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Can anybody explain why the Hubble would be unable to see the
equipment left behind by the lunar landings in the late 60's early 70's? I have heard that some intelligence agencies have satellites that can see objects as small as cigarette cartons. I'm sure the answer has to do with optics, and perhaps distance from the object being observed. If anybody could speak on this topic, I would be very interested to read. Thanks much! |
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In article ,
arteec wrote: Can anybody explain why the Hubble would be unable to see the equipment left behind by the lunar landings in the late 60's early 70's? I have heard that some intelligence agencies have satellites that can see objects as small as cigarette cartons. I'm sure the answer has to do with optics, and perhaps distance from the object being observed. That's right, it does. The Moon is considerably further away from Hubble than spy satellites are from the Earth (by roughly a factor of 1000). If I've done the arithmetic correctly, the finest details Hubble could see on the surfact of the Moon are a few hundred meters. If you want to work out the details, look up "angular resolution" and "small-angle formula" in an astronomy textbook. I'd bet that the Hubble can't take high-resolution pictures of the Moon's surface anyway, simply because the Moon's too bright. Hubble's instruments are designed to look at much fainter things. I'd bet that pointing them at the Moon would lead at best to overexposed images and probably to frying the electronics. But I don't observe with Hubble, so I'm guessing about this. -Ted -- [E-mail me at , as opposed to .] |
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Can anybody explain why the Hubble would be unable to see the
equipment left behind by the lunar landings in the late 60's early 70's? I have heard that some intelligence agencies have satellites that can see objects as small as cigarette cartons. I'm sure the answer has to do with optics, and perhaps distance from the object being observed. Correct both times. The angular resolution of a telescope depends on its diameter, D, and the wavelength of the light it collects, lambda. To a rough approximation, the smallest angle a telescope can resolve is angle (radians) = lambda / D where lambda and D are measured in the same units. For HST, D = 2.3 meters, and a representative wavelength is lambda = 400 nm = 400 x 10^(-9) meters. Thus, the angle is 1.7 x 10^(-7) radians, or about 1 x 10^(-5) degrees, or about 0.04 arcseconds. If an object of length L is placed a distance M away from you, its angular size will be (again in radians) roughly (when M L) angle (radians) = L / M The distance to the Moon is roughly M = 384,000,000 meters. The smallest object HST could resolve at the Moon's distance is roughly L = M * (lambda / D) which is about 67 meters in size. The only overhead pictures we have of hardware on the Moon come from the Lunar Orbiter. You can see a few examples at http://stupendous.rit.edu/richmond/a...ar_lander.html |
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I'd bet that the Hubble can't take high-resolution pictures of the
Moon's surface anyway, simply because the Moon's too bright. Hubble's instruments are designed to look at much fainter things. I'd bet that pointing them at the Moon would lead at best to overexposed images and probably to frying the electronics. But I don't observe with Hubble, so I'm guessing about this. Good guess, and a common one, but wrong. Only one of HST's instruments was really too sensitive to observe the Moon lest it be damaged. Some of the others tried using the Moon -- or the Earth! -- for flatfield exposures. As an example, look at http://hubblesite.org/gallery/album/...on/pr1999014c/ |
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