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The following post was banned from sci.astro.research, sans notice (as
usual). ========================== "Phillip Helbig---remove CLOTHES to reply" wrote in message ... In article , "Lars Wahlin" writes: A few years ago data from the Ia Supernova Cosmology Project found that Hubble's law is not linear but changes in a nonlinear fashion at large distances, i.e. The universe is accelerating. This is just plain wrong. Hubble's Law says that recession velocity is proportional to distance. The "Hubble's law" to which you are referring is a theoretical construct. Hubble's data connects distance with redshift -- not with recession velocity. This is actually quite trivial, since this is the only relation which allows a homogeneous and isotropic universe to remain so. Your assumption has nothing to do with the discussion of the Hubble relation. And it may have nothing to do with the real universe. However, both the distance and velocity are not observable. The distance is observable. The redshift is observable. The assumption that velocity is the only contribution to redshift is pure theory (not observable). Just like the last time this was discussed on this N.G. http://www.google.com/groups?selm=10....supernews.com Hubble's actual discovery was the linear apparent-magnitude--redshift relation. Carl Wirtz' discovery was the empirical redshift-distance relation in 1924 (pre Cepheid variable identification). Hubble gave us the distance - redshift relation. He used Cepheid variable stars to set the distance. And it is apparently linear for galaxies with resolveable Cepheids. Again, just like it was discussed before in this N.G. http://www.google.com/groups?selm=mt...tar.bris.ac.uk FOR LOW REDSHIFT, one can use the former as a measure of distance and the latter as a measure of velocity. However, this relation is almost always observed whatever the cosmological parameters, and is just a consequence of the fact that "things are linear to first order". In other words, "Hubble's Law" is by definition linear. Argument-by-definition is not valid in the scientific method. That you, and other theorists, like to assume that the distance-redshift relationship is purely linear does not constrain the real universe. The effect you are looking at may not be linear ... it may simply be the first part of an exponential function. What you mean is that a departure from this linearity is observed at higher redshift, which indicates an expanding universe. It only indicates an expanding universe if your assumption is true. Which is not a given. Well, this was actually suggested long ago by Karachentsev .Commun. Buyrakan Obs. 39 96. (1967), Ozernoy,Zh. Eksper. Teor. Fiz (Letters) 10, 394 (=JETP Letters 10 251), (1969), de Vacouleurs, Publ. Astron. Pacific 83, 113 (1971) and verified theoretically by myself (Wahlin, Astrophysics and space Science 74, 157 (1981)). As Bill Press said in 1995, someone knows the value of the Hubble constant to 1%---we just don't know who that person is. Totally irrelevant. I am not aware of ANY observation-based arguments for an accelerating universe before the 1990s which still stand up today. Sure, some people made some observations and drew some conclusions. Maybe by chance the conclusions were even correct. But it was just luck. Make a thousand predictions, and one might be right. Like your conclusion that the distance - redshift relation might be linear? Unfortunately, this assumption will no longer 'stand up today.' The supernovae data blew it away. -- greywolf42 ubi dubium ibi libertas {remove planet for e-mail} |
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![]() "greywolf42" wrote in message ... "George Dishman" wrote in message ... .... Linearity is not assumed, A false statement. It *IS* explicitly assumed. As demonstrated above and in the references provided (which you snipped). it is related to anisotropy and homogeneity which again can be measured (though not easily). Meaning such have never been measured, merely assumed. ![]() How much data do you need before an assumption becomes a measured result? Peebles lists some of the evidence in "Principals of Physical Cosmology". Take a look at Figure 3.10, Condon's 1991 map of bright radio sources, for example. What you mean is that a departure from this linearity is observed at higher redshift, which indicates an expanding universe. It only indicates an expanding universe if your assumption is true. Which is not a given. It indicates a time variation of the coefficient in the law. But only if your assumption is true. Which is the question. You mean only if the evidence isn't misleading us ;-) Perhaps "Hubble 'constant'" was a poor choice of name (with hindsight). The term itself is not the issue under discussion. Like your conclusion that the distance - redshift relation might be linear? Unfortunately, this assumption will no longer 'stand up today.' The supernovae data blew it away. Methinks thou trollst! You know better than that. Not in the least. The nonlinear effect was predicted years ago. Hubble Distance was defined years ago too, yet you talk as if you had never heard of it. (The link is my other reply if you really haven't.) George |
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"George Dishman" wrote in message
... "greywolf42" wrote in message ... "George Dishman" wrote in message ... ... Linearity is not assumed, A false statement. It *IS* explicitly assumed. As demonstrated above and in the references provided (which you snipped). it is related to anisotropy and homogeneity which again can be measured (though not easily). Meaning such have never been measured, merely assumed. ![]() How much data do you need before an assumption becomes a measured result? At least one *direct* measurement in support, and *no* results contrary. The supernova data are contrary to the linear assumption, however. They fit on an exponential curve. Peebles lists some of the evidence in "Principals of Physical Cosmology". But none of those address the specific issue under discussion. (If you disagree, please provide the specifics. Not simply a vague allusion.) Take a look at Figure 3.10, Condon's 1991 map of bright radio sources, for example. This does not address the issue of linearity of the Hubble graph. What you mean is that a departure from this linearity is observed at higher redshift, which indicates an expanding universe. It only indicates an expanding universe if your assumption is true. Which is not a given. It indicates a time variation of the coefficient in the law. But only if your assumption is true. Which is the question. You mean only if the evidence isn't misleading us ;-) No, I mean if you can only think along the lines of one theory. The evidence is the variation from linearity on the Hubble curve, shown by the supernovae. *You* are ignoring the evidence. Perhaps "Hubble 'constant'" was a poor choice of name (with hindsight). The term itself is not the issue under discussion. Like your conclusion that the distance - redshift relation might be linear? Unfortunately, this assumption will no longer 'stand up today.' The supernovae data blew it away. Methinks thou trollst! You know better than that. Not in the least. The nonlinear effect was predicted years ago. Hubble Distance was defined years ago too, yet you talk as if you had never heard of it. (The link is my other reply if you really haven't.) ??? The "Hubble Distance" is not germaine to the assumption of linearity of the Hubble curve. -- greywolf42 ubi dubium ibi libertas {remove planet for e-mail} |
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![]() "greywolf42" wrote in message . .. "George Dishman" wrote in message ... "greywolf42" wrote in message ... "George Dishman" wrote in message ... ... Linearity is not assumed, A false statement. It *IS* explicitly assumed. As demonstrated above and in the references provided (which you snipped). it is related to anisotropy and homogeneity which again can be measured (though not easily). Meaning such have never been measured, merely assumed. ![]() How much data do you need before an assumption becomes a measured result? At least one *direct* measurement in support, By definition that is impossible since distant observations are of the past. An indirect measurement is given below. and *no* results contrary. The supernova data are contrary to the linear assumption, however. Sorry, that's simply not true. Learn the definition of the Hubble Distance and you will see why. They fit on an exponential curve. Perhaps, but it would be an exponential function of time while the Hubble Law is linear with distance at a given time. The two are not incompatible. Peebles lists some of the evidence in "Principals of Physical Cosmology". But none of those address the specific issue under discussion. (If you disagree, please provide the specifics. Not simply a vague allusion.) They specifically address whether the universe is homogenous and isotropic which leads to linearity as a function of distance at a common time. Take a look at Figure 3.10, Condon's 1991 map of bright radio sources, for example. This does not address the issue of linearity of the Hubble graph. It addresses the linearity of the Hubble Law, not a plot of redshift versus _observable_ distance. What you mean is that a departure from this linearity is observed at higher redshift, which indicates an expanding universe. It only indicates an expanding universe if your assumption is true. Which is not a given. It indicates a time variation of the coefficient in the law. But only if your assumption is true. Which is the question. You mean only if the evidence isn't misleading us ;-) No, I mean if you can only think along the lines of one theory. The evidence is the variation from linearity on the Hubble curve, shown by the supernovae. *You* are ignoring the evidence. No, I understand that there are two separate dependencies which you are conflating. The supernova data provides information about the time dependency while evidence relating to homogeneity relates to the spatial dependence. Perhaps "Hubble 'constant'" was a poor choice of name (with hindsight). The term itself is not the issue under discussion. Like your conclusion that the distance - redshift relation might be linear? Unfortunately, this assumption will no longer 'stand up today.' The supernovae data blew it away. Methinks thou trollst! You know better than that. Not in the least. The nonlinear effect was predicted years ago. Hubble Distance was defined years ago too, yet you talk as if you had never heard of it. (The link is my other reply if you really haven't.) ??? The "Hubble Distance" is not germaine to the assumption of linearity of the Hubble curve. The Hubble Law, which is believed to be linear, is a corelation with the Hubble Distance. How can you discuss whether it is linear or not without first knowing how that distance is defined? George |
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"g" == greywolf42 writes:
g Then why do you constantly ignore the possibility that the g redshift-distance relation is an exponential curve? Do the data support such a notion? -- Lt. Lazio, HTML police | e-mail: No means no, stop rape. | http://patriot.net/%7Ejlazio/ sci.astro FAQ at http://sciastro.astronomy.net/sci.astro.html |
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"Joseph Lazio" wrote in message
... "g" == greywolf42 writes: g Then why do you constantly ignore the possibility that the g redshift-distance relation is an exponential curve? Do the data support such a notion? Yes. For a quick reference, see Perlmutter, Figure 3, Physics Today, April 2003, "Supernovae, Dark Energy, and the Accelerating Universe". http://www.slac.stanford.edu/econf/C...perlmutter.pdf Just notice that instead of "accelerating universe" and "decelerating universe" (which require a linear assumption), one should read: "exponential redshift-distance relation" and "inverse exponential redshift-distance relation," respectively. Pure Hubble constant (linear assumption) lies on the straight line. -- greywolf42 ubi dubium ibi libertas {remove planet for e-mail} |
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"George Dishman" wrote in message
... "greywolf42" wrote in message . .. "George Dishman" wrote in message ... {snip higher levels} There are two unknowns at work, how redshift varies with location and how it varies with time. You manifest the fallacy of the excluded middle. There are more than two options. There are an infinite number of options, I said "two unknowns". What you provided are two theories, not unknowns. The latter term denotes a constant to be solved for. And once again, you are assuming that the redshift-distance relation is a constant (at a given time and place). The other option is that the redshift-distance relation does not vary with location or time. But simply is not a straight line. We can only directly observe a sample through that, a diagonal so to speak. Again, it is only a 'diagonal' if you first assume a line. That line is simply the relation between distance and the age of the galaxies we observe, not an assumption of linearity. The "age of the galaxies" that you claim is determined based upon a distance that is calculated using the Hubble Law ... which is a linear assumption. You are giving the impression that you think one-dimensionally and cannot see the bigger picture, which I doubt. The classic ad hominem fallacy. "which I doubt" ???? If you are serious, I suggest you start by understanding the definition of distance used in the Hubble Law: Followed by the classic special plead fallacy. http://www.astro.ucla.edu/~wright/cosmo_02.htm#md It explains the Hubble Distance. No, it doesn't even mention the Hubble distance. Did you mean the "Hubble law distance" term that Ned uses? That's not the same as the Hubble distance. At least according to http://www.astro.ufl.edu/~guzman/ast...project01.html (See parallel post for references and details.) How can you discuss the law if you don't know the definition of the quantities it relates? "Hubble's Law" is not defined using Hubble distance. Misner, Thorne and Wheeler do just fine discussing the Hubble Law and cosmology. And they don't use the term "Hubble Distance." The Hubble distance is a theoretical distance number that is calculated *from* the Hubble Law. (See parallel post for references and details.) You might then understand Phillip's comments. Repeat the classic special plead fallacy. I understand both Phillip and you just fine, thanks. Note that it is Phillip who is cutting out responses that he doesn't want to deal with. Or perhaps he dropped aspects that you cannot discuss because you don't understand the basic definitions. The classic special plead fallacy. But the use of terminology is an irrelevant issue. Let's get back to physics. Why are you so fixated Fixated? I mentioned it once purely in the context of the source of the term. You've used it at least a dozen times in the thread. I'm not talking about the word use. I'm talking about the assumption that you keep making. The evidence supports it so far. Then let's discuss the evidence, shall we? Instead of going off on snide tangents. on a "constant of proportionality," to the exclusion of the beginning of an exponential function? Apparently it's my turn to expand your mind, they are not exclusive. Then why do you constantly ignore the possibility that the redshift-distance relation is an exponential curve? An exponential function of what? Distance. As I have stated many times. I have already said that an exponential versus time is what I expect as dark energy becomes dominant. I know you keep repeating this irrelevancy. But that assumes a linear distance relation. The recession velocity at any given cosmic age can be proportional to the Hubble distance while the 'constant of proportionality' in that relation could vary exponentially with time. (*^*^%^ I am not talking about variations with time. Or with variations in space. No, but everybody else is. ??? At the date and time of your post, no one other than you and me posted in this sci.astro thread. Lt. Lazio added a one question post this morning ("Do the data support such a notion?"). You are talking about the relation between observable distance and observable red-shift which is a combination of the two dependencies, the Hubble Law and a(t). Only if you first assume the Hubble law is absolute *Truth*. The relation between the observable redshift and the observable distance simply *IS*. It is not dependent upon a popular theory (the Hubble Law). In fact if you put the most likely measured values into GR, current theory says that is exactly what will happen as dark energy becomes dominant. The measured values of what? Of the constants in GR. The constants in GR are the speed of gravity and the value 8 pi (conversion to Newtonian gravitational constant). GR is not Relativistic Cosmology, but Relativistic cosmology contains GR. The Big Bang theory is not Relativistic Cosmology, but the current BB theory contains Relativistic Cosmology. I presume you mean the "constants" in the Big Bang theory. Please specify which ones you are talking about. Better yet, please focus on the parallel post. Maybe I've found a way to get the message across. -- greywolf42 ubi dubium ibi libertas {remove planet for e-mail} |
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"George Dishman" wrote in message
... "greywolf42" wrote in message . .. "George Dishman" wrote in message ... "greywolf42" wrote in message ... {snip higher levels} How much data do you need before an assumption becomes a measured result? At least one *direct* measurement in support, By definition that is impossible since distant observations are of the past. An indirect measurement is given below. I suspect you are making things more difficult for yourself. Direct does not mean that it must happen simultaneously with some other event. If this were the case, there would never be a direct observation of anything, anywhere. and *no* results contrary. The supernova data are contrary to the linear assumption, however. Sorry, that's simply not true. Learn the definition of the Hubble Distance and you will see why. The classic special plead fallacy. I know the definition of the Hubble distance, thanks. Even though MTW doesn't even bother with the term. The Hubble distance is a theoretical derivative number. One starts with the observed local value of the redshift-distance relation. Then one assumes that the r-d relation is explicitly linear -- this is called the "Hubble Law." One then derives a "Hubble time" (according to MTW, p. 709) by "linearly extrapolating to zero separation on the basis of the expansion rate observed today." One then determines the "Hubble distance" by multiplying the speed of light by the Hubble time. http://www.astro.ufl.edu/~guzman/ast...project01.html They fit on an exponential curve. Perhaps, but it would be an exponential function of time No. What makes you insist on assuming spatial linearity? while the Hubble Law is linear with distance at a given time. The two are not incompatible. We aren't discussing the "Hubble Law". Of course the Hubble Law is linear with distance at a given time! That's because it assumes linearity! We are discussing the *basis* for the theoretical Hubble Law. Specifically, the redshift-distance relationship. Peebles lists some of the evidence in "Principals of Physical Cosmology". But none of those address the specific issue under discussion. (If you disagree, please provide the specifics. Not simply a vague allusion.) They specifically address whether the universe is homogenous and isotropic which leads to linearity as a function of distance at a common time. That is an incorrect conclusion. As noted before, a steady-state universe could be both homegenous and isotropic, and STILL not have a linear function of redshift versus distance (at common time). The linear assumption is a completely separate assumption, limited to the Big Bang theory. And you still haven't provided the specific reference (page) or excerpt. Take a look at Figure 3.10, Condon's 1991 map of bright radio sources, for example. This does not address the issue of linearity of the Hubble graph. It addresses the linearity of the Hubble Law, not a plot of redshift versus _observable_ distance. On the contrary, a simple review of my prior posts in this thread shows that the issue *IS* the evidence supporting this assumption: the observational plot of redshift versus distance. The Hubble Law -- per se -- is a theoretical construct, which is -- by definition -- linear. And no one has ever denied or implied that the theory is not linear. Here is the initial exchange, from http://www.google.com/groups?selm=pD...ewsgroup s.co m Phillip Helbig: "Hubble's Law says that recession velocity is proportional to distance." greywolf42: "The 'Hubble's law' to which you are referring is a theoretical construct. Hubble's data connects distance with redshift -- not with recession velocity." {Of course, that's likely the reason that Phillip refused to let this reply to his post get onto sci.astro.research.} (aside) =========================== Let's try this with math, instead of words. As we seem to be talking past one another. For the moment, let us ignore possible changes with time. The standard Hubble Law is of the form: V = H D Where D is the distance in Mpc, V is the recessional velocity in kps, and the Hubble constant is given in units of kps/Mpc. This equation is explicitly linear. "H" is assumed to be constant throughout the universe. Now let us convert this back to approximate redshift units (approximations are fine, because the value of H is not claimed to better precision than about +- 20%) -- since the data is all in redshift ... not velocity: delta lambda / lambda = H' D. Since delta lambda over lambda is dimensionless, the units for H' would be Mpc^-1. Where H' = H / c. [The conversion (at least at resolvable Cepheid distance) is straightforward doppler effect: delta lambda / lamda = v / c.] Both equations are the same observable effect. Both are explicitly linear, as written. Now, let us examine a simple exponential version: delta lambda / lambda = 1 - exp(-mu D) delta lambda / lambda = mu D + (mu D)^2 / 2 - ...... At near distances (like those of resolvable Cepheid stars), there is no way to distinguish the linear from the exponential change. At substantial distances (like those of the newer supernovae data), however, the higher order terms in the approximation are no longer negligible. So, I could as easily use: delta lambda / lambda = 1 - exp(-H' D) In the case of the linear assumptions, the supernovae data must be addressed through an additional, ad hoc, cosmological term. In the case of the exponential fit, no additional cosmological term is needed. =========================== {snip higher levels} You mean only if the evidence isn't misleading us ;-) No, I mean if you can only think along the lines of one theory. The evidence is the variation from linearity on the Hubble curve, shown by the supernovae. *You* are ignoring the evidence. No, I understand that there are two separate dependencies which you are conflating. No. You are not addressing the point at issue. You are stuck in a linear theory. I am addressing the observational data. The supernova data provides information about the time dependency while evidence relating to homogeneity relates to the spatial dependence. Only if you first assume linearity of the Hubble *DATA*. {snip higher levels} Hubble Distance was defined years ago too, yet you talk as if you had never heard of it. (The link is my other reply if you really haven't.) ??? The "Hubble Distance" is not germaine to the assumption of linearity of the Hubble curve. The Hubble Law, which is believed to be linear, is a corelation with the Hubble Distance. How can you discuss whether it is linear or not without first knowing how that distance is defined? Well, Misner, Thorne, and Wheeler do an admirable job of discussing cosmology and Hubble's law (and the Hubble time) without ever mentioning the "Hubble Distance." Again, we aren't talking about the Hubble Distance at all. The "Hubble Law" (both theory and term) was created long before there was a concept or term "Hubble Distance." But we are talking about the *data* in the redshift-distance relation. -- greywolf42 ubi dubium ibi libertas {remove planet for e-mail} |
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[Reposting as this seems to have got lost]
"greywolf42" wrote in message . .. "George Dishman" wrote in message ... "greywolf42" wrote in message . .. "George Dishman" wrote in message ... "greywolf42" wrote in message ... {snip higher levels} I'm going to do some major snipping and some rearranging too, these posts are becoming entirely swamped by side issues. I guess you may feel I have altered the context but it's difficult to avoid if this is to be a readable reply. First let's get the topic clear. You said: We aren't discussing the "Hubble Law". Of course the Hubble Law is linear with distance at a given time! That's because it assumes linearity! and you give this reference: Here is the initial exchange, from http://www.google.com/groups?selm=pD...wsgroup s.com Phillip Helbig: "Hubble's Law says that recession velocity is proportional to distance." greywolf42: "The 'Hubble's law' to which you are referring is a theoretical construct. Hubble's data connects distance with redshift -- not with recession velocity." However, that is only part of the exchange: Here is the whole quote from Lars and Phillip: "Phillip Helbig---remove CLOTHES to reply" wrote in message ... In article , "Lars Wahlin" writes: A few years ago data from the Ia Supernova Cosmology Project found that Hubble's law is not linear but changes in a nonlinear fashion at large distances, i.e. The universe is accelerating. This is just plain wrong. Hubble's Law says that recession velocity is proportional to distance. To me it is clear that Lars was referring to the relationship between observed redshift and distance, which is non-linear, while Phillip is clearly referring to the relationship between recession speed and distance at a particluar epoch which is linear as discussed below. So when you say "We aren't discussing the 'Hubble Law'.", I have to disagree, and when you say But the use of terminology is an irrelevant issue. Let's get back to physics. I also think what started this is that Lars and Phillip were talking about different relationships, though each might consider it to be "The Hubble Law". Now you also said above "Of course the Hubble Law is linear with distance at a given time! That's because it assumes linearity!" and you seem to confirm that opinion he The Hubble distance is a theoretical derivative number. One starts with the observed local value of the redshift-distance relation. Then one assumes that the r-d relation is explicitly linear -- this is called the "Hubble Law." ... Again you seem to be implying linearity is purely an assumption. They specifically address whether the universe is homogenous and isotropic which leads to linearity as a function of distance at a common time. That is an incorrect conclusion. As noted before, a steady-state universe could be both homegenous and isotropic, and STILL not have a linear function of redshift versus distance (at common time). The linear assumption is a completely separate assumption, limited to the Big Bang theory. You were correct when you said "One starts with the observed local value of the redshift-distance relation." but the assumption is that this is due to expansion over local scales. If the universe is homogenous then you can imagine a slice through the universe at a given epoch to be tiled with regions all similar to the local area we can observe and linearity of velocity with distance then follows if the universe is homogeneous and isotropic but ONLY at a given epoch, i.e. over a surface of uniform cosmic age. I'm sure you follow, the logic is trivial. Linearity itself is therefore not an assumption but a consequence of the cosmological principle plus the observed linearity at small scales. Incidentally, in a homegenous and isotropic steady-state universe, the relationship between speed and distance is still linear but with a constant of proportionality with the value zero. Let's try this with math, instead of words. As we seem to be talking past one another. For the moment, let us ignore possible changes with time. I agree, that's a sensible approach. The standard Hubble Law is of the form: V = H D Where D is the distance in Mpc, V is the recessional velocity in kps, and the Hubble constant is given in units of kps/Mpc. This equation is explicitly linear. "H" is assumed to be constant throughout the universe. You cited this page http://www.astro.ufl.edu/~guzman/ast...project01.html but ignored this fundamental definition: "The Hubble constant H_0 is the constant of proportionality between recession speed v and distance d in the expanding Universe; v = H_0 d The subscripted "0" refers to the present epoch because in general H changes with time." Since you obviously read the page and quoted parts, I again get the impression you deliberately ignored this definition since it clearly repeats what I have been pointing out to you all along. Now let us convert this back to approximate redshift units (approximations are fine, because the value of H is not claimed to better precision than about +- 20%) -- since the data is all in redshift ... not velocity: delta lambda / lambda = H' D. Since delta lambda over lambda is dimensionless, the units for H' would be Mpc^-1. Where H' = H / c. [The conversion (at least at resolvable Cepheid distance) is straightforward doppler effect: delta lambda / lamda = v / c.] Both equations are the same observable effect. Both are explicitly linear, as written. Now, let us examine a simple exponential version: delta lambda / lambda = 1 - exp(-mu D) delta lambda / lambda = mu D + (mu D)^2 / 2 - ...... At near distances (like those of resolvable Cepheid stars), there is no way to distinguish the linear from the exponential change. At substantial distances (like those of the newer supernovae data), however, the higher order terms in the approximation are no longer negligible. The variation of H(t) with t is also no longer negligible. So, I could as easily use: delta lambda / lambda = 1 - exp(-H' D) No, instead of the constant value H', you need to use H(t) and integrate the effect over the lookback time. The converse (finding the time from z) is mentioned in equation (29) of: http://www.astro.ufl.edu/~guzman/ast...project01.html In the case of the linear assumptions, the supernovae data must be addressed through an additional, ad hoc, cosmological term. In the case of the exponential fit, no additional cosmological term is needed. That is not true, you are oversimplifying by ignoring the variation of H(t) at high redshift. This produces non-linearity even when there is a linear relationship with distance at any given epoch. George |
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"George Dishman" wrote in message
... [Reposting as this seems to have got lost] "greywolf42" wrote in message . .. "George Dishman" wrote in message ... "greywolf42" wrote in message . .. "George Dishman" wrote in message ... "greywolf42" wrote in message ... {snip higher levels} I'm going to do some major snipping and some rearranging too, these posts are becoming entirely swamped by side issues. I guess you may feel I have altered the context but it's difficult to avoid if this is to be a readable reply. Fair enough. I've had to do this from time to time with other posts, and posters. First let's get the topic clear. You said: We aren't discussing the "Hubble Law". Of course the Hubble Law is linear with distance at a given time! That's because it assumes linearity! and you give this reference: Here is the initial exchange, from http://www.google.com/groups?selm=pD...ewsgroup s.co m Phillip Helbig: "Hubble's Law says that recession velocity is proportional to distance." greywolf42: "The 'Hubble's law' to which you are referring is a theoretical construct. Hubble's data connects distance with redshift -- not with recession velocity." However, that is only part of the exchange: Here is the whole quote from Lars and Phillip: "Phillip Helbig---remove CLOTHES to reply" wrote in message ... In article , "Lars Wahlin" writes: A few years ago data from the Ia Supernova Cosmology Project found that Hubble's law is not linear but changes in a nonlinear fashion at large distances, i.e. The universe is accelerating. This is just plain wrong. Hubble's Law says that recession velocity is proportional to distance. To me it is clear that Lars was referring to the relationship between observed redshift and distance, which is non-linear, while Phillip is clearly referring to the relationship between recession speed and distance at a particluar epoch which is linear as discussed below. So when you say "We aren't discussing the 'Hubble Law'.", I have to disagree, That's one heck of a roundabout and turbid way of "clarifying" the topic! What exactly are you disagreeing with? Do you understand the difference between Hubble's data and the "Hubble law?" and when you say But the use of terminology is an irrelevant issue. Let's get back to physics. I also think what started this is that Lars and Phillip were talking about different relationships, though each might consider it to be "The Hubble Law". That was part of my point, thanks. ![]() The Hubble Law is explicitly theoretical, not observational. I was attempting to clarify. Now you also said above "Of course the Hubble Law is linear with distance at a given time! That's because it assumes linearity!" and you seem to confirm that opinion he The Hubble distance is a theoretical derivative number. One starts with the observed local value of the redshift-distance relation. Then one assumes that the r-d relation is explicitly linear -- this is called the "Hubble Law." ... Again you seem to be implying linearity is purely an assumption. Actually, I've stated so explicitly, several times. I'm not simply implying it. They specifically address whether the universe is homogenous and isotropic which leads to linearity as a function of distance at a common time. That is an incorrect conclusion. As noted before, a steady-state universe could be both homegenous and isotropic, and STILL not have a linear function of redshift versus distance (at common time). The linear assumption is a completely separate assumption, limited to the Big Bang theory. You were correct when you said "One starts with the observed local value of the redshift-distance relation." but the assumption is that this is due to expansion over local scales. It doesn't matter what ad hoc explanation you make to back up the linear assumption. The assumption of a linear relationship is still an assumption. If the universe is homogenous then you can imagine a slice through the universe at a given epoch to be tiled with regions all similar to the local area we can observe and linearity of velocity with distance then follows if the universe is homogeneous and isotropic but ONLY at a given epoch, i.e. over a surface of uniform cosmic age. I'm sure you follow, the logic is trivial. The assumption *is* trivial. Linearity itself is therefore not an assumption but a consequence of the cosmological principle plus the observed linearity at small scales. Uh, no. The assumption came first. Then the "cosmological principle" was built upon the edifice of the linear assumption. You can see the linear assumption explicitly in Hubble's original graph. Velocity versus distance. When Hubble's data was redshift vs. distance. Incidentally, in a homegenous and isotropic steady-state universe, the relationship between speed and distance is still linear but with a constant of proportionality with the value zero. Only if you assume the Big-bang relationship, that redshift is ever and always only due to doppler shift or expansion. Let's try this with math, instead of words. As we seem to be talking past one another. For the moment, let us ignore possible changes with time. I agree, that's a sensible approach. The standard Hubble Law is of the form: V = H D Where D is the distance in Mpc, V is the recessional velocity in kps, and the Hubble constant is given in units of kps/Mpc. This equation is explicitly linear. "H" is assumed to be constant throughout the universe. You cited this page http://www.astro.ufl.edu/~guzman/ast...project01.html but ignored this fundamental definition: "The Hubble constant H_0 is the constant of proportionality between recession speed v and distance d in the expanding Universe; v = H_0 d The subscripted "0" refers to the present epoch because in general H changes with time." I did not ignore it. Since you obviously read the page and quoted parts, I again get the impression you deliberately ignored this definition since it clearly repeats what I have been pointing out to you all along. It was irrelevant to the issue at hand. The addition of this wrinkle affects the mathematical issue not at all. Now let us convert this back to approximate redshift units (approximations are fine, because the value of H is not claimed to better precision than about +- 20%) -- since the data is all in redshift ... not velocity: delta lambda / lambda = H' D. Since delta lambda over lambda is dimensionless, the units for H' would be Mpc^-1. Where H' = H / c. [The conversion (at least at resolvable Cepheid distance) is straightforward doppler effect: delta lambda / lamda = v / c.] Both equations are the same observable effect. Both are explicitly linear, as written. Now, let us examine a simple exponential version: delta lambda / lambda = 1 - exp(-mu D) delta lambda / lambda = mu D + (mu D)^2 / 2 - ...... At near distances (like those of resolvable Cepheid stars), there is no way to distinguish the linear from the exponential change. At substantial distances (like those of the newer supernovae data), however, the higher order terms in the approximation are no longer negligible. The variation of H(t) with t is also no longer negligible. Only if you assume that H is always linear. Sure, you can make this assumption. But it's not the only one available. So, I could as easily use: delta lambda / lambda = 1 - exp(-H' D) No, instead of the constant value H', you need to use H(t) and integrate the effect over the lookback time. Only if the value changes with time. Which isn't the only option. The converse (finding the time from z) is mentioned in equation (29) of: http://www.astro.ufl.edu/~guzman/ast...project01.html Yes, I know. But this is irrelevant to the point under discussion. In the case of the linear assumptions, the supernovae data must be addressed through an additional, ad hoc, cosmological term. In the case of the exponential fit, no additional cosmological term is needed. That is not true, On the contrary, it is explicitly true. This is called "dark energy" or the "cosmological constant." you are oversimplifying by ignoring the variation of H(t) at high redshift. I did not "ignore" your assumption of time-dependence. Because it is used solely to get around the linear distance dependence that I am discussing. This produces non-linearity even when there is a linear relationship with distance at any given epoch. Yes. But the fact that you can arbitrarily add an ad hoc time-dependence to a linear term; does not mean that a non-linear term is just as valid. Why do you avoid acknowledging that a nonlinear term is even conceivable? -- greywolf42 ubi dubium ibi libertas {remove planet for e-mail} |
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