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i calculated the value of an electron radius and i got it has
1.498754637*10^-22 meters |
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"peter" schrieb im Newsbeitrag
om... i calculated the value of an electron radius and i got it has 1.498754637*10^-22 meters nice rb |
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Rainer Borchmann (or somebody else of the same name) wrote in message
thusly: "peter" schrieb im Newsbeitrag om... i calculated the value of an electron radius and i got it has 1.498754637*10^-22 meters nice rb Now take it's spin angular momentum (h/4pi), turn that into an rpm and so find the surface spin speed at the "equator". You'll find it's many times greater than c. -- Paul Townsend I put it down there, and when I went back to it, there it was GONE! Interchange the alphabetic elements to reply |
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Don't you mean "turn it into a speed"? Rotations per minute don't tell you
much about the velocity of something. Something 2m wide spinning at 1000 RPM will have different parts of it moving at different speeds. ![]() Now take it's spin angular momentum (h/4pi), turn that into an rpm and so find the surface spin speed at the "equator". You'll find it's many times greater than c. -- Paul Townsend I put it down there, and when I went back to it, there it was GONE! Interchange the alphabetic elements to reply --- Outgoing mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.561 / Virus Database: 353 - Release Date: 13/01/2004 |
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Alexander Whiteside (or somebody else of the same name) wrote in message
thusly: Don't you mean "turn it into a speed"? Rotations per minute don't tell you much about the velocity of something. Something 2m wide spinning at 1000 RPM will have different parts of it moving at different speeds. ![]() No, I asked for the speed at the *surface* at the *equator*. That is a single unique figure for a given spinning sphere, e.g. just over 1000 mph for the Earth. Now take it's spin angular momentum (h/4pi), turn that into an rpm and so find the surface spin speed at the "equator". You'll find it's many times greater than c. -- Paul Townsend I put it down there, and when I went back to it, there it was GONE! Interchange the alphabetic elements to reply |
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My fault, misread the question...
Of course, spin has nothing to do with actual movement on those scales, and is more similar to a symmetry function. For example, a king in a deck of playing cards has a spin of 2, and a sphere has a spin of infinity. Or something like that, I forget. "Prai Jei" wrote in message ... Alexander Whiteside (or somebody else of the same name) wrote in message thusly: Don't you mean "turn it into a speed"? Rotations per minute don't tell you much about the velocity of something. Something 2m wide spinning at 1000 RPM will have different parts of it moving at different speeds. ![]() No, I asked for the speed at the *surface* at the *equator*. That is a single unique figure for a given spinning sphere, e.g. just over 1000 mph for the Earth. Now take it's spin angular momentum (h/4pi), turn that into an rpm and so find the surface spin speed at the "equator". You'll find it's many times greater than c. -- Paul Townsend I put it down there, and when I went back to it, there it was GONE! Interchange the alphabetic elements to reply |
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"Alexander Whiteside" wrote in message
... Don't you mean "turn it into a speed"? Rotations per minute don't tell you much about the velocity of something. Something 2m wide spinning at 1000 RPM will have different parts of it moving at different speeds. ![]() The OP proposed a value for the radius of the electron. Presumably he also implied that the electron is a spherical particle. The intrinsic angular momentum of the electron is known to be L = h/(4pi), or about 5.27x10^-35 kg-m^2/sec. The moment of inertia of a uniform sphere of mass M and radius r spinning about an axis is I = (2/5)M*r^2 For the electron with mass M = 9.11x10^-31 kg and the OP's radius, this yields I = 8.19x10^-75 kg-m^2. If w is the angular velocity of the rotating sphere, then we have the angular momentum L: L = I*w so that w = L/I and the tangential velocity at the equator of the sphere is v = rxw. w = L/I = 6.44x10^39 Hz rxw = 9.66x10^17 m/sec That's waaay faster than light. |
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