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Steve Willner wrote in
http://groups.google.com/group/sci.a...10441b2?hl=en& : SW At high temperatures, molecules tend to dissociate to form SW individual atoms. At even higher temperatures, the atoms break SW up into separate nuclei and electrons. And at temperatures SW higher still (far above anything relevant to stellar SW atmospheres), the nuclei themselves break up. In article .com, "Radium" writes: Huh? If that was the case, then there would be nuclear fusion would require much lower temperatures. Why would you think that? Fusion means combining nucleons, not separating them. Fusion is the combining of nucleons. However, you said nuclei break up at extremely high temperatures. That is fission, not fusion. Nuclear fusion in stars occurs when the temperature is sufficient to overcome the Coulomb barrier: i.e., the electrical repulsion of the protons in colliding nuclei. For p-p fusion, the necessary temperature is around 10 million kelvins. For the carbon cycle, the repulsion is 12 times higher, and temperature needs to be higher by about the same factor (actually a bit less because 12C + p goes by the strong interaction, not the weak one). Okay. Temperature to dissociate molecules is about 1000 K, to ionize atoms about 10000 K, and to break up nuclei about 10^11 K. Once again, breaking up a nucleus is fission, not fusion. -- Steve Willner Phone 617-495-7123 Cambridge, MA 02138 USA (Please email your reply if you want to be sure I see it; include a valid Reply-To address to receive an acknowledgement. Commercial email may be sent to your ISP.) |
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"Radium" wrote in news:1157684993.657003.116110
@e3g2000cwe.googlegroups.com: Steve Willner wrote in http://groups.google.com/group/sci.a...10441b2?hl=en& : SW At high temperatures, molecules tend to dissociate to form SW individual atoms. At even higher temperatures, the atoms break SW up into separate nuclei and electrons. And at temperatures SW higher still (far above anything relevant to stellar SW atmospheres), the nuclei themselves break up. In article .com, "Radium" writes: Huh? If that was the case, then there would be nuclear fusion would require much lower temperatures. Why would you think that? Fusion means combining nucleons, not separating them. Fusion is the combining of nucleons. However, you said nuclei break up at extremely high temperatures. That is fission, not fusion. Actually it is normally referred to as photo-disintigration to make clear that an endothermic process is occurring. This is believed to occur during the collapse phase of a Type II supernova. This is followed by inverse beta decay, another endothermic reaction resulting in the bulk of the protons being converted to neutrons. Nuclear fusion in stars occurs when the temperature is sufficient to overcome the Coulomb barrier: i.e., the electrical repulsion of the protons in colliding nuclei. For p-p fusion, the necessary temperature is around 10 million kelvins. For the carbon cycle, the repulsion is 12 times higher, and temperature needs to be higher by about the same factor (actually a bit less because 12C + p goes by the strong interaction, not the weak one). Okay. Temperature to dissociate molecules is about 1000 K, to ionize atoms about 10000 K, and to break up nuclei about 10^11 K. Once again, breaking up a nucleus is fission, not fusion. The terms fission and fusion are normally reserved for exothermic reactions. As I said the breaking up of nuclei due to such extreme temperatures is specifically called photo-disintegration. Klazmon. -- Steve Willner Phone 617-495-7123 Cambridge, MA 02138 USA (Please email your reply if you want to be sure I see it; include a valid Reply-To address to receive an acknowledgement. Commercial email may be sent to your ISP.) |
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![]() Temperature to dissociate molecules is about 1000 K, to ionize atoms about 10000 K, and to break up nuclei about 10^11 K. How do you explain critical mass in a fission reaction? Do the nucleons just possess the kinetic energy equivalent to 10*11K? (how do you make a carrat?) |
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Radium wrote:
Steve Willner wrote in http://groups.google.com/group/sci.a...10441b2?hl=en& : SW At high temperatures, molecules tend to dissociate to form SW individual atoms. At even higher temperatures, the atoms break SW up into separate nuclei and electrons. And at temperatures SW higher still (far above anything relevant to stellar SW atmospheres), the nuclei themselves break up. In article .com, "Radium" writes: Huh? If that was the case, then there would be nuclear fusion would ^^^^^^^^^^^^^^^ require much lower temperatures. Why would you think that? Fusion means combining nucleons, not separating them. Fusion is the combining of nucleons. However, you said nuclei break up at extremely high temperatures. That is fission, not fusion. The source of the confusion is that you used the term "nuclear fusion". Perhaps you should clarify if that was just a typo or what you meant if not. HTH George |
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In article 9J6Mg.127$Lb5.11@edtnps89,
"Thomas Mickle" writes: How do you explain critical mass in a fission reaction? Fission in reactors is an exothermic process. It involves neutrons -- hence no Coloumb barrier -- and unstable nuclei. Critical mass means that there's enough fissionable material to absorb the neutrons and create more of them rather than having most of the neutrons escape and the reaction fizzle. Fission can take place at extremely low temperatures, though in usual situations the energy released will make everything hot. First startup of a nuclear reactor can be at room temperature (or even colder) as far as the nuclear reaction itself is concerned. (Pumps, pipes, or other components may require preheating in some reactor designs, and in general one wants to allow temperatures to rise gradually, not suddenly, but this is because of ordinary mechanical properties of materials, nothing to do with the nuclear reaction itself.) Offhand I can't think of a situation in astronomy where fission is relevant, but I may be missing something. Photo-disintegration is an exothermic process, relevant only at extreme temperatures. If temperature is sufficiently high, any nucleus -- even a normally stable one -- will be broken apart, absorbing energy from whatever created the extreme temperature in the first place. This is analogous to dissociation of molecules or ionization of atoms, which are endothermic processes that take place at much lower temperatures. Mention of one particular physical process doesn't mean that no other processes exist. -- Steve Willner Phone 617-495-7123 Cambridge, MA 02138 USA (Please email your reply if you want to be sure I see it; include a valid Reply-To address to receive an acknowledgement. Commercial email may be sent to your ISP.) |
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