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DOPPLER TEST OF LIGHT SPEED DELAY FROM DISTANT SPACECRAFT
Doppler Test Shows Light Speed Does Not Extrapolate Beyond 1 Minute An analysis of Doppler data produced by the Pioneer 10 spacecraft shows that the speed of light delay from the spacecraft when it was billions of miles and supposedly hours away was, despite this great distance, actually less than a minute away. In short, we have evidence that light speed does not extrapolate indefinitely as generally assumed. This result is supported by a previous experiment of the author using Pockells cell shutters,a laser and a photodiode that showed radiation was only received if the receiver was exposed to the emitter/scatterer during the time of emission/scattering(ref1) Pioneer 10 was launched in 1972 and by 2003 had traveled beyond the solar system and communication with the craft’s 8Watt transponder has ceased. The Doppler data over the life of the mission has been archived and was used by John Anderson and others(ref2) to show a small anomalous acceleration of the craft toward the sun beyond that due to the gravitational influence of the sun for most of the life of the mission. The roughly 29km/sec orbital motion of the earth and .465km/sec spin motion of the earth produce various Doppler shifts of the radiation sent to the spacecraft and received by the spacecraft. The motion of the spacecraft,in the time period considered here about 12km/sec, also imparts a Doppler shift to the radiation it receives and reradiates in phase back to the earth. This phenomena offered the possibility of testing the hypothesis that radiation sent to the spacecraft and reflected back to earth was sent seconds before it was received and not possibly hours before from a possibly different site according to the conventional speed of light delay assumption. The problem was to find times of reception where the spin motion of the earth at the receiving site was as different as possible from the motion of the earth at the transmission site; eg 12 hours apart as opposed to 24 hours apart etc. And among these times to choose those where the transmitter at the receiving site was on and the reception was in lock. Then one could compare the recorded received frequency with the shifted frequency expected if the reception was due to radiation transmitted a minute before with essentially the same earth motion and not to radiation transmitted from a possibly different site at a time implied by the assumed speed of light delay and with a different earth motion. This plan was carried out with the help of the NASA Horizons Telnet ephemeris which gives instantaneous position coordinates of hundreds of objects in the solar system besides planets and spacecraft, minute by minute. The coordinates are given with respect to a coordinate center such as the sun or the site of one of the DSN antennas near Madrid, Los Angeles and Canberra Australia. In summary, the results for radiation received each minute on Oct 7 1987 from 21:15 to 22:45 at Madrid were 2,292,134,xxx Hz observed and 2,292,144,xxx predicted according to the standard model and 2,292,136,xxx predicted according to the 1 minute model. That is, for the most part only the last three digits varied and in the 90 cases where the transmitter was clearly on, the 1 minute model was 800 times more accurate. The procedure used to derive these results was as follows: A)Obtain from the archived tracking records, fields that show the date, time and site and if the transmitter is on(zero) or off(1), at the site and the transmitter/exciter frequency at the site, and the Cumulative Doppler count and a code which is zero if the receiver is in lock. Make calculations according to p 8 of the Anderson paper(ref 2) The Exciter Assembly multiplies the Track Synthesizer Frequency~22MHz times 96 to produce the S Band carrier signal at ~2.2GHz…the current transmitter signal from the exciter is multiplied by 240/221 and a bias of 1MHz is added to the Doppler. That is 240/221 times 96 times the tr/ex frequency which is item 116 divided by 10 in the tracking records gives Tx, From this is subtracted the Doppler cumulative count difference which I call the down converted frequency and is calculated from items 31 and 32 in the tracking record plus 1MHz which is item 20 in the tracking record. This gives the received frequency, Tx*=Tx-dn cnv frq + 1MHz.. Also on page 8 and 9(ref2) At each tenth of a second the number of Doppler pulses are counted[This represents the number of upward zero crossings per second of the received radiation or rather that of a locally generated frequency in phase lock with the received radiation eg 2,292,xxx,xxx minus a fixed frequency eg 2,292,000,000. That is, each upward zero crossing of the downconverted version of the received frequency is made to occur at almost exactly the same time as a locally generated frequency-within .01 of the period, using the familiar phase locked loop procedure] The difference in cumulative total counts in successive minutes is the down converted representation of the received frequency during that time. According to the Tracking Data File specifications( ref 3), the high part of the Doppler is multiplied by 10,000 and added to the low part of the Doppler divided by 1,000 to yield the cumulative Doppler count. B)Obtain instantaneous data from Horizons Telnet ephemeris by selecting the option for no light time correction. 1)Obtain from telnet ephemeris, (target) sun xyz coordinates and sun velocity xyz components wrt (coordinate center)earth site eg LA at Tx time eg each minute from 9:45 to 17:45 Oct 7, 1987 and compute average velocity for each minute interval. 2)Obtain similarly, craft coordinates and craft velocity components and Light Time wrt site eg LA at Tx times+LT eg 15:30 to 1700 3)Compute craft coordinates and craft velocity components wrt sun. a)craft coord wrt sun = craft coord wrt earth site plus earth site coord wrt sun where earth site coord wrt sun = -sun coord wrt earth. b)craft velocity comp wrt sun = craft velocity comp wrt earth site minus earth site vel wrt sun where earth site velocity components wrt sun =- sun velocity components wrt earth site. C )Calculate projections of velocities at earth site transmitter onto direction in which transmission is going. Thus if the earth site’s total spin and orbital motion is toward the craft, the projection will be positive,+v, that is the Doppler shift factor, (1+(v)/c), will be greater than 1. And if vice versa or in the case of the craft velocity projection, the projection will be negative and (1+(-v)/c) will be less than 1. The projection in general is vcos(theta) where theta is the angle between the velocity vector and the direction vector from the emitter or receiver or reflector in the direction of the radiation. It is equal to the dot product of the direction vector and the velocity vector, When the direction vector is in the opposite direction of the velocity vector the magnitude of the dot product is the negative of the magnitude when the direction vector and velocity vectors are in the same direction.Thus the direction of the line between earth site and craft could be from the earth site or the craft site ie respectively plus or minus (c1-e1,c2-e2,c3-e3) From these considerations we calculated (1-v1/c)(1-v2/c)(1-v3/c)(1-v4/c) times the effective transmitted radiation where v1 was the projected velocity of the earth site at the time of transmission onto the radiation direction vector;v2, the projected velocity of the of the craft, a light time later onto the radiation direction vector from the earlier earth site to the later craft position. Similarly for v3 and v4. We also calculated (1-v5/c)^2 times (1-v6/c)^2 from similar projected velocities v5 and v6 which are the velocities of the earth motion and the craft motion projected on the direction line between them. The results(ref9) Discussion The conventional measurement of Spacecraft Doppler assumes that light speed extrapolates beyond a minute although this assumption has never been explicitly tested in a way that is not subject to other interpretations. That is, Roemer ascribed the differences in timing of the occultation and reappearance of some of the moons of Jupiter when the Earth is on the same side of the Sun as Jupiter or on the opposite side. But as Cassini, the expert on such observations at the time said, the differences could be due to differences in viewing angle. A similar argument applies to pulsars. Bradley’s aberration measurement of the position of polar stars when the Earth is moving in opposite directions ‘under’ these stars can also be ascribed to a nanosecond difference in response time which would change the direction to the star at opposite times of the year. Supposed radar reflections from surfaces of Venus etc from powerful radar emissions on Earth have such large error bars that the results could equally well be considered noise. The supposed 1.25 second delay in moon radar and lidar given secondary reflections and given the precision of the measurements a 1 second delay is also possible. Many circumlocutions and problems in modern physics are avoided if electromagnetic radiation is regarded not as moving photons or wave fronts or probabilistic photons but rather as an instantaneous force at a distance which involves a response delay that does not exeed a second or so. The results here suggest that the delay does not exceed a minute but could be less. References 1)Electric Gravity and Instantaneous Light, Ralph Sansbury, 1998, http://www.bestweb.net/~sansbury/book03.pdf 2) "Study of the anomalous acceleration of Pioneer 10 and 11", Anderson, J.D., Laing, P.A., Lau, E.L., Liu, A.S., Nieto, M.M., and Turyshev, S.G., Physics Review D, v65, 082004, (2002)) 3)http://pdsgeophys.wustl.edu/pds/mars...t/trk_2_25.txt 4) C++ compiler http://simtel.net/product.download.mirrors.php?id=17456 5)Doppler data in binary files and related documents with definitions of some terms.. http://windsor.gsfc.nasa.gov/spacecr...tdf/atdf_data/ 4) http://deepspace.jpl.nasa.gov/dsndoc...tationdata.cfm 5) http://descanso.jpl.nasa.gov/Monogra...rce_external=0 6) “Doppler Tracking of Planetary Spacecraft, Peter Kinman ,IEEE trans on microwave theory and techniques” vol 40,no.6,June 1992 p1199.. 7) http://tda.jpl.nasa.gov/tmo/progress...2-120/120B.pdf 8) “Radio Science Performance Analysis Software” , Morabito and Asmar ,TDA Progress Report 42-120, February 15, 1995. 9)http://www.bestweb.net/~sansbury/Doppler |
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Ralph Sansbury wrote:
DOPPLER TEST OF LIGHT SPEED DELAY FROM DISTANT SPACECRAFT Doppler Test Shows Light Speed Does Not Extrapolate Beyond 1 Minute An analysis of Doppler data produced by the Pioneer 10 spacecraft shows that the speed of light delay from the spacecraft when it was billions of miles and supposedly hours away was, despite this great distance, actually less than a minute away. Folks should read at the papers http://www.google.com/search?q=pione...te%3AarXiv.org |
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Ralph Sansbury wrote:
DOPPLER TEST OF LIGHT SPEED DELAY FROM DISTANT SPACECRAFT Doppler Test Shows Light Speed Does Not Extrapolate Beyond 1 Minute An analysis of Doppler data produced by the Pioneer 10 spacecraft shows that the speed of light delay from the spacecraft when it was billions of miles and supposedly hours away was, despite this great distance, actually less than a minute away. [snip] BULL****. You haven't the slightest idea how Dopper shfit interacts with the Hubble constant. -- Uncle Al http://www.mazepath.com/uncleal/ (Toxic URL! Unsafe for children and most mammals) "Quis custodiet ipsos custodes?" The Net! |
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You still haven't told me how much data an antenna can hold before it gets
filled up! In addition, you haven't described how an antenna can receive data from somewhere that it isn't pointed at. Ralphie IFS, you really don't know what you are talking about. -- Bob May Losing weight is easy! If you ever want to lose weight, eat and drink less. Works every time it is tried! |
#5
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![]() "Ralph Sansbury" skrev i melding om... DOPPLER TEST OF LIGHT SPEED DELAY FROM DISTANT SPACECRAFT Doppler Test Shows Light Speed Does Not Extrapolate Beyond 1 Minute An analysis of Doppler data produced by the Pioneer 10 spacecraft shows that the speed of light delay from the spacecraft when it was billions of miles and supposedly hours away was, despite this great distance, actually less than a minute away. In short, we have evidence that light speed does not extrapolate indefinitely as generally assumed. This result is supported by a previous experiment of the author using Pockells cell shutters,a laser and a photodiode that showed radiation was only received if the receiver was exposed to the emitter/scatterer during the time of emission/scattering(ref1) Pioneer 10 was launched in 1972 and by 2003 had traveled beyond the solar system and communication with the craft’s 8Watt transponder has ceased. The Doppler data over the life of the mission has been archived and was used by John Anderson and others(ref2) to show a small anomalous acceleration of the craft toward the sun beyond that due to the gravitational influence of the sun for most of the life of the mission. The roughly 29km/sec orbital motion of the earth and .465km/sec spin motion of the earth produce various Doppler shifts of the radiation sent to the spacecraft and received by the spacecraft. The motion of the spacecraft,in the time period considered here about 12km/sec, also imparts a Doppler shift to the radiation it receives and reradiates in phase back to the earth. This phenomena offered the possibility of testing the hypothesis that radiation sent to the spacecraft and reflected back to earth was sent seconds before it was received and not possibly hours before from a possibly different site according to the conventional speed of light delay assumption. The problem was to find times of reception where the spin motion of the earth at the receiving site was as different as possible from the motion of the earth at the transmission site; eg 12 hours apart as opposed to 24 hours apart etc. And among these times to choose those where the transmitter at the receiving site was on and the reception was in lock. Then one could compare the recorded received frequency with the shifted frequency expected if the reception was due to radiation transmitted a minute before with essentially the same earth motion and not to radiation transmitted from a possibly different site at a time implied by the assumed speed of light delay and with a different earth motion. This plan was carried out with the help of the NASA Horizons Telnet ephemeris which gives instantaneous position coordinates of hundreds of objects in the solar system besides planets and spacecraft, minute by minute. The coordinates are given with respect to a coordinate center such as the sun or the site of one of the DSN antennas near Madrid, Los Angeles and Canberra Australia. In summary, the results for radiation received each minute on Oct 7 1987 from 21:15 to 22:45 at Madrid were 2,292,134,xxx Hz observed and 2,292,144,xxx predicted according to the standard model and 2,292,136,xxx predicted according to the 1 minute model. That is, for the most part only the last three digits varied and in the 90 cases where the transmitter was clearly on, the 1 minute model was 800 times more accurate. The procedure used to derive these results was as follows: A)Obtain from the archived tracking records, fields that show the date, time and site and if the transmitter is on(zero) or off(1), at the site and the transmitter/exciter frequency at the site, and the Cumulative Doppler count and a code which is zero if the receiver is in lock. Make calculations according to p 8 of the Anderson paper(ref 2) The Exciter Assembly multiplies the Track Synthesizer Frequency~22MHz times 96 to produce the S Band carrier signal at ~2.2GHz…the current transmitter signal from the exciter is multiplied by 240/221 and a bias of 1MHz is added to the Doppler. That is 240/221 times 96 times the tr/ex frequency which is item 116 divided by 10 in the tracking records gives Tx, From this is subtracted the Doppler cumulative count difference which I call the down converted frequency and is calculated from items 31 and 32 in the tracking record plus 1MHz which is item 20 in the tracking record. This gives the received frequency, Tx*=Tx-dn cnv frq + 1MHz.. Also on page 8 and 9(ref2) At each tenth of a second the number of Doppler pulses are counted[This represents the number of upward zero crossings per second of the received radiation or rather that of a locally generated frequency in phase lock with the received radiation eg 2,292,xxx,xxx minus a fixed frequency eg 2,292,000,000. That is, each upward zero crossing of the downconverted version of the received frequency is made to occur at almost exactly the same time as a locally generated frequency-within .01 of the period, using the familiar phase locked loop procedure] The difference in cumulative total counts in successive minutes is the down converted representation of the received frequency during that time. According to the Tracking Data File specifications( ref 3), the high part of the Doppler is multiplied by 10,000 and added to the low part of the Doppler divided by 1,000 to yield the cumulative Doppler count. B)Obtain instantaneous data from Horizons Telnet ephemeris by selecting the option for no light time correction. 1)Obtain from telnet ephemeris, (target) sun xyz coordinates and sun velocity xyz components wrt (coordinate center)earth site eg LA at Tx time eg each minute from 9:45 to 17:45 Oct 7, 1987 and compute average velocity for each minute interval. 2)Obtain similarly, craft coordinates and craft velocity components and Light Time wrt site eg LA at Tx times+LT eg 15:30 to 1700 3)Compute craft coordinates and craft velocity components wrt sun. a)craft coord wrt sun = craft coord wrt earth site plus earth site coord wrt sun where earth site coord wrt sun = -sun coord wrt earth. b)craft velocity comp wrt sun = craft velocity comp wrt earth site minus earth site vel wrt sun where earth site velocity components wrt sun =- sun velocity components wrt earth site. C )Calculate projections of velocities at earth site transmitter onto direction in which transmission is going. Thus if the earth site’s total spin and orbital motion is toward the craft, the projection will be positive,+v, that is the Doppler shift factor, (1+(v)/c), will be greater than 1. And if vice versa or in the case of the craft velocity projection, the projection will be negative and (1+(-v)/c) will be less than 1. The projection in general is vcos(theta) where theta is the angle between the velocity vector and the direction vector from the emitter or receiver or reflector in the direction of the radiation. It is equal to the dot product of the direction vector and the velocity vector, When the direction vector is in the opposite direction of the velocity vector the magnitude of the dot product is the negative of the magnitude when the direction vector and velocity vectors are in the same direction.Thus the direction of the line between earth site and craft could be from the earth site or the craft site ie respectively plus or minus (c1-e1,c2-e2,c3-e3) From these considerations we calculated (1-v1/c)(1-v2/c)(1-v3/c)(1-v4/c) times the effective transmitted radiation where v1 was the projected velocity of the earth site at the time of transmission onto the radiation direction vector;v2, the projected velocity of the of the craft, a light time later onto the radiation direction vector from the earlier earth site to the later craft position. Similarly for v3 and v4. We also calculated (1-v5/c)^2 times (1-v6/c)^2 from similar projected velocities v5 and v6 which are the velocities of the earth motion and the craft motion projected on the direction line between them. The results(ref9) Discussion The conventional measurement of Spacecraft Doppler assumes that light speed extrapolates beyond a minute although this assumption has never been explicitly tested in a way that is not subject to other interpretations. That is, Roemer ascribed the differences in timing of the occultation and reappearance of some of the moons of Jupiter when the Earth is on the same side of the Sun as Jupiter or on the opposite side. But as Cassini, the expert on such observations at the time said, the differences could be due to differences in viewing angle. A similar argument applies to pulsars. Bradley’s aberration measurement of the position of polar stars when the Earth is moving in opposite directions ‘under’ these stars can also be ascribed to a nanosecond difference in response time which would change the direction to the star at opposite times of the year. Supposed radar reflections from surfaces of Venus etc from powerful radar emissions on Earth have such large error bars that the results could equally well be considered noise. The supposed 1.25 second delay in moon radar and lidar given secondary reflections and given the precision of the measurements a 1 second delay is also possible. Many circumlocutions and problems in modern physics are avoided if electromagnetic radiation is regarded not as moving photons or wave fronts or probabilistic photons but rather as an instantaneous force at a distance which involves a response delay that does not exeed a second or so. The results here suggest that the delay does not exceed a minute but could be less. References 1)Electric Gravity and Instantaneous Light, Ralph Sansbury, 1998, http://www.bestweb.net/~sansbury/book03.pdf 2) "Study of the anomalous acceleration of Pioneer 10 and 11", Anderson, J.D., Laing, P.A., Lau, E.L., Liu, A.S., Nieto, M.M., and Turyshev, S.G., Physics Review D, v65, 082004, (2002)) 3)http://pdsgeophys.wustl.edu/pds/mars...t/trk_2_25.txt 4) C++ compiler http://simtel.net/product.download.mirrors.php?id=17456 5)Doppler data in binary files and related documents with definitions of some terms.. http://windsor.gsfc.nasa.gov/spacecr...tdf/atdf_data/ 4) http://deepspace.jpl.nasa.gov/dsndoc...tationdata.cfm 5) http://descanso.jpl.nasa.gov/Monogra...rce_external=0 6) “Doppler Tracking of Planetary Spacecraft, Peter Kinman ,IEEE trans on microwave theory and techniques” vol 40,no.6,June 1992 p1199.. 7) http://tda.jpl.nasa.gov/tmo/progress...2-120/120B.pdf 8) “Radio Science Performance Analysis Software” , Morabito and Asmar ,TDA Progress Report 42-120, February 15, 1995. 9)http://www.bestweb.net/~sansbury/Doppler There should be no delay in the change in Doppler shift due to the spin and orbital motion of the Earth. When YOU accelerate, the Doppler shift YOU observe will change immediately. Paul |
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![]() "Paul B. Andersen" wrote in message ... | | "Ralph Sansbury" skrev i melding om... | DOPPLER TEST OF LIGHT SPEED DELAY FROM DISTANT SPACECRAFT | Doppler Test Shows Light Speed Does Not Extrapolate Beyond 1 Minute [snip] | There should be no delay in the change in Doppler shift due | to the spin and orbital motion of the Earth. | | When YOU accelerate, the Doppler shift YOU observe | will change immediately. | | Paul You didn't understand he word he said, did you? "There should be..." ROFL! Sansbury is discussing actual measurement, not "should be" measurement, you idiot. Androcles |
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![]() "Sam Wormley" wrote in message ... | Androcles should read at the papers | http://www.google.com/search?q=pione...te%3AarXiv.org Sam Wormley should read the paper at http://www.fourmilab.ch/etexts/einstein/specrel/www/ and then consider the concept "moving clocks run slow" Let a clock emit a frequency of 1 Hz be moving relative to an observer with velocity 0.866c t-vx/c^2 t' = _______________ sqrt(1-v^2/c^2) ref (Electrodynamics, section 3) = t * sqrt(1-v^2/c^2) = 1 * 0.5 = 0.5 seconds = 1 tick per 2 seconds Consider Einstein's doppler shift, to be found in the equation 1-cos(phi).v/c nu' = nu. ________________ sqrt(1-v^2/c^2) ref (Electrodynamics, section 7) Let phi = pi/2 1-0 nu' = 1 . ___________ 0.5 = 2 ticks per second. So according to Einstein, 0.5 = 2 Thus we have a proof by contradiction that Einstein's is bull****. Androcles |
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![]() "Androcles" skrev i melding ... Let a clock emit a frequency of 1 Hz be moving relative to an observer with velocity 0.866c t-vx/c^2 t' = _______________ sqrt(1-v^2/c^2) ref (Electrodynamics, section 3) = t * sqrt(1-v^2/c^2) = 1 * 0.5 = 0.5 seconds = 1 tick per 2 seconds Consider Einstein's doppler shift, to be found in the equation 1-cos(phi).v/c nu' = nu. ________________ sqrt(1-v^2/c^2) ref (Electrodynamics, section 7) Let phi = pi/2 1-0 nu' = 1 . ___________ 0.5 = 2 ticks per second. So according to Einstein, 0.5 = 2 Thus we have a proof by contradiction that Einstein's is bull****. Androcles Androcles, was my challenge posted in the thread "Honourable mentions" too difficult for you? It is relevant to the confusion you display above. Paul |
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So we're down to having a guy that can't explain how fast light is telling
us what is causing the apparent discrepency of the position of those probes? Ralphie IFS hasn't yet explained how an antenna not pointed at a particular probe can recover the data from that probe and hold it for hours or days before spitting it out to the rest of the receiver system. -- Bob May Losing weight is easy! If you ever want to lose weight, eat and drink less. Works every time it is tried! |
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