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I would like to draw the line of "Galactic Equator" in my own star map,
but for this I need some junctures. Does anyone know the formula of "Galactic Equator" or does anyone know data of rectascension and declination? Because it is an ellipse/circle I need only few values (ca. 8) of rectascension and declination to connect the points. Any idea? Heinz |
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"Heinz" wrote in
ups.com: I would like to draw the line of "Galactic Equator" in my own star map, but for this I need some junctures. Does anyone know the formula of "Galactic Equator" or does anyone know data of rectascension and declination? Because it is an ellipse/circle I need only few values (ca. 8) of rectascension and declination to connect the points. Any idea? Heinz Actually you only need two points to draw a great circle. Do yourself a favour and download Sky Charts (Cartes Du Ciel). It will plot the galactic equator if you set it to do that. http://www.stargazing.net/astropc/ Klazmon |
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In article . com,
"Heinz" wrote: I would like to draw the line of "Galactic Equator" in my own star map, but for this I need some junctures. Does anyone know the formula of "Galactic Equator" or does anyone know data of rectascension and declination? Because it is an ellipse/circle I need only few values (ca. 8) of rectascension and declination to connect the points. As Llanzlan said, in principle you only need two--as long as they're not opposite each other. According to Peter Duffett-Smith's _Practical Astronomy With Your Calculator_, the north galactic pole is at RA 12:49 Dec +27°24', and the galactic longitude of the plane's ascending node on the celestial equator is 33°. So to plot the galactic equator in right ascension and declination, you could use the following pair of formulae, where L is the longitude of a point on the GE: Dec = asn(cos(27°24')sin(L - 33°)) RA = 12h49m + (atn(cos(L - 33°)/sin(27°24')sin(33° - L)))/(15°/h). Run through values of L up to 360°, taking however many steps you need. -- Odysseus |
#4
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On 10 Jul 2006 14:22:42 -0700, "Heinz"
wrote: I would like to draw the line of "Galactic Equator" in my own star map, but for this I need some junctures. Does anyone know the formula of "Galactic Equator" or does anyone know data of rectascension and declination? Because it is an ellipse/circle I need only few values (ca. 8) of rectascension and declination to connect the points. The galactic equator has declination 0 for all 24 hours of RA. Remove del for email |
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Barry Schwarz wrote in
: On 10 Jul 2006 14:22:42 -0700, "Heinz" wrote: I would like to draw the line of "Galactic Equator" in my own star map, but for this I need some junctures. Does anyone know the formula of "Galactic Equator" or does anyone know data of rectascension and declination? Because it is an ellipse/circle I need only few values (ca. 8) of rectascension and declination to connect the points. The galactic equator has declination 0 for all 24 hours of RA. That's the celestial equator, not the galactic equator. Klazmon. Remove del for email |
#6
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In article ,
Llanzlan Klazmon wrote: Barry Schwarz wrote in : snip The galactic equator has declination 0 for all 24 hours of RA. That's the celestial equator, not the galactic equator. Indeed! Note that the formulae I posted upthread were simplified by assuming a galactic *latitude* of zero; some cos(B)s and entire terms in sin(B) nicely disappear that way. -- Odysseus |
#7
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Hi all,
thanks for your help it was quite useful. Cheers Heinz |
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