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  #1  
Old October 12th 03, 04:19 PM
Jeff Root
external usenet poster
 
Posts: n/a
Default Up and down the spectrum

I'd like to check my understanding of these factoids about the
EM spectrum. In addition to correcting my errors, what other
characteristics distinguish the various parts of the spectrum?

Radio waves are characterized by their ability to be emitted
and detected by antennae. Metals reflect them; other materials
are transparent to them.

Microwaves are distinguished from other radio waves by their
ability to be channeled by waveguides. Electronic components
used to generate and detect microwaves are about the same size
as the waves themselves.

Infrared is distinguished from radio and microwaves by its
ability to interact with individual electrons in atoms, the
photoelectric effect, and its ability to be optically lensed.
Infrared is absorbed by most materials.

Visible light is distinguished from infrared and ultraviolet
by its visibility to humans. (I'm sure I got this one right!)

Ultraviolet is ionizing. (Starting at what frequencies in
what materials?) UV is absorbed by most materials.

X-Ray is distinguished from ultraviolet by its ability to
penetrate materials, roughly in inverse proportion to the
material's density, and its inability to be optically lensed.

Gamma is distinguished from X-ray by its ability to interact
with nucleons. (Do gammas usually whizz right past electrons
in atoms without interacting? Or do they interact with
electrons just as often as lower-energy X-rays do?)

-- Jeff, in Minneapolis

Subtract 1 from my e-mail address above for my real address.
..
  #2  
Old October 12th 03, 06:07 PM
[email protected] \(formerly\)
external usenet poster
 
Posts: n/a
Default Up and down the spectrum

Dear Jeff Root:

"Jeff Root" wrote in message
om...
I'd like to check my understanding of these factoids about the
EM spectrum. In addition to correcting my errors, what other
characteristics distinguish the various parts of the spectrum?

Radio waves are characterized by their ability to be emitted
and detected by antennae.


antennae - devices made of conductors (such as metals)

Metals


CONDUCTORS

reflect them; other materials
are transparent to them.


translucent might be a better term. There are always losses. I suppose it
doesn't matter, since a color change is not inherent, and translucent can
imply a color change.

Microwaves are distinguished from other radio waves by their
ability to be channeled by waveguides.


The EM spectrum is assigned by wavelength as standard description. The
above sentence would be better stated "Microwaves are distinguished from
other light..."

Electronic components
used to generate and detect microwaves are about the same size
as the waves themselves.


Look at the physical size of a Klystron tube. Much larger than microwaves.
Also reflected by conductors (microwave antenna dishes, for example)

Infrared is distinguished from radio and microwaves by its
ability to interact with individual electrons in atoms, the
photoelectric effect, and its ability to be optically lensed.
Infrared is absorbed by most materials.


You can lens any light, if you can establish a medium with a different
propagation speed. You can lens microwaves, and radio waves. It might
take miles of material to do it with radio waves, but you could do it.

Visible light is distinguished from infrared and ultraviolet
by its visibility to humans. (I'm sure I got this one right!)

Ultraviolet is ionizing. (Starting at what frequencies in
what materials?) UV is absorbed by most materials.


The frequency (or wavelength) thresholds are established by convention.

X-Ray is distinguished from ultraviolet by its ability to
penetrate materials, roughly in inverse proportion to the
material's density, and its inability to be optically lensed.


X-rays can be lensed. At some point lensing is just an engineering
problem. The more dense a material is, the more likely it is to absorb
X-rays.

Gamma is distinguished from X-ray by its ability to interact
with nucleons. (Do gammas usually whizz right past electrons
in atoms without interacting? Or do they interact with
electrons just as often as lower-energy X-rays do?)


Here is where a number of sources will conflict. Gamma is commonly
reserved for light that is emitted from a nuclear decay. In this context
it can be inclusive of what others will call X-rays (in energy).
Personally, I like it if we start out with cutoffs based on wavelength,
that we stick to it.

Gamma is ionizing radiation. The common physical sources are less intense
(in the number of photons emitted) than the average candle. To the gamma
photons emitted from a lump of Co-60, we are like smoke. And thin smoke at
that.

David A. Smith


  #3  
Old October 12th 03, 07:15 PM
Alan Moore
external usenet poster
 
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Default Up and down the spectrum

On 12 Oct 2003 08:19:36 -0700, (Jeff Root) wrote:

I'd like to check my understanding of these factoids about the
EM spectrum. In addition to correcting my errors, what other
characteristics distinguish the various parts of the spectrum?

Radio waves are characterized by their ability to be emitted
and detected by antennae. Metals reflect them; other materials
are transparent to them.

Well, not exactly. Any change in dielectric properties can cause a
reflection. Radar at sufficiently high frequencies will detect
animals, and even at moderate frequencies, flocks of birds or insects.

Microwaves are distinguished from other radio waves by their
ability to be channeled by waveguides. Electronic components
used to generate and detect microwaves are about the same size
as the waves themselves.


This is also true for other radio waves. Just keep in mind the
necessary relationship between waveguide dimension and signal
wavelength, and you'll see that there comes a point at which
waveguides become inconveniently large.

Infrared is distinguished from radio and microwaves by its
ability to interact with individual electrons in atoms, the
photoelectric effect, and its ability to be optically lensed.
Infrared is absorbed by most materials.

Visible light is distinguished from infrared and ultraviolet
by its visibility to humans. (I'm sure I got this one right!)


Indeed. Visibility is the criterion for visibility...

Ultraviolet is ionizing. (Starting at what frequencies in
what materials?) UV is absorbed by most materials.


You can look up ionization potentials for elements in standard
physical and chemical handbooks. Actually this starts in the
infra-red. Otherwise vacuum tubes wouldn't work, as they rely on those
energy levels to get electrons away from the solid cathode and into
the vacuum where they can be accelerated away from it.

X-Ray is distinguished from ultraviolet by its ability to
penetrate materials, roughly in inverse proportion to the
material's density, and its inability to be optically lensed.


Yes, sort of. Whereas lower energy photons may result in ionization of
atoms by ejecting an electron from an outer shell, x-rays may eject
electrons from inner shells.

Gamma is distinguished from X-ray by its ability to interact
with nucleons. (Do gammas usually whizz right past electrons
in atoms without interacting? Or do they interact with
electrons just as often as lower-energy X-rays do?)


As often, or oftener. This is why they are grouped with the "soft"
x-rays and UV as ionizing radiation.

Al Moore
  #4  
Old October 13th 03, 07:47 AM
Jeff Root
external usenet poster
 
Posts: n/a
Default Up and down the spectrum

David A. Smith replied to Jeff Root:

Radio waves are characterized by their ability to be emitted
and detected by antennae.


antennae - devices made of conductors (such as metals)


Do you know of any antenna made of a conductive material other
than metal? Can you provide a link to a description of such
an antenna?

Microwaves are distinguished from other radio waves by their
ability to be channeled by waveguides.


The EM spectrum is assigned by wavelength as standard description.


That has nothing to do with the info I'm looking for.

The above sentence would be better stated "Microwaves are
distinguished from other light..."


How is that better? I worded it as I did to indicate that
microwaves are included in the "radio" part of the spectrum,
but have characteristics that distinguish them from other
radio waves. My understanding is that microwaves and higher
frequencies can be channeled by waveguides, while radio waves
of lower frequencies cannot. My understanding may be way off.
Do the Earth and ionosphere form a waveguide for shortwave
radio? Is that essentially the same phenomenon? If so, then
what *does* distinguish microwaves from other radio waves?

Electronic components used to generate and detect microwaves
are about the same size as the waves themselves.


Look at the physical size of a Klystron tube. Much larger than
microwaves.


It appears that any assertion on the Internet generates its
antithesis. I included the info about the size of components
because of this reply to a similar question last December:

| What distinguishes radio waves from microwaves, and microwaves
| from infrared?
|
| Radio waves which are not microwaves are handled with normal
| electronics, i.e. components which are much smaller than the
| wavelength.
|
| Infrared waves are handled with optics, i.e. components which
| are much larger than the wavelength.
|
| Microwaves are handled with microwave electronics, i.e. components
| which are of approximately the same size as the wavelength.

Do you disagree with that?

Infrared is distinguished from radio and microwaves by its
ability to interact with individual electrons in atoms, the
photoelectric effect, and its ability to be optically lensed.
Infrared is absorbed by most materials.


You can lens any light, if you can establish a medium with a
different propagation speed. You can lens microwaves, and radio
waves. It might take miles of material to do it with radio waves,
but you could do it.


Ah. I asked about that last year but got no answer.

Ultraviolet is ionizing. (Starting at what frequencies in
what materials?) UV is absorbed by most materials.


The frequency (or wavelength) thresholds are established by
convention.


That makes no sense to me. Shine a low-intensity monochromatic
light on some material. Depending on the material, if the light
has a high enough frequency, the material will ionize. If the
frequency is not that high, it won't. No conventions involved.

X-Ray is distinguished from ultraviolet by its ability to
penetrate materials, roughly in inverse proportion to the
material's density, and its inability to be optically lensed.


X-rays can be lensed.


Can you provide a source for that bit of info?

An earlier answer to the question:

| What distinguishes X-rays from ultraviolet?
|
| UV can be reflected and refracted using optics (although special
| optics of course); X-rays no longer can.
|
| Many years after this distinction was made, it was found that X-rays
| _can_ be reflected under some very special circumstances: during
| grazing incidence i.e. when the incident ray is very nearly parallell
| to the reflecting surface. By using this principle the first X-ray
| telescopes (the Wollter telescopes) were constructed in the 1970's.

By "optically lensed" I meant "refracted", and deliberately
left out mention of reflection.

Gamma is distinguished from X-ray by its ability to interact
with nucleons. (Do gammas usually whizz right past electrons
in atoms without interacting? Or do they interact with
electrons just as often as lower-energy X-rays do?)


Here is where a number of sources will conflict. Gamma is commonly
reserved for light that is emitted from a nuclear decay. In this
context it can be inclusive of what others will call X-rays (in energy).
Personally, I like it if we start out with cutoffs based on wavelength,
that we stick to it.


I don't need legal definitions. I don't need boundary lines
between different parts of the spectrum-- I need characteristics
which distinguish different parts of the spectrum.

My impression is that *most* nuclear transitions which emit or
absorb photons are at higher energy levels (higher frequency)
than electron transitions in atoms. Electron transitions are
generally caused by and emit IR through X-Ray, while nuclear
transitions are generally caused by and emit higher frequencies.

Is that right?

Gamma is ionizing radiation. The common physical sources are
less intense (in the number of photons emitted) than the average
candle. To the gamma photons emitted from a lump of Co-60, we
are like smoke. And thin smoke at that.


Okay, that means the gammas go through us easily. But does it
mean that they knock electrons out of atoms all along the path
as they pass through, or do they just pass through with usually
no effect at all, but are stopped when they hit a nucleus?

-- Jeff, in Minneapolis

Subtract 1 from my e-mail address above for my real address.
..
  #5  
Old October 13th 03, 07:49 AM
Jeff Root
external usenet poster
 
Posts: n/a
Default Up and down the spectrum

Alan Moore replied to Jeff Root:

Radio waves are characterized by their ability to be emitted
and detected by antennae. Metals reflect them; other materials
are transparent to them.

Well, not exactly. Any change in dielectric properties can cause
a reflection. Radar at sufficiently high frequencies will detect
animals, and even at moderate frequencies, flocks of birds or
insects.


Radar is in the microwave part of the spectrum. I traded some
clarity for brevity, but the layout of my list should have made
it fairly obvious that I was referring mainly to the part of
the radio spectrum with frequencies lower than microwaves.

Do the qualifications apply below the microwave region?

Microwaves are distinguished from other radio waves by their
ability to be channeled by waveguides. Electronic components
used to generate and detect microwaves are about the same size
as the waves themselves.


This is also true for other radio waves. Just keep in mind the
necessary relationship between waveguide dimension and signal
wavelength, and you'll see that there comes a point at which
waveguides become inconveniently large.


Do I understand you to be saying that all radio waves could be
handled by waveguides and other components of about the same
size as the waves, but that below the microwave region, those
waveguides and other components become impractical because of
their size, and so are generally not used?

Does it mean that the distinction between microwaves and the
rest of the radio portion of the spectrum is in the practical
choice of components actually used for generating and detecting
the waves?

Ultraviolet is ionizing. (Starting at what frequencies in
what materials?) UV is absorbed by most materials.


You can look up ionization potentials for elements in standard
physical and chemical handbooks. Actually this starts in the
infra-red. Otherwise vacuum tubes wouldn't work, as they rely
on those energy levels to get electrons away from the solid
cathode and into the vacuum where they can be accelerated away
from it.


Are we talking about the same thing? The cathode in a tube
needs to be hot. I'd say ionization by EM radiation is when
that EM radiation falls on a material and ionizes it, without
a need for the material to be particularly hot. Am I wrong?

X-Ray is distinguished from ultraviolet by its ability to
penetrate materials, roughly in inverse proportion to the
material's density, and its inability to be optically lensed.


Yes, sort of. Whereas lower energy photons may result in ionization
of atoms by ejecting an electron from an outer shell, x-rays may
eject electrons from inner shells.


Why only "sort of"? It looks to me like you added a detail
of how and where the ionization takes place, but didn't
change anything I said, at all.

Gamma is distinguished from X-ray by its ability to interact
with nucleons. (Do gammas usually whizz right past electrons
in atoms without interacting? Or do they interact with
electrons just as often as lower-energy X-rays do?)


As often, or oftener. This is why they are grouped with the
"soft" x-rays and UV as ionizing radiation.


I'm guessing that you said '"soft" x-rays' rather than simply
"x-rays" because hard x-rays are the same as gamma rays.
Is that right?

So if I shine a million soft x-ray photons at my left hand,
and a million gamma rays at my right hand, not only will my
right hand be hit harder by each ray than my left hand is,
but more electrons will be hit and knocked out of their atoms
than will happen in my left hand?

-- Jeff, in Minneapolis

Subtract 1 from my e-mail address above for my real address.
..
  #6  
Old October 13th 03, 06:45 PM
Jonathan Silverlight
external usenet poster
 
Posts: n/a
Default Up and down the spectrum

In message , Jeff Root
writes
David A. Smith replied to Jeff Root:

Radio waves are characterized by their ability to be emitted
and detected by antennae.


antennae - devices made of conductors (such as metals)


Do you know of any antenna made of a conductive material other
than metal?


Oddly enough, yes, as this is an astronomy group. There's that radio
interferometer that was mounted on a cliff and used the sea as one
element.
--
"It is written in mathematical language"
Remove spam and invalid from address to reply.
  #7  
Old October 13th 03, 07:28 PM
Paul Schlyter
external usenet poster
 
Posts: n/a
Default Up and down the spectrum

In article ,
Jeff Root wrote:

David A. Smith replied to Jeff Root:

Radio waves are characterized by their ability to be emitted
and detected by antennae.


antennae - devices made of conductors (such as metals)


Do you know of any antenna made of a conductive material other
than metal? Can you provide a link to a description of such
an antenna?


E.g. rods of carbon ought to work too.....

Microwaves are distinguished from other radio waves by their
ability to be channeled by waveguides.


The EM spectrum is assigned by wavelength as standard description.


That has nothing to do with the info I'm looking for.

The above sentence would be better stated "Microwaves are
distinguished from other light..."


How is that better? I worded it as I did to indicate that
microwaves are included in the "radio" part of the spectrum,
but have characteristics that distinguish them from other
radio waves. My understanding is that microwaves and higher
frequencies can be channeled by waveguides, while radio waves
of lower frequencies cannot. My understanding may be way off.
Do the Earth and ionosphere form a waveguide for shortwave
radio?


Not for shortwave radio, but for longwave radio! Shortwave radio
work by having the radio waves reflected in the electron layers in
the ionosphere.

An EM radiation can be channeled by waveguides, however the
cross section of the waveguide must have a size comparable to
the wavelength of the EM radiation to be guided. So you can build
a waveguide for shortwave, but it would be quite large....

Is that essentially the same phenomenon? If so, then
what *does* distinguish microwaves from other radio waves?


The distinction was originally defined something like this:

Normal radio waves: the wavelength is much longer than the size of
the individual components.

Microwaves: the wavelength is of a size comparable to (= of the same
order of magnitude as) the size of the individual components.

Optics: the wavelength is much shorter than the size of the
individual components.

This was made at a time before the transistor was invented, and
thus the vacuum electron tube was the only electronic component
available which provided amplification. Since then the electronics
has been miniaturized, and thus it's today feasible to, in the
longer wavelengths parts of the traditional microwave band, use
discrete components. But the definition of "microwaves" remains
approximately the same as in the 1930-40's. And there are no
precise limits defined for "microwaves"; different sources give
somewhat different wavelength limits.

Electronic components used to generate and detect microwaves
are about the same size as the waves themselves.


Look at the physical size of a Klystron tube. Much larger than
microwaves.


It appears that any assertion on the Internet generates its
antithesis. I included the info about the size of components
because of this reply to a similar question last December:

| What distinguishes radio waves from microwaves, and microwaves
| from infrared?
|
| Radio waves which are not microwaves are handled with normal
| electronics, i.e. components which are much smaller than the
| wavelength.
|
| Infrared waves are handled with optics, i.e. components which
| are much larger than the wavelength.
|
| Microwaves are handled with microwave electronics, i.e. components
| which are of approximately the same size as the wavelength.

Do you disagree with that?

Infrared is distinguished from radio and microwaves by its
ability to interact with individual electrons in atoms, the
photoelectric effect, and its ability to be optically lensed.
Infrared is absorbed by most materials.


You can lens any light, if you can establish a medium with a
different propagation speed. You can lens microwaves, and radio
waves. It might take miles of material to do it with radio waves,
but you could do it.


Ah. I asked about that last year but got no answer.

Ultraviolet is ionizing. (Starting at what frequencies in
what materials?) UV is absorbed by most materials.


The frequency (or wavelength) thresholds are established by
convention.


That makes no sense to me. Shine a low-intensity monochromatic
light on some material. Depending on the material, if the light
has a high enough frequency, the material will ionize. If the
frequency is not that high, it won't. No conventions involved.


However the minimum frequency which will cause ionization varies
a lot between different materials.

Nah, the limit between UV and visible light is instead determined
by what the human eye can see.

--
----------------------------------------------------------------
Paul Schlyter, Grev Turegatan 40, SE-114 38 Stockholm, SWEDEN
e-mail: pausch at stockholm dot bostream dot se
WWW: http://www.stjarnhimlen.se/
http://home.tiscali.se/pausch/
  #8  
Old October 14th 03, 12:00 AM
John Oliver
external usenet poster
 
Posts: n/a
Default Up and down the spectrum

Jonathan Silverlight wrote:
In message , Jeff Root
writes

David A. Smith replied to Jeff Root:

Radio waves are characterized by their ability to be emitted
and detected by antennae.


antennae - devices made of conductors (such as metals)



Do you know of any antenna made of a conductive material other
than metal?



Oddly enough, yes, as this is an astronomy group. There's that radio
interferometer that was mounted on a cliff and used the sea as one element.


Well, the sea was used as a reflector. The energy was still
collected by a more conventional antenna.

  #9  
Old October 15th 03, 03:06 AM
Alan Moore
external usenet poster
 
Posts: n/a
Default Up and down the spectrum

On 12 Oct 2003 23:49:15 -0700, (Jeff Root) wrote:

Alan Moore replied to Jeff Root:

Radio waves are characterized by their ability to be emitted
and detected by antennae. Metals reflect them; other materials
are transparent to them.

Well, not exactly. Any change in dielectric properties can cause
a reflection. Radar at sufficiently high frequencies will detect
animals, and even at moderate frequencies, flocks of birds or
insects.


Radar is in the microwave part of the spectrum. I traded some
clarity for brevity, but the layout of my list should have made
it fairly obvious that I was referring mainly to the part of
the radio spectrum with frequencies lower than microwaves.

Do the qualifications apply below the microwave region?

Oh, yes. Even quite long wavelenght signals are reflected by the rocky
surfaces of the moon and planets, although under some circumstances,
they may penetrate to some depth.

Microwaves are distinguished from other radio waves by their
ability to be channeled by waveguides. Electronic components
used to generate and detect microwaves are about the same size
as the waves themselves.


This is also true for other radio waves. Just keep in mind the
necessary relationship between waveguide dimension and signal
wavelength, and you'll see that there comes a point at which
waveguides become inconveniently large.


Do I understand you to be saying that all radio waves could be
handled by waveguides and other components of about the same
size as the waves, but that below the microwave region, those
waveguides and other components become impractical because of
their size, and so are generally not used?


Exactly.

Does it mean that the distinction between microwaves and the
rest of the radio portion of the spectrum is in the practical
choice of components actually used for generating and detecting
the waves?

There are other differences, of course. The ionosphere is absorbing at
some wavelengths, reflecting at others, transparent at sufficiently
high frequencies. The cutoffs vary depending on the degree of
ionization present.

Ultraviolet is ionizing. (Starting at what frequencies in
what materials?) UV is absorbed by most materials.


You can look up ionization potentials for elements in standard
physical and chemical handbooks. Actually this starts in the
infra-red. Otherwise vacuum tubes wouldn't work, as they rely
on those energy levels to get electrons away from the solid
cathode and into the vacuum where they can be accelerated away
from it.


Are we talking about the same thing? The cathode in a tube
needs to be hot. I'd say ionization by EM radiation is when
that EM radiation falls on a material and ionizes it, without
a need for the material to be particularly hot. Am I wrong?


I wouldn't say right or wrong. It takes less energy to remove an
electron from an atom when that atom is already in an excited state,
with the electron "boosted" into a higher orbital. So, given atoms or
molecules in excited states, lower energy EM radiation will result in
ionization than would be required at very low temperatures.

X-Ray is distinguished from ultraviolet by its ability to
penetrate materials, roughly in inverse proportion to the
material's density, and its inability to be optically lensed.


Yes, sort of. Whereas lower energy photons may result in ionization
of atoms by ejecting an electron from an outer shell, x-rays may
eject electrons from inner shells.


Why only "sort of"? It looks to me like you added a detail
of how and where the ionization takes place, but didn't
change anything I said, at all.


Without knowing where the electron is being ejected from, there isn't
any difference. I hadn't noticed your statement about refraction, but
in fact, x-rays can be refracted. The significance of the ejection of
electrons from inner shells is that there are secondary effects as
further radiation is emitted as electrons from outer shells move into
the vacated inner shell, emitting longer wavelength x-rays, UV and
visible light.

Gamma is distinguished from X-ray by its ability to interact
with nucleons. (Do gammas usually whizz right past electrons
in atoms without interacting? Or do they interact with
electrons just as often as lower-energy X-rays do?)


As often, or oftener. This is why they are grouped with the
"soft" x-rays and UV as ionizing radiation.


I'm guessing that you said '"soft" x-rays' rather than simply
"x-rays" because hard x-rays are the same as gamma rays.
Is that right?


Hmm... Sounds as if some historical background is in order.

So if I shine a million soft x-ray photons at my left hand,
and a million gamma rays at my right hand, not only will my
right hand be hit harder by each ray than my left hand is,
but more electrons will be hit and knocked out of their atoms
than will happen in my left hand?


Yes. Generally speaking, higher energy photons will do more damage
than lower energy photons.

Al Moore
  #10  
Old October 15th 03, 08:49 AM
Jeff Root
external usenet poster
 
Posts: n/a
Default Up and down the spectrum

Alan Moore replied to Jeff Root:

Radio waves are characterized by their ability to be emitted
and detected by antennae. Metals reflect them; other materials
are transparent to them.

Well, not exactly. Any change in dielectric properties can cause
a reflection. Radar at sufficiently high frequencies will detect
animals, and even at moderate frequencies, flocks of birds or
insects.


Radar is in the microwave part of the spectrum. I traded some
clarity for brevity, but the layout of my list should have made
it fairly obvious that I was referring mainly to the part of
the radio spectrum with frequencies lower than microwaves.

Do the qualifications apply below the microwave region?

Oh, yes. Even quite long wavelength signals are reflected by
the rocky surfaces of the moon and planets, although under some
circumstances, they may penetrate to some depth.


Rocks aren't exactly metal-free. I tend to think of silicon as
being rather metallic. But perhaps the silicon in quartz or the
calcium in marble or even the iron, magnesium, and titanium in
basalt lose their relevant metallic properties when compounded?

Does it mean that the distinction between microwaves and the
rest of the radio portion of the spectrum is in the practical
choice of components actually used for generating and detecting
the waves?

There are other differences, of course. The ionosphere is
absorbing at some wavelengths, reflecting at others, transparent
at sufficiently high frequencies. The cutoffs vary depending on
the degree of ionization present.


Ionized material of any kind has metal-like properties, because
of those free electrons...

Ultraviolet is ionizing. (Starting at what frequencies in
what materials?) UV is absorbed by most materials.

You can look up ionization potentials for elements in standard
physical and chemical handbooks. Actually this starts in the
infra-red. Otherwise vacuum tubes wouldn't work, as they rely
on those energy levels to get electrons away from the solid
cathode and into the vacuum where they can be accelerated away
from it.


Are we talking about the same thing? The cathode in a tube
needs to be hot. I'd say ionization by EM radiation is when
that EM radiation falls on a material and ionizes it, without
a need for the material to be particularly hot. Am I wrong?


I wouldn't say right or wrong. It takes less energy to remove an
electron from an atom when that atom is already in an excited state,
with the electron "boosted" into a higher orbital. So, given atoms or
molecules in excited states, lower energy EM radiation will result in
ionization than would be required at very low temperatures.


Okay. Clearly I need to review the basics. Temperature is
obviously on an equal footing with incident light as a factor
in causing ionization. I need to see how the two factors work
together, and not ignore one when I study the other.

X-Ray is distinguished from ultraviolet by its ability to
penetrate materials, roughly in inverse proportion to the
material's density, and its inability to be optically lensed.

Yes, sort of. Whereas lower energy photons may result in ionization
of atoms by ejecting an electron from an outer shell, x-rays may
eject electrons from inner shells.


Why only "sort of"? It looks to me like you added a detail
of how and where the ionization takes place, but didn't
change anything I said, at all.


Without knowing where the electron is being ejected from, there isn't
any difference. I hadn't noticed your statement about refraction, but
in fact, x-rays can be refracted. The significance of the ejection of
electrons from inner shells is that there are secondary effects as
further radiation is emitted as electrons from outer shells move into
the vacated inner shell, emitting longer wavelength x-rays, UV and
visible light.


Hey, that's interesting! I'll be looking for support of the
assertion that x-rays can be refracted, though. The consensus
*seems* to be that they can't.

So if I shine a million soft x-ray photons at my left hand,
and a million gamma rays at my right hand, not only will my
right hand be hit harder by each ray than my left hand is,
but more electrons will be hit and knocked out of their atoms
than will happen in my left hand?


Yes. Generally speaking, higher energy photons will do more damage
than lower energy photons.


I think *everybody* knows that. I just want to confirm whether
higher-energy photons (hard x-ray or gamma) are more likely to
interact with electrons in atoms than lower-energy photons (UV
or soft x-ray) are, or if they are less likely to interact,
though either way they interact more energetically when they do.

-- Jeff, in Minneapolis

Subtract 1 from my e-mail address above for my real address.
..
 




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