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If there were another planet, same mass as Earth and in the same orbit but
at the precise opposite orbital position, we would presumably never see it because it would always be eclipsed by the sun. Is there any way we can be sure that there isn't such a planet? Jim Hawkins |
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![]() "Jim Hawkins" wrote in message m... If there were another planet, same mass as Earth and in the same orbit but at the precise opposite orbital position, we would presumably never see it because it would always be eclipsed by the sun. Is there any way we can be sure that there isn't such a planet? Jim Hawkins It would be detectable due to its perturbation of the orbits of other solar system objects. |
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"OG" wrote in message
... "Jim Hawkins" wrote in message m... If there were another planet, same mass as Earth and in the same orbit but at the precise opposite orbital position, we would presumably never see it because it would always be eclipsed by the sun. Is there any way we can be sure that there isn't such a planet? Jim Hawkins It would be detectable due to its perturbation of the orbits of other solar system objects. Yes. And perturbations by other planets would move it out from behind the sun where it could be seen, and from time to time it would approach the longitude of the Earth, when all hell would break loose due to tides while the two passed each other. The situation would resemble the co-orbital moons of Saturn, Janus and Epimetheus. Even the "presumably" of the OP is wrong. At total eclipses of the Sun, any Earth-similar planet on the opposite side of the Sun would be directly visible more times than not. The Earth's orbit isn't circular and Kepler's second law would apply, so it would not always be exactly 180 deg different in true anomaly. Objects like Cruithne (which has the same period as Earth) could not exist in a captured orbit if an Earth-like planet had a similar orbit. This goes back to OG's point, of course. -- Mike Dworetsky (Remove pants sp*mbl*ck to reply) |
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![]() "Mike Dworetsky" wrote in message ... "OG" wrote in message ... "Jim Hawkins" wrote in message m... If there were another planet, same mass as Earth and in the same orbit but at the precise opposite orbital position, we would presumably never see it because it would always be eclipsed by the sun. Is there any way we can be sure that there isn't such a planet? Jim Hawkins It would be detectable due to its perturbation of the orbits of other solar system objects. Yes. And perturbations by other planets would move it out from behind the sun where it could be seen, and from time to time it would approach the longitude of the Earth, when all hell would break loose due to tides while the two passed each other. The situation would resemble the co-orbital moons of Saturn, Janus and Epimetheus. Even the "presumably" of the OP is wrong. At total eclipses of the Sun, any Earth-similar planet on the opposite side of the Sun would be directly visible more times than not. The Earth's orbit isn't circular and Kepler's second law would apply, so it would not always be exactly 180 deg different in true anomaly. Objects like Cruithne (which has the same period as Earth) could not exist in a captured orbit if an Earth-like planet had a similar orbit. This goes back to OG's point, of course. -- Mike Dworetsky Thanks for the explanations, Mike and OG (and thanks to A N Other who sent me an email on the same lines). Jim Hawkins |
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On Jun 16, 12:24*am, "Jim Hawkins" wrote:
"Mike Dworetsky" wrote in message ... "OG" wrote in message ... "Jim Hawkins" wrote in message news:dNednQy4CJfjqcjVnZ2dneKdnZydnZ2d@supernews. com... If there were another planet, same mass as Earth and in the same orbit but at the precise opposite orbital position, we would presumably never see it because it would always be eclipsed by the sun. Is there any way we can be sure that there isn't such a planet? Jim Hawkins It would be detectable due to its perturbation of the orbits of other solar system objects. Yes. And perturbations by other planets would move it out from behind the sun where it could be seen, and from time to time it would approach the longitude of the Earth, when all hell would break loose due to tides while the two passed each other. *The situation would resemble the co-orbital moons of Saturn, Janus and Epimetheus. Even the "presumably" of the OP is wrong. *At total eclipses of the Sun, any Earth-similar planet on the opposite side of the Sun would be directly visible more times than not. *The Earth's orbit isn't circular and Kepler's second law would apply, so it would not always be exactly 180 deg different in true anomaly. Objects like Cruithne (which has the same period as Earth) could not exist in a captured orbit if an Earth-like planet had a similar orbit. *This goes back to OG's point, of course. -- Mike Dworetsky Thanks for the explanations, Mike and OG (and thanks to A N Other who sent me an email on the same lines). Jim Hawkins- Hide quoted text - - Show quoted text - The only thing that is perturbed are these guys and their thinking for while they talk of an elliptical orbital geometry,the framework they use is circular - http://upload.wikimedia.org/wikipedi...3%A9reo.en.png Your hypothetical question aside,the ability to believe that you can reference axial rotation off celestial sphere geometry while referencing orbital motion off the central Sun is truly a remarkable belief in a simpleminded sort of way,the genuine belief among empiricists that they actually can justify axial rotation in 23 hours 56 minutes 04 seconds because they can see a star returning back to a observed location in that time.Aaarrr, Jim lad,were it only that simple. If the anonymous science entity thinks it can script whatever explanation it wants and sell it to the general population then they should learn that the trick of obfuscation,no matter how elaborate and supported,does not work. In this respect,there is some joy this week in seeing ordinary people reject a European treaty even though the treaty had the backing of every organisation with power,a re-packaged treaty that was given a new name and wrapped up in legalise in order to bludgeon people into acceptance,the same tactic used in a section of science day in and day out.Only this time it failed. Given a chance,people do find their voice,the dismay of politicians in seeing that people will not follow something because they are told it is good for them is outweighed by the sense that originality and the tendency to fight against mediocrity and bureocracy is not quite dead yet.Oh that it existed in these forums where even those who towed an anonymous empirical line realised the damage that was and is still being done using terrestrial/celestial phenomena. |
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On 17 Jun, 05:16, oriel36 wrote:
the genuine belief among empiricists that they actually can justify axial rotation in 23 hours 56 minutes 04 seconds because they can see a star returning back to a observed location in that time.Aaarrr, Jim lad,were it only that simple. Of course it could be that you are correct and thousands of professional and amateur astronomers are wrong. However until you can be bothered to publish a detailed explanation of your theories in a peer reviewed journal I am inclined to believe the majority. |
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On Jun 16, 10:16 pm, oriel36 wrote:
Your hypothetical question aside,the ability to believe that you can reference axial rotation off celestial sphere geometry while referencing orbital motion off the central Sun Nah. Celestial sphere geometry is just a convenience for knowing where to point things. If you're going to do any calculating, there's only one geometry to use - Cartesian coordinates, x, y, and z. Unless, of course, general relativistic effects are so strong that they're nonlinear; then there's nothing for it but to go whole hog with tensor calculus. Thankfully, while general relativistic effects are strong enough to be *detectable* in the precession of Mercury, they're still nowhere near strong enough to require THAT. (Depending on the precision you need, of course.) is truly a remarkable belief in a simpleminded sort of way,the genuine belief among empiricists that they actually can justify axial rotation in 23 hours 56 minutes 04 seconds because they can see a star returning back to a observed location in that time. Well, we have to start with the simple stuff. Aaarrr, Jim lad, were it only that simple. Celestial motions *are* a whole lot simpler if you can untangle them, and look at one motion at a time. Using the distant stars as an approximation to a stationary coordinate system _is_ a great way to get started. If you don't like it - that's your problem, not ours, I'm afraid. In this respect, there is some joy this week in seeing ordinary people reject a European treaty even though the treaty had the backing of every organisation with power, Here's something I agree with you about. Most Europeans don't want a less-responsive European Parliament and are happy with their own national governments. However, with a free trade area, a common currency - the Euro - _is_ needed to gain the full benefits, so a case can be made for some additional integration over and above that of the original European Economic Community. And from what I've heard about the issue, you are also right that the new treaty is much the same as the old one that was rejected in referendums despite it being claimed that it is different enough so that no referendums are appropriate this time. But modern science is hard to understand *not* because scientists have dressed it up in jargon, but because it genuinely *depends* on fancy mathematics. Oh that it existed in these forums where even those who towed an anonymous empirical line realised the damage that was and is still being done using terrestrial/celestial phenomena. I can't even guess what damage you are referring to that we were aware of. I wish I could usefully communicate with you to get information about where we're supposed to be wrong that I could get a grip on. John Savard |
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In uk.sci.astronomy message dNednQy4CJfjqcjVnZ2dneKdnZydnZ2d@supernews.
com, Sun, 15 Jun 2008 16:25:46, Jim Hawkins posted: If there were another planet, same mass as Earth and in the same orbit but at the precise opposite orbital position, we would presumably never see it because it would always be eclipsed by the sun. Is there any way we can be sure that there isn't such a planet? Even if the Universe consisted solely of the Sun, Earth in circular orbit, and counter-Earth, the system would not be dynamically stable; it would be like an infinitely-sharp pencil balanced on its point in an infinitely-hard flat surface. That conclusion is independent of the mass of counter-Earth. Plus what others have said. The argument that the Earth's orbit is not circular, and hence its angular velocity is not constant, implies that a body in the same orbital path would not remain diametrically opposite. But a body in an orbit of the same shape but "pointing" in the opposite direction to ours, if initially behind the Sun, would remain so until the effects of perturbations and instability accrued. That's analogous to L4 & L5 still working for elliptical orbits. -- (c) John Stockton, nr London, UK. Turnpike v6.05 MIME. Web URL:http://www.merlyn.demon.co.uk/ - FAQqish topics, acronyms & links; Astro stuff via astron-1.htm, gravity0.htm ; quotings.htm, pascal.htm, etc. No Encoding. Quotes before replies. Snip well. Write clearly. Don't Mail News. |
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