![]() |
|
|
|
Thread Tools | Display Modes |
#1
|
|||
|
|||
![]() "DaveC" wrote in message al.net... How does LST correlate to our terrestrial time? I'm not looking for a definition, or an explanation that includes angles of the equinox, or such. I just want to know if a particular time in LST is fixed in relation to the clock on the wall, or if it changes over the year, and how to calculate it or look it up. Thanks, You are really saying, "I don't want a definition", but "I want a definition"... A sidereal day, is four seconds shorter then the normal 'clock' day. So a particular sidereal 'time' arrives four seconds earlier each day (when compared to a normal clock). Now the question of calculating it, depends on just how accurate you want to go?. The simplest way (which is accurate enough for most uses), is to use a chart, based on this 'drift' between the clocks. One is at: http://pietro.org.tripod.com/Astro_U...ealVSCivil.htm This is accurate enough for probably 98% of uses. The formula to calculate the sidereal time is at: http://www.space-plasma.qmul.ac.uk/h...rt/node10.html and this is accurate enough for 99.9999% of applications. Even this though, has a small amount of residual error. Best Wishes |
#2
|
|||
|
|||
![]()
Roger Hamlett wrote:
"DaveC" wrote in message al.net... How does LST correlate to our terrestrial time? I'm not looking for a definition, or an explanation that includes angles of the equinox, or such. I just want to know if a particular time in LST is fixed in relation to the clock on the wall, or if it changes over the year, and how to calculate it or look it up. Thanks, You are really saying, "I don't want a definition", but "I want a definition"... A sidereal day, is four seconds shorter then the normal 'clock' day. So a particular sidereal 'time' arrives four seconds earlier each day (when compared to a normal clock). Four minutes, surely? ;-) Steve -- www.frontierastro.co.uk FrontierAstro - dedicated to Frontier and Astronomy |
#3
|
|||
|
|||
![]() "Steve" wrote in message news ![]() Roger Hamlett wrote: "DaveC" wrote in message al.net... How does LST correlate to our terrestrial time? I'm not looking for a definition, or an explanation that includes angles of the equinox, or such. I just want to know if a particular time in LST is fixed in relation to the clock on the wall, or if it changes over the year, and how to calculate it or look it up. Thanks, You are really saying, "I don't want a definition", but "I want a definition"... A sidereal day, is four seconds shorter then the normal 'clock' day. So a particular sidereal 'time' arrives four seconds earlier each day (when compared to a normal clock). Four minutes, surely? ;-) Steve Sometimes they just pass like seconds... :-) Dead right, a 'slip of the keyboard'. Best Wishes |
#4
|
|||
|
|||
![]()
DaveC wrote in
al.net: How does LST correlate to our terrestrial time? I'm not looking for a definition, or an explanation that includes angles of the equinox, or such. I just want to know if a particular time in LST is fixed in relation to the clock on the wall, or if it changes over the year, and how to calculate it or look it up. Thanks, Here are the principles. Sidereal time is determined by the rotation of the earth with refernce to the equinox. It takes 23h56m to make a 360 degree rotation. Clock time based on a mean solar time and is the rotation of the earth with refernce to a mean Sun. It is 24h00m and a 361 degree rotation. Why 361 degrees? Sun advances nearly 1 degree in the ecliptic every sidereal day. Therefore the earth must rotate a further 1 degree or 4 minutes to catch up to complete a solar day. The sidereal clock thus gains 4 minutes accumulatively on a solar clock every day. The two clocks are by convention synchronized at 00h00m at the September equinox. Thereafter they diverge by 4 minutes per day until they are 12 hours apart 6 months later at the March equinox. They contiune until they once more synchronize at the following September equinox. Martin Lewicki |
#5
|
|||
|
|||
![]()
At one day for fraction of a secont local time an ST are the same. At the
start of fall in Sept. |
#6
|
|||
|
|||
![]()
In message et, DaveC
writes Is there a web site where I can enter Longitude and get a chart of LST? Something done in Java, perhaps? Thanks, If you google on 'sidereal clock' you should find a nice little freeware clock that you can download that reads your system clock and then converts. I think one of the sites also has Java source code to download as well. Sorry I can't remember the domain but it should be pretty easy to find. Denis -- DT Replace nospam with the antithesis of hills ******************************************* |
#7
|
|||
|
|||
![]()
On Wed, 17 Dec 2003 8:01:23 -0800, DaveC wrote:
On Wed, 17 Dec 2003 1:28:16 -0800, Roger Hamlett wrote (in message ): "DaveC" wrote in message al.net... How does LST correlate to our terrestrial time? I'm not looking for a definition, or an explanation that includes angles of the equinox, or such. I just want to know if a particular time in LST is fixed in relation to the clock on the wall, or if it changes over the year, and how to calculate it or look it up. Thanks, You are really saying, "I don't want a definition", but "I want a definition"... A sidereal day, is four seconds shorter then the normal 'clock' day. So a particular sidereal 'time' arrives four seconds earlier each day (when compared to a normal clock). Now the question of calculating it, depends on just how accurate you want to go?. The simplest way (which is accurate enough for most uses), is to use a chart, based on this 'drift' between the clocks. One is at: http://pietro.org.tripod.com/Astro_U...ealVSCivil.htm Is there a web site where I can enter Longitude and get a chart of LST? Something done in Java, perhaps? Thanks, http://www.jgiesen.de/astro/astroJS/...lock/index.htm Good night! Benoît Morrissette |
#8
|
|||
|
|||
![]()
Martin Lewicki wrote in message ...
DaveC wrote in al.net: How does LST correlate to our terrestrial time? I'm not looking for a definition, or an explanation that includes angles of the equinox, or such. I just want to know if a particular time in LST is fixed in relation to the clock on the wall, or if it changes over the year, and how to calculate it or look it up. Thanks, Here are the principles. Sidereal time is determined by the rotation of the earth with refernce to the equinox. It takes 23h56m to make a 360 degree rotation. Thoroughly incorrect. It is necessary to define a 24 hour day first before you determine that the annual cycle is 365.25 days. The basis for the 24 hour clock day relies on the axial rotation in 24 hours exactly and accurate clocks were developed by John Harrison on that principle. http://rubens.anu.edu.au/student.pro...aval/defin.htm Clock time based on a mean solar time and is the rotation of the earth with refernce to a mean Sun. It is 24h00m and a 361 degree rotation. Thoroughly incorrect. Nothing rotates more than 360 degrees and clocks maintain the 24 hour/360 degree equivalency for the axial rotation of the Earth.The principles behind clocks for solving the longitude problem is that it is noon along an entire longitude meridian at some location on the planet.Because there is no observed equality from one axial rotation to the next,brilliant men devised a computation known as the Equation of Time to equalise the variation from one axial rotation to the next or what amounts to the same thing,one 24 hour day to the next. Why 361 degrees? Sun advances nearly 1 degree in the ecliptic every sidereal day. Therefore the earth must rotate a further 1 degree or 4 minutes to catch up to complete a solar day. By the sidereal method .986 deg or 3 min 56 seconds. Because the true rotation rate is calculated as 24 hours = 360 degrees 1 deg = 4 min clock time ..986 deg = 3 min 56 sec clock time 24 hours minus 3 min 56 sec = 23 hours 56 min 04 sec. http://www.absolutebeginnersastronomy.com/sidereal.gif The catastrophic error is that you need to define a 24 hour clock day first before you determine that there is 365 days 5 hours and 49 min in an annual cycle and all justifications for the sidereal value begin on the wrong footing,the day is defined by the axial rotation of the Earth via the Equation of Time and insofar as this reflects the 24 hour/360 degree equivalency. Newton,in defining the difference between the natural unequal day and the constant 24 hour clock day as the Equation of Time or the difference between absolute time and relative time may have unwittingly paved the way for tampering with the original determination of the day linked to the isolation of the Earth's rotation to 24 hours/360 degrees. "Absolute time, in astronomy, is distinguished from relative, by the equation or correlation of the vulgar time. For the natural days are truly unequal, though they are commonly considered as equal and used for a measure of time; astronomers correct this inequality for their more accurate deducing of the celestial motions. It may be, that there is no such thing as an equable motion, whereby time may be accurately measured." Principia http://members.tripod.com/~gravitee/definitions.htm The price of tampering with the association between axial rotation through 360 degrees and the 24 hour clock as Newton's absolute time is that in the 21st century,men believe that the Earth has a constant equable motion through 360 degrees and that motion is stellar circumpolar motion. Not even the creationist doctrine can compare to reasoning that links the Earth's rotation directly to the sidereal value and stellar circumpolar motion for ultimately it leads to the stellar circumpolar framework. http://home.t-online.de/home/sjkowollik/polaris.jpg Now are you certain that the Earth's axial rotation through 360 degrees corresponds to the return of a reference star to the same position in 23 hours 56 min 04 sec. The sidereal clock thus gains 4 minutes accumulatively on a solar clock every day. The Equation of Time (EoT) contains positive and negative values of minutes and seconds which were applied at observed noon to maintain the transition from one 24 hour clock day to the next or one axial rotation to the next.The EoT equalises the variation in a natural day by treating axial rotation as constant and modifying the variation in orbital motion due to Kepler's second law which generates the natural inequality for each axial rotation. Again,you cannot even to begin to define the sidereal value without the 24 hour/360 degree equivalency but it appears that it does not stop you from trying. http://www.burnley.gov.uk/towneley/tryall/eot3.htm The two clocks are by convention synchronized at 00h00m at the September equinox. Thereafter they diverge by 4 minutes per day until they are 12 hours apart 6 months later at the March equinox. They contiune until they once more synchronize at the following September equinox. Martin Lewicki Clocks and the longitude problem,the only means to sort all this out and restore the Earth's axial rotation to the 24 hour/360 degree equivalency.It does not matter that men got it badly wrong in 1905 by tampering with the definition of a constant 24 hour day from the natural unequal day via the EoT,it is a matter of appreceation. "In default of better information we may without serious error (in days of sail) take the recorded hour as in the apparent time of the meridian of longitude mentioned in the account, and for form's sake apply the equation of time to reduce to civil time of the meridian." http://www.aandc.org/research/nautic..._and_date.html I assure you that the Earth takes 24 hours to rotate 360 degrees on its axis,that is the way it always was and will be.Ask anyone on the street and they will tell you,they may not know the particulars of defining a 24 hour day but it appears neither do you,no offense intended. |
#9
|
|||
|
|||
![]()
Sidereal time is determined by the rotation of the earth with refernce to
the equinox. It takes 23h56m to make a 360 degree rotation. Well, not quite, although if you mean referenced to a point on the celestial sphere like the vernal or autumnal equinoxes, you would be right. Sidereal time is determined by the rotation rate with respect to the stars. The Earth rotates 360 degrees with respect to the stars in a period of 23 hrs, 56 minutes, 4.092 seconds. We generally say that local sidereal time is the right ascension of the local meridian (or the hour-angle of the vernal equinox). Clear skies to you. -- David W. Knisely Prairie Astronomy Club: http://www.prairieastronomyclub.org Hyde Memorial Observatory: http://www.hydeobservatory.info/ ********************************************** * Attend the 11th Annual NEBRASKA STAR PARTY * * July 18-23, 2004, Merritt Reservoir * * http://www.NebraskaStarParty.org * ********************************************** |
|
Thread Tools | |
Display Modes | |
|
|
![]() |
||||
Thread | Thread Starter | Forum | Replies | Last Post |
Pioneer 10 anomaly: Galileo, Ulysses? | James Harris | Astronomy Misc | 58 | January 28th 04 11:15 PM |
Empirically Confirmed Superluminal Velocities? | Robert Clark | Astronomy Misc | 42 | November 11th 03 03:43 AM |
Empirically Refuted Superluminal Velocities. | EL | Astronomy Misc | 22 | October 31st 03 04:07 PM |
Wesley Clark Support Warp Drive, Time Travel | Mark R. Whittington | Policy | 97 | October 17th 03 03:10 AM |
Correlation between CMBR and Redshift Anisotropies. | The Ghost In The Machine | Astronomy Misc | 172 | August 30th 03 10:27 PM |