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(Apologies if this thread goes diverted, this google retriveable
errors driving me up the wall.) Ian Beardsley wrote on my glowing phosphorescence screen: Wouldn't such a radius depend on the direction you go, like towards the center of the galaxy would be brighter than going in the opposite direction, or am I looking at this the wrong way?--Ian Well no because the Milky Way's centre is so far away from the sun, it will be negligible in how bright it looks from going _inwards_ toward it compared to going _outward_ away from it. Besides Ahad's flux constant is a derivative of the milky way + nearby stars. So the radius ought to be fixed, I think. Then suppose saying that, does the sun radiate equally in all directions? If the sun has more power equatorial;ly, (because it is _flat_) then Ahad's _vanity sphere_ may actually be no sphere at all, but a _spereoid_ instead! Who knows... Rob |
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"Robert" wrote in message
om... (Apologies if this thread goes diverted, this google retriveable errors driving me up the wall.) Ian Beardsley wrote on my glowing phosphorescence screen: Wouldn't such a radius depend on the direction you go, like towards the center of the galaxy would be brighter than going in the opposite direction, or am I looking at this the wrong way?--Ian Well no because the Milky Way's centre is so far away from the sun, it will be negligible in how bright it looks from going _inwards_ toward it compared to going _outward_ away from it. Besides Ahad's flux constant is a derivative of the milky way + nearby stars. So the radius ought to be fixed, I think. You only have to stand outside on a clear night under non light-polluted skies to know that the average light flux differs from place to place in the sky. The Milky Way has a much higher average illumination per square degree than, say, directions galactic-poleward. |
#3
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![]() "Greg Neill" wrote in message .. . "Robert" wrote in message om... (Apologies if this thread goes diverted, this google retriveable errors driving me up the wall.) Ian Beardsley wrote on my glowing phosphorescence screen: Wouldn't such a radius depend on the direction you go, like towards the center of the galaxy would be brighter than going in the opposite direction, or am I looking at this the wrong way?--Ian Well no because the Milky Way's centre is so far away from the sun, it will be negligible in how bright it looks from going _inwards_ toward it compared to going _outward_ away from it. Besides Ahad's flux constant is a derivative of the milky way + nearby stars. So the radius ought to be fixed, I think. You only have to stand outside on a clear night under non light-polluted skies to know that the average light flux differs from place to place in the sky. The Milky Way has a much higher average illumination per square degree than, say, directions galactic-poleward. True but he is finding the surface where the solar flux is equal to the total flux from the rest of the sky. That will be close to a sphere centered on the Sun, though the nearby stars may dimple it a bit, so defining a mean radius seems reasonable. George |
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Didn't Greg Neill write on my glowing screen in such colourful
language: You only have to stand outside on a clear night under non light-polluted skies to know that the average light flux differs from place to place in the sky. The Milky Way has a much higher average illumination per square degree than, say, directions galactic-poleward. Ahhaa, but the sphere is a conceptual one, and based on _total_ flux of the night sky. Its radius is only 0.18 - light year compared to a 30,000 light year distance to the centre of our galaxy. So whether you are 0.18 light-year out from the sun in a direction _opposite_ to the galactic core or _toward_ the galactic core, the point of flux equivalence will be the same. Check his vanity art-- http://uk.geocities.com/aa_spaceagen...erstellar.html My other Q, is does the sun radiate _equally_ equatorially as polar? That could change the dimensions of this sphere of light. Rob |
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robert wrote:
Didn't Greg Neill write on my glowing screen in such colourful language: You only have to stand outside on a clear night under non light-polluted skies to know that the average light flux differs from place to place in the sky. The Milky Way has a much higher average illumination per square degree than, say, directions galactic-poleward. Ahhaa, but the sphere is a conceptual one, and based on _total_ flux of the night sky. Its radius is only 0.18 - light year compared to a 30,000 light year distance to the centre of our galaxy. So whether you are 0.18 light-year out from the sun in a direction _opposite_ to the galactic core or _toward_ the galactic core, the point of flux equivalence will be the same. Check his vanity art-- http://uk.geocities.com/aa_spaceagen...erstellar.html My other Q, is does the sun radiate _equally_ equatorially as polar? That could change the dimensions of this sphere of light. Good question! I don't know the answer :-) However, I suspect there might be a slight bias toward the equatorial regions because of sunspots during the peak in the solar cycle. But there are also strong solar flares that occur during this time near the equatorial regions. Also, I understand that the solar wind from the polar regions of the Sun is almost twice as fast as from the equatorial regions during the solar cycle minimums (not sure how this affects the radiated flux though). Rob |
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![]() Alfred A. Aburto Jr. wrote: My other Q, is does the sun radiate _equally_ equatorially as polar? That could change the dimensions of this sphere of light. Good question! I don't know the answer :-) However, I suspect there might be a slight bias toward the equatorial regions because of sunspots during the peak in the solar cycle. But there are also strong solar flares that occur during this time near the equatorial regions. Also, I understand that the solar wind from the polar regions of the Sun is almost twice as fast as from the equatorial regions during the solar cycle minimums (not sure how this affects the radiated flux though). Doesn't a pulsar flash mainly equatorially, and this is similar to the sun. So the sun has a definite _flatenning profile_ on its sphere because of faster rotation. So I am thinking sun radiates more energy equatorially than polar? Was there some findings on Ulyssis that flew over the sun few years back.. Jav |
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