Why are the 'Fixed Stars' so FIXED?

"Henri Wilson" HW@.... wrote in message
...
On Sat, 10 Mar 2007 23:22:08 -0000, "George Dishman"
wrote:
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So now that we have confirmed the phase is OK, what does
your program give for the velocity from the blue curve
when the red matches the observations and distance is
3720 light years Henry? You seem to be saying you have
done the work and got a linear scale to read it off but
you haven't actually given me the number yet.

Like I said, I can only give you a figure for the product (blue velocity x
distance).

Like I said, the distance is 3720 light years.

For instance, for an extinction distance of about 120 Ldays, and a red
velocity variation of 0.00019, the blue velocity is about 15m/s.

For 12 Ldays, the blue velocity is 150 m/s.

OK, so for a distance of 3720 light years or 1357830 light
days that would be

15 * 120 / 1357800 = 0.0013 m/s

The orbital circumference would be that times 1.5 days or
172 m, a radius of 27 m. Do you agree with those numbers?

Just as a matter of curiosity, what is your value for the
eccentricity?

The next question, again assuming no extinction, is what
orbital inclination would you need to get a reasonable
radius. If you don't follow my reason for asking, it is
that a nearly face-on orbit will give a low radial
component of the velocity even for high actual speeds.

George