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"Uncle Al" wrote in message
... Dieter Britz ,in ... There used to be, at least, an October issue of some physics journal (Physics Today?) in which there was an update on the values of some physical constants. Which journal was that please, and is it still doing that October issue? I am trying to find out how the Avogrado constant can be measured to about 8-9 decimal plces, when it surely must involve weighing some sample of matter. Dieter Britz, Kemisk Institut, Aarhus Universitet, Danmark. [Al] Current accepted value 6.0221415(10) x 10^23/mol, http://physics.nist.gov./cgi-bin/cuu...s.x=78&All+val ues.y=18 1998 CODATA, 6.02214199(47) x 10^23/mol However, folks doing exceptionally accurate x-ray diffraction on silicon (to replace the Pt-Ir kilogram artifact) get a different value, ............... Becker, P. et al. "Determination of the Avogadro constant via the silicon route," Metrologia 40 271-287 (2003) 6.0221353 x 10^23/mol PTB Standards Laboratory in Braunschweig, Germany thus gives number which is way the Hell different. http://www.ptb.de/en/index.html Uncle Al [hanson] There seem to be more to Avogadro's constant, N_A, then is normally portrayed about it in literature. These, N_A's unspoken traits, may be one of the causes giving the problems that make it difficult to nail down a very accurate numerical result for N_A. It may have to do with the fact that all fundamental, physical constants are ultimately compared to and expressed in/by the (completely arbitrated/chosen/selected) metric system units, AND... complicating that fact is that N_A is tied to other fundamental physical constants such as h, c, and G, & so it is difficult to say which is the most fundamental one. h & c have been measured to great accuracy, but Newton's G is still problematic when it comes to the accuracy of its numerical value. There are a few old (1930?) relations/equations that may illuminate this accuracy-dependcency problem, such as: One mole of Planck time equals the atomic time unit: tau / t_pl = a^(-1) * (N_A*pi*sqrt3) or one mole of Planck length equals the H-Bohr radius or the classical electron radius: r_H / l_pl = a^(0) * (N_A*pi*sqrt3) r_e / l_pl = a ^(2) * (N_A*pi*sqrt3) or that one mole of electron masses equals the Planck mass m_pl / m_e = a^(1) * (N_A*pi*sqrt3) So, since all Planck units are combos of hbar, c & G, one can see that there are, for instance, the following relationsships between N_A and Newton's G, when re-expressing the above equations by straight forward means and substituting the Planck units, *_pl, with hbar, c, & G, as: G * N_A^2 = [1/3] * [ hbar * c] / [pi* a* m_e]^2 = const or equivalently: G * N_A^2 = [2/(3pi)] * [c^3] * [r_H^2 / h] = const or there are others like, G * N_A^2 = f(tau, etc) = f(Lyman freq, etc) = const These 2 lines loosely state or can be interpreted as to say that the product of the gravitational mass attraction at the gigantic mole-squared size level has something to do with or is equivalent to expressing some gravitational event/state or phenomena seen quantized (hbar) at the atomic level caused by EM effects. It may be akin to something like k*N_A = R(gas) or e*N_A = F where N_A couples the atomic domain of heat or electricity to/with the everyday cgs/MKS mole sized experience in the respective fields. Similarly, this G* N_A^2 product may be applicable/useful to estimate gravitational effects on other then the levels/magnitudes/domains where G is currently measured or tested at. From/with these two equations we can concoct a further story, a theory, for the accuracy issue at hand. 1) I leave it to the aficionado to make the numerical error analysis with the right side (atomic realm) of these 2 equations. 2) the result of (1) gives the projected possible min. uncertainty or max. accuracy spread of the product of G * N_A^2. 3) Being deep in the atomic domain here, where uncertainty is the order of the day (according to heuristic paradigm) we may have a demonstration and example of the HUP, manifesting itself here in the uncertainty of either G or N_A values. If so, then only the unwieldy product of G * N_A^2 may be of or may have a "fixed +/-" determinable numerical size/value, but either one of each one, the N_A or G values alone, may only be knowable in its accuracy at the expense of the accuracy of the other one. ... Classic HUP gig??..... However, since this product of G * N_A^2 is having the size of ~ 10^40 cm^3/(gr*s^2*mol^2), I won't loose too much sleep over it....unless some clever ****, or a dumb one by luck, discovers a new amplification mechanism thru which this product affects visibly/phenomenologically our macroworld and shows up measurably in the games that are playing out in astronomy, astrophysics or cosmology............will see! it would be rad!....... ahahahaha...... ahahahahanson ref: 11-avogadro-3 |
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![]() Uncle Al, mensa. Has a badge and everything. Prodes himself on his math. (Has no personal skills but then Einstein had trouble tieing his shoes, and I am too lazy to use a spell checker. Uncle Al's position. to find out how the Avogrado constant can be measured to about 8-9 decimal plces, when it surely must involve weighing some sample of matter. Dieter Britz, Kemisk Institut, Aarhus Universitet, Danmark. hanson's position. (sorry hanson, unless you are a member of a boy band, I do not know who you are, so I cannot comment on your person. We will assume you are a normal genius.) It may have to do with the fact that all fundamental, physical constants are ultimately compared to and expressed in/by the (completely arbitrated/chosen/selected) metric system units, AND... complicating that fact is that N_A is tied to other fundamental physical constants such as h, c, and G, & so it is difficult to say which is the most fundamental one. h & c have been measured to great accuracy, but Newton's G is still problematic when it comes to the accuracy of its numerical value. There are a few old (1930?) relations/equations that may illuminate this accuracy-dependcency problem, such as: One mole of Planck time equals the atomic time unit: tau / t_pl = a^(-1) * (N_A*pi*sqrt3) or one mole of Planck length equals the H-Bohr radius or the classical electron radius: r_H / l_pl = a^(0) * (N_A*pi*sqrt3) r_e / l_pl = a ^(2) * (N_A*pi*sqrt3) or that one mole of electron masses equals the Planck mass m_pl / m_e = a^(1) * (N_A*pi*sqrt3) So, since all Planck units are combos of hbar, c & G, one can see that there are, for instance, the following relationsships between N_A and Newton's G, when re-expressing the above equations by straight forward means and substituting the Planck units, *_pl, with hbar, c, & G, as: G * N_A^2 = [1/3] * [ hbar * c] / [pi* a* m_e]^2 = const or equivalently: G * N_A^2 = [2/(3pi)] * [c^3] * [r_H^2 / h] = const or there are others like, G * N_A^2 = f(tau, etc) = f(Lyman freq, etc) = const These 2 lines loosely state or can be interpreted as to say that the product of the gravitational mass attraction at the gigantic mole-squared size level has something to do with or is equivalent to expressing some gravitational event/state or phenomena seen quantized (hbar) at the atomic level caused by EM effects. It may be akin to something like k*N_A = R(gas) or e*N_A = F where N_A couples the atomic domain of heat or electricity to/with the everyday cgs/MKS mole sized experience in the respective fields. Similarly, this G* N_A^2 product may be applicable/useful to estimate gravitational effects on other then the levels/magnitudes/domains where G is currently measured or tested at. From/with these two equations we can concoct a further story, a theory, for the accuracy issue at hand. 1) I leave it to the aficionado to make the numerical error analysis with the right side (atomic realm) of these 2 equations. 2) the result of (1) gives the projected possible min. uncertainty or max. accuracy spread of the product of G * N_A^2. 3) Being deep in the atomic domain here, where uncertainty is the order of the day (according to heuristic paradigm) we may have a demonstration and example of the HUP, manifesting itself here in the uncertainty of either G or N_A values. If so, then only the unwieldy product of G * N_A^2 may be of or may have a "fixed +/-" determinable numerical size/value, but either one of each one, the N_A or G values alone, may only be knowable in its accuracy at the expense of the accuracy of the other one. ... Classic HUP gig??..... However, since this product of G * N_A^2 is having the size of ~ 10^40 cm^3/(gr*s^2*mol^2), I won't loose too much sleep over it....unless some clever ****, or a dumb one by luck, discovers a new amplification mechanism thru which this product affects visibly/phenomenologically our macroworld and shows up measurably in the games that are playing out in astronomy, astrophysics or cosmology............will see! it would be rad!....... ahahahaha...... ahahahahanson ref: 11-avogadro-3 (Well almost normal genius) My position. If you take a big pile of pure gold. One atom of pure gold, will be exactly divisible to this larger pile of gold. There are no half atoms. How would one weigh an atom of gold? First, one would look at the most accurate measurement to date, of the expansion of the universe to arrive at G. Based on the fact, that the universe is expanding, causing gravity. You can then say, that with a force of G, the nucleus of the gold atom, is generating an electron with the energy of e*79 http://education.jlab.org/qa/pen_number.html That is to say that it is causing a wave of energy equal to e*79 What this does, is to bridge the gap between the quantum world, (you would use your little measuring units based on accurate information of the Hydrogen atom, and we called it the motam.) ;the macro, you have purified a block of gold and placed it in a tall vacuum bell jar and you dropped it at sea level and timed it's decent with a laser and a cesium clock.) and the astronomical with the Hubble telescope and Hubbles constant to obtain G the universal gravitational constant. Now you can hypothetically weigh one atom of gold, and arrive at the proper Avagrado's number. What you will find, is that if you use these new measuring units which you name, based on fundamental values, instead of such things as a meter, you will be able to obtain the exact values. Or the best possible values given the most advanced abilities of your present technology. You are trying to make time machines, and do molecular biology, using stone axes and chipped pieces of flint. Once you know the relationships. That gravity is causing electrons. Then all you have to do is measure one accurately. Macro gravity, using the smallest most accuract tools at your disposal, Plank's constant and the value of c, and then you will arrive at a precise value of an electron, which will be a standard value, that is far more accurate, than any Miliken oil drop experiment. Half of the problem with quantum physics is that whenever any value was slightly incorrect, even though the experimenter knew what the result should be, due to the use of know relational formulae, it was deemed necessary, to add a flavor or a spin, or a twist, or some sort of compensating value, when the proper thing to do, is to merely start out with the most accurate tools available for measurement in the first place. I know this is difficult to comprehend for some people. But those who get it, are able to do amazing things with it. Because you find, that in fact, the values and relationships between things on the atomic scale are in fact exact. (Again copper lead zinc etc) And their frequencies also exact. Which can allow you to calibrate equipment exactly, and remove most experimental error. With that, you can begin to see things like other dimensions and other timelines, because you can detect them. The data is not lost in the noise of statistics. So how do you make a C024 dual songularity gravity distortion time machine such as the one John Titor from 2036 had in 2000? http://www.johntitor.com/ http://www.anomalies.net/time_travel/john.html I imagine that a singularity, is an atom, which has no electron waves being emitted. It is stabilized and kept as a nucleus bubble, in exact tune with expansion of the universe, in a vacuum and a magnetic containment field of some sort. Then by applying exact values from a laser, you entice, the nucleus to create the exact electron waves you want, to create the gravitational field you want, keeping in mind, that the closer to the nucleus, the wave crest is, the different your time frame will be from that outside the gravitational field. By spinning the singularity, I assume that it spins it may not, you can form a spiral eddie, and begin to descend back through time, at about 10 years per hour. To get a grav lock, you need to be able to exactly calculate the values that would exist, if you imagined the universe moving in the opposite direction, (opposite to expansion) as per some universal time frame, based on your best cesium clocks. That's my best educated guess. Apparently CERN makes the first singularity in 2004. It probably takes a number of years before the machine is created. It sounds doable to me. |
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In article xN9Eb.18958$gN.3524@fed1read05, dlzc1.cox@net says...
Dear Rick Sobie: "Rick Sobie" wrote in message news:md8Eb.745272$9l5.166726@pd7tw2no... In article . net, says... ... Forget the values for one minute. Let x represent Avagrados number. Let m represent a unit of length. No, I do not mean a meter. Why should I choose a meter as my unit of length? Because in France, is this bar that says meter on it? No. Because that standard is no longer used. The meter is now defined as the speed of light times time. Well what fundamental property of nature, that is exactly relative to this bar of yours, caused you to choose such length? Light and time. Would it not be better then, to choose a unit of length, which is in accordane with some fundamental measurement, that is unchanging and more accurate? Like light and time? Say the radius of the Hydrogen Atom at a certain temperature - in its rest state for instance. A very accurate measurement.... not! Would that not be a more accurate measuring stick, than such an awkward inaccurate item, such as a bar kept in a glass case in some building in France? Old news since the 60's. And if we were to say that the diameter or radius of the Hydrogen atom, was equal to one Motam. (For instance) Then could we not merely say that for each atom in the periodic table, there would exist a predictable value that has a direct relation to this Motam? No. It is just another number. And further if we went ahead and accurately measured all known qualities of the Hydrogen atom, and created a new set of meauring units, such as frequency etc, then would those values not also directly apply to all other atoms? Yes they would. Because thery are all just numbers. Look up the units "barn" and "shed" as relates to nuclear physics. Newton, needed a meter stick. IBM needs a motam. It is just a number. If you read this message enough times, you will understand if you do not understand already. Yes. It went downhill right after you noted that they are just numbers. David A. Smith Well at least someone almost gets it. Just enough to not understand the important bits though I am sure. Which will keep him in his prejudiced closed mindset, and prevent him from understanding why, some people able to create time machines, and some are not. And why some know how to travel with electro gravitics and some do not, and why some can traverse the multiverse through dimensions and why some are not. And why you can learn more from listening to people who have called into old Art Bell shows, than you will ever learn from some of the people here. Why did John Titor he call himself timetraveller_0? Well, you might want to listen to Timetraveller 1 2 and 3 on Kazaa Lite, other possible time travellers who have visited our timeline/worldline. I won't tell you who I believe to be legitamite in the totality of callers to the time traveller call in line, or the paranormal line, or the area 51 line, but for sure, someone in 1997, knew about 9/11 And if this is not a time travel machine, then someone went to a rediculous amount of effort for absolutely no reason. http://www.anomalies.net/time_travel/john.html And David, the next time you go to 2036, tell them I said, that they should take out London England, New York, L.A. Detroit Pittsburg, and Houston. That should be sufficient to teach those evil doers a lesson they will never forget. And that should save the planet. We could go further, and say, if they did, then that would mean that the world would exist past 2050, and then we should see a time traveller from some time past 2050. At this point, there is no civilization past 2050 except for underground. And it stays like that for some 2 million years. The people started dying off in 2015. It took 35 years for them to die off. Now there is one more solution. The arrest of the Bush gang for crimes against humanity, and the complete release of all classified documents in the US and GB with further prosecutions based on those docs. It is not likley they will comply. These are not good people, they could care less if they take their countries with them when they go. |
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![]() "Rick Sobie" wrote in message news:md8Eb.745272$9l5.166726@pd7tw2no... The point that even some Mensa people just seem to have a mental block about, with regards to physics is this. Forget the values for one minute. ok, we'll use seconds instead then....carry on... Let x represent Avagrados number. You've been corrected at least twice and still get it wrong, it is AVOGADRO - unless you have just made up a new constant of course. Let m represent a unit of length. No, I do not mean a meter. Why should I choose a meter as my unit of length? errr, maybe because it's the unit of length used by engineers and physicists Because in France, is this bar that says meter on it? wrong Well what fundamental property of nature, that is exactly relative to this bar of yours, caused you to choose such length? speed of light and time 1m = length of the path traveled by light in a vacuum in the time interval of 1/299,792,458 of a second. Would it not be better then, to choose a unit of length, which is in accordane with some fundamental measurement, that is unchanging and more accurate? the m is a fundamental unit of measurement Say the radius of the Hydrogen Atom at a certain temperature - in its rest state for instance. let me see YOU measure it. Doesn't sound too accurate to me, but go on, convince me. Would that not be a more accurate measuring stick, than such an awkward inaccurate item, such as a bar kept in a glass case in some building in France? no, because you're wrong And if we were to say that the diameter or radius of the Hydrogen atom, was equal to one Motam. (For instance) Then could we not merely say that for each atom in the periodic table, there would exist a predictable value that has a direct relation to this Motam? and this achieves what exactly? Can you imagine how much hastle changing a fundamental unit would cause? Every book of tables would need to be amended, every physical contant would need to be amended, every physics book and paper would need to be amended, every engineering book would need to be amended. And for what? Even with TWO systems of measurement NASA still can't tell the difference between feet and metres. Now you want a third set of untis. And further if we went ahead and accurately measured all known qualities of the Hydrogen atom, and created a new set of meauring units, such as frequency etc, then would those values not also directly apply to all other atoms? no Yes they would. prove it Newton, needed a meter stick. why? IBM needs a motam. why? What is wrong with using nm like the rest of the world? Or pm come to that? The CO24 for time travel, based on dual singularities, and gravity distortion, needs a motam. oh ****! Shiny side out boy, shiny side out! http://zapatopi.net/afdb.html For accuracy. Otherwise you could end up anywhere. If you're basing a fundamental unit on something that can't be measured you could end up anywhere. In the multiverse, 8 decimal places is like horseshoes, and handgrenades. Close just don't make it. ????what??? 8 decimal places of WHAT exactly? Go to 8 decimal places of a pico metre and you're measuring what? So once you create a new measuring stick, you use the same formulas to transpose those measurements to other things in physics, and voila, if it don't all work out to be exact. Where did you say you went to school? Sue the teachers! That sentance just didn't parse Because the relationships between forces, and between things, are exact. tell that to the QM types. As exact as copper is copper, and lead is exactly lead. And a big pile of pure lead, is still exactly lead, just as one atom of lead, is still exactly lead. The smallest units of measurement is Plank length. Can you explain in your own words what Plank Length is please. Using plank length and c, you can meausre the force of gravity. A gazillion times more accurately than with a set of balances. Go for it then I'm not sure how, so please go through the experiment as to how this will be carried out. If you read this message enough times, you will understand if you do not understand already. No, it still makes no sense at all. Grade F- |
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In article 5uaEb.745688$9l5.453170@pd7tw2no, Rick Sobie
wrote: And David, the next time you go to 2036, tell them I said, that they should take out London England, New York, L.A. Detroit Pittsburg, and Houston. That should be sufficient to teach those evil doers a lesson they will never forget. And that should save the planet. And thus Sobie takes just a small step from a discussion of physical constants to end up advocating the killing of millions. Here is a free clue -- look up the meaning of the middle word in Science Fiction/Fantasy. Any English dictionary should help. -=-=-=-=- |
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![]() "Rick Sobie" wrote in message news:md8Eb.745272$9l5.166726@pd7tw2no... [snip] Would it not be better then, to choose a unit of length, which is in accordane with some fundamental measurement, that is unchanging and more accurate? Say the radius of the Hydrogen Atom at a certain temperature - in its rest state for instance. The Hydrogen atom does not have a sharply defined radius. And even if it did, how would you propose to make use of it? [snip] Franz |
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On Thu, 18 Dec 2003 15:45:01 +0000 (UTC), "Franz Heymann"
wrote: "Rick Sobie" wrote in message news:md8Eb.745272$9l5.166726@pd7tw2no... [snip] Would it not be better then, to choose a unit of length, which is in accordane with some fundamental measurement, that is unchanging and more accurate? Say the radius of the Hydrogen Atom at a certain temperature - in its rest state for instance. The Hydrogen atom does not have a sharply defined radius. And even if it did, how would you propose to make use of it? [snip] Franz Rick is here to have conversations with himself and no one else. Don't waste your time. -- Dr.Postman USPS, MBMC, BsD; "Disgruntled, But Unarmed" Member,Board of Directors of afa-b, SKEP-TI-CULT® member #15-51506-253. You can email me at: TuriFake(at)hotmail.com "Shake it like a polaroid picture." - Andre 3000 of Outkast |
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"Franz Heymann" wrote in message ...
"Rick Sobie" wrote in message news:md8Eb.745272$9l5.166726@pd7tw2no... [snip] Would it not be better then, to choose a unit of length, which is in accordane with some fundamental measurement, that is unchanging and more accurate? Say the radius of the Hydrogen Atom at a certain temperature - in its rest state for instance. The Hydrogen atom does not have a sharply defined radius. And even if it did, how would you propose to make use of it? [snip] Franz [EL] Most probably he would end up with a table of conversion from Hatometers to meters. ![]() Just saying the "diameter" of the hydrogen atom implies a spherical shape, which is not so in any static reality but a dynamic one perhaps. The variance of such would cause agony. I prefer a standard measure of the most invariant material length wise when temperature, pressure, humidity and gravitational field vary and to take it as a "long form" such that atomic vibrations become completely insignificant. Thus, rather than finding the shortest length to take as a reference, I would prefer the shank which is about 180 cm long to be a standard measure and extract all other units accordingly. But they are all arbitrations so replacing one by another makes no big difference really. EL |
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