also the individual photon wavelengh. Yes, that is what I have been saying all along and which you denied in the past. ....not for monochromatic light. If the latter is VDoppler or ADoppler shifted, so is the whole beam. Again, that is what I have been telling you. But George, the bunching effect doesn't have to be in the same proportion. The brightness can change by much more than the wavelength. It doesn't matter if individual photons move wrt others in the beam. That's less clear. Obviously it can only happen in ballistic theory but the effect would be that sometimes overlapping photons add constructively but sometimes destructively. I say this is purely a numbers effect.... Do you thnk there is interference between individual photons making up a beam? In fact it is quite possibly their random phase distribution that accounts for Huygen's Principle. No, the principle works for an individual photon. Again bear in mind that individual photons are deflected from a grating at the same angle as the macroscopic waves. Well, there are many ways that can be interpreted. maths well enough to see the unavoidable connection. I understand the maths perfectly well George. I also know that what you are saying is not relevant to my model. It is relevant since it defines how light is observed to behave. Only in diffraction phenomena.... It doesn't tell us anything about light in transit. Not possible Henry - how do you make a pure sine wave out of components at a different frequency? I'll give you a hint - it isn't possible. Of course it isn't. I never said it was. Yes you did, you said an RF CW signal was actually amplitude modulated white light. The frequencies in white light are many orders higher than RF. I said this COULD BE done. An RF signal can be made by modulating white light. Diffraction angle should be independent of the arrival phases of individual photons. Can you not see the possible link between phase randomicity and reinforcement? I can't see how you think that can explain why each _individual_ photon is diffracted by the angle. Single photons form the same diffraction pattern that a beam of them would. I'm suggesting that a photon's so called 'wave function' is none other than the phase of its 'intrinsic oscillation' at the time of arrival. Use my 'traveling oboe' model again George. Yes so Henry. There are two possibilities. If it does as you say then the only way to check is to determine the doppler shift of the white light that makes up each pulse......not easy... Not at all, and this is where you don't know how to use the maths. You can take a monochromatic beam and apply sine wave amplitude modulation. That produces sidebands which can be separated from the carrier by reflecting the modulated beam from a grating. Just as I said.... YOU said the grating would be sensitive to only the beam wavelength and NOT the modulation wavelength. Have you changed your mind. See the papers on terabit WDM for the spectrum showing the sidebands and the specification of a grating designed for this purpose or see if you can find what part Fujitsu or Alcatel used. Each of the three resulting beams is itself monochromatic at fc-fm, fc and fc+fm respectively. How can you prove that? Above you said: the observed wavelength IS also the individual photon wavelengh. which is correct, so the photons in the lower sideband all have a frequency of fc-fm. That doesn't follow at all. You can confirm that by considering what you would see if you took the extracted sideband of a WDM channel carrying a single sine wave, shone it on an echelle and then turned the brightness down until you saw single photons on a PM tube. Don't speculate on what MIGHT happen George.... Now if you emit that waveform from an accelerated source, your Doppler equation applies to each of the three beams separately. If you then recombine them by the reverse method and detect it with a photodiode, you get back the modulation. The 'bunching' of the waves in the modulation is defined by the Doppler shift formula that was applied to the three monochromatic beams so there is a direct mathematical link between individual photon Doppler and the pulse bunching formula. If you want the sine waves in the modulation to move at c+v, the photons must have the Doppler shift corresponding to the bunching formula so they must be fully compressible. George, this conclusion is based on too many assumptions. I understand what you are saying but I don't accept a word of it. It is pure speculation. However I agree that investigation of side band diffraction might be able to tell us something interesting about the nature of photons. If it does not, then my claim that pulsar velocites are a lot smaller than they appear is correct. We have analysed the pulsars and we derived results from observations. It's one of the few areas where we were able to work through and reach agreement. The mathematical link from considering the effect on sidebands tells us that photon Doppler must be the same as macroscopic bunching formula. George, why do you always jump to outrageous conclusions when other possible explanations are obvious? That doesn't conflict with any of the observations or experiments and is directly derivable from ballistic theory, it only disagrees with your 'concept' of photon being like springs. No, ....you're making it up as you go...and getting deeper and deeper iin strife... All your handwaving about photons being like springs does nothing but indicate that you don't really understand ballistic theory yet and you haven't progressed beyond Sekerin's error. I am obviously way ahead of both YOU and Sekerin. Not if you can't even understand a simple Fourier analysis, you are way behind most undergraduates and every radio designer on the planet. The plain fact is, you can't understand MY model. The plain fact is that I not only understand it but have shown how your handwaving is incompatible with ballistic theory while you can't even follow the link despite numerous explanations. You haven't found the correct link. You are relying totally on classical wave models. Give some thought to the terabit WDM spectrum and perhaps you will start to follow. At some point I expect you to say "wait a minute, that's impossible" for one specific reason and when you do I'll know you've grasped the implications. In fact that aspect is not only possible but the basis of the technology, but I'm sure you'l argue it can't happen nonetheless. I understand this is a relatively new technique. It MAY actually be able to tell us a few things about photon/photon interaction. George www.users.bigpond.com/hewn/index.htm Einstein's Relativity - the greatest HOAX since jesus christ's virgin mother. |
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On Fri, 08 Jun 2007 00:18:44 -0700, George Dishman
wrote: On 8 Jun, 00:18, HW@....(Henri Wilson) wrote: On Wed, 6 Jun 2007 20:41:44 +0100, "George Dishman" wrote: "Henri Wilson" HW@.... wrote in message news ![]() wrote: On 4 Jun, 22:52, HW@....(Henri Wilson) wrote: It has been modified. I can't dpo any beter without spending a lot more time and it I would prefer you used your imagination.....which you have done below. I think you could have done better with less effort, it still shows the overall sphere moving which is not correct. Yes it is. The big sphere belongs to the larger star and moves with IT. There are two aspects, first consider an alpha particle in the solar wind at the radius of Pluto but far from any of the planets. The motion of the Jupiter slightly changes the gravitational _acceleration_ but not the location or speed directly so from that point of view changes in the sphere are limited to distances from the source star comparable to the radius of its movement round the barycentre. On the other hand, we have detected signals from CMEs running into the termination shock. There is significant random variation from such outbursts. Basically the effect of motion due to that of the source is far less than the noise and showing the outer regions as unmoving would be more accurate. George, I would like to dissociate my 'sphere' from the solar wind. There might be a connection but I suspect other factors are far more important. The small sphere is centred around the smaller star. In actual fact the large sphere should have a bump on it..but that's too hard. Only close in. Well let's not be too fussy at this stage. It obviously depends entirely on the relative sizes of the two stars. I assume also , the shorter the period, the greater the phase lag between sphere and star. Probabably but it is moot beyond a small region in the centre. ......depending entirely on relative sizes.... If you want to do it properly, you should probably calculate an inverse square for each star and add them at each point and then plot a contour map but that's a lot of effort for little gain. Yes. I have shown the basic principle. That's enough at this stage. It is misleading though, the sphere shouldn't be moving. Yes it should. Each star's sphere moves with the star. Even in the middle diagram, the sphere should be slightly distorted...but I didn't show that. There will alway be some ADoppler...even though very small in the case of contact binaries. Did you read what I said in the other thread about using Maxwell's equation to explain this? I didn't but I don't see that it relates to my point, the light can only respond in one way so it must be the combination and showing two separate spheres is misleading. Ah, but you shouldn't assume that light speed is completely determined by the sphere. I have stressed that it is a weak effect, that takes time and distance. It isn't an assumption, we calculated distances of circa a light minute and the sphere is many light hours in radius. You can't put a firm figure on the size. It varies from one star to another. (use fixed pitch) -S |a |b b--|---------------------------//--------------------------|---------------*-----------------------Earth -s |a' |b' S and s represent a binary pair of stars, orbiting a barycentre b. At points a and a', which are near the two stars and at rest wrt the baycentre, Maxwell's two constants are measured. The resulting calculation shows light speed to be c+v and c-v respectively wrt the barycentre. (The readings are clearly affected by the movement of the two masses). You get the permeability and permittivity of the material and from that a refractive index. The speed is then c/n relative to the material for both stars. That would transform to the frame of the barycentre in accordance with Fizeau's measurements. It wouldn't be c+v or c-v but a speed that depended primarily on the outward speed of the material wrt the barycentre. I'm not thinking in terms of 'solar wind' any more. I'm suggesting other factors are responsible such as charge. The only charges _are_ the solar wind. .....the whole star can be charged...in which case its relative movement will be detectable...and affect the maxwellian calculation of 'c'. I reckon if you measure Maxwell's two factors when moving relative to a star you will not get c for an answer. the closer you ar to it, the greater will be the deviation...just a hunch... You don't get c, you get c/n and yes n it will be greater in the denser material closer to the star. Ignore n for the moment. In summary, my concept of EM reference spheres is fully supported and explained by Maxwell's equations. Not true, for a given set of measurements, Maxwell's Equations only give a single value of speed. Ballistic theory requires that, at least initially, light from one star has a different speed from light from the other so ballistic theory is always going to be incompatible with Maxwell's Equations. You didn't read my experiment. I did but it doesn't illustrate the problem so I wrote a similar version that does. where? according to ballistic theory. Forget Maxwell's Equations Henry, they are of no use to you. On the contrary. If you had bothered to think about the experiment I described you would understand why. And if you read mine you should see why ballistic theory is incompatible. Your version only has a single light source so doesn't show the problem that Maxwell's Equations give one value for the speed while ballistic theory requires light from different sources to move at different speeds. George, you still haven't understaood my experimnt. Take two stars x kms apart. -v P1 P2 S1 | | | | | x | | | | | S2 | | v- I say that mu and e will have very different values when measured across the line P1 but those differences decreasing with distance (line P2) from the source stars. That's oversimplifying the problem. There is a 'field around every charge. It permeates space. What does that imply? That the absence of charges implies an absence of fields and that the fields move with the charges. In our topic the charges are those in the stellar wind. George, you seem incapable of reasoning properly these days. A bar magnet wrapped in a plastic bag filled with electrons doesn't need any stellar wind to exist... I don't see your point, I am saying the change to uniform speed is essentially complete before the light leaves the sphere. Are you disagreeing? Yes. I am assuming planets don't have significant 'spheres'. Well they have an atmosphere perhaps but it is of limited extent. Very limited. It wont significantly affect the light from the star. Right, so we can ignore planets and my point stands, the change to uniform speed is essentially complete before the light leaves the sphere of the star. Yes, molecular speeds are filtered out and light leaves the sphere at c/n wrt the star and c/n+v wrt the observer. We can assume n approaches 1 at the outskirts of the sphere. ADoppler continues and my Bath brightness curves are vindicated. Two points: We can probably assume the inverse square law applies...so what happesn son the outskirts maty not be very important. We know the distance is short overall. It might not be all that short. If the equalisation factor varies as inverse square, the equalised speed would be in equilibrium with the material close in but might decouple in the farther regions, but the flow speed becomes relatively constant there (variations due to CMEs and other stellar events are more significant). I suppose there could be small phase diffferences and other effects. secondly, we cannot assume refractive index operates as it would in the case of a pure 'matter medium'. We can because refractive index is simply defined as the ratio of the speed to c. Let's assume it is 1 on the outskirts anyway. Sure, they both drop at around inverse square but so what? The light rapidly reaches c/n relative to the mean motion of the mix. As it departs the sphere, its speed approaches c wrt the mix...ie., basically, wrt the star. No, wrt the mix is correct but remember the mix is moving at perhaps 400 km/s relative to the Sun and should be something of that order for other stars too. You 'mix' is not MY mix. It might be very slightly different from c due to an 'outer layer' effect....and this could indeed explain certain small differences between BaTh predictions and actual observed brightness curves. Not really, all the light is moving at the same speed so the c+v and c-v difference has been eliminated. NO. That is the case in the middle diagram. Otherwise, the whole bloody sphere still moves at +/- v wrt the observer. You need to study the history of science a bit, (I've written a book on it, will that do?). Maybe you should have learnt the subject before writing the book, physics starts with observations and tries to derive concepts to explain them. that's basically what I said. ...the maths come later... No, _empirical_ maths is how the observations are made into usable tools, concepts follow from the maths. Concepts can indeed follow the revelation of the maths....maths which already followed concepts derived from previous observations and the creative endeavours of usually a single individual. No amount of conventional teaching will ever turn the eric geeses of this world into useful scientists. Planck merely fiddled with curves till he found one that fitted. Exactly - the empirical maths came before the concept, and Rayleigh and Wein's maths came before Planck's work. That is only one example. What about something like Boyle's Law? In the case of the Bohr atom, the concept clearly came before the maths. The same applies to my BaTh curve simulations. The program was designed to perfom the maths AFTER the concept was fully identified. The results tend to verify the concept... The results USING THE MATHS subsequently bring to light other concepts that can be further modelled and investigateed with more refined maths. They're nice to have - we all want to understand, but physics isn't about understanding, it is about making accurate predictions. Predictions are indeed important. My program correctly predicts variable star curves, using BaTh. No, you still have your maths wrong. It cant be too wrong George if it consistently comes up with the right answers. Huygens tells you their direction of motion, your handwaving doesn't so it isn't 'better', in fact it isn't a theory since it doesn't allow you to calculate the direction of the beam while Huygens' method does. Leonard Kellogg agrees with me. I haven't seen his post yet. George www.users.bigpond.com/hewn/index.htm Einstein's Relativity - the greatest HOAX since jesus christ's virgin mother. |
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![]() "Henri Wilson" HW@.... wrote in message ... On Fri, 08 Jun 2007 05:57:23 -0700, George Dishman wrote: It seems this went missing. "Henri Wilson" HW@.... wrote in message . .. On Mon, 4 Jun 2007 22:44:06 +0100, "George Dishman" Can you not get it into your head that Fourier analysis is based on pure maths and applies to _all_ arbitrary waveforms. It is nothing more than the repeated application of a simple identity. If you are thinking of a monochromatic beam, Why would I be thinking of a monochromatic beam when I clearly said "_all_ arbitrary waveforms"? You said you had used Fourier Transforms but it looks as though you have no idea what they are at all. An FT takes any arbitrary waveform and tells you the amplitudes and phases of a series of sine waves which, if added, reproduce the waveform. In terms of light, it tells you what set of monochromatic beams need to be mixed to create the total. I'm thoroughly aware of what a Fourier series can produce George. Apparently not. It basically says that any periodic function can be expressed as a series of terms containing multiples of the fundamental frequency. The function doesn't need to be periodic, consider the sum of two monochromatic components at 1Hz and sqrt(2) Hz. Any curve can be broken down into separate single frequency components. That's better. However if it is not periodic, then there is no point in trying....because you will get a different answer every time you repeat the experiment. Garbage. I fail to see any connection between Fourier analysis and my theory of light rays. That doesn't surprise me, but I've told you the link many times. Here it is again: Take a monochromatic source and modulate it with a rectangular wave. That produces 'pulses' of the source or equivalently a carrier and sidebands. You can separate the sidebands from the carrier with a grating (c.f. terabit WDM). If the pulses are to travel at c+v, the same Doppler shift must apply to each of the component frequencies as applies to the discrete pulses hence the Doppler equation must be the same as that for the pulsar that we worked out some time ago. the observed wavelength IS also the individual photon wavelengh. Yes, that is what I have been saying all along and which you denied in the past. ...not for monochromatic light. Yes, even for monochromatic light. You started with that and switched to white later. Anyway as yyou said above "Any curve can be broken down into separate single frequency components." so what applies to one applies to the other. If the latter is VDoppler or ADoppler shifted, so is the whole beam. Again, that is what I have been telling you. But George, the bunching effect doesn't have to be in the same proportion. Yes it does Henry - you said you were "thoroughly aware of what a Fourier series can produce" so you should already know that. The brightness can change by much more than the wavelength. It doesn't matter if individual photons move wrt others in the beam. That's less clear. Obviously it can only happen in ballistic theory but the effect would be that sometimes overlapping photons add constructively but sometimes destructively. I say this is purely a numbers effect.... Do you thnk there is interference between individual photons making up a beam? As I say, that's much more complex and since it only applies in ballistic theory, I would have to guess, but consider two photons in a laser beam that partially overlap. If they are moving at slightly different speeds, they will drift between constructive and destructive interference as they propagate until they move far enough to cease to overlap. In fact it is quite possibly their random phase distribution that accounts for Huygen's Principle. No, the principle works for an individual photon. Again bear in mind that individual photons are deflected from a grating at the same angle as the macroscopic waves. Well, there are many ways that can be interpreted. Not really, it is a simple fact that the probability of single photon landing at some point on a screen depends on its frequency (or wavelength). maths well enough to see the unavoidable connection. I understand the maths perfectly well George. I also know that what you are saying is not relevant to my model. It is relevant since it defines how light is observed to behave. Only in diffraction phenomena.... It doesn't tell us anything about light in transit. It tells you the Doppler equation for monochromatic light. Not possible Henry - how do you make a pure sine wave out of components at a different frequency? I'll give you a hint - it isn't possible. Of course it isn't. I never said it was. Yes you did, you said an RF CW signal was actually amplitude modulated white light. The frequencies in white light are many orders higher than RF. I said this COULD BE done. An RF signal can be made by modulating white light. ********. Get your brain in gear Henry, think about the Fourier transform of modulated light and that of a CW signal. Diffraction angle should be independent of the arrival phases of individual photons. Can you not see the possible link between phase randomicity and reinforcement? I can't see how you think that can explain why each _individual_ photon is diffracted by the angle. Single photons form the same diffraction pattern that a beam of them would. Exactly what I said above Henry. You do like to waste time, don't you. I'm suggesting that a photon's so called 'wave function' is none other than the phase of its 'intrinsic oscillation' at the time of arrival. Use my 'traveling oboe' model again George. Yes so Henry. There are two possibilities. If it does as you say then the only way to check is to determine the doppler shift of the white light that makes up each pulse......not easy... Not at all, and this is where you don't know how to use the maths. You can take a monochromatic beam and apply sine wave amplitude modulation. That produces sidebands which can be separated from the carrier by reflecting the modulated beam from a grating. Just as I said.... No, what you said several times was "There are NO sidebands!". Do I need to dig up the quotes? YOU said the grating would be sensitive to only the beam wavelength and NOT the modulation wavelength. Exactly. If you modulate frequency fc with fm, you get three components at fc-fm, fc and fc+fm and when you shine that on a grating you see three reflected lines Have you changed your mind. No, but you have. You previously said there were NO sidebands (your emphasis) and now you agree not only that there _are_ sidebands but they can be separated from the carrier with a grating. See the papers on terabit WDM for the spectrum showing the sidebands and the specification of a grating designed for this purpose or see if you can find what part Fujitsu or Alcatel used. Each of the three resulting beams is itself monochromatic at fc-fm, fc and fc+fm respectively. How can you prove that? I showed you the equation several times and you can see from the links on WDM that the industry uses gratings to confirm the performance of terabit systems by examinimg the sidebands. Above you said: the observed wavelength IS also the individual photon wavelengh. which is correct, so the photons in the lower sideband all have a frequency of fc-fm. That doesn't follow at all. You said above: the observed wavelength IS also the individual photon wavelengh. and later: Single photons form the same diffraction pattern that a beam of them would. so I'm not saying anything you haven't already agreed. You can confirm that by considering what you would see if you took the extracted sideband of a WDM channel carrying a single sine wave, shone it on an echelle and then turned the brightness down until you saw single photons on a PM tube. Don't speculate on what MIGHT happen George.... I don't need to, WDM developers test systems by looking at the spectrum, single photon detection is a common experiment and heterodyning is used for very accurate Doppler measurement including photon counting detectors. It's all done on a regular basis but there's no fuss at they are all just mundane tools. Now if you emit that waveform from an accelerated source, your Doppler equation applies to each of the three beams separately. If you then recombine them by the reverse method and detect it with a photodiode, you get back the modulation. The 'bunching' of the waves in the modulation is defined by the Doppler shift formula that was applied to the three monochromatic beams so there is a direct mathematical link between individual photon Doppler and the pulse bunching formula. If you want the sine waves in the modulation to move at c+v, the photons must have the Doppler shift corresponding to the bunching formula so they must be fully compressible. George, this conclusion is based on too many assumptions. No assumptions, just a series of steps all of which are well known. I understand what you are saying but I don't accept a word of it. It is pure speculation. However I agree that investigation of side band diffraction might be able to tell us something interesting about the nature of photons. Not really, if you modulate a fine line with a clean sine wave, you get three monochromatic lines. Extract any one and it is no different to any other monochromatic source. If it does not, then my claim that pulsar velocites are a lot smaller than they appear is correct. We have analysed the pulsars and we derived results from observations. It's one of the few areas where we were able to work through and reach agreement. The mathematical link from considering the effect on sidebands tells us that photon Doppler must be the same as macroscopic bunching formula. George, why do you always jump to outrageous conclusions when other possible explanations are obvious? Because I studied maths to a level that lets me use it to reach such conclusions while you still think these aspects are unconnected. That doesn't conflict with any of the observations or experiments and is directly derivable from ballistic theory, it only disagrees with your 'concept' of photon being like springs. No, You seen all the maths above, and you claimed you were familiar with Fourier so you shouldn't even need me pointing it out. .... Give some thought to the terabit WDM spectrum and perhaps you will start to follow. At some point I expect you to say "wait a minute, that's impossible" for one specific reason and when you do I'll know you've grasped the implications. In fact that aspect is not only possible but the basis of the technology, but I'm sure you'l argue it can't happen nonetheless. I understand this is a relatively new technique. It is a new application but the techniques fundamentally the same as the earliest telephone trunk connections where many conversations were sent down a single cable using frequency division multiplexing. George |
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![]() "Henri Wilson" HW@.... wrote in message ... On Fri, 08 Jun 2007 00:18:44 -0700, George Dishman wrote: I started writing a reply to this post but had network problems so it's stuck elsewhere. I'll post that tomorrow. Predictions are indeed important. My program correctly predicts variable star curves, using BaTh. You keep telling me that the luminosity of Cepheids is due to ADoppler while the velocity curve is VDoppler so have a look at this page. It is purely illustrative, drawn as graphs in Excel and not real data. I just want you to get the idea. The acceleration is constant for two periods with a raised joining them. The velocity and radius are just the integrals of course: http://www.georgedishman.f2s.com/Hen...lustrative.png Compare that with this: http://www.users.bigpond.com/hewn/stupidjerry.jpg I'm sure you can see that the velocity curve is the same in both, just inverted. You will find the radius curve matches that shown in other Cepheid documents we looked at though I can't find the reference at the moment. Now tell me, does the luminosity curve he http://www.users.bigpond.com/hewn/stupidjerry.jpg match the acceleration (ADoppler) or the velocity (VDoppler) from he http://www.georgedishman.f2s.com/Hen...lustrative.png George |
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On Mon, 11 Jun 2007 19:08:27 +0100, "George Dishman"
wrote: "Henri Wilson" HW@.... wrote in message .. . On Fri, 08 Jun 2007 05:57:23 -0700, George Dishman You said you had used Fourier Transforms but it looks as though you have no idea what they are at all. An FT takes any arbitrary waveform and tells you the amplitudes and phases of a series of sine waves which, if added, reproduce the waveform. In terms of light, it tells you what set of monochromatic beams need to be mixed to create the total. I'm thoroughly aware of what a Fourier series can produce George. Apparently not. It basically says that any periodic function can be expressed as a series of terms containing multiples of the fundamental frequency. The function doesn't need to be periodic, consider the sum of two monochromatic components at 1Hz and sqrt(2) Hz. You're adding two periodic functions. The result is periodic. You can't use an irrational number. Any curve can be broken down into separate single frequency components. That's better. However if it is not periodic, then there is no point in trying....because you will get a different answer every time you repeat the experiment. Garbage. I don't think you understand what 'periodic' means. I fail to see any connection between Fourier analysis and my theory of light rays. That doesn't surprise me, but I've told you the link many times. Here it is again: Take a monochromatic source and modulate it with a rectangular wave. That produces 'pulses' of the source or equivalently a carrier and sidebands. You can separate the sidebands from the carrier with a grating (c.f. terabit WDM). If the pulses are to travel at c+v, the same Doppler shift must apply to each of the component frequencies as applies to the discrete pulses hence the Doppler equation must be the same as that for the pulsar that we worked out some time ago. You're diverging and speculating. Again, that is what I have been telling you. But George, the bunching effect doesn't have to be in the same proportion. Yes it does Henry - you said you were "thoroughly aware of what a Fourier series can produce" so you should already know that. I have described my model George. It works. Individual photons DO NOT have to change in the same way as the bunching pattern....but the phasing is the same. I say this is purely a numbers effect.... Do you thnk there is interference between individual photons making up a beam? As I say, that's much more complex and since it only applies in ballistic theory, I would have to guess, but consider two photons in a laser beam that partially overlap. If they are moving at slightly different speeds, they will drift between constructive and destructive interference as they propagate until they move far enough to cease to overlap. yes we could speculate about such happenings.. No, the principle works for an individual photon. Again bear in mind that individual photons are deflected from a grating at the same angle as the macroscopic waves. Well, there are many ways that can be interpreted. Not really, it is a simple fact that the probability of single photon landing at some point on a screen depends on its frequency (or wavelength). I would like to see a better explanation. Yes you did, you said an RF CW signal was actually amplitude modulated white light. The frequencies in white light are many orders higher than RF. I said this COULD BE done. An RF signal can be made by modulating white light. ********. Get your brain in gear Henry, think about the Fourier transform of modulated light and that of a CW signal. I didn't say it could be detected with a tuned circuit...although I'm not sure it couldn't be at UHF. I said an RF signal could be made. It can be detected optically. Diffraction angle should be independent of the arrival phases of individual photons. Can you not see the possible link between phase randomicity and reinforcement? I can't see how you think that can explain why each _individual_ photon is diffracted by the angle. Single photons form the same diffraction pattern that a beam of them would. Exactly what I said above Henry. You do like to waste time, don't you. Because you claimed this means the bunching pattern must be the same as the individual photon shift. beam from a grating. Just as I said.... No, what you said several times was "There are NO sidebands!". Do I need to dig up the quotes? YOU said the grating would be sensitive to only the beam wavelength and NOT the modulation wavelength. Exactly. If you modulate frequency fc with fm, you get three components at fc-fm, fc and fc+fm and when you shine that on a grating you see three reflected lines Have you changed your mind. No, but you have. You previously said there were NO sidebands (your emphasis) and now you agree not only that there _are_ sidebands but they can be separated from the carrier with a grating. Sometimes I wonder if we're talking about the same things. Each of the three resulting beams is itself monochromatic at fc-fm, fc and fc+fm respectively. How can you prove that? I showed you the equation several times and you can see from the links on WDM that the industry uses gratings to confirm the performance of terabit systems by examinimg the sidebands. Above you said: the observed wavelength IS also the individual photon wavelengh. which is correct, so the photons in the lower sideband all have a frequency of fc-fm. That doesn't follow at all. You said above: the observed wavelength IS also the individual photon wavelengh. and later: Single photons form the same diffraction pattern that a beam of them would. so I'm not saying anything you haven't already agreed. You can confirm that by considering what you would see if you took the extracted sideband of a WDM channel carrying a single sine wave, shone it on an echelle and then turned the brightness down until you saw single photons on a PM tube. Don't speculate on what MIGHT happen George.... I don't need to, WDM developers test systems by looking at the spectrum, single photon detection is a common experiment and heterodyning is used for very accurate Doppler measurement including photon counting detectors. It's all done on a regular basis but there's no fuss at they are all just mundane tools. George, what happens in the lab and in outer space are totally different things. If white light leaves a remote star at c wrt that star, it has no other light to worry about and can bunch together or separate without having to worry about what its individual photons do. Now if you emit that waveform from an accelerated source, your Doppler equation applies to each of the three beams separately. If you then recombine them by the reverse method and detect it with a photodiode, you get back the modulation. The 'bunching' of the waves in the modulation is defined by the Doppler shift formula that was applied to the three monochromatic beams so there is a direct mathematical link between individual photon Doppler and the pulse bunching formula. If you want the sine waves in the modulation to move at c+v, the photons must have the Doppler shift corresponding to the bunching formula so they must be fully compressible. George, this conclusion is based on too many assumptions. No assumptions, just a series of steps all of which are well known. I understand what you are saying but I don't accept a word of it. It is pure speculation. However I agree that investigation of side band diffraction might be able to tell us something interesting about the nature of photons. Not really, if you modulate a fine line with a clean sine wave, you get three monochromatic lines. Extract any one and it is no different to any other monochromatic source. Well this is all very interesting stuff but it is not related to the main discussion. We have analysed the pulsars and we derived results from observations. It's one of the few areas where we were able to work through and reach agreement. The mathematical link from considering the effect on sidebands tells us that photon Doppler must be the same as macroscopic bunching formula. George, why do you always jump to outrageous conclusions when other possible explanations are obvious? Because I studied maths to a level that lets me use it to reach such conclusions while you still think these aspects are unconnected. I have a degree in applied maths George. However I DO tend to avoid maths if I can see the answer anyway. As I said above, we are not in a lab. We are dealing with white light from a remote star... or pair of stars. None of your Fourier analysis or classical wave stuff applies. That doesn't conflict with any of the observations or experiments and is directly derivable from ballistic theory, it only disagrees with your 'concept' of photon being like springs. No, You seen all the maths above, and you claimed you were familiar with Fourier so you shouldn't even need me pointing it out. ... Give some thought to the terabit WDM spectrum and perhaps you will start to follow. At some point I expect you to say "wait a minute, that's impossible" for one specific reason and when you do I'll know you've grasped the implications. In fact that aspect is not only possible but the basis of the technology, but I'm sure you'l argue it can't happen nonetheless. I understand this is a relatively new technique. It is a new application but the techniques fundamentally the same as the earliest telephone trunk connections where many conversations were sent down a single cable using frequency division multiplexing. well it might be one of your pet subjects but it has no relevance to brightness curves that are predicted by BaTh. George www.users.bigpond.com/hewn/index.htm Einstein's Relativity - the greatest HOAX since jesus christ's virgin mother. |
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On Mon, 11 Jun 2007 19:21:00 +0100, "George Dishman"
wrote: "Henri Wilson" HW@.... wrote in message .. . On Fri, 08 Jun 2007 00:18:44 -0700, George Dishman wrote: I started writing a reply to this post but had network problems so it's stuck elsewhere. I'll post that tomorrow. Predictions are indeed important. My program correctly predicts variable star curves, using BaTh. You keep telling me that the luminosity of Cepheids is due to ADoppler while the velocity curve is VDoppler so have a look at this page. I tell you nothing of the sort!!! I tell you both curves are due to ADoppler but the velocity curve does not have the same degree of change. That idea is very simple George. X = Y/K It is purely illustrative, drawn as graphs in Excel and not real data. I just want you to get the idea. The acceleration is constant for two periods with a raised joining them. The velocity and radius are just the integrals of course: http://www.georgedishman.f2s.com/Hen...lustrative.png Compare that with this: http://www.users.bigpond.com/hewn/stupidjerry.jpg I'm sure you can see that the velocity curve is the same in both, just inverted. You will find the radius curve matches that shown in other Cepheid documents we looked at though I can't find the reference at the moment. Now tell me, does the luminosity curve he http://www.users.bigpond.com/hewn/stupidjerry.jpg match the acceleration (ADoppler) or the velocity (VDoppler) from he http://www.georgedishman.f2s.com/Hen...lustrative.png You're not making sense George. What the hell are those three graphs? They aren't cepheid curves. George www.users.bigpond.com/hewn/index.htm Einstein's Relativity - the greatest HOAX since jesus christ's virgin mother. |
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On Jun 12, 1:20 am, HW@....(Henri Wilson) wrote:
On Mon, 11 Jun 2007 19:21:00 +0100, "George Dishman" wrote: It is purely illustrative, drawn as graphs in Excel and not real data. I just want you to get the idea. The acceleration is constant for two periods with a raised joining them. The velocity and radius are just the integrals of course: http://www.georgedishman.f2s.com/Hen...lustrative.png Compare that with this: http://www.users.bigpond.com/hewn/stupidjerry.jpg I'm sure you can see that the velocity curve is the same in both, just inverted. You will find the radius curve matches that shown in other Cepheid documents we looked at though I can't find the reference at the moment. Now tell me, does the luminosity curve he http://www.users.bigpond.com/hewn/stupidjerry.jpg match the acceleration (ADoppler) or the velocity (VDoppler) from he http://www.georgedishman.f2s.com/Hen...lustrative.png You're not making sense George. What the hell are those three graphs? They aren't cepheid curves. As George plainly stated, his are illustrative curves, not taken from actual data. However, if you DO take actual radial velocity data and differentiate to get acceleration curves, and integrate to get radius versus time curves, you might figure out what his curves are supposed to represent and their relevance to the present discussion. To anybody with even a modicum of mathematical background beyond algebra, the meaning of his curves is obvious. Jerry Henri Wilson's Faked Diploma http://mysite.verizon.net/cephalobus...ri_diploma.htm Henri Wilson's Use of Deceptive Language or, Would You Buy A Used Ballistic Theory From This Man? http://mysite.verizon.net/cephalobus..._deception.htm RT Aurigae versus Emission Theory or, Henri Wilson's Faked Program Output http://mysite.verizon.net/cephalobus...rt_aurigae.htm Henri Wilson Attempts to Rewrite the Historical Record http://mysite.verizon.net/cephalobus...ri_history.htm |
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On Tue, 12 Jun 2007 04:32:59 -0700, Jerry
wrote: On Jun 12, 1:20 am, HW@....(Henri Wilson) wrote: On Mon, 11 Jun 2007 19:21:00 +0100, "George Dishman" wrote: It is purely illustrative, drawn as graphs in Excel and not real data. I just want you to get the idea. The acceleration is constant for two periods with a raised joining them. The velocity and radius are just the integrals of course: http://www.georgedishman.f2s.com/Hen...lustrative.png Compare that with this: http://www.users.bigpond.com/hewn/stupidjerry.jpg I'm sure you can see that the velocity curve is the same in both, just inverted. You will find the radius curve matches that shown in other Cepheid documents we looked at though I can't find the reference at the moment. Now tell me, does the luminosity curve he http://www.users.bigpond.com/hewn/stupidjerry.jpg match the acceleration (ADoppler) or the velocity (VDoppler) from he http://www.georgedishman.f2s.com/Hen...lustrative.png You're not making sense George. What the hell are those three graphs? They aren't cepheid curves. As George plainly stated, his are illustrative curves, not taken from actual data. However, if you DO take actual radial velocity data and differentiate to get acceleration curves, and integrate to get radius versus time curves, you might figure out what his curves are supposed to represent and their relevance to the present discussion. To anybody with even a modicum of mathematical background beyond algebra, the meaning of his curves is obvious. Jerry Quite obviously neither you nor George has the faintest idea of the BaTh and how it produces brightness curves. The typical luminosity curve of a cepheid, as shown in www.users.bigpond.com/hewn/stupidjerry.jpg is 100% ADoppler derived using an eccentricity of around 0.25 and a yaw angle of 60-70. We can assume the velocity curve has about the same shape and phase as the brightness curve but with a smaller percentage change.... due to my K factor. That is, if the photon density increases by 1% due to ADoppler bunching then individual photons in that bunch also shrink due to ADoppler but by only 1/K %. It must be understood that by 'velocity curve' I mean that which is calculated from the observed wavelengths using a grating and the conventional VDoppler equation. It bears no similarity to the true source velocity curve. Hence the gross errors in many velocity estimates throughout the whole of astronomy. www.users.bigpond.com/hewn/index.htm Einstein's Relativity - the greatest HOAX since jesus christ's virgin mother. |
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