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What is it?
Thank you, Christopher Lusardi |
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Llanzlan Klazmon wrote:
wrote in news:1144244869.312028.216920 @v46g2000cwv.googlegroups.com: What is it? Thank you, Christopher Lusardi I'm not sure that Bill's explanation is quite right. Historically, a Keplerian trajectory would be a segment of a Keplerian orbit as described by Keplers first law. This means a segment of an ellipse (or circle as a circle is just an ellipse with zero eccentricity). The other conic sections mentioned, a parabola or hyperbolia, which are also solutions to Newton's laws for a two body problem involving gravity would not qualify, as Kepler himself did not know of such orbits. Klazmon. A bit of a nit, you'll admit, but I'm hit. I accept your correction; thanks. -- Bill |
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