|
|
|||||||
|
|
Thread Tools | Display Modes |
|
#1
October 14th 09, 09:46 AM
posted to sci.astro.amateur
|
|||
|
|||
urgent need of solution
what is the probablity of getting 4 threes by throwing 10 dice
nubering 1 to 6. 
|
|
#2
October 15th 09, 04:47 PM
posted to sci.astro.amateur
|
|||
|
|||
|
urgent need of solution
"sudra" wrote in message ... what is the probablity of getting 4 threes by throwing 10 dice nubering 1 to 6. I believe the answer is 0.054266.
|
|
#3
October 16th 09, 10:55 PM
posted to sci.astro.amateur
|
|||
|
|||
|
urgent need of solution
On Oct 15, 8:47 am, "TR Oltrogge" wrote:
"sudra" wrote in message ... what is the probablity of getting 4 threes by throwing 10 dice nubering 1 to 6. I believe the answer is 0.054266. Hi Is the problem to throw only 4 threes and not more or throw at least 4 threes? Dwight
|
|
#4
October 17th 09, 02:35 AM
posted to sci.astro.amateur
|
|||
|
|||
|
urgent need of solution
wrote in message ... On Oct 15, 8:47 am, "TR Oltrogge" wrote: "sudra" wrote in message ... what is the probablity of getting 4 threes by throwing 10 dice nubering 1 to 6. I believe the answer is 0.054266. Hi Is the problem to throw only 4 threes and not more or throw at least 4 threes? Dwight My answer assumed *only* 4 threes and no more. Tim
|
|
#5
October 17th 09, 03:56 AM
posted to sci.astro.amateur
|
|||
|
|||
|
urgent need of solution
On Oct 14, 1:46*am, sudra wrote:
what is the probablity of getting 4 threes by throwing 10 dice nubering 1 to 6. Well, you start w/ 6 to the 10th power, plus One... berk I worked that part out for myself when I was in the single digits....
|
|
#6
October 17th 09, 04:04 AM
posted to sci.astro.amateur
|
|||
|
|||
|
urgent need of solution
On Oct 16, 7:56*pm, TBerk wrote:
On Oct 14, 1:46*am, sudra wrote: what is the probablity of getting 4 threes by throwing 10 dice nubering 1 to 6. Well, you start w/ 6 to the 10th power, plus One... berk I worked that part out for myself when I was in the single digits.... Wait, I think I need to amend my response... That would be 6 x 6 x6 x6 x6 x6 x6 x6 x6 x6, minus One... Sorry, it's been a long time since I was a young child. And of course, that's only the beginning. berk
|
|
#7
October 17th 09, 03:33 PM
posted to sci.astro.amateur
|
|||
|
|||
|
urgent need of solution
"TBerk" wrote in message ... On Oct 14, 1:46 am, sudra wrote: what is the probablity of getting 4 threes by throwing 10 dice nubering 1 to 6. Well, you start w/ 6 to the 10th power, plus One... berk I worked that part out for myself when I was in the single digits.... Hmmmmm, not sure what "plus One..." is all about, but 6 to the 10th power is the denominator of the probability fraction and represents the total number of possible outcomes when rolling 10 dice, all outcomes of which have an equal probability of occuring. The numerator is the total number of outcomes that meet the "success" criterion of having exactly 4 threes and that is given by... 10! ------- * 5 ^ 6 4! * 6! Thus, the probability fraction (numerator and denominator) is... 10! ------- * 5 ^ 6 4! * 6! ---------------- = 0.054266 (to five significant digits) 6 ^ 10 Tim
|
| Thread Tools | |
| Display Modes | |
|
|
Similar Threads
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| urgent! | [email protected] | Amateur Astronomy | 27 | March 8th 09 12:50 PM |
| Web page for first dark matter solution, solution made in June, 2007,3D wheels | gb[_3_] | Astronomy Misc | 0 | December 14th 08 11:01 PM |
| Get back to me urgent. | gawazo | Misc | 1 | June 7th 08 05:47 PM |
| Get back to me urgent. | gawazo | Misc | 0 | May 28th 08 05:54 PM |
| Urgent: Help Us Help Other | [email protected] | Solar | 0 | December 20th 03 09:24 PM |
Linear Mode
