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![]() You will note a problem here. Since the Earth is made of proton and electrons, then a tiny charge asymmetry will produce a net charge of one sign, as you say. However, the Moon is also made of protons and electrons, and the same charge asymmetry will produce a net charge of the same sign as the Earth. In your scenario, the Earth and the Moon would then have the same sign of net charge, and if you recall Coulomb's law, like charges repel. Thus you would predict that the Earth repels the Moon, not attracts it. To account for attraction via Coulomb's law, you would have to explain how it is that the Moon and the Earth acquire opposite charge. Likewise, you would also have to explain how the Sun and the Earth acquire opposite charge. You will also note that it is difficult to arrange the Sun and the Earth and the Moon all to have opposite charges, so that at least one of those pairs would have to repel each other, which is counter to experiment. PD [snip] I think this recent post by Mitchell Jones neatly explains how an electrostatic force generated by a slight difference between the attraction of opposite charges versus the replusion of similar charges can produce a gravity-like force. This isn't due to an imbalance between the charge ratios of electrons/protons that would lead to an overall imbalance of charges, but rather a difference in force when considering the attractive force versus the repelling force generated by charges. This is a pretty straight forward application of Columbs law. http://groups.google.com/group/sci.p...532d05a4ffd0a1 I used to think that there would be a net charge that generated the field. A net charge does exist due to electrons blown off the Earth and this generates the electric field, but this is not the main mechanism behind gravity. fhusummary |
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