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The Motion of the Perihelion of Mercury



 
 
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Old January 6th 09, 07:00 AM posted to sci.physics,sci.physics.relativity,sci.astro
George Hammond[_2_]
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Default The Motion of the Perihelion of Mercury

On Mon, 5 Jan 2009 22:16:57 -0800 (PST), Koobee Wublee
wrote:

On Jan 5, 2:18 pm, George Hammond wrote:
Koobee Wublee wrote:


To describe any geometry, you must choose a set of coordinate system
first. Without any coordinate system, you cannot describe any
geometry. Try to understand this very basic concept.


Holy Curvature almighty God!!!! How many times do you
have to repeat it?


It looks like the great reverend Hammond has just run out of his
scriptures. Oh, well. It is time for you to check yourself into a
mental institution. shrug

Thus, I just want you to show me how the following spacetimes ds1 [and]
ds2 are the same.


** ds1^2 = c^2 (1 K / r) dt^2 dr^2 / (1 K / r) r^2 dO^2


** ds2^2 = c^2 dt^2 / (1 + K / r) (1 + K / r) dr^2 (r + K)^2 dO^2


Since both solutions came from the same set of field equations with
coordinate system chosen right from the very beginning (Christoffel
symbols), the coordinate system in both is the same.


ds1 is just the plain vanilla Schwarzchild Metric.


Well, why is that a surprise for you?

[Hammond]
Never said it was.

If you
make the substitution r=r+K simple algebra immediately gives
you ds2 !!!!


If (r = r + K) and (K != 0), the (r = 0).

[Hammond]
I said "SUBSTITUTE" r+K for r, Tricycle.

It sounds like you have not
passed grade school mathematics. shrug

[Hammond]
You couldn't pass grammar Pearl Diver, never mind math.
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