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![]() Discrete Scale Relativity models subatomic particles as quantized Kerr- Newman ultracompact objects. In the following paper the masses of 27 well-known particles were retrodicted at the 98.4% level, on average. http://arxiv.org/ftp/astro-ph/papers/0701/0701006.pdf [see section 4] The relevant equation based on a Kerr solution is M = (sqrt n)(revised Planck mass of 674.8 MeV). Here is a demonstration for a particle NOT included in the published paper. J/Psi mass = 3095 MeV Does the M = (sqrt n)(674.8 MeV) equation work for J/Psi? You betcha! M = (sqrt 21)(674.8 MeV) = 3092.3 MeV That's agreement at the 99.9% level. No quarks needed. Just classical General Relativity and a little Quantum Mechanics. Hmmm, time for a new paradigm? RLO www.amherst.edu/~rloldershaw |
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On Apr 16, 5:47*pm, General Omar Windbottom
wrote: Discrete Scale Relativity models subatomic particles as quantized Kerr- Newman ultracompact objects. In the following paper the masses of 27 well-known particles were retrodicted at the 98.4% level, on average. *http://arxiv.org/ftp/astro-ph/papers/0701/0701006.pdf* * *[see section 4] The relevant equation based on a Kerr solution is M = (sqrt n)(revised Planck mass of 674.8 MeV). Here is a demonstration for a particle NOT included in the published paper. J/Psi mass = 3095 MeV Does the M = (sqrt n)(674.8 MeV) equation work for J/Psi? *You betcha! M = (sqrt 21)(674.8 MeV) = 3092.3 MeV Regarding the J/psi (a charmonium vector meson), of what significance is the number 21? In other words, 21 quantum units of what? That's agreement at the 99.9% level. So? Demonstrate that this is not mere numerology. Try beginning with the actual measurements of particle masses with their actual margins of error, back-derive your alleged values of n without skipping over particles which you don't like (such as the electron (0.511) or the delta baryon (1232)), and then do a proper statistical analysis of the results, taking into account that the square-root function produces values which get progressively closer to each other for progressively larger integer n. [snip] DWIII |
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On Apr 18, 12:08*pm, DWIII wrote:
Done that, in spite of several glaring inconsistencies within that paper, inconsistencies between that paper and your claims here and on other fora, and clear evidence of cherry-picking from the available data. Would you care to specify what the problems are, rather than just insinuate putative problems? Also note that the value of a new theoretical model lies not on just retrodiction, but also very much on falsifiable predictions. *For example, what new particles does your model predict for those values of n that are conspiciously missing from your table? The linked paper contains a major, multi-component, definitive prediction. Specifically it is that going from the Kerr solution to the full Kerr-Newman solution with give one the fine structure of the particle mass function, rather than just a rough 1st approximation based on the Kerr solution. I have not done this, and to my knowledge no one else has either, so at this point no one can know whether this works the way I predict it will or not. Therefore it is a definitive prediction. Frankly, I wouldn't be a bit surprized if one could achieve similar results by selective derivation from the collective literary works of James Joyce. Let's see you use that method to retrodict the mass of the J/Psi particle at the 99.9% level. Put up or shut up. Yes, QCD is thorny in that regard (http://en.wikipedia.org/wiki/ Lattice_QCD). Wow, we agree on something! See how easy it is. With my method one person can achieve better results (for 28 particles!) with a hand calculator and a few hours of free time. *That is worth thinking about. For the most massive hadrons, a trivial summation of quark masses is even easier, just as (or more than as) accurate, and one hardly needs a calculator for that. Yes but you have to put in the quark masses BY HAND!!! Get it? The substandard model cannot predict the masses of the quarks or the Higgs bozo. It's all fudged to fit the experimental data. I derive the revised Planck mass from first principles, then use it and GR to retrodict particle masses. DO YOU SEE THE HUGE DIFFERENCE BETWEEN THE SUBSTANDARD MODEL'S PTOLEMAIC MODEL-BUILDING AND THE DISCRETE SELF- SIMILAR PARADIGM'S DERIVATION FROM PRINCIPLE? Do you want to see the diference? Or do you not want to see the difference? Yours in science, RLO www.amherst.edu/~rloldershaw |
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On Apr 18, 5:31 pm, General Omar Windbottom
wrote: On Apr 18, 12:08 pm, DWIII wrote: Done that, in spite of several glaring inconsistencies within that paper, inconsistencies between that paper and your claims here and on other fora, and clear evidence of cherry-picking from the available data. Would you care to specify what the problems are, rather than just insinuate putative problems? The bulk of your paper claims to deal with hadron mass spectroscopy, but brings in the muon and tau leptons, and also small nuclei such as H3, He3, and He4 for no apparent reason. You suggest in the paper that higher values of n (n10) seem to be preferentially even (by way of vague allusion to nuclear "magic numbers"), but brazenly announce here that n=21 for the J/psi is somehow an additional confirmation. Also, the J/psi spin-1 meson (3097) is an excited state of the eta_c spin-0 meson (2980) which you ignore, along with the previously mentioned delta baryon (1232). Why? Because they don't "fit"? Also note that the value of a new theoretical model lies not on just retrodiction, but also very much on falsifiable predictions. For example, what new particles does your model predict for those values of n that are conspiciously missing from your table? The linked paper contains a major, multi-component, definitive prediction. Specifically it is that going from the Kerr solution to the full Kerr-Newman solution with give one the fine structure of the particle mass function, rather than just a rough 1st approximation based on the Kerr solution. I have not done this, and to my knowledge no one else has either, so at this point no one can know whether this works the way I predict it will or not. Therefore it is a definitive prediction. Which is not what I asked for. What particle is represented by n=9? What properties (if it existed) would it have other than trivially being within a small range of mass? [snip] I derive the revised Planck mass from first principles, then use it and GR to retrodict particle masses. You have done nothing of the sort. With suitable scaling, you might as well be retrodicting _any_ given set of real-world or randomly- generated data with similarly unimpressive results. DWIII |
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On Apr 18, 7:15*pm, DWIII wrote:
Firstly, it is clear that you are involved in a gladiatorial battle and not in a search for a better understanding of nature. You have no interest in finding anything of value in the Discrete Self-Similar Paradigm. Instead you feel you must kill it because it is a threat to your world view. Knowing that, I will still continue to make my case for the benefit of those readers who maintain an open mind and a keen interest in a better understanding of nature. The bulk of your paper claims to deal with hadron mass spectroscopy, but brings in the muon and tau leptons, and also small nuclei such as H3, He3, and He4 for no apparent reason. No, no! That is a main point. Atomic Scale mass is discretized and it does not matter whether the masses are called "leptons" or "hadrons" or "nuclei". They are ALL Kerr-Newman ultracompact objects (black holes and virtually naked singularities) and regardless of what "family" of particles they belong to, they still obey the discrete mass spectrum of the Atomic Scale. This is due to the fact that only certain combinations of J, M and q are allowed as stable states or excited states. Understand now? that higher values of n (n10) seem to be preferentially even (by way of vague allusion to nuclear "magic numbers"), but brazenly announce here that n=21 for the J/psi is somehow an additional confirmation. I expect that each of the n values will have a particle or resonance, unless the K-N model forbids it. Also, the J/psi spin-1 meson (3097) is an excited state of the eta_c spin-0 meson (2980) which you ignore, along with the previously mentioned delta baryon (1232). *Why? *Because they don't "fit"? The J/Psi "fits" at the 99.9% level The n = 19 gives (sqrt 19)(674.8 MeV) = 2941 MeV ( agrees well w/2980, 98.7%) The n = 3 gives (sqrt 3)(674.8 MeV) = 1168 MeV (off by ~5% from 1232) But we will not really know how well this idea can do until the full K- N solution is used. Get it - the Kerr solution is only a 1st approximation? The linked paper contains a major, multi-component, definitive prediction. *Specifically it is that going from the Kerr solution to the full Kerr-Newman solution with give one the fine structure of the particle mass function, rather than just a rough 1st approximation based on the Kerr solution. *I have not done this, and to my knowledge no one else has either, so at this point no one can know whether this works the way I predict it will or not. *Therefore it is a definitive prediction. Which is not what I asked for. *What particle is represented by n=9? What properties (if it existed) would it have other than trivially being within a small range of mass? The Xi (2030 MeV) = (sqrt 9)(674.8 MeV) = 2024 MeV at the 99.7% level. You can look up the properties on your own. Getting the picture yet? I derive the revised Planck mass from first principles, then use it and GR to retrodict particle masses. You have done nothing of the sort. *With suitable scaling, you might as well be retrodicting _any_ given set of real-world or randomly- generated data with similarly unimpressive results. If you understood the Discrete Self-Similar Paradigm and its even more restricted form of Discrete Scale Relativity, then you would know that the scaling equations were published in 1985 and the new paradigm is based on definite principles. It cannot be fudged or "adjusted", and it makes definitive predictions. But of course, "The Church of the Substandard Paradigm" does not want competitors and its defenders/apologists work like the devil to stamp out any "unorthodox" thought. Theoretical physicists are often quoted in Nature and the NYTimes saying: 'If there were good new ideas out there we would embrace them and study them diligently'. I don't know if they realize their disconnect with reality. Most humans fight against challenges to their world views with a closed-minded tenacity. Alas. Send more "criticism". Since nature seems to smile on the Discrete Self-Similar Cosmological Paradigm, I have full confidence that I can defend it against you, or Lenny Susskind, or Stephen Weinberg, or Frank Wlizcek, or Ed Witten, or T'Hooft, or Igor Khav..., or whoever. RLO www.amherst.edu/~rloldershaw |
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On Apr 18, 9:48*pm, General Omar Windbottom
wrote: On Apr 18, 7:15*pm, DWIII wrote: Firstly, it is clear that you are involved in a gladiatorial battle and not in a search for a better understanding of nature. *You have no interest in finding anything of value in the Discrete Self-Similar Paradigm. *Instead you feel you must kill it because it is a threat to your world view. Knowing that, I will still continue to make my case for the benefit of those readers who maintain an open mind and a keen interest in a better understanding of nature. Glad to hear you intend to make such an effort; I wouldn't have it otherwise, even though it seems the "Paradigm" has already died several times over. Benefit for the onlookers, as you say; but why is this not posted on sci.physics in the first place (where it belongs)? [snip] Also, the J/psi spin-1 meson (3097) is an excited state of the eta_c spin-0 meson (2980) which you ignore, along with the previously mentioned delta baryon (1232). *Why? *Because they don't "fit"? The J/Psi "fits" at the 99.9% level The n = 19 gives (sqrt 19)(674.8 MeV) = 2941 MeV ( agrees well w/2980, 98.7%) The n = 3 gives (sqrt 3)(674.8 MeV) = 1168 MeV (off by ~5% from 1232) But we will not really know how well this idea can do until the full K- N solution is used. *Get it - the Kerr solution is only a 1st approximation? Let's focus on these two so-called "retrodictions", shall we? For simplicity, I will grant you your 674.8 MeV; let's call it "k". According to: m = k*sqrt(n) the associated differential equation is: dm = (1/2)*k*n^(-1/2)*dn which we can approximate as: Dm =approx (1/2)*k*n(-1/2)*Dn where Dm and Dm stand respectively for "delta m" and "delta n" for reasonably small changes in "n". Agreed? Rewriting this in terms of Dm/m (the ratio of the corresponding change in mass to the total mass, which easily converts to a percentage, your favorite method of comparison): Dm/m =approx Dn/2n Notice that "k" cancels out, showing how irrelevant it is. For n=19, let us also assume the worst possible case that the actual value of n is off by a full 0.5, knocking quantization for a loop: Dm/m =approx 0.5/(2*19) = 0.013 = 1.3% yielding 1.3 % knocked off of 100%, and thus equivalent to an "accuracy" of 98.7% Doesn't look so impressive now, does it? n=3 fares little better; any n from 2.85 to 3.15 will yield Dm/m within 5% of 100% for an "accuracy" not less than 95%. The linked paper contains a major, multi-component, definitive prediction. *Specifically it is that going from the Kerr solution to the full Kerr-Newman solution with give one the fine structure of the particle mass function, rather than just a rough 1st approximation based on the Kerr solution. *I have not done this, and to my knowledge no one else has either, so at this point no one can know whether this works the way I predict it will or not. *Therefore it is a definitive prediction. Which is not what I asked for. *What particle is represented by n=9? What properties (if it existed) would it have other than trivially being within a small range of mass? The Xi (2030 MeV) = (sqrt 9)(674.8 MeV) = 2024 MeV at the 99.7% level.. You can look up the properties on your own. *Getting the picture yet? There are in fact several resonances of the Xi baryon; that particular one is neither the lowest, nor the currently-known highest. Cherry- picking again, aren't we? DWIII |
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On Apr 18, 9:48*pm, General Omar Windbottom
wrote: [snip] The J/Psi "fits" at the 99.9% level The n = 19 gives (sqrt 19)(674.8 MeV) = 2941 MeV ( agrees well w/2980, 98.7%) The n = 3 gives (sqrt 3)(674.8 MeV) = 1168 MeV (off by ~5% from 1232) But we will not really know how well this idea can do until the full K- N solution is used. *Get it - the Kerr solution is only a 1st approximation? A brief side note: http://en.wikipedia.org/wiki/Texas_sharpshooter Need I say more? DWIII |
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