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On 28 Mar, 11:40, HW@....(Henri Wilson) wrote:
On 28 Mar 2007 02:16:59 -0700, "George Dishman" wrote: On 28 Mar, 08:10, HW@....(Henri Wilson) wrote: On Sun, 25 Mar 2007 23:34:03 +0100, "George Dishman" wrote: "Henri Wilson" HW@.... wrote in message George, when you can, have a look at http://www.users.bigpond.com/hewn/ellip_circle.jpg This shows how an elliptical orbit can produce a near perfect sine wave under certain condition whilst the circular orbit produces nothing like one for exactly the same parameter values. Yaw angle is -90 (periastron closest to observer). The white curve is an exact sinewave. You might like to consider how the elliptical orbit's curve will change with distance. For small changes in magnitude I cannot tell the difference between the output for a circular orbit and one with a small eccentricity. What I expect is that as the distance changes, the ratio of VDoppler to ADoppler changes giving a change in phase. To compensate for that, you might need to alter the yaw or a change of eccerntricity might do it. The shape of the 'sinewave' produced for an elliptical orbit certainly changes with distance, as expected. However it is certainly interseting to note that a perfect sine wave 'bunching curve' can be produced by a star in an elliptical orbit. There is probably an algebraic reason for this ...but I don't think I'll bother to find out what it is. That is what I was alluding to a couple of weeks ago. For small values you can probably get a match by eye but the equation for an ellipse and those for Kepler's Laws are quite different from the effect of ballistic theory. It would be a curious though unimportant coincidence if they exactly matched. Just as Ptolemy was able to get a good but imperfect match with combined circles, I think if you did the analytical investigation, you would find there was a small difference but perhaps third or fourth order. That is what would show up as the shape of a pattern in your residuals. theory For example can you do the same at a distance where VDoppler and ADoppler are of equat magnitude (the 45 degree case for a circular orbit). George, I think what you are calling VDoppler is what you would get if you placed a large number of equally spaced lights around a spinning wheel (Edge on). Those on the sides would be 'VDoppler bunched' or separated. I'm not sure I follow that but it is certainly not what I am doing. This is not the situation we are examining. The pulses are emitted in sequence and not all at the same instant..and not at exactly the same point. .... I have finally realised there is no VDoppler in the classical sense (as in the case of the spinning wheel, above) What the program measures is the rate at which pulses arrive. The ones on the edge are emitted under constant velocity conditions and arrive at *very nearly* the rate at which they are emitted. There is a very small difference due to the fact that consecutive pulses are not emitted at the same point. Right, that is the cause of classical VDoppler. Two pulses emitted 2.295 ms apart travel slightly different distances due to the motion of the source. At an orbital speed of 27983 m/s when the pulsar is moving directly towards us, the second pulse would travel 64.22 m less than the first which corresponds to about 214 ns. The VDoppler would be about 93 parts per million. The diagram would be like this: g h --- O + B The pulsar sends one pulse from g and the next from h, it is orbiting round the barycentre B and the observer is at O. Obviously there is a v*cos(theta) term for other parts of the orbit, it is the distance change in the direction of the line of sight that matters. I have incorporated that by adding an Rsin(x) term to the star distance. It is generally negligible. It will certainly be small but it is not negligible, it will produce a 45 degree phase shift when the ADoppler is about 93 parts per million too and in fact we know that the VDoppler is probably larger than the ADoppler _except_that_ the phase can be changed by the effect you describe at the top of the post regarding an elliptical orbit looking circular. I have held off replying to see if you would clarify that (and also I was out last night and we had visitors at the weekend). I've also been tinkering with a GUI and might do a simulation for comparison with yours but I have a couple of other projects I'm working on too so I may not spend too much time duplicating what you've already done. Does your program actually include VDoppler or not? George, I think your model is something like a spinning wheel with many lights equally spaced around its rim. No, it is what you describe above. You say you have an R*sin(x) factor in the distance to address it, though whether that works or not depends on your code obviously. VDoppler shift will occur in that model, if you assume constant light speed to the observer from all sources. The correct model is a spinning wheel that has one *flashing* light on its rim. There is a subtle difference. Conventional VDoppler does not occur in this case. You seem to have an odd idea of "conventional VDoppler", the single flashing light on the rim of the wheel is how I would think of it. The shift in the former is (c+v)/c. In the latter it is something like (D-Rsin(xt))/D and very soon disappears. Do you see what I'm getting at? Not really. The classical Doppler is c/(c-v) for a single source that moves which is how the pulsar behaves. Balistic theory changes the speed so it becomes (c+v)/c where v is the component along the line of sight and includes the sin(theta) term. I don't know where you get this idea of multiple sources. George |
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