What will be the gravity if we dig a hole in earth?

BG A 199LB man weighs 200LB at the north pole. That has to tell you
something Go figure Trebert

Bert wrote,

A 199LB man weighs 200LB at the north
pole. That has to tell you something.

The difference will register on a spring scale, but not on a balance
scale.

On Jan 9, 4:03*pm, (G=EMC^2 Glazier) wrote:
BG A 199LB man weighs 200LB at the north pole. That has to tell you
something * Go figure *Trebert


In lbf but not lbm.

Double-A

On Jan 9, 4:03*pm, (G=EMC^2 Glazier) wrote:
BG A 199LB man weighs 200LB at the north pole. That has to tell you
something * Go figure *Trebert

Yes, it tells us about centripetal force.

The 384,400 km tidal radius of having Selene in orbit is what takes
2e20 N/sec (20.4e18 kgf) of centripetal force = 55.555e12 kw

That's also the amount of mutual gravity attraction. (impressive,
isn't it)

~ BG

oc right you are. If not for a balance scale a person could make a
fortune of money on gold. Best to realize that is why a balance scale is
used. Still its interesting how that 13 mile bulge figures,and
centrifugal force of a 1030 mph does not meAN VERY MUCH Go figure
Trebert

Bert wrote,

Still its interesting how that 13 mile
bulge figures, and centrifugal force of a
1030 mph does not mean very much.

Maybe one of the resident math jockeys could calcumilate just how much
the centrifufagal effect figures into the weight differnce.

On Jan 10, 4:37*am, (G=EMC^2 Glazier) wrote:
oc right you are. If not for a balance scale a person could make a
fortune of money on gold. Best to realize that is why a balance scale is
used. Still its interesting how that 13 mile bulge figures,and
centrifugal force of a 1030 mph does not meAN VERY MUCH *Go figure
Trebert

Add 384,400 km to that radius, and 1.023 km/s velocity to the 7.35e22
kg mass, and lo and behold you've got a centripetal force of 2e20 N/
sec to deal with. No wonder the crust of Earth flexes by 55 cm.

~ BG

oc True since gravity and motion are equivalent. That tornado
ride(Revere Beach) kept me pressed to the wall and it was not going all
that fast. Jupiter spin of about once in 10 hours has to show its
centrifugal effects. Possibly keeps that red eye vortex going. I read
that red spot scoots around the planet. Amazing 3 Earths can fit inside
that red spot go figure TreBert

On Jan 10, 5:15*am, (oldcoot) wrote:
Bert wrote,

Still its interesting how that 13 mile
bulge figures, and centrifugal force of a
1030 mph does not mean very much.

Maybe one of the resident math jockeys could calcumilate just how much
the centrifufagal effect figures into the weight differnce. *


"The nominal value of g on a smooth Earth, taking into account
oblateness and rotation is, at sea level:


g = 9.78031846(1+0.005278895sin^2(phi)+0.000023462sin^ 4(phi))


where phi is the latitude of the location."


Unfortunately the site I originally got this formula from is no longer
functional.

Double-A